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Arithmetic Aptitude

Surds and Indices

Speed maths and word problems — the backbone of every placement and competitive paper.

About Surds and Indices

A surd is a root that cannot be worked out exactly, and an index is a power. Both are manipulated by a small set of laws, and questions in this topic are really tests of whether those laws are known well enough to be applied without hesitation.

What you need to understand

  • A power of a power multiplies the indices: a to the m, all raised to the n, is a to the mn.
  • Multiplying powers of the same base adds the indices; dividing them subtracts the indices.
  • Anything raised to the power zero is 1, and a negative index means the reciprocal.
  • A surd is in its simplest form when the number inside has no square factor left.
  • The square root of a product is the product of the square roots, which is what lets a surd be split.
  • Two surds can be multiplied or divided directly, but they can be added only if the parts inside are identical.

Formulas to remember

  • a^m x a^n = a^(m + n)
  • a^m / a^n = a^(m - n)
  • (a^m)^n = a^(mn)
  • a^0 = 1
  • Root of (a x b) = root of a x root of b
  • Root of (k squared x m) = k x root of m

How to work through these questions

  1. Deal with the indices first and the numbers afterwards, because the index laws are mechanical.
  2. When more than one law applies, work from the innermost bracket outwards.
  3. To simplify a surd, look for the largest square factor of the number inside it.
  4. To solve an equation with the unknown in the index, write both sides as powers of the same base and then equate the indices.
  5. Check by substituting a small numerical case, which catches a misapplied law immediately.

Mistakes that cost marks

  • Adding the indices when the powers are being multiplied inside a bracket instead of multiplying them.
  • Assuming the square root of a sum equals the sum of the square roots.
  • Leaving a surd unsimplified when the question asks for its simplest form.
  • Taking the square outside the root instead of its square root, so that root 48 becomes 48 root 2.
  • Substituting the number for the index, which turns a power into an ordinary product.

Worked example

Simplify the square root of 448.
  1. Look for the largest square factor of 448. Since 448 = 64 x 7 and 64 is a perfect square, that factor is 64.
  2. So the square root of 448 is the square root of 64 multiplied by the square root of 7.
  3. The square root of 64 is 8, which gives 8 root 7.
  4. Check: 8 root 7 squared is 64 x 7 = 448, so the simplification is correct.
Answer: 8 root 7

Practice questions with answers

A few Surds and Indices questions with the full solution shown, so you can see how the method is applied before you attempt the timed set.

Question 1
Find the value of $(2^{3})^{2} \div 2^{4}$.
  • A 16777216
  • B 4
  • C 1024
  • D 48
Answer: Option B — with explanation
A power of a power multiplies the indices, and division subtracts them. $(2^{3})^{2} = 2^{6}$, and $2^{6} \div 2^{4} = 2^{2} = 4$. Common mistakes - subtracted the two values instead of the indices: 48 - multiplied the indices again at the division step: 16777216 - added the indices instead of subtracting them: 1024
Question 2
Solve for x: $5^{x + 3} = 625$.
  • A 4
  • B 1
  • C 1.33
  • D 7
Answer: Option B — with explanation
Write the right hand side as a power of 5: $625 = 5^{4}$. So $x + 3 = 4$, giving $x = 4 - 3 = 1$. Common mistakes - divided by the constant instead of subtracting it: 1.33 - added the constant instead of subtracting it: 7 - read off the index of the right hand side and stopped: 4
Question 3
Express the surd $\sqrt{486}$ in simplest form.
  • A $81\sqrt{6}$
  • B $6\sqrt{9}$
  • C $\sqrt{486}$
  • D $9\sqrt{6}$
Answer: Option D — with explanation
Look for the largest square factor of 486: $486 = 81 \times 6$. So $\sqrt{486} = \sqrt{81} \times \sqrt{6} = 9\sqrt{6}$. Common mistakes - swapped the numbers inside and outside the surd: $6\sqrt{9}$ - left the surd untouched: $\sqrt{486}$ - took the square outside instead of its square root: $81\sqrt{6}$
Question 4
Simplify $(2^{3})^{2} \div 2^{4}$.
  • A 1024
  • B 16777216
  • C 48
  • D 4
Answer: Option D — with explanation
A power of a power multiplies the indices, and division subtracts them. $(2^{3})^{2} = 2^{6}$, and $2^{6} \div 2^{4} = 2^{2} = 4$. Common mistakes - subtracted the two values instead of the indices: 48 - multiplied the indices again at the division step: 16777216 - added the indices instead of subtracting them: 1024
Question 5
Find x if $2^{x + 2} = 32$.
  • A 2.5
  • B 5
  • C 3
  • D 7
Answer: Option C — with explanation
Write the right hand side as a power of 2: $32 = 2^{5}$. So $x + 2 = 5$, giving $x = 5 - 2 = 3$. Common mistakes - read off the index of the right hand side and stopped: 5 - added the constant instead of subtracting it: 7 - divided by the constant instead of subtracting it: 2.5

Frequently asked questions

What is a surd?

A surd is a root of a number that cannot be written exactly as a fraction or a terminating decimal. The square root of 2 is a surd, while the square root of 9 is not, because it is exactly 3.

How do I know when a surd is in its simplest form?

When the number inside the root has no square factor left except 1. Root 12 is not simplified, because 12 has the square factor 4 and it becomes 2 root 3.

Can I add two surds?

Only if the numbers inside the roots are the same. Root 3 plus root 3 is 2 root 3, but root 3 plus root 5 cannot be combined.

What does a negative index mean?

It means the reciprocal of the positive power. Two to the power minus three is one over two cubed, which is one eighth.

Take the Surds and Indices test

Two timed papers on the same syllabus — sit the foundation paper first, then the advanced one. Both use the real exam paper format with a full step-by-step review of every question once you submit.

Set 01 • Foundation Level
Surds and Indices — Foundation Paper
25 Questions
30 Minutes
+2 / −0.5 Marking
Start this paper
Set 02 • Advanced Level
Surds and Indices — Advanced Paper
25 Questions
30 Minutes
+2 / −0.5 Marking
Start this paper

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