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MSBSHSE • Class 6 • Mathematics • Ch 17
Estimated Time: 45 Mins
Study Progress: In Progress

Geometrical Constructions

In Class 7 Mathematics, Chapter 14 "Constructions and Tilings" bridges practical geometric drafting and artistic spatial mathematics. Aligned with the 2026–27 NCERT Ganita Prakash curriculum, this master material covers compass-and-straightedge constructions (perpendicular bisectors, angle bisectors, special angles $60^\circ, 90^\circ, 45^\circ, 30^\circ$) and the mathematics of Tilings (Tessellations), explaining why only three regular polygons can tile a flat plane without gaps.

🐝 Have You Ever Wondered?

Why do bees build hexagonal honeycombs instead of circles or squares?

If bees built circular cells, gaps would appear between adjacent circles, wasting precious wax. If they used squares or triangles, the cells would pack without gaps, but hexagons have the shortest perimeter for the same interior area—meaning bees store the maximum honey using the minimum beeswax!

Covering a flat floor with repeating geometric tiles without any gaps or overlaps is called a Tessellation (Tiling). Why can equilateral triangles, squares, and hexagons tile a floor, but regular pentagons leave awkward gaps?

The answer is an exact angular law: the interior angles meeting at every vertex must add up to strictly $360^\circ$! With a pair of compasses and a straightedge, you can construct these precise angles and create breathtaking geometric tile patterns.

Why This Chapter Matters

In Class 7 Mathematics, Chapter 14 "Constructions and Tilings" bridges practical geometric drafting and artistic spatial mathematics. Aligned with the 2026–27 NCERT Ganita Prakash curriculum, this master material covers compass-and-straightedge constructions (perpendicular bisectors, angle bisectors, special angles $60^\circ, 90^\circ, 45^\circ, 30^\circ$) and the mathematics of Tilings (Tessellations), explaining why only three regular polygons can tile a flat plane without gaps.

Before You Begin (Prerequisites)

  • Basic compass handling: drawing arcs and circles of fixed radii.
  • Perpendicular lines and angle measurements from Chapter 5.
  • Sum of angles around a point is strictly $360^\circ$.

What You Will Learn (Core Objectives)

  • Construct the Perpendicular Bisector of a given line segment using ruler and compass.
  • Construct the Angle Bisector of any given angle.
  • Construct standard geometric angles ($60^\circ, 120^\circ, 90^\circ, 45^\circ, 30^\circ$) without a protractor.
  • Define tessellation (tiling) and state the Vertex Angle Sum condition ($\sum \theta = 360^\circ$).
  • Explain why only Equilateral Triangles, Squares, and Regular Hexagons form regular tessellations.

Chapter Roadmap & Progression

1 1. Fundamental Compass Construction...
2 2. Constructing Special Angles ($60...
3 3. The Mathematics of Tilings: Why...

Complete Concept Guide (100% Curriculum Coverage)

1. Fundamental Compass Constructions: Bisectors

1. Perpendicular Bisector of a Segment

A perpendicular bisector is a line that divides a line segment into two equal halves at an exact right angle ($90^\circ$).

Steps of Construction:

  1. Given segment $AB$, open the compass to a radius strictly greater than half of $AB$.
  2. With center $A$, draw two arcs—one above $AB$ and one below $AB$.
  3. With center $B$ and the exact same radius, draw two arcs intersecting the previous arcs at points $P$ and $Q$.
  4. Draw the straight line joining $P$ and $Q$. Line $PQ$ is the perpendicular bisector of $AB$!
2. Bisector of an Angle

An angle bisector is a ray that cuts an angle into two equal halves ($\angle 1 = \angle 2 = \frac{1}{2}\angle \text{Original}$).

Steps of Construction:

  1. Given $\angle ABC$, with center $B$, draw an arc cutting arm $BA$ at $P$ and arm $BC$ at $Q$.
  2. With center $P$ and radius $> \frac{1}{2}PQ$, draw an arc inside the angle.
  3. With center $Q$ and the same radius, draw an arc intersecting the previous arc at $R$.
  4. Draw ray $BR$. Ray $BR$ bisects $\angle ABC$!
4. Pitfall & Examiner Trap
⚠️ Trap: Opening Compass Less Than Half the Segment
If the compass radius is less than or equal to half of $AB$, the arcs drawn from $A$ and $B$ will never meet! Always ensure radius $> \frac{1}{2}AB$.
5. Why This Matters in Life

Road planners use perpendicular bisectors to find the ideal location for a hospital equidistant from two neighboring towns.

2. Constructing Special Angles ($60^\circ, 120^\circ, 90^\circ, 45^\circ, 30^\circ$)

1. The Master $60^\circ$ Arc

An equilateral triangle has all angles equal to $60^\circ$ and all sides equal to radius $r$. Therefore, keeping the compass radius fixed naturally constructs $60^\circ$!

  • $60^\circ$ Angle: Draw an arc from vertex $O$ cutting the ray at $P$. With center $P$ and same radius, cut the arc at $Q$. Ray $OQ$ forms an exact $\mathbf{60^\circ}$ angle.
  • $120^\circ$ Angle: From $Q$, cut the arc a second time with the same radius → $\mathbf{120^\circ}$.
  • $90^\circ$ Angle: Bisect the angle between $60^\circ$ and $120^\circ$ → $60^\circ + \frac{60^\circ}{2} = \mathbf{90^\circ}$.
  • $30^\circ$ Angle: Bisect the $60^\circ$ angle → $\mathbf{30^\circ}$.
  • $45^\circ$ Angle: Bisect the $90^\circ$ angle → $\mathbf{45^\circ}$.
3. Concrete Worked Example

Example: How can you construct an angle of $75^\circ$ using compass and ruler only?

Reasoning: $75^\circ$ lies exactly halfway between $60^\circ$ and $90^\circ$ ($60^\circ + \frac{30^\circ}{2} = 75^\circ$).

Construction: Construct $60^\circ$ and $90^\circ$, then bisect the $30^\circ$ angle between their arms!

5. Why This Matters in Life

Carpenters and metal fabricators use $90^\circ$ and $45^\circ$ miter joints to construct sturdy window frames and picture borders.

3. The Mathematics of Tilings: Why Only 3 Regular Polygons Tile a Plane

1. What is a Tessellation?

A tessellation (tiling) is a pattern of geometric shapes that completely covers a two-dimensional surface with zero gaps and zero overlapping.

2. The Vertex Angle Sum Law

For regular polygons of the same kind to fit together around a single vertex, the interior angles meeting at that vertex must add up to exactly $360^\circ$:

$$\mathbf{k \times \theta = 360^\circ} \quad (\text{where } k \text{ is an integer } \ge 3)$$

Regular PolygonInterior Angle ($\theta$)$360^\circ \div \theta$Can it Tile Alone?
Equilateral Triangle$60^\circ$$\frac{360}{60} = 6$ (integer)YES (6 meet at a vertex)
Square$90^\circ$$\frac{360}{90} = 4$ (integer)YES (4 meet at a vertex)
Regular Pentagon$108^\circ$$\frac{360}{108} = 3.33$NO (Leaves a gap of $36^\circ$!)
Regular Hexagon$120^\circ$$\frac{360}{120} = 3$ (integer)YES (3 meet at a vertex)
Regular Octagon$135^\circ$$\frac{360}{135} = 2.67$NO (Needs squares to fill gaps)

Conclusion: There are ONLY THREE regular polygons that can form a regular tiling of a plane: Triangles, Squares, and Hexagons!

4. Pitfall & Examiner Trap
⚠️ Trap: Believing Pentagonal Tilings Exist with Regular Pentagons
Three regular pentagons give $3 \times 108^\circ = 324^\circ$ (leaving a $36^\circ$ gap); four give $432^\circ$ (overlapping). A regular pentagon can NEVER tile a plane alone!
5. Why This Matters in Life

The historic Mughal monuments in Agra and Delhi (such as the Taj Mahal and Red Fort) feature intricate marble *Jali* lattices and mosaic floors based on these exact geometric tiling laws.

Visual Learning & Conceptual Map

The Three Regular Tilings of the Plane

Angles meeting at each vertex sum to strictly $360^\circ$
TRIANGLE TILING
$6 \times 60^\circ$
$= 360^\circ$ (6 triangles)
SQUARE TILING
$4 \times 90^\circ$
$= 360^\circ$ (4 squares)
HEXAGON TILING
$3 \times 120^\circ$
$= 360^\circ$ (3 hexagons)

Chapter Summary & 10 Key Takeaways

Takeaway 1
Perpendicular Bisector: Divides a line segment into two equal halves at $90^\circ$, constructed using compass arcs of radius $> \frac{1}{2}\text{length}$.
Takeaway 2
Angle Bisector: A ray dividing an angle into two equal halves, constructed using intersecting arcs.
Takeaway 3
Special Angles: $60^\circ$ is constructed directly using the circle radius; bisecting yields $30^\circ$; bisecting $60^\circ \to 120^\circ$ yields $90^\circ$; bisecting $90^\circ$ yields $45^\circ$.
Takeaway 4
Tessellation (Tiling): Covering a 2D surface with shapes leaving zero gaps and zero overlaps.
Takeaway 5
Tiling Condition: The interior angles of shapes meeting around any vertex must sum to exactly $360^\circ$.
Takeaway 6
The Three Regular Tilings: Only Equilateral Triangles ($60^\circ$), Squares ($90^\circ$), and Regular Hexagons ($120^\circ$) can tile a plane alone.

Check Your Understanding (Diagnostic Practice Questions)

Diagnostic questions testing core conceptual clarity. Answers are hidden initially — solve each problem first, then click to reveal the step-by-step verified solution.

1
Why can regular octagons (interior angle $135^\circ$) not tile a floor alone?
Reveal Answer & Explanation
Answer: Two octagons give $270^\circ$ (leaving a $90^\circ$ gap); three give $405^\circ$ (overlapping). Since $360$ is not divisible by $135$, gaps occur (which can only be filled by squares).
Check if $360^\circ \div 135^\circ$ is a whole number.
2
How many equilateral triangles meet at each vertex in a regular triangular tiling?
Reveal Answer & Explanation
Answer: 6 triangles
Each interior angle is $60^\circ$. $360^\circ \div 60^\circ = 6$.
3
If an angle of $120^\circ$ is bisected, and one of the resulting angles is bisected again, what is the measure of the smallest angle obtained?
Reveal Answer & Explanation
Answer: $30^\circ$
$120^\circ \div 2 = 60^\circ$, and $60^\circ \div 2 = 30^\circ$.
4
What is the minimum compass radius needed when constructing the perpendicular bisector of an $8\text{ cm}$ line segment?
Reveal Answer & Explanation
Answer: Any radius strictly greater than $4\text{ cm}$ ($r > 4\text{ cm}$).
The radius must be greater than half the segment length ($8 \div 2 = 4\text{ cm}$).
5
How can you construct an angle of $105^\circ$ using compass and ruler only?
Reveal Answer & Explanation
Answer: Construct $90^\circ$ and $120^\circ$, then bisect the $30^\circ$ angle between them ($90^\circ + 15^\circ = 105^\circ$).
$105^\circ$ is halfway between $90^\circ$ and $120^\circ$.
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