Home
School Test Series
Jharkhand Academic Council (JAC)
Class XI
Chemistry
Chemical Bonding and Molecular Structure (Set 01 (Foundation Level))

Select Medium:

🇬🇧 English Medium Active 🇮🇳 हिन्दी माध्यम

Jharkhand Academic Council (JAC) Class XI Chemistry Set 01 (Foundation Level) English Medium 100% Free Practice Test

JAC Board Class 11 Chemistry: Chemical Bonding and Molecular Structure Online Test (Set 01 (Foundation Level)) | Jharkhand Board

Chemical Bonding and Molecular Structure — Set 01 (Foundation Level)

Practise free online MCQ mock test for JAC Board Class 11 Chemistry chapter 'Chemical Bonding and Molecular Structure'. 20 MCQs with timer countdown, detailed explanations, and instant results as per board syllabus.

📝

20 MCQs

Questions

⏱️

20 Mins

Duration

🎯

20 Marks

Total Marks

➕

+1.0

Per Correct

🛡️

0.0

Negative Mark

🌐

English

Language

Start Test Now (English Medium)

Instant Scorecard Step-by-Step Solutions JCERT / JAC Curriculum

Chapter Study Guide & In-Depth Notes

Master the key concepts, vocabulary, and high-yield questions before starting the test.

3 Sections

Chapter Overview & Core Concepts: Chemical Bonding and Molecular Structure

Class 11 Study Guide

Mastering Chemical Bonding and Molecular Structure in Class 11 provides critical subject intuition, analytical skills, and examination readiness.

Examinations test fundamental principles, definitions, cause-and-effect reasoning, and real-world applications under timed conditions.

Core Moral & Key Takeaway:

Grasping core concepts and practicing with timed chapter-wise CBT tests guarantees top performance in board exams.

Key Terminology, Definitions & Principles

Glossary & Concepts

Term / Formula	Type	Definition / Meaning	Explanation / Notes	Example / Usage
Core Concept	Principle	Primary concept governing Chemical Bonding and Molecular Structure.	मुख्य सिद्धांत	"Understand and apply the principle accurately."
Analytical Deduction	Skill	Evaluating evidence to draw correct conclusions.	तार्किक विश्लेषण	"Examine question clues systematically."

Key Features & Devices Explored:

Systematic Elimination

Eliminate distractor choices before selecting the best answer.

Pacing & Accuracy

Complete each question within 60 seconds to maintain steady momentum.

High-Yield Revision Points & Solved Board Exam Q&A

Revision Notes

⚡ High-Yield Exam Takeaways:

Review all key textbook terms, definitions, and formulas.
Pay attention to units, boundary values, and key keywords in questions.
Solve Foundation Set 01 to build confidence, followed by Advanced Set 02 for exam excellence.

Frequently Asked Questions & Model Answers:

Q1 How should students prepare for Chemical Bonding and Molecular Structure exams?

Answer: Read the chapter thoroughly, practice step-by-step solved examples, memorize key definitions, and evaluate preparation using timed online CBT mock tests.

Sample Questions Preview

Free Sneak Peek

Here is a sneak peek of the questions included in this test set. Test your preparation by viewing the answer and detailed explanation before starting the timed exam.

What is the shape and bond angle of the Methane (CH_4), Ammonia (NH_3), and Water (\(H_2O\)) molecules according to VSEPR Theory? / VSEPR सिद्धांत के अनुसार CH_4, NH_3 तथा H_2O की ज्यामिति एवं बंध कोण क्या हैं?

VSEPR सिद्धांत के अनुसार मीथेन (CH_4), अमोनिया (NH_3), और पानी (\(H_2O\)) अणुओं का आकार और बंधन कोण क्या है? / VSEPR सिद्धांत के अनुसार CH_4, NH_3 तथा H_2O की ज्यामिति एवं बंध कोण क्या हैं?

CH_4: Planar; NH_3: Linear; H_2O: Bentसीएच₄: तलीय; NH_3: रैखिक; H_2O: मुड़ा हुआ

CH_4: Tetrahedral (109.5°); NH_3: Trigonal Pyramidal (107°); H_2O: BentV-shaped (104.5°)

All three are regular Tetrahedral with 109.5° angleतीनों 109.5° कोण के साथ नियमित चतुष्फलकीय हैं

CH_4: 90°; NH_3: 120°; H_2O: 180°सीएच₄: 90°; एनएच₃: 120°; H_2O: 180°

Correct Answer: Option B

Explanation:

All three have sp^3 hybridization (4 electron pairs). Lone pairs repel more strongly than bond pairs (lp-lp > lp-bp > bp-bp), reducing the bond angle from 109.5° in CH_4 (0 lp) to 107° in NH_3 (1 lp) and 104.5° in H_2O (2 lp).

एकाकी युग्म-बंध युग्म प्रतिकर्षण के कारण बंध कोण 109.5° से घटकर 107° व 104.5° हो जाता है।

What is the hybridization and geometric shape of Phosphorus Pentachloride (PCl_5) and why are its axial bonds longer than equatorial bonds? / PCl_5 का संकरण एवं ज्यामिति क्या है तथा इसके अक्षीय बंध निरक्षीय बंधों से बड़े क्यों होते हैं?

फॉस्फोरस पेंटाक्लोराइड (पीसीएल₅) का संकरण और ज्यामितीय आकार क्या है और इसके अक्षीय बंधन भूमध्यरेखीय बंधन से अधिक लंबे क्यों हैं? / पीसीएल₅ का संकरण एवं सिमित क्या है तथा इसके अक्षीय बंध निरक्षीय बंधों से बड़े क्यों होते हैं?

dsp^2 hybridization (Square Planar)dsp^2 संकरण (स्क्वायर प्लेनर)

sp^3 hybridization (Tetrahedral)एसपी³ संकरण (टेट्राहेड्रल)

sp^3d hybridization (Trigonal Bipyramidal); Axial P-Cl bonds experience greater repulsion from 3 equatorial bonds at 90°sp^3d संकरण (त्रिकोणीय द्विपिरामिडी); 3 निरक्षीय बंधों से 90° पर अधिक प्रतिकर्षण के कारण अक्षीय बंध लंबे होते हैं

sp^3d^2 hybridization (Octahedral); All bonds are equalsp^3d^2 संकरण (ऑक्टाहेड्रल); सभी बंधन समान हैं

Correct Answer: Option C

Explanation:

PCl_5 has sp^3d hybridization forming a trigonal bipyramidal geometry with 3 equatorial bonds (120°) and 2 axial bonds (90°). Because axial bonds suffer 3 bp-bp repulsions at 90°, they are longer and weaker (240 pm vs 202 pm). / 90° पर अधिक प्रतिकर्षण के कारण 2 अक्षीय बंध लंबे और दुर्बल होते हैं।

PCl_5 में 3 भूमध्यरेखीय बंध (120°) और 2 अक्षीय बंध (90°) के साथ एक त्रिकोणीय द्विपिरामिडीय ज्यामिति बनाने वाला स्पंद संकरण होता है। क्योंकि अक्षीय बंधन 90° पर 3 बीपी-बीपी प्रतिकर्षण झेलते हैं, वे लंबे और कमजोर होते हैं (240 बजे बनाम 202 बजे)। / 90° पर अधिक प्रतिकर्षण के कारण 2 अक्षीय बंध लंबे और दुर्बल होते हैं।

How Chapter-Wise Online CBT Tests Build Winning Habits for Future Competitive Exams

Focused chapter-wise CBT practice builds the speed, mental stamina, and analytical discipline required to ace CUET, JEE Main, NEET UG, NDA, CA Foundation, and College Entrance Exams.

Competitive Edge

Real-Time Clock Awareness & Pacing

समय प्रबंधन एवं गति नियंत्रण

In school examinations, students write answers without active pacing. In national entrance tests, students have barely 45-60 seconds per MCQ. Practicing with a 20-minute timer instills instinctive time-budgeting and prevents last-minute exam panic.

Mastery of the Elimination Technique

विकल्प निष्कासन विधि में दक्षता

Top rankers in competitive exams rarely compute every problem blindly. They spot subtle traps, evaluate extreme values, and eliminate 2 out of 4 distractors within seconds. Our 4-option sets teach critical distractor analysis.

CBT Screen Stamina & Digital Comfort

कंप्यूटर आधारित परीक्षा का सहज अभ्यास

Almost all major national exams (CUET, JEE, NEET, SSC, Banking) are 100% computer-based. Students who only study on paper experience eye strain and navigation mistakes on exam day. Early CBT practice creates effortless digital fluency.

Immunity to Negative Marking

सटीकता और नकारात्मक अंकन से सुरक्षा

Careless errors—such as misreading "NOT" or "EXCEPT"—ruin thousands of competitive aspirations each year. Regular objective testing builds the habit of double-checking question keywords before locking answers.

Instant Diagnostic Feedback Loop

तत्काल त्रुटि निवारण एवं आत्म-मूल्यांकन

Traditional paper tests take weeks to grade, by which time the student has forgotten their thought process. TargetExams provides instant scorecards and step-by-step solutions while the conceptual puzzle is still fresh.

Syllabus Concepts Evaluated in this Chapter

This test series specifically evaluates the core competencies and learning objectives outlined in the official syllabus:

Core definitions, fundamental theorems, and essential concepts of this chapter.
Step-by-step mathematical reasoning and deductive problem-solving.
Application of standard formulas and operations in real-world scenarios.
Critical examination of common exam pitfalls and misleading options.
Higher-order thinking skill (HOTS) questions to prepare for school examinations.
Speed and accuracy mastery under standard timed CBT exam conditions.

Exam Rules & Test Taking Guidelines

Total Questions: The test consists of exactly 20 objective type questions.
Time Allowed: 20 Minutes countdown timer begins as soon as the test launches.
Marking Scheme: +1.0 mark is awarded for each correct answer.
Zero Penalty: There is 0.0 negative marking for incorrect or unattempted questions.
Question Palette: Freely navigate between questions and flag questions for later review.
Review & Solutions: Access instant scorecard and full step-by-step solutions upon submission.

Frequently Asked Questions (FAQs)

Yes! Foundation Practice Set 01 for every chapter in Jharkhand Academic Council (JAC) Class XI Chemistry is 100% free to attempt. Students can test their knowledge without any payment or hidden fees.

This page is dedicated to English Medium. You can also attempt this test in Hindi Medium by clicking the switcher at the top.

Absolutely. All 20 multiple-choice questions are strictly designed in line with the latest guidelines, covering both basic conceptual understanding and higher-order thinking skills.

The test contains 20 MCQs to be solved in 20 minutes. Each question carries +1.0 mark for a correct answer, and there is zero (0.0) negative marking for incorrect answers.

Yes. Immediately upon submitting your test, you receive a comprehensive performance summary including your total score, accuracy percentage, time spent per question, and full step-by-step explanations for all 20 questions.

Chemical Bonding and Molecular Structure (Set 01 (Foundation Level))

20 MCQs • 20 Mins • 100% Free Practice Test

JAC Board Class 11 Chemistry: Chemical Bonding and Molecular Structure Online Test (Set 01 (Foundation Level)) | Jharkhand Board

Chapter Study Guide & In-Depth Notes

Chapter Overview & Core Concepts: Chemical Bonding and Molecular Structure