Select Medium:

🇬🇧 English Medium Active 🇮🇳 हिन्दी माध्यम

National Institute of Open Schooling (NIOS) Class XII Physics (312) Set 02 (Advanced Level) English Medium 100% Free Practice Test

National Institute of Open Schooling (NIOS) Class XII Physics (312): Kinetic Theory of Gases Online Test (Set 02 (Advanced Level)) | TargetExams

Kinetic Theory of Gases — Set 02 (Advanced Level)

Take free online mock test for National Institute of Open Schooling (NIOS) Class XII Physics (312) chapter 'Kinetic Theory of Gases'. 20 MCQs, 20 minutes, detailed solutions & score analysis.

📝

20 MCQs

Questions

⏱️

20 Mins

Duration

🎯

20 Marks

Total Marks

➕

+1.0

Per Correct

🛡️

0.0

Negative Mark

🌐

English

Language

Start Test Now (English Medium)

Instant Scorecard Step-by-Step Solutions NIOS Self-Learning Material (SLM) Pattern

Chapter Study Guide & In-Depth Notes

Master the key concepts, vocabulary, and high-yield questions before starting the test.

3 Sections

Chapter Overview & Core Concepts: Kinetic Theory of Gases

Class 12 Study Guide

Mastering Kinetic Theory of Gases in Class 12 provides critical subject intuition, analytical skills, and examination readiness.

Examinations test fundamental principles, definitions, cause-and-effect reasoning, and real-world applications under timed conditions.

Core Moral & Key Takeaway:

Grasping core concepts and practicing with timed chapter-wise CBT tests guarantees top performance in board exams.

Key Terminology, Definitions & Principles

Glossary & Concepts

Term / Formula	Type	Definition / Meaning	Explanation / Notes	Example / Usage
Core Concept	Principle	Primary concept governing Kinetic Theory of Gases.	मुख्य सिद्धांत	"Understand and apply the principle accurately."
Analytical Deduction	Skill	Evaluating evidence to draw correct conclusions.	तार्किक विश्लेषण	"Examine question clues systematically."

Key Features & Devices Explored:

Systematic Elimination

Eliminate distractor choices before selecting the best answer.

Pacing & Accuracy

Complete each question within 60 seconds to maintain steady momentum.

High-Yield Revision Points & Solved Board Exam Q&A

Revision Notes

⚡ High-Yield Exam Takeaways:

Review all key textbook terms, definitions, and formulas.
Pay attention to units, boundary values, and key keywords in questions.
Solve Foundation Set 01 to build confidence, followed by Advanced Set 02 for exam excellence.

Frequently Asked Questions & Model Answers:

Q1 How should students prepare for Kinetic Theory of Gases exams?

Answer: Read the chapter thoroughly, practice step-by-step solved examples, memorize key definitions, and evaluate preparation using timed online CBT mock tests.

Sample Questions Preview

Free Sneak Peek

Here is a sneak peek of the questions included in this test set. Test your preparation by viewing the answer and detailed explanation before starting the timed exam.

In the microscopic derivation of gas pressure for $N$ identical molecules of mass $m$ in a cubic box of side $L$ (shown below):

A molecule with velocity component $v_x$ undergoes elastic collisions with the perpendicular face of area $L^2$. Considering all molecules with isotropic velocity distribution $\overline{v_x^2} = \frac{1}{3} v_{\text{rms}}^2$, the pressure exerted on the face is:

पक्ष के एक घन बॉक्स में $N$ द्रव्यमान के समान अणुओं $m$ के लिए गैस के दबाव की सूक्ष्म व्युत्पत्ति में $L$ (नीचे दिखाया गया है):

[[एच0एच]]

वेग घटक वाला एक अणु $v_x$ क्षेत्र के लंबवत चेहरे के साथ लोचदार टकराव से गुजरता है $L^2$। आइसोट्रोपिक वेग वितरण वाले सभी अणुओं को ध्यान में रखते हुए $\overline{v_x^2} = \frac{1}{3} v_{\text{rms}}^2$, चेहरे पर लगाया गया दबाव है:

$P = \frac{1}{3}\rho v_{\text{rms}}^2$

$P = \frac{1}{2}\rho v_{\text{rms}}^2$

$P = \rho v_{\text{rms}}^2$

$P = \frac{2}{3}\rho v_{\text{rms}}^2$

Correct Answer: Option A

Explanation:

Step-by-step solution:

1. In each elastic collision with the wall at $x = L$, momentum change is $\Delta p_x = 2 m v_x$.

2. The time between successive collisions of this molecule with the same wall is $\Delta t = \frac{2L}{v_x}$.

3. Average force contributed by this molecule: $F_i = \frac{\Delta p_x}{\Delta t} = \frac{m v_{xi}^2}{L}$.

4. Total force on the wall of area $A = L^2$:

$$F_{\text{total}} = \sum_{i=1}^N \frac{m v_{xi}^2}{L} = \frac{m}{L} N \overline{v_x^2}$$

5. By isotropy, $\overline{v_x^2} = \frac{1}{3} v_{\text{rms}}^2$, and volume is $V = L^3$:

$$P = \frac{F_{\text{total}}}{L^2} = \frac{N m}{L^3} \left(\frac{1}{3} v_{\text{rms}}^2\right) = \frac{1}{3}\rho v_{\text{rms}}^2$$

चरण-दर-चरण समाधान:

1. $x = L$ पर दीवार के साथ प्रत्येक लोचदार टकराव में, गति परिवर्तन $\Delta p_x = 2 m v_x$ होता है।

2. एक ही दीवार से इस अणु के क्रमिक टकराव के बीच का समय $\Delta t = \frac{2L}{v_x}$ है।

3. इस अणु द्वारा योगदान किया गया औसत बल: $F_i = \frac{\Delta p_x}{\Delta t} = \frac{m v_{xi}^2}{L}$।

4. क्षेत्र की दीवार पर कुल बल $A = L^2$:

$$F_{\text{total}} = \sum_{i=1}^N \frac{m v_{xi}^2}{L} = \frac{m}{L} N \overline{v_x^2}$$

5. आइसोट्रॉपी द्वारा, $\overline{v_x^2} = \frac{1}{3} v_{\text{rms}}^2$, और आयतन है $V = L^3$:

$$P = \frac{F_{\text{total}}}{L^2} = \frac{N m}{L^3} \left(\frac{1}{3} v_{\text{rms}}^2\right) = \frac{1}{3}\rho v_{\text{rms}}^2$$

A chamber containing Helium ($\text{He}$, $M_1 = 4.0\text{ g/mol}$) and another containing an unknown hydrocarbon gas are set up at identical temperature and pressure, as depicted below:

Helium effuses through the pinhole into the vacuum at a rate that is $4.0\text{ times}$ faster than the unknown hydrocarbon. The molar mass $M_{\text{unknown}}$ of the hydrocarbon is:

एक कक्ष जिसमें हीलियम ($\text{He}$, $M_1 = 4.0\text{ g/mol}$ ) और एक अन्य कक्ष जिसमें अज्ञात हाइड्रोकार्बन गैस है, समान तापमान और दबाव पर स्थापित किए गए हैं, जैसा कि नीचे दर्शाया गया है:

[[एच0एच]]

हीलियम पिनहोल के माध्यम से निर्वात में उस दर से प्रवाहित होता है जो अज्ञात हाइड्रोकार्बन की तुलना में $4.0\text{ times}$ तेज है। हाइड्रोकार्बन का दाढ़ द्रव्यमान $M_{\text{unknown}}$ है:

$16.0\text{ g/mol}$

$64.0\text{ g/mol}$

$32.0\text{ g/mol}$

$128.0\text{ g/mol}$

Correct Answer: Option B

Explanation:

Step-by-step solution:

1. By Graham's law of effusion, the effusion rate $r$ of a gas through a small pinhole at constant $(P, T)$ is inversely proportional to the square root of its molar mass:

$$\frac{r_{\text{He}}}{r_{\text{unknown}}} = \sqrt{\frac{M_{\text{unknown}}}{M_{\text{He}}}}$$

2. Given $\frac{r_{\text{He}}}{r_{\text{unknown}}} = 4.0$ and $M_{\text{He}} = 4.0\text{ g/mol}$:

$$4.0 = \sqrt{\frac{M_{\text{unknown}}}{4.0}}$$

3. Squaring both sides:

$$16.0 = \frac{M_{\text{unknown}}}{4.0} \implies M_{\text{unknown}} = 16.0 \times 4.0 = 64.0\text{ g/mol}$$

चरण-दर-चरण समाधान:

1. ग्राहम के प्रवाह के नियम के अनुसार, स्थिर $(P, T)$ पर एक छोटे पिनहोल के माध्यम से गैस की प्रवाह दर $r$ उसके दाढ़ द्रव्यमान के वर्गमूल के व्युत्क्रमानुपाती होती है:

$$\frac{r_{\text{He}}}{r_{\text{unknown}}} = \sqrt{\frac{M_{\text{unknown}}}{M_{\text{He}}}}$$

2। दिया गया है $\frac{r_{\text{He}}}{r_{\text{unknown}}} = 4.0$ और $M_{\text{He}} = 4.0\text{ g/mol}$:

$$4.0 = \sqrt{\frac{M_{\text{unknown}}}{4.0}}$$

3. दोनों पक्षों का वर्ग करने पर:

$$16.0 = \frac{M_{\text{unknown}}}{4.0} \implies M_{\text{unknown}} = 16.0 \times 4.0 = 64.0\text{ g/mol}$$

How Chapter-Wise Online CBT Tests Build Winning Habits for Future Competitive Exams

Focused chapter-wise CBT practice builds the speed, mental stamina, and analytical discipline required to ace CUET, JEE Main, NEET UG, NDA, CA Foundation, and College Entrance Exams.

Competitive Edge

Real-Time Clock Awareness & Pacing

समय प्रबंधन एवं गति नियंत्रण

In school examinations, students write answers without active pacing. In national entrance tests, students have barely 45-60 seconds per MCQ. Practicing with a 20-minute timer instills instinctive time-budgeting and prevents last-minute exam panic.

Mastery of the Elimination Technique

विकल्प निष्कासन विधि में दक्षता

Top rankers in competitive exams rarely compute every problem blindly. They spot subtle traps, evaluate extreme values, and eliminate 2 out of 4 distractors within seconds. Our 4-option sets teach critical distractor analysis.

CBT Screen Stamina & Digital Comfort

कंप्यूटर आधारित परीक्षा का सहज अभ्यास

Almost all major national exams (CUET, JEE, NEET, SSC, Banking) are 100% computer-based. Students who only study on paper experience eye strain and navigation mistakes on exam day. Early CBT practice creates effortless digital fluency.

Immunity to Negative Marking

सटीकता और नकारात्मक अंकन से सुरक्षा

Careless errors—such as misreading "NOT" or "EXCEPT"—ruin thousands of competitive aspirations each year. Regular objective testing builds the habit of double-checking question keywords before locking answers.

Instant Diagnostic Feedback Loop

तत्काल त्रुटि निवारण एवं आत्म-मूल्यांकन

Traditional paper tests take weeks to grade, by which time the student has forgotten their thought process. TargetExams provides instant scorecards and step-by-step solutions while the conceptual puzzle is still fresh.

Syllabus Concepts Evaluated in this Chapter

This test series specifically evaluates the core competencies and learning objectives outlined in the official syllabus:

Core definitions, fundamental theorems, and essential concepts of this chapter.
Step-by-step mathematical reasoning and deductive problem-solving.
Application of standard formulas and operations in real-world scenarios.
Critical examination of common exam pitfalls and misleading options.
Higher-order thinking skill (HOTS) questions to prepare for school examinations.
Speed and accuracy mastery under standard timed CBT exam conditions.

Exam Rules & Test Taking Guidelines

Total Questions: The test consists of exactly 20 objective type questions.
Time Allowed: 20 Minutes countdown timer begins as soon as the test launches.
Marking Scheme: +1.0 mark is awarded for each correct answer.
Zero Penalty: There is 0.0 negative marking for incorrect or unattempted questions.
Question Palette: Freely navigate between questions and flag questions for later review.
Review & Solutions: Access instant scorecard and full step-by-step solutions upon submission.

Frequently Asked Questions (FAQs)

Yes! Foundation Practice Set 01 for every chapter in National Institute of Open Schooling (NIOS) Class XII Physics (312) is 100% free to attempt. Students can test their knowledge without any payment or hidden fees.

This page is dedicated to English Medium. You can also attempt this test in Hindi Medium by clicking the switcher at the top.

Absolutely. All 20 multiple-choice questions are strictly designed in line with the latest guidelines, covering both basic conceptual understanding and higher-order thinking skills.

The test contains 20 MCQs to be solved in 20 minutes. Each question carries +1.0 mark for a correct answer, and there is zero (0.0) negative marking for incorrect answers.

Yes. Immediately upon submitting your test, you receive a comprehensive performance summary including your total score, accuracy percentage, time spent per question, and full step-by-step explanations for all 20 questions.

Kinetic Theory of Gases (Set 02 (Advanced Level))

20 MCQs • 20 Mins • 100% Free Practice Test

National Institute of Open Schooling (NIOS) Class XII Physics (312): Kinetic Theory of Gases Online Test (Set 02 (Advanced Level)) | TargetExams

Chapter Study Guide & In-Depth Notes

Chapter Overview & Core Concepts: Kinetic Theory of Gases