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ICSE • कक्षा XII • Chemistry • अध्याय 1
अनुमानित समय: 90 Mins
प्रगति: अध्ययनरत

विलयन (Solutions)

In Class 12 Chemistry, "Solutions" provides an authoritative, curriculum-verified master resource aligned with the 2026–27 NCERT syllabus.

⚗️ Have You Ever Wondered?

Why do deep-sea scuba divers breathe an artificial mixture of helium and oxygen to avoid the agonizing 'bends', or why do municipal road crews scatter...

Why do deep-sea scuba divers breathe an artificial mixture of helium and oxygen to avoid the agonizing 'bends', or why do municipal road crews scatter rock salt on icy highways in winter to melt ice below $0^\circ\text{C}$? Colligative properties and Henry's Law govern liquid solutions.

यह अध्याय क्यों महत्वपूर्ण है

In Class 12 Chemistry, "Solutions" provides an authoritative, curriculum-verified master resource aligned with the 2026–27 NCERT syllabus.

अध्ययन से पूर्व (आवश्यक ज्ञान)

  • Molarity and molality from Class 11.
  • Vapor pressure.
  • Ideal gases.

इस अध्याय के लक्ष्य

  • State and apply Henry's Law of gas solubility: $p = K_H x$.
  • State and apply Raoult's Law for volatile liquid mixtures: $p_A = p_A^\circ x_A$.
  • Distinguish between Ideal and Non-Ideal solutions (Positive and Negative deviations, Azeotropes).
  • Derive and apply the four Colligative Properties: Relative Lowering of Vapor Pressure, Elevation of Boiling Point ($\Delta T_b = K_b m$), Depression of Freezing Point ($\Delta T_f = K_f m$), and Osmotic Pressure ($\Pi = CRT$).
  • Calculate Abnormal Molar Masses using the Van't Hoff Factor ($i$).

अध्याय रूपरेखा एवं प्रगति

1 1. Henry's Law & Raoult's Law
2 2. Colligative Properties (Depend s...
3 3. Abnormal Molar Mass & Van't Hoff...

सम्पूर्ण सैद्धांतिक एवं वैचारिक अध्ययन

1. Henry's Law & Raoult's Law

  • Henry's Law: The solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid: $\mathbf{p = K_H x}$. (Explains deep-sea diver 'bends' and soda carbonation).
  • Raoult's Law: For a solution of volatile liquids, the partial vapor pressure of each component is: $\mathbf{p_A = p_A^\circ x_A}$. Total pressure: $\mathbf{P_{\text{total}} = p_A + p_B}$.

2. Colligative Properties (Depend strictly on particle number)

  • Relative Lowering of Vapor Pressure: $\frac{p_1^\circ - p_1}{p_1^\circ} = x_2$.
  • Elevation of Boiling Point: $\mathbf{\Delta T_b = K_b \cdot m}$ ($K_b$ is Ebullioscopic constant).
  • Depression of Freezing Point: $\mathbf{\Delta T_f = K_f \cdot m}$ ($K_f$ is Cryoscopic constant; ethylene glycol antifreeze).
  • Osmotic Pressure: $\mathbf{\Pi = C R T} = \frac{n_2}{V}RT$ (used to determine molecular weights of polymers and biomolecules!).

3. Abnormal Molar Mass & Van't Hoff Factor ($i$)

When solutes dissociate or associate in solution: $$\mathbf{i = \frac{\text{Normal Molar Mass}}{\text{Abnormal Molar Mass}} = \frac{\text{Total moles of particles after dissociation/association}}{\text{Initial moles of solute}}}$$ For $\text{NaCl} \to \text{Na}^+ + \text{Cl}^-$, $i = 2$; for dimerizing acetic acid in benzene, $i = 0.5$.

महत्वपूर्ण रासायनिक सूत्र, अभिक्रियाएँ एवं समीकरण

Answer architecture
$$Concept \to Evidence \to Application \to Evaluation$$
Use the chapter principle, show the working or evidence, and state the conclusion.
Revision loop
$$Learn \to Practise \to Check \to Correct \to Reattempt$$
Keep an error log and revisit questions that exposed a misconception.

अवधारणात्मक हल उदाहरण एवं अनुप्रयोग (Solved Examples)

उदाहरण 1
State Henry's Law and mention two of its important applications.
विस्तृत समाधान / उत्तर:
Henry's Law states that at constant temperature, the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas over the solution ($p = K_H x$). Applications: (1) Sealing carbonated soft drinks under high pressure to increase CO2 solubility, (2) Deep-sea scuba divers using helium-diluted oxygen to prevent nitrogen bubbles ('bends').
उदाहरण 2
Why does the boiling point of a solvent increase when a non-volatile solute is added to it?
विस्तृत समाधान / उत्तर:
Adding a non-volatile solute decreases the solvent's vapor pressure because solute molecules occupy surface space. To make the vapor pressure equal atmospheric pressure, higher thermal kinetic energy (higher temperature) is needed, elevating the boiling point.
उदाहरण 3
What are Azeotropes? Distinguish between minimum-boiling and maximum-boiling azeotropes.
विस्तृत समाधान / उत्तर:
Azeotropes are binary liquid mixtures that boil at a constant temperature and distill over without change in composition. Solutions showing large positive deviation from Raoult's law form Minimum-Boiling azeotropes (e.g. 95% ethanol); solutions showing large negative deviation form Maximum-Boiling azeotropes (e.g. 68% nitric acid).

सामान्य गलतियाँ एवं परीक्षक के जाल (Examiner Traps)

सामान्य भ्रम / गलत उत्तर

Reciting a definition without applying it to the question or data.

सही वैज्ञानिक तथ्य

Identify the concept, show the relevant evidence or calculation, and explain the final implication.

सामान्य भ्रम / गलत उत्तर

Skipping conditions, units, domain restrictions, or adjustment effects.

सही वैज्ञानिक तथ्य

State assumptions, preserve units, check boundary cases, and verify the answer against the original problem.

सामान्य भ्रम / गलत उत्तर

Treating a correct intermediate result as proof that the whole solution is correct.

सही वैज्ञानिक तथ्य

Perform an independent reasonableness check and connect the result back to the chapter principle.

चित्रात्मक व्याख्या एवं मॉडल

Solutions Master Matrix

Conceptual framework, core mechanisms, and analytical relationships
Academic Architecture

1. Henry's Law & Raoult's Law • 2. Colligative Properties (Depend strictly on particle number)

अध्याय का सार संक्षेप एवं 10 मुख्य निष्कर्ष

मुख्य बिंदु 1
Henry's Law: Gas solubility scaling linearly with partial headspace pressure.
मुख्य बिंदु 2
Raoult's Law: Partial vapor pressure equals pure component pressure times mole fraction.
मुख्य बिंदु 3
Colligative Property: Thermodynamic property depending exclusively on the number of solute particles.
मुख्य बिंदु 4
Osmotic Pressure: Hydrostatic pressure preventing net solvent diffusion across semi-permeable membrane.
मुख्य बिंदु 5
Van't Hoff Factor ($i$): Multiplier accounting for solute electrolytic ionization or dimerization.

स्व-मूल्यांकन अभ्यास (Check Your Understanding)

मूल वैचारिक स्पष्टता की जांच के लिए नैदानिक प्रश्न। पहले स्वयं हल करें, फिर उत्तर देखें।

1
State Henry's Law and mention two of its important applications.
उत्तर एवं व्याख्या देखें
उत्तर: Henry's Law states that at constant temperature, the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas over the solution ($p = K_H x$). Applications: (1) Sealing carbonated soft drinks under high pressure to increase CO2 solubility, (2) Deep-sea scuba divers using helium-diluted oxygen to prevent nitrogen bubbles ('bends').
p = K_H x; carbonated drinks and scuba diving.
2
Why does the boiling point of a solvent increase when a non-volatile solute is added to it?
उत्तर एवं व्याख्या देखें
उत्तर: Adding a non-volatile solute decreases the solvent's vapor pressure because solute molecules occupy surface space. To make the vapor pressure equal atmospheric pressure, higher thermal kinetic energy (higher temperature) is needed, elevating the boiling point.
Vapor pressure lowers, requiring higher temperature to boil.
3
What are Azeotropes? Distinguish between minimum-boiling and maximum-boiling azeotropes.
उत्तर एवं व्याख्या देखें
उत्तर: Azeotropes are binary liquid mixtures that boil at a constant temperature and distill over without change in composition. Solutions showing large positive deviation from Raoult's law form Minimum-Boiling azeotropes (e.g. 95% ethanol); solutions showing large negative deviation form Maximum-Boiling azeotropes (e.g. 68% nitric acid).
Constant-boiling binary mixtures with identical vapor/liquid composition.
4
Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving $1.0\text{ g}$ of polymer of molar mass $185,000$ in $450\text{ mL}$ of water at $37^\circ\text{C}$.
उत्तर एवं व्याख्या देखें
उत्तर: $n = \frac{1.0}{185,000}\text{ mol}$. $V = 0.450\text{ L}$. $T = 310.15\text{ K}, R = 8.314 \times 10^3\text{ Pa}\cdot\text{L}/(\text{mol}\cdot\text{K})$. $\Pi = \frac{n}{V}RT = \frac{1.0 \times 8.314 \times 10^3 \times 310.15}{185,000 \times 0.450} = \frac{2578587}{83250} \approx 30.97\text{ Pa}$.
30.97 Pa.
5
What is the Van't Hoff factor for complete dissociation of $\text{K}_2\text{SO}_4$ in aqueous solution?
उत्तर एवं व्याख्या देखें
उत्तर: $\text{K}_2\text{SO}_4 \to 2\text{K}^+ + \text{SO}_4^{2-}$. Total ions produced per molecule $= 2 + 1 = 3$. For 100% dissociation, Van't Hoff factor $i = 3$.
i = 3.
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