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ICSE • कक्षा 8 • Mathematics • अध्याय 11
अनुमानित समय: 45 Mins
प्रगति: अध्ययनरत

प्रत्यक्ष और व्युत्क्रम भिन्नताएँ (Direct and Inverse Variations)

In ICSE Class 8 Mathematics, "Direct and Inverse Variations" provides an authoritative, mathematically rigorous master study guide investigating proportional relationships, functional dependencies, constant of proportionality, and unitary methods. This comprehensive chapter explores Concept of Variation (Two quantities $x$ and $y$ changing in tandem such that an alteration in one induces a corresponding alteration in the other), Direct Variation / Proportion (Two quantities vary directly if their ratio remains strictly constant: $\frac{x}{y} = k$ or $\frac{x_1}{y_1} = \frac{x_2}{y_2}$; Constant of variation $k > 0$; Graphical representation: straight line passing through the origin; Real-world applications: cost of articles vs quantity, distance vs time at uniform speed, petrol consumed vs distance traveled, scale map distances), Inverse Variation / Indirect Proportion (Two quantities vary inversely if their product remains strictly constant: $x \times y = k$ or $x_1 y_1 = x_2 y_2$; As $x$ increases, $y$ decreases proportionally; Constant of variation $k$; Graphical representation: rectangular hyperbola; Real-world applications: speed vs time for fixed distance, number of workers vs days to complete a job, pipes filling a cistern, garrison food provisions and soldiers), Compound / Mixed Variations, Time and Work Problems (Work done in 1 day $= \frac{1}{n}$; Pipes and cisterns: inlet and outlet rates), and Distinguishing Between Direct and Inverse Word Problems aligned with the 2026–27 CISCE ICSE curriculum.

How Can Increasing the Number of Workers on a Construction Site Make the Total Job Finish Days Earlier Instead of Later?

If you buy 5 mangoes for 100 rupees, 10 mangoes will cost you 200 rupees. Both quantities go UP together—that is DIRECT VARIATION! More items mean more money. But now imagine a construction contractor hiring 10 workers to dig a canal in 30 days. If he doubles the workforce to 20 workers, will it take 60 days? Absolutely not! The job finishes in just 15 days! As the number of workers goes UP, the time required goes DOWN! This is the magic of INVERSE VARIATION! While direct variation keeps the ratio $\frac{x}{y}$ constant, inverse variation keeps the product $x \times y$ constant! If a military garrison of 500 soldiers has food rations for 30 days, and 100 more soldiers arrive, how many days will the food last? How does a pipe filling a water tank work in tandem with a leak draining it? Let's master direct and inverse variations.

यह अध्याय क्यों महत्वपूर्ण है

Variation is the foundation of scientific scaling laws: Ohm's law in physics ($V = IR$), Newton's law of gravitation ($F \propto \frac{1}{r^2}$), Boyle's gas law ($PV = k$), construction project scheduling, and industrial assembly-line logistics. Mastering direct and inverse proportions is essential for ICSE Class 8 mathematics and competitive aptitude examinations.

अध्ययन से पूर्व (आवश्यक ज्ञान)

  • Ratio and proportion fundamentals from Class 7.
  • Solving simple linear equations in one variable.
  • Unitary method.

इस अध्याय के लक्ष्य

  • Identify whether two physical quantities are in direct or inverse variation.
  • Determine the constant of variation $k$ for direct ($\frac{x}{y}=k$) and inverse ($xy=k$) relations.
  • Set up and solve proportion equations: $\frac{x_1}{y_1} = \frac{x_2}{y_2}$ and $x_1 y_1 = x_2 y_2$.
  • Solve multi-person Time and Work problems using unitary day-rates.
  • Solve Pipes and Cisterns problems involving both inlet taps and drainage leaks.
  • Solve food garrison and camp provision variation word problems.

अध्याय रूपरेखा एवं प्रगति

1 1. Direct Variation: Ratio Invarian...
2 2. Inverse Variation: Product Invar...
3 3. Time & Work Mathematical Framewo...
4 4. Pipes and Cisterns Mechanics

सम्पूर्ण सैद्धांतिक एवं वैचारिक अध्ययन

1. Direct Variation: Ratio Invariance

Understand
A. Definition of Direct Variation:

Two quantities $x$ and $y$ are said to be in Direct Variation (or direct proportion) if an increase (or decrease) in $x$ produces a proportional increase (or decrease) in $y$ such that their ratio remains constant:

$$\mathbf{\frac{x}{y} = k \quad (\text{Constant of Variation})} \quad \Longleftrightarrow \quad \mathbf{\frac{x_1}{y_1} = \frac{x_2}{y_2}}$$
  • Examples:
    • Distance traveled and time taken (at constant speed).
    • Total purchase cost and number of articles bought.
    • Weight of a metal rod and its length.
  • Graphical Plot: A straight line passing directly through the coordinate origin $(0, 0)$.

2. Inverse Variation: Product Invariance

Inverse Proportion
A. Definition of Inverse Variation:

Two quantities $x$ and $y$ are said to be in Inverse Variation (or indirect proportion) if an increase in $x$ produces a proportional decrease in $y$ (and vice versa) such that their product remains constant:

$$\mathbf{x \times y = k \quad (\text{Constant})} \quad \Longleftrightarrow \quad \mathbf{x_1 y_1 = x_2 y_2}$$
  • Examples:
    • Speed of a vehicle and time taken to cover a fixed journey distance.
    • Number of workers and time taken to complete a specific task.
    • Number of people sharing food provisions and the days the food lasts.
  • Graphical Plot: A smooth rectangular hyperbola curving asymptotically toward both axes.

3. Time & Work Mathematical Framework

Time & Work
Fundamental Axioms of Work:
  1. If a person can finish a piece of work in $n$ days, then the work done by that person in $1\text{ day}$ is: $$\mathbf{\text{Work done in 1 day} = \frac{1}{n}}$$
  2. Conversely, if a person completes $\frac{1}{n}$ of the work in 1 day, the total time taken to complete the entire job is $n\text{ days}$.
  3. If person $A$ finishes work in $x$ days and person $B$ in $y$ days, their combined 1-day work is: $$\text{Combined 1-day work} = \frac{1}{x} + \frac{1}{y} = \frac{x + y}{xy}$$ $$\mathbf{\text{Total Days Together} = \frac{xy}{x + y}}$$

4. Pipes and Cisterns Mechanics

Pipes & Cisterns
  • Inlet Pipe: Fills the tank. If it fills a tank in $T_1$ hours, its 1-hour filling rate is $+\frac{1}{T_1}$.
  • Outlet / Leak Pipe: Empties the tank. If it drains the tank in $T_2$ hours, its 1-hour emptying rate is $-\frac{1}{T_2}$.
  • If both pipes are open simultaneously: $$\mathbf{\text{Net 1-hour Work} = \frac{1}{T_1} - \frac{1}{T_2} = \frac{T_2 - T_1}{T_1 T_2}}$$ $$\mathbf{\text{Time to Fill Tank} = \frac{T_1 T_2}{T_2 - T_1} \quad (T_2 > T_1)}$$

महत्वपूर्ण सूत्र, सर्वसमिकाएँ एवं प्रमेय

Direct Variation Formula
$$\frac{x_1}{y_1} = \frac{x_2}{y_2} \quad \left( \frac{x}{y} = k \right)$$
Ratio remains constant.
Inverse Variation Formula
$$x_1 y_1 = x_2 y_2 \quad (x \cdot y = k)$$
Product remains constant.

Mathematics: Direct vs Inverse Variation Curves

Direct vs Inverse Variations: Algebraic Laws & Graphs DIRECT VARIATION (RATIO CONSTANT) y = kx x / y = k ⇒ x1 / y1 = x2 / y2 • Straight line through origin (0, 0) • More items = More cost • More speed = More distance INVERSE VARIATION (PRODUCT CONSTANT) xy = k x × y = k ⇒ x1 y1 = x2 y2 • Rectangular hyperbola curve • More workers = Fewer days • Faster speed = Less time DIRECT: x1/y1 = x2/y2 (RATIO CONSTANT) • INVERSE: x1*y1 = x2*y2 (PRODUCT CONSTANT)

अध्याय का सार संक्षेप एवं 10 मुख्य निष्कर्ष

मुख्य बिंदु 1
Direct variation occurs when two quantities increase or decrease together: x/y = k.
मुख्य बिंदु 2
In direct variation, x1 / y1 = x2 / y2; its graph is a straight line through the origin.
मुख्य बिंदु 3
Inverse variation occurs when an increase in one causes a decrease in the other: x * y = k.
मुख्य बिंदु 4
In inverse variation, x1 * y1 = x2 * y2; its graph is a rectangular hyperbola.
मुख्य बिंदु 5
Worker-time relationships are inverse variations: more workers take fewer days.
मुख्य बिंदु 6
Speed and travel time for a fixed distance are in inverse variation.
मुख्य बिंदु 7
In Time and Work, a person completing a job in n days accomplishes 1/n of the work in 1 day.
मुख्य बिंदु 8
Combined time for two workers is (x * y) / (x + y) days.
मुख्य बिंदु 9
Pipes filling a cistern add work (+1/T1); drainage leaks subtract work (-1/T2).
मुख्य बिंदु 10
Always verify whether the problem scenario is direct (ratio) or inverse (product) before calculating.

स्व-मूल्यांकन अभ्यास (Check Your Understanding)

मूल वैचारिक स्पष्टता की जांच के लिए नैदानिक प्रश्न। पहले स्वयं हल करें, फिर उत्तर देखें।

1
If $15$ men can build a wall in $48\text{ hours}$, how many workers will be required to build the same wall in $30\text{ hours}$?
उत्तर एवं व्याख्या देखें
उत्तर:

Step 1: Identify the type of variation:
More workers will require LESS time to build the same wall. Therefore, this is an INVERSE VARIATION problem.
Step 2: Let the number of workers required be $x_2$.
Here $x_1 = 15$ men, $y_1 = 48$ hours; $y_2 = 30$ hours.
Step 3: Apply the Inverse Variation formula ($x_1 y_1 = x_2 y_2$):

$$15 \times 48 = x_2 \times 30$$


$$720 = 30 x_2$$


$$x_2 = \frac{720}{30} = \mathbf{24\text{ men}}$$

.
Exactly $24$ workers will be required.


Inverse variation: $15 \times 48 = x \times 30 \implies x = 720 / 30 = 24\text{ men}$.
2
A loaded truck travels $14\text{ kilometers}$ in $25\text{ minutes}$. If the speed remains constant, how far will it travel in $5\text{ hours}$?
उत्तर एवं व्याख्या देखें
उत्तर:

Step 1: Identify the type of variation:
At constant speed, more time means MORE distance covered. Therefore, this is a DIRECT VARIATION problem.
Step 2: Convert time into the same unit (minutes):

$$5\text{ hours} = 5 \times 60 = 300\text{ minutes}$$


Step 3: Let the distance traveled be $x_2\text{ km}$.
Here $x_1 = 14\text{ km}, y_1 = 25\text{ mins}; y_2 = 300\text{ mins}$.
Step 4: Apply the Direct Variation formula ($\frac{x_1}{y_1} = \frac{x_2}{y_2}$):

$$\frac{14}{25} = \frac{x_2}{300}$$


$$x_2 = \frac{14 \times 300}{25} = 14 \times 12 = \mathbf{168\text{ kilometers}}$$

.


Direct variation: $14 / 25 = x / 300 \implies x = 14 \times 12 = 168\text{ km}$.
3
$A$ can complete a piece of work in $12\text{ days}$, while $B$ can complete the same work in $24\text{ days}$. In how many days can they complete the work together?
उत्तर एवं व्याख्या देखें
उत्तर: Step 1: Calculate 1-day work for each person:
• Work done by $A$ in $1\text{ day} = \frac{1}{12}$
• Work done by $B$ in $1\text{ day} = \frac{1}{24}$
Step 2: Calculate their combined 1-day work:
$$\text{Work done by } (A + B) \text{ in 1 day} = \frac{1}{12} + \frac{1}{24} = \frac{2 + 1}{24} = \frac{3}{24} = \frac{1}{8}$$
Step 3: Total time required is the reciprocal of their 1-day work:
$$\text{Total Days} = \mathbf{8\text{ days}}$$.
Combined 1-day work is $1/12 + 1/24 = 3/24 = 1/8$. Total time is 8 days.
4
A military garrison of $300$ soldiers had provisions for $45\text{ days}$. After $15\text{ days}$, $50$ more soldiers joined the garrison. How many days will the remaining provisions last?
उत्तर एवं व्याख्या देखें
उत्तर: Step 1: Calculate remaining food provisions:
Provisions left after $15\text{ days}$ are sufficient for the original $300$ soldiers for $(45 - 15) = \mathbf{30\text{ days}}$.
Step 2: New total soldiers in garrison:
$$\text{New count} = 300 + 50 = \mathbf{350\text{ soldiers}}$$
Step 3: More soldiers will exhaust food in FEWER days (Inverse Variation):
$$x_1 y_1 = x_2 y_2$$
$$300 \times 30 = 350 \times y_2$$
$$9000 = 350 y_2$$
$$y_2 = \frac{9000}{350} = \frac{900}{35} = \frac{180}{7} = \mathbf{25 \frac{5}{7}\text{ days}}$$.
For 300 men, food lasts 30 days. For 350 men, $300 \times 30 = 350 \times y \implies y = 180 / 7 = 25\frac{5}{7}$ days.
5
A tap can fill a cistern in $8\text{ hours}$, while an outlet pipe can empty it in $12\text{ hours}$. If both pipes are opened simultaneously, in how many hours will the empty cistern be completely filled?
उत्तर एवं व्याख्या देखें
उत्तर:

Step 1: Rate of filling in $1\text{ hour} = +\frac{1}{8}$.
Step 2: Rate of emptying in $1\text{ hour} = -\frac{1}{12}$.
Step 3: Net filling work done in $1\text{ hour}$ when both are open:

$$\text{Net Rate} = \frac{1}{8} - \frac{1}{12}$$


LCM of 8 and 12 is 24:

$$= \frac{3 - 2}{24} = \mathbf{\frac{1}{24}}$$


Step 4: Since $\frac{1}{24}$ of the tank fills in 1 hour, the cistern will be completely filled in $24\text{ hours}$.


Net rate is $1/8 - 1/12 = (3 - 2)/24 = 1/24$. Time taken is 24 hours.
6
A train traveling at a uniform speed of $75\text{ km/h}$ covers a certain distance in $4\text{ hours}$. How long will the same journey take if the train speed is increased to $100\text{ km/h}$?
उत्तर एवं व्याख्या देखें
उत्तर:

Step 1: Higher speed requires LESS travel time (Inverse Variation):

$$x_1 y_1 = x_2 y_2$$


Here $x_1 = 75\text{ km/h}, y_1 = 4\text{ hours}; x_2 = 100\text{ km/h}, y_2 = ?$

$$75 \times 4 = 100 \times y_2$$


$$300 = 100 y_2 \implies y_2 = \frac{300}{100} = \mathbf{3\text{ hours}}$$

.
The journey will take $3\text{ hours}$.


Inverse variation: $75 \times 4 = 100 \times y \implies y = 300 / 100 = 3\text{ hours}$.
7
If the weight of $12$ sheets of thick paper is $40\text{ grams}$, how many sheets of the same paper would weigh $2 \frac{1}{2}\text{ kilograms}$?
उत्तर एवं व्याख्या देखें
उत्तर: Step 1: Direct Variation (more sheets weigh more):
Convert $2 \frac{1}{2}\text{ kg}$ to grams: $2.5 \times 1000 = 2500\text{ grams}$.
Step 2: Let the number of sheets be $x_2$.
$$\frac{x_1}{y_1} = \frac{x_2}{y_2}$$
$$\frac{12}{40} = \frac{x_2}{2500}$$
$$x_2 = \frac{12 \times 2500}{40} = \frac{30,000}{40} = \mathbf{750\text{ sheets}}$$.
Direct variation: $12 / 40 = x / 2500 \implies x = (12 \times 2500) / 40 = 750\text{ sheets}$.
8
Explain how to determine whether a given table of values represents Direct Variation or Inverse Variation.
उत्तर एवं व्याख्या देखें
उत्तर:

• Direct Variation Test: Calculate the ratio $\frac{x}{y}$ for every data pair $(x_1, y_1), (x_2, y_2)$. If the ratio $\frac{x}{y} = k$ is constant for all pairs, the relationship is Direct Variation.
• Inverse Variation Test: Calculate the product $x \times y$ for every data pair. If the product $x \times y = k$ is constant for all pairs, the relationship is Inverse Variation.


Check if the ratio $x/y$ is constant (Direct) or if the product $x \times y$ is constant (Inverse).
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कक्षा 8 Mathematics के सभी अध्याय

अध्याय 1: गुणनखंडन (Factorisation) अध्याय 2: परिमेय संख्याएँ (Rational Numbers) अध्याय 3: घातांक (Exponents) अध्याय 4: वर्ग और वर्गमूल (Squares and Square Roots) अध्याय 5: घन और घनमूल (Cubes and Cube Roots) अध्याय 6: संख्याओं के साथ खेलना (Playing With Numbers) अध्याय 7: समुच्चय (Sets) अध्याय 8: प्रतिशतता (Percentage) अध्याय 9: लाभ, हानि और छूट (Profit, Loss and Discount) अध्याय 10: सरल एवं चक्रवृद्धि ब्याज (Simple and Compound Interest) अध्याय 11: प्रत्यक्ष और व्युत्क्रम भिन्नताएँ (Direct and Inverse Variations) अध्याय 12: बीजीय व्यंजक (Algebraic Expressions) अध्याय 13: बीजगणितीय सर्वसमिकाएँ (Algebraic Identities) अध्याय 14: रैखिक असमिकाएँ (Linear Inequations) अध्याय 15: रैखिक समीकरण (Linear Equations) अध्याय 16: आकारों की समझ (Understanding Shapes) अध्याय 17: त्रिविमीय आकारों का द्विविमीय निरूपण (Representing 3D in 2D) अध्याय 18: विशेष प्रकार के चतुर्भुजों का निर्माण (Construction of Special Types of Quadrilaterals) अध्याय 19: आलेखों से परिचय (Introduction to Graphs) अध्याय 20: रेखा समरूपता और परावर्तन (Line Symmetry and Reflection) अध्याय 21: घेरा (Circle) अध्याय 22: सरलरेखीय आकृतियों का क्षेत्रफल (Area of Rectilinear Figures) अध्याय 23: ठोसों का सतही क्षेत्रफल और आयतन (Surface Area and Volume of Solids) अध्याय 24: आँकड़ों का प्रबंधन (Data Handling) अध्याय 25: प्रायिकता (Probability)

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प्रत्यक्ष और व्युत्क्रम भिन्नताएँ (Direct and Inverse Variations) में कोई संदेह या प्रश्न है? हमारे AI अध्ययन मित्र से तुरंत समझें।

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