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WBB • Class 7 • Mathematics (গণিত প্রভা) • Ch 12
Estimated Time: 55 minutes
Study Progress: In Progress

Algebraic Formulae

Welcome to Chapter 12: "Algebraic Formulae" (বীজগাণিতিক সূত্রাবলী / बीजीय सूत्र) of the West Bengal Board (WBBSE) Class 7 Mathematics curriculum (Ganit Prabha). Built upon the TargetExams Gold-Standard 5-Step Pedagogy System, this foundational algebra chapter provides deep geometric proofs and algebraic mastery of binomial squares $(a+b)^2 = a^2 + 2ab + b^2$ and $(a-b)^2 = a^2 - 2ab + b^2$, the difference of two squares $a^2 - b^2 = (a+b)(a-b)$, critical derived corollaries ($4ab$, $2(a^2+b^2)$, $ab$ as difference of two squares), reciprocal variable value evaluations ($x \pm 1/x = k$), and trinomial expansions $(a+b+c)^2$.

⚡ The Magic of Algebra: Mental Multiplication of $105 \times 95$ in 2 Seconds!

If asked to compute $105 \times 95$, traditional long multiplication takes at least a minute of tedious scratchpad work. But with one elegant algebraic identity, you can find the answer in a flash mentally!

Observe: $105 \times 95 = (100 + 5)(100 - 5) = 100^2 - 5^2 = 10,000 - 25 = 9,975$! Instant, flawless precision without paper or pencil!

Algebraic formulae are not just abstract manipulations—they are lightning-fast mathematical superpowers. In this chapter, you will discover the visual geometry behind why these formulas work and master their versatile applications.

Why This Chapter Matters

Welcome to Chapter 12: "Algebraic Formulae" (বীজগাণিতিক সূত্রাবলী / बीजीय सूत्र) of the West Bengal Board (WBBSE) Class 7 Mathematics curriculum (Ganit Prabha). Built upon the TargetExams Gold-Standard 5-Step Pedagogy System, this foundational algebra chapter provides deep geometric proofs and algebraic mastery of binomial squares $(a+b)^2 = a^2 + 2ab + b^2$ and $(a-b)^2 = a^2 - 2ab + b^2$, the difference of two squares $a^2 - b^2 = (a+b)(a-b)$, critical derived corollaries ($4ab$, $2(a^2+b^2)$, $ab$ as difference of two squares), reciprocal variable value evaluations ($x \pm 1/x = k$), and trinomial expansions $(a+b+c)^2$.

Before You Begin (Prerequisites)

  • Basic understanding of variables, constants, and like terms
  • Multiplication of polynomials and exponent laws ($x^m \times x^n = x^{m+n}$)
  • Formula for area of a square ($\text{Side} \times \text{Side} = \text{Side}^2$)
  • Sign conventions for multiplication of signed integers ($+ \times + = +$, $- \times - = +$, $+ \times - = -$)

What You Will Learn (Core Objectives)

  • State, geometrically prove, and algebraically expand $(a+b)^2$ and $(a-b)^2$
  • Apply the difference of two squares identity $a^2 - b^2 = (a+b)(a-b)$ for rapid factorization and mental multiplication
  • Utilize the key corollaries $4ab$, $2(a^2+b^2)$, and $ab = ((a+b)/2)^2 - ((a-b)/2)^2$
  • Evaluate higher powers $x^2 + 1/x^2$ and $x^4 + 1/x^4$ given $x \pm 1/x = k$
  • Expand and simplify trinomial squares $(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca$

Chapter Roadmap & Progression

1 Concept 1: Binomial Square of Sum &...
2 Concept 2: Binomial Square of Diffe...
3 Concept 3: Difference of Two Square...
4 Concept 4: Corollaries—$4ab$, $2(a^...
5 Concept 5: Value Evaluations with R...

Complete Concept Guide (100% Curriculum Coverage)

Concept 1: Binomial Square of Sum & Geometric Area Proof ($(a+b)^2 = a^2 + 2ab + b^2$)

Step 1
Algebraic Derivation (Core Theory)

Multiplying the binomial $(a+b)$ by itself using the distributive law:

$(a+b)^2 = (a+b)(a+b) = a(a+b) + b(a+b) = a^2 + ab + ba + b^2$

Since multiplication is commutative ($ab = ba$), the like terms combine to $2ab$: $(a+b)^2 = a^2 + 2ab + b^2$.

Step 2
Geometric Area Proof

A large square of side $(a+b)$ has total area $(a+b)^2$. Subdividing the sides into segments $a$ and $b$ divides the square into four distinct geometric regions:

  • One blue square of side $a$ with area $= a^2$
  • Two orange rectangles of dimensions $a \times b$ with combined area $= 2ab$
  • One green square of side $b$ with area $= b^2$
Step 3
Worked Examples
Example 1: Expand $(5m + 2n)^2$ using the identity.
Solution:
Setting $a = 5m$ and $b = 2n$:
$(5m + 2n)^2 = (5m)^2 + 2(5m)(2n) + (2n)^2 = 25m^2 + 20mn + 4n^2$.
Example 2 (Mental Arithmetic): Evaluate $103^2$ using algebra.
Solution:
$103^2 = (100 + 3)^2 = 100^2 + 2(100)(3) + 3^2 = 10000 + 600 + 9 = 10,609$.
Step 4
Examiner Traps & Precautions

Never omit coefficients: $(5m)^2 \ne 5m^2$. You must square both $5$ and $m$ to get $25m^2$.

Step 5
Real-World Application

Architecture & Land Planning: When a square plot is expanded by $a$ meters on one side and $b$ meters on the other, civil engineers calculate the additional concrete and paving needed by expanding $(a+b)^2$.

Concept 2: Binomial Square of Difference & Trinomial Square ($(a-b)^2$ & $(a+b+c)^2$)

Step 1
Formula Expansion & Extension

$(a-b)^2 = (a-b)(a-b) = a^2 - 2ab + b^2$.

Trinomial Square: $(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca$.

Step 2
Sign Rule Logic

Notice that $(-b)^2 = +b^2$, making the squared terms unconditionally positive, whereas cross-products containing one negative sign become negative ($-2ab$).

Step 3
Worked Examples
Example 1: Compute $97^2$ using the difference formula.
Solution:
$97^2 = (100 - 3)^2 = 100^2 - 2(100)(3) + 3^2 = 10000 - 600 + 9 = 9,409$.
Example 2 (Trinomial): Expand $(2x - y + 3z)^2$.
Solution:
$=(2x)^2 + (-y)^2 + (3z)^2 + 2(2x)(-y) + 2(-y)(3z) + 2(3z)(2x)
$= 4x^2 + y^2 + 9z^2 - 4xy - 6yz + 12zx$.
Step 4
Examiner Traps & Precautions

Do not write $(-y)^2 = -y^2$. The square of any real term is strictly positive ($+y^2$).

Step 5
Real-World Application

Data Science & Variance Calculation: In statistics, the squared deviation from the mean $(x_i - \bar{x})^2 = x_i^2 - 2x_i\bar{x} + \bar{x}^2$ forms the foundation of variance and standard deviation across millions of data points.

Concept 3: Difference of Two Squares & Rapid Factorization ($a^2 - b^2 = (a+b)(a-b)$)

Step 1
Algebraic Proof

$(a+b)(a-b) = a(a-b) + b(a-b) = a^2 - ab + ba - b^2 = a^2 - b^2$.

Conversely, the difference between two perfect squares factors into the sum and difference of their bases: $a^2 - b^2 = (a+b)(a-b)$.

Step 2
Mental Math Power

When two numbers have an easy midpoint, this formula delivers lightning-fast multiplication: $62 \times 58 = (60+2)(60-2) = 3600 - 4 = 3596$.

Step 3
Worked Examples
Example 1: Factorize $49x^2 - 64y^2$.
Solution:
$(7x)^2 - (8y)^2 = (7x + 8y)(7x - 8y)$.
Example 2 (Continued Product): Find the product $(x+y)(x-y)(x^2+y^2)(x^4+y^4)$.
Solution:
$(x^2 - y^2)(x^2 + y^2)(x^4 + y^4) = (x^4 - y^4)(x^4 + y^4) = x^8 - y^8$.
Step 4
Examiner Traps & Precautions

Always factor out the greatest common divisor first: in $2x^2 - 32$, factor out $2$ to get $2(x^2 - 16) = 2(x+4)(x-4)$.

Step 5
Real-World Application

Annular Ring & Hollow Pipe Cross-Sections: The cross-sectional area of a hollow metal pipe of outer radius $R$ and inner radius $r$ is $\pi R^2 - \pi r^2 = \pi(R^2 - r^2) = \pi(R+r)(R-r)$. Mechanical engineers use this formula to calculate weight and manufacturing costs.

Concept 4: Corollaries—$4ab$, $2(a^2+b^2)$, and Product as Difference of Two Squares

Step 1
Mathematical Derivations

$(a+b)^2 + (a-b)^2 = 2(a^2 + b^2)$

$(a+b)^2 - (a-b)^2 = 4ab$

$ab = \left(\frac{a+b}{2}\right)^2 - \left(\frac{a-b}{2}\right)^2$.

Step 2
Selection of Strategy

Whenever $(a+b)$ and $(a-b)$ are provided, $ab$ and $a^2+b^2$ can be directly computed without solving for $a$ and $b$ individually.

Step 3
Worked Examples
Example 1: If $a+b=9$ and $a-b=5$, find $8ab(a^2+b^2)$.
Solution:
$8ab(a^2+b^2) = 4ab \times 2(a^2+b^2) = [9^2 - 5^2] \times [9^2 + 5^2] = 56 \times 106 = 5,936$.
Example 2: Express $44$ as the difference of two squares.
Solution:
$44 = 22 \times 2 = (\frac{22+2}{2})^2 - (\frac{22-2}{2})^2 = 12^2 - 10^2$.
Step 4
Examiner Traps & Precautions

Do not forget to square the denominator 2: $(\frac{a+b}{2})^2 = \frac{(a+b)^2}{4}$.

Step 5
Real-World Application

Cryptography & Cybersecurity: Expressing composite odd integers as the difference of two squares is the core mechanism of Fermat's factorization algorithm, used to audit the strength of RSA cryptographic keys.

Concept 5: Value Evaluations with Reciprocals ($x + 1/x = k$ Form)

Step 1
Reciprocal Property in Binomials

Because $x \cdot \frac{1}{x} = 1$, the cross-product simplifies to a pure constant $2$:

$x^2 + \frac{1}{x^2} = (x + \frac{1}{x})^2 - 2 = (x - \frac{1}{x})^2 + 2$.

Step 2
Higher-Power Ladder ($x^4 + 1/x^4$)

Square once to determine $x^2 + \frac{1}{x^2}$. Then square that result once more to obtain $x^4 + \frac{1}{x^4}$ systematically.

Step 3
Worked Examples
Example 1: If $m - \frac{1}{m} = 4$, find $m^2 + \frac{1}{m^2}$ and $m^4 + \frac{1}{m^4}$.
Solution:
$(m - \frac{1}{m})^2 = 4^2 \implies m^2 - 2 + \frac{1}{m^2} = 16 \implies m^2 + \frac{1}{m^2} = 18$.
Squaring again:
$(m^2 + \frac{1}{m^2})^2 = 18^2 \implies m^4 + 2 + \frac{1}{m^4} = 324 \implies m^4 + \frac{1}{m^4} = 322$.
Example 2: For what value of $k$ is $c^2 + kc + 36$ a perfect square?
Solution:
Middle term $=\pm 2 \cdot c \cdot 6 = \pm 12c$. Therefore, $k = \pm 12$.
Step 4
Examiner Traps & Precautions

Watch transposition signs: for $(m - 1/m)^2$, the $-2$ becomes $+2$ when moved to the other side ($16 + 2 = 18$).

Step 5
Real-World Application

Electronics & Resonance Circuits: In RLC circuits, minimizing total impedance involves expressions with frequency terms $f + 1/f$. The minimum energy dissipation is derived using this reciprocal identity.

Key Formulas, Identities & Theorems

Square of Sum of Two Terms
$$(a+b)^2 = a^2 + 2ab + b^2$$
Square of 1st term + 2(1st term)(2nd term) + Square of 2nd term.
Square of Difference of Two Terms
$$(a-b)^2 = a^2 - 2ab + b^2$$
Middle term is always negative ($-2ab$).
Difference of Two Squares
$$a^2 - b^2 = (a+b)(a-b)$$
Product of sum and difference equals the difference of squares.
Sum of Squares Corollaries
$$a^2 + b^2 = (a+b)^2 - 2ab = (a-b)^2 + 2ab = \frac{(a+b)^2 + (a-b)^2}{2}$$
Choose the variation corresponding to given quantities.
Four-Product & Product as Difference of Squares
$$4ab = (a+b)^2 - (a-b)^2, \quad ab = \left(\frac{a+b}{2}\right)^2 - \left(\frac{a-b}{2}\right)^2$$
Represents any product as the difference of two squares.
Square of a Trinomial
$$(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca$$
Sum of individual squares + double of all pairwise products.

Conceptual Solved Examples & Case Studies

Example 1
Expand using formula: $(3x + 4y)^2$.
Step-by-Step Solution:
Let $a = 3x$ and $b = 4y$.
$(a+b)^2 = a^2 + 2ab + b^2$
$(3x + 4y)^2 = (3x)^2 + 2(3x)(4y) + (4y)^2 = 9x^2 + 24xy + 16y^2$.
Example 2
If $x + \frac{1}{x} = 5$, find the values of $x^2 + \frac{1}{x^2}$ and $x^4 + \frac{1}{x^4}$.
Step-by-Step Solution:
Squaring both sides:
$(x + \frac{1}{x})^2 = 5^2 \implies x^2 + 2 \cdot x \cdot \frac{1}{x} + \frac{1}{x^2} = 25$
$\implies x^2 + 2 + \frac{1}{x^2} = 25 \implies x^2 + \frac{1}{x^2} = 23$.
Squaring again:
$(x^2 + \frac{1}{x^2})^2 = 23^2 \implies x^4 + 2 + \frac{1}{x^4} = 529 \implies x^4 + \frac{1}{x^4} = 527$.
Example 3
Express $12xy$ as the difference of two squares.
Step-by-Step Solution:
$12xy = (6x)(2y)$. Let $a = 6x, b = 2y$.
Using $ab = (\frac{a+b}{2})^2 - (\frac{a-b}{2})^2$:
$12xy = (\frac{6x+2y}{2})^2 - (\frac{6x-2y}{2})^2 = (3x+y)^2 - (3x-y)^2$.

Common Misconceptions & Examiner Traps

Common Misconception

Writing $(a+b)^2 = a^2 + b^2$ or $(a-b)^2 = a^2 - b^2$.

Scientific Reality & Correction

This is the most frequent blunder in algebra. The cross product term $\pm 2ab$ must never be omitted.

Common Misconception

Failing to square the coefficient: e.g. writing $(5m)^2 = 5m^2$.

Scientific Reality & Correction

Every factor inside parentheses is squared: $(5m)^2 = 5^2 \times m^2 = 25m^2$.

Common Misconception

Confusing $x^2 - y^2$ with $(x-y)^2$.

Scientific Reality & Correction

$x^2 - y^2 = (x+y)(x-y)$ (difference of two squares), whereas $(x-y)^2 = x^2 - 2xy + y^2$ (square of a difference). They are entirely different expressions.

Geometric Model of Binomial Square: Visual Area Proof of $(a+b)^2 = a^2 + 2ab + b^2$

Geometric Proof: Total Area of Square with Side (a + b) = a² + 2ab + b² a² (a × a Square) ab (b × a) ab (a × b) b² (b × b) a b a b Total Side = (a + b) Dissection Breakdown ■ Blue Square = a × a = a² ■ Orange Rectangles (2) = ab + ab = 2ab ■ Green Square = b × b = b² Total Area = a² + 2ab + b² Crucial: (a + b)² ≠ a² + b² (2ab is omitted!)

Chapter Summary & 10 Key Takeaways

Takeaway 1
Square of sum: $(a+b)^2 = a^2 + 2ab + b^2$ (never drop the middle term $2ab$).
Takeaway 2
Square of difference: $(a-b)^2 = a^2 - 2ab + b^2$ (middle term is negative).
Takeaway 3
Difference of two squares: $a^2 - b^2 = (a+b)(a-b)$ (key to factorization and rapid calculation).
Takeaway 4
Sum of squares identity: $a^2 + b^2 = (a+b)^2 - 2ab = (a-b)^2 + 2ab$.
Takeaway 5
Four-product identity: $4ab = (a+b)^2 - (a-b)^2$.
Takeaway 6
Product as difference of two squares: $ab = (\frac{a+b}{2})^2 - (\frac{a-b}{2})^2$.
Takeaway 7
Trinomial square: $(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca$.
Takeaway 8
Reciprocal variable relations: $x^2 + 1/x^2 = (x \pm 1/x)^2 \mp 2$.

Check Your Understanding (Diagnostic Practice Questions)

Diagnostic questions testing core conceptual clarity. Answers are hidden initially — solve each problem first, then click to reveal the step-by-step verified solution.

1
Expand using formula: $(4a - 5b)^2$.
Reveal Answer & Explanation
Answer: $(4a)^2 - 2(4a)(5b) + (5b)^2 = 16a^2 - 40ab + 25b^2$.
Use $(x-y)^2 = x^2 - 2xy + y^2$.
2
Calculate $103 \times 97$ using an algebraic identity.
Reveal Answer & Explanation
Answer: $10,000 - 9 = 9,991$.
$(100+3)(100-3) = 100^2 - 3^2$.
3
If $x + \frac{1}{x} = 4$, find $x^2 + \frac{1}{x^2}$ and $x^4 + \frac{1}{x^4}$.
Reveal Answer & Explanation
Answer: $x^2 + \frac{1}{x^2} = 4^2 - 2 = 14$ and $x^4 + \frac{1}{x^4} = 14^2 - 2 = 194$.
Square both sides sequentially twice.
4
Find $p$ and $q$ such that $25x^2 - 30x + 9 = (px + q)^2$.
Reveal Answer & Explanation
Answer: $p = 5, q = -3$ (or $p = -5, q = 3$).
Compare with $(5x - 3)^2$.
5
Express $15xy$ as the difference of two squares.
Reveal Answer & Explanation
Answer: $(\frac{5x+3y}{2})^2 - (\frac{5x-3y}{2})^2$.
Set $15xy = (5x)(3y)$ and use $ab = (\frac{a+b}{2})^2 - (\frac{a-b}{2})^2$.
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