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CISCE (ICSE & ISC) Class XI Physics Set 02 (Advanced Level) English Medium 100% Free Practice Test

CISCE (ICSE & ISC) Class XI Physics: Behaviour of Perfect Gases and Kinetic Theory of Gases Online Test (Set 02 (Advanced Level)) | TargetExams

Behaviour of Perfect Gases and Kinetic Theory of Gases — Set 02 (Advanced Level)

Take free online mock test for CISCE (ICSE & ISC) Class XI Physics chapter 'Behaviour of Perfect Gases and Kinetic Theory of Gases'. 20 MCQs, 20 minutes, detailed solutions & score analysis.

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20 MCQs
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20 Mins
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20 Marks
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Instant Scorecard Step-by-Step Solutions ICSE Pattern

Chapter Study Guide & In-Depth Notes

Master the key concepts, vocabulary, and high-yield questions before starting the test.

3 Sections

Chapter Overview & Core Concepts: Behaviour of Perfect Gases and Kinetic Theory of Gases

Class 11 Study Guide

Mastering Behaviour of Perfect Gases and Kinetic Theory of Gases in Class 11 provides critical subject intuition, analytical skills, and examination readiness.

Examinations test fundamental principles, definitions, cause-and-effect reasoning, and real-world applications under timed conditions.

Core Moral & Key Takeaway:

Grasping core concepts and practicing with timed chapter-wise CBT tests guarantees top performance in board exams.

Key Terminology, Definitions & Principles

Glossary & Concepts
Term / Formula Type Definition / Meaning Explanation / Notes Example / Usage
Core Concept Principle Primary concept governing Behaviour of Perfect Gases and Kinetic Theory of Gases. मुख्य सिद्धांत "Understand and apply the principle accurately."
Analytical Deduction Skill Evaluating evidence to draw correct conclusions. तार्किक विश्लेषण "Examine question clues systematically."

Key Features & Devices Explored:

Systematic Elimination
Eliminate distractor choices before selecting the best answer.
Pacing & Accuracy
Complete each question within 60 seconds to maintain steady momentum.

High-Yield Revision Points & Solved Board Exam Q&A

Revision Notes
⚡ High-Yield Exam Takeaways:
  • Review all key textbook terms, definitions, and formulas.
  • Pay attention to units, boundary values, and key keywords in questions.
  • Solve Foundation Set 01 to build confidence, followed by Advanced Set 02 for exam excellence.
Frequently Asked Questions & Model Answers:
Q1 How should students prepare for Behaviour of Perfect Gases and Kinetic Theory of Gases exams?
Answer: Read the chapter thoroughly, practice step-by-step solved examples, memorize key definitions, and evaluate preparation using timed online CBT mock tests.

Sample Questions Preview

Free Sneak Peek

Here is a sneak peek of the questions included in this test set. Test your preparation by viewing the answer and detailed explanation before starting the timed exam.

Q1
According to the Law of Equipartition of Energy, the average thermal energy associated with EACH independent quadratic degree of freedom of a molecule in thermal equilibrium at temperature T is:
ऊर्जा के समविभाजन नियम के अनुसार, तापमान T पर तापीय साम्यावस्था में किसी अणु की प्रत्येक स्वतंत्र द्विघात स्वतंत्रता की कोटि से संबंधित औसत तापीय ऊर्जा क्या होती है?
A
\(\frac{1}{2}\) k_B T\(\frac{1}{2}\) k_B T
B
k_B Tk_B T
C
\(\frac{3}{2}\) k_B T\(\frac{3}{2}\) k_B T
D
\(\frac{5}{2}\) k_B T\(\frac{5}{2}\) k_B T
Correct Answer: Option A
Explanation:
Boltzmann's equipartition theorem states that in thermal equilibrium, the total energy of a dynamic system is shared equally among all independent degrees of freedom that appear quadratically in the energy Hamiltonian (e.g., \(\frac{1}{2}\) m v_x^2, \(\frac{1}{2}\) I ω_x^2, \(\frac{1}{2}\) k x^2). Each quadratic degree of freedom contributes exactly \(\frac{1}{2}\) k_B T to the average energy per molecule (or \(\frac{1}{2}\) R T per mole).
बोल्ट्ज़मान के ऊर्जा समविभाजन नियम के अनुसार, तापीय साम्यावस्था में किसी निकाय की कुल ऊर्जा सभी स्वतंत्र स्वतंत्रता की कोटियों में समान रूप से विभाजित होती है। ऊर्जा व्यंजक में आने वाले प्रत्येक द्विघात पद (जैसे \(\frac{1}{2}\) m v^2) के संगत प्रति अणु औसत ऊर्जा \(\frac{1}{2}\) k_B T (या प्रति मोल \(\frac{1}{2}\) R T) होती है।
Q2
Maxwell-Boltzmann Distribution
The Maxwell-Boltzmann speed distribution curves for a gas at two temperatures T_1 and T_2 (with T_2 > T_1) along with characteristic speeds are shown below:
Based on the distribution curves, which of the following statements is correct?
दो तापमानों T_1 और T_2 (जहाँ T_2 > T_1) पर एक गैस के मैक्सवेल-बोल्ट्ज़मान आणविक चाल वितरण वक्र और लाक्षणिक चालें नीचे दिखाई गई हैं:
वितरण वक्रों के आधार पर निम्नलिखित में से कौन सा कथन सही है?
A
The area under curve T_2 is larger than under curve T_1 because temperature is higherवक्र T_2 के नीचे का क्षेत्रफल वक्र T_1 से बड़ा है क्योंकि तापमान अधिक है
B
As temperature increases from T_1 to T_2, the peak shifts toward higher speeds and broadens, while the total area under both curves remains identical and equal to 1जैसे-जैसे तापमान T_1 से T_2 तक बढ़ता है, शिखर उच्च चाल की ओर खिसकता है और चौड़ा हो जाता है, जबकि दोनों वक्रों के नीचे का कुल क्षेत्रफल समान (1 के बराबर) रहता है
C
The most probable speed v_mp decreases with increasing temperatureतापमान बढ़ने पर अधिकतम प्रायिक चाल v_mp घटती है
D
v_rms < v_avg < v_mp at all temperaturesसभी तापमानों पर v_rms < v_avg < v_mp होता है
Correct Answer: Option B
Explanation:
The area under the Maxwell-Boltzmann probability density curve represents total probability: ∫₀^∞ f(v) dv = 1 (or total number of molecules N), which is strictly conserved and independent of temperature. As temperature rises (T_2 > T_1): (1) The peak shifts rightward because v_mp = √\(\frac{2RT}{M}\) increases proportional to √T; and (2) The peak height decreases and broadens to maintain constant total area. Furthermore, v_mp : v_avg : \(v_rms = 1 : 1\).128 : 1.225, so v_mp < v_avg < v_rms.
मैक्सवेल-बोल्ट्ज़मान प्रायिकता घनत्व वक्र के नीचे का कुल क्षेत्रफल कुल प्रायिकता ∫ f(v) dv = 1 (या कुल अणुओं की संख्या N) को दर्शाता है, जो स्थिर रहती है। तापमान बढ़ने पर (T_2 > T_1): शिखर दाहिनी ओर (उच्च चाल की ओर) खिसकता है और वक्र चौड़ा व चपटा हो जाता है ताकि कुल क्षेत्रफल नियत रहे। साथ ही v_mp < v_avg < v_rms रहता है।

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Mastery of the Elimination Technique

विकल्प निष्कासन विधि में दक्षता

Top rankers in competitive exams rarely compute every problem blindly. They spot subtle traps, evaluate extreme values, and eliminate 2 out of 4 distractors within seconds. Our 4-option sets teach critical distractor analysis.

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कंप्यूटर आधारित परीक्षा का सहज अभ्यास

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Immunity to Negative Marking

सटीकता और नकारात्मक अंकन से सुरक्षा

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तत्काल त्रुटि निवारण एवं आत्म-मूल्यांकन

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Syllabus Concepts Evaluated in this Chapter

This test series specifically evaluates the core competencies and learning objectives outlined in the official syllabus:

  • Core definitions, fundamental theorems, and essential concepts of this chapter.
  • Step-by-step mathematical reasoning and deductive problem-solving.
  • Application of standard formulas and operations in real-world scenarios.
  • Critical examination of common exam pitfalls and misleading options.
  • Higher-order thinking skill (HOTS) questions to prepare for school examinations.
  • Speed and accuracy mastery under standard timed CBT exam conditions.

Exam Rules & Test Taking Guidelines

  • Total Questions: The test consists of exactly 20 objective type questions.
  • Time Allowed: 20 Minutes countdown timer begins as soon as the test launches.
  • Marking Scheme: +1.0 mark is awarded for each correct answer.
  • Zero Penalty: There is 0.0 negative marking for incorrect or unattempted questions.
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  • Review & Solutions: Access instant scorecard and full step-by-step solutions upon submission.

Frequently Asked Questions (FAQs)

Yes! Foundation Practice Set 01 for every chapter in CISCE (ICSE & ISC) Class XI Physics is 100% free to attempt. Students can test their knowledge without any payment or hidden fees.
This page is dedicated to English Medium. You can also attempt this test in Hindi Medium by clicking the switcher at the top.
Absolutely. All 20 multiple-choice questions are strictly designed in line with the latest guidelines, covering both basic conceptual understanding and higher-order thinking skills.
The test contains 20 MCQs to be solved in 20 minutes. Each question carries +1.0 mark for a correct answer, and there is zero (0.0) negative marking for incorrect answers.
Yes. Immediately upon submitting your test, you receive a comprehensive performance summary including your total score, accuracy percentage, time spent per question, and full step-by-step explanations for all 20 questions.

Practice Sets in this Chapter

Set 01 (Foundation)

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Set 02 (Advanced)

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Behaviour of Perfect Gases and Kinetic Theory of Gases (Set 02 (Advanced Level))
20 MCQs • 20 Mins • 100% Free Practice Test

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