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CBSE • Class XII • Chemistry • Ch 1
Estimated Time: 45 Mins
Study Progress: In Progress

Solutions

In Class 12 Chemistry, "Solutions" provides an authoritative, curriculum-verified master resource aligned with the 2026–27 NCERT syllabus.

⚗️ Have You Ever Wondered?

Why do deep-sea scuba divers breathe an artificial mixture of helium and oxygen to avoid the agonizing 'bends', or why do municipal road crews scatter...

Why do deep-sea scuba divers breathe an artificial mixture of helium and oxygen to avoid the agonizing 'bends', or why do municipal road crews scatter rock salt on icy highways in winter to melt ice below $0^\circ\text{C}$? Colligative properties and Henry's Law govern liquid solutions.

Why This Chapter Matters

In Class 12 Chemistry, "Solutions" provides an authoritative, curriculum-verified master resource aligned with the 2026–27 NCERT syllabus.

Before You Begin (Prerequisites)

  • Molarity and molality from Class 11.
  • Vapor pressure.
  • Ideal gases.

What You Will Learn (Core Objectives)

  • State and apply Henry's Law of gas solubility: $p = K_H x$.
  • State and apply Raoult's Law for volatile liquid mixtures: $p_A = p_A^\circ x_A$.
  • Distinguish between Ideal and Non-Ideal solutions (Positive and Negative deviations, Azeotropes).
  • Derive and apply the four Colligative Properties: Relative Lowering of Vapor Pressure, Elevation of Boiling Point ($\Delta T_b = K_b m$), Depression of Freezing Point ($\Delta T_f = K_f m$), and Osmotic Pressure ($\Pi = CRT$).
  • Calculate Abnormal Molar Masses using the Van't Hoff Factor ($i$).

Chapter Roadmap & Progression

1 1. Henry's Law & Raoult's Law
2 2. Colligative Properties (Depend s...
3 3. Abnormal Molar Mass & Van't Hoff...

Complete Concept Guide (100% Curriculum Coverage)

1. Henry's Law & Raoult's Law

  • Henry's Law: The solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid: $\mathbf{p = K_H x}$. (Explains deep-sea diver 'bends' and soda carbonation).
  • Raoult's Law: For a solution of volatile liquids, the partial vapor pressure of each component is: $\mathbf{p_A = p_A^\circ x_A}$. Total pressure: $\mathbf{P_{\text{total}} = p_A + p_B}$.

2. Colligative Properties (Depend strictly on particle number)

  • Relative Lowering of Vapor Pressure: $\frac{p_1^\circ - p_1}{p_1^\circ} = x_2$.
  • Elevation of Boiling Point: $\mathbf{\Delta T_b = K_b \cdot m}$ ($K_b$ is Ebullioscopic constant).
  • Depression of Freezing Point: $\mathbf{\Delta T_f = K_f \cdot m}$ ($K_f$ is Cryoscopic constant; ethylene glycol antifreeze).
  • Osmotic Pressure: $\mathbf{\Pi = C R T} = \frac{n_2}{V}RT$ (used to determine molecular weights of polymers and biomolecules!).

3. Abnormal Molar Mass & Van't Hoff Factor ($i$)

When solutes dissociate or associate in solution: $$\mathbf{i = \frac{\text{Normal Molar Mass}}{\text{Abnormal Molar Mass}} = \frac{\text{Total moles of particles after dissociation/association}}{\text{Initial moles of solute}}}$$ For $\text{NaCl} \to \text{Na}^+ + \text{Cl}^-$, $i = 2$; for dimerizing acetic acid in benzene, $i = 0.5$.

Visual Learning & Conceptual Map

Solutions Master Matrix

Conceptual framework, core mechanisms, and analytical relationships
Academic Architecture

1. Henry's Law & Raoult's Law • 2. Colligative Properties (Depend strictly on particle number)

Chapter Summary & 10 Key Takeaways

Takeaway 1
Henry's Law: Gas solubility scaling linearly with partial headspace pressure.
Takeaway 2
Raoult's Law: Partial vapor pressure equals pure component pressure times mole fraction.
Takeaway 3
Colligative Property: Thermodynamic property depending exclusively on the number of solute particles.
Takeaway 4
Osmotic Pressure: Hydrostatic pressure preventing net solvent diffusion across semi-permeable membrane.
Takeaway 5
Van't Hoff Factor ($i$): Multiplier accounting for solute electrolytic ionization or dimerization.

Check Your Understanding (Diagnostic Practice Questions)

Diagnostic questions testing core conceptual clarity. Answers are hidden initially — solve each problem first, then click to reveal the step-by-step verified solution.

1
State Henry's Law and mention two of its important applications.
Reveal Answer & Explanation
Answer: Henry's Law states that at constant temperature, the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas over the solution ($p = K_H x$). Applications: (1) Sealing carbonated soft drinks under high pressure to increase CO2 solubility, (2) Deep-sea scuba divers using helium-diluted oxygen to prevent nitrogen bubbles ('bends').
p = K_H x; carbonated drinks and scuba diving.
2
Why does the boiling point of a solvent increase when a non-volatile solute is added to it?
Reveal Answer & Explanation
Answer: Adding a non-volatile solute decreases the solvent's vapor pressure because solute molecules occupy surface space. To make the vapor pressure equal atmospheric pressure, higher thermal kinetic energy (higher temperature) is needed, elevating the boiling point.
Vapor pressure lowers, requiring higher temperature to boil.
3
What are Azeotropes? Distinguish between minimum-boiling and maximum-boiling azeotropes.
Reveal Answer & Explanation
Answer: Azeotropes are binary liquid mixtures that boil at a constant temperature and distill over without change in composition. Solutions showing large positive deviation from Raoult's law form Minimum-Boiling azeotropes (e.g. 95% ethanol); solutions showing large negative deviation form Maximum-Boiling azeotropes (e.g. 68% nitric acid).
Constant-boiling binary mixtures with identical vapor/liquid composition.
4
Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving $1.0\text{ g}$ of polymer of molar mass $185,000$ in $450\text{ mL}$ of water at $37^\circ\text{C}$.
Reveal Answer & Explanation
Answer: $n = \frac{1.0}{185,000}\text{ mol}$. $V = 0.450\text{ L}$. $T = 310.15\text{ K}, R = 8.314 \times 10^3\text{ Pa}\cdot\text{L}/(\text{mol}\cdot\text{K})$. $\Pi = \frac{n}{V}RT = \frac{1.0 \times 8.314 \times 10^3 \times 310.15}{185,000 \times 0.450} = \frac{2578587}{83250} \approx 30.97\text{ Pa}$.
30.97 Pa.
5
What is the Van't Hoff factor for complete dissociation of $\text{K}_2\text{SO}_4$ in aqueous solution?
Reveal Answer & Explanation
Answer: $\text{K}_2\text{SO}_4 \to 2\text{K}^+ + \text{SO}_4^{2-}$. Total ions produced per molecule $= 2 + 1 = 3$. For 100% dissociation, Van't Hoff factor $i = 3$.
i = 3.
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