To locate a point on a line, you only need one number. But to locate a point on a flat sheet of paper, you need two independent measurements: distance left/right and distance up/down. That is why a plane is two-dimensional.
- $X$-axis: The horizontal number line $X'OX$.
- $Y$-axis: The vertical number line $Y'OY$, intersecting perpendicularly at the Origin $O(0, 0)$.
- Abscissa: The perpendicular distance from the $Y$-axis (the $x$-value).
- Ordinate: The perpendicular distance from the $X$-axis (the $y$-value).
| Quadrant | $X$-coordinate (Abscissa) | $Y$-coordinate (Ordinate) | Sign Pattern | Example Point |
|---|---|---|---|---|
| Quadrant I | Positive ($>0$) | Positive ($>0$) | $(+, +)$ | $(3, 5)$ |
| Quadrant II | Negative ($<0$) | Positive ($>0$) | $(-, +)$ | $(-4, 2)$ |
| Quadrant III | Negative ($<0$) | Negative ($<0$) | $(-, -)$ | $(-3, -6)$ |
| Quadrant IV | Positive ($>0$) | Negative ($<0$) | $(+, -)$ | $(5, -2)$ |
Problem: Identify the quadrant or axis for each point: $A(-3, 4)$, $B(5, -2)$, $C(-4, -5)$, $D(0, 7)$, $E(-6, 0)$.
- $A(-3, 4)$: $x < 0, y > 0 \implies$ Quadrant II.
- $B(5, -2)$: $x > 0, y < 0 \implies$ Quadrant IV.
- $C(-4, -5)$: $x < 0, y < 0 \implies$ Quadrant III.
- $D(0, 7)$: $x = 0 \implies$ lies on the $Y$-axis (positive $Y$-axis).
- $E(-6, 0)$: $y = 0 \implies$ lies on the $X$-axis (negative $X$-axis).
$(a, b)$ is strictly an ordered pair! $(3, 5)$ is completely different from $(5, 3)$. $(3, 5)$ means 3 units along $X$ and 5 units along $Y$; $(5, 3)$ means 5 units along $X$ and 3 units along $Y$.
Every digital computer screen is a 2D Cartesian grid of pixels (e.g. $1920 \times 1080$), where graphics software updates pixel colors by referencing exact $(x, y)$ coordinate positions.