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CBSE • Class 9 • Science • Ch 3
Estimated Time: 45 Mins
Study Progress: In Progress

Atoms and Molecules

In Class 9 Science, "Atoms and Molecules" provides an authoritative, curriculum-verified master resource aligned with the 2026–27 NCERT syllabus.

⚛️ Have You Ever Wondered?

If you take a piece of gold and divide it in half again and again, do you eventually reach an indivisible speck? Ancient Indian philosopher Maharishi ...

If you take a piece of gold and divide it in half again and again, do you eventually reach an indivisible speck? Ancient Indian philosopher Maharishi Kanad named it 'Paramanu'; today, modern chemistry calls it the Atom.

Why This Chapter Matters

In Class 9 Science, "Atoms and Molecules" provides an authoritative, curriculum-verified master resource aligned with the 2026–27 NCERT syllabus.

Before You Begin (Prerequisites)

  • Elements, compounds, and symbols.
  • Basic chemical formulas ($H_2O, CO_2$).
  • Law of conservation of mass.

What You Will Learn (Core Objectives)

  • State and verify the Law of Conservation of Mass and the Law of Constant Proportions.
  • Describe Dalton's Atomic Theory and evaluate its historical postulates.
  • Write chemical formulas of ionic and molecular compounds using the Criss-Cross valency method.
  • Calculate Molecular Mass and Formula Unit Mass in unified atomic mass units (u).
  • Explain the Mole Concept and Avogadro's Number ($6.022 \times 10^{23}$).

Chapter Roadmap & Progression

1 1. The Two Fundamental Laws of Chem...
2 2. Writing Chemical Formulas: Criss...
3 3. The Mole Concept & Avogadro's Nu...

Complete Concept Guide (100% Curriculum Coverage)

1. The Two Fundamental Laws of Chemical Combination

  • Law of Conservation of Mass (Lavoisier): Mass can neither be created nor destroyed in a chemical reaction. Total mass of reactants equals total mass of products!
  • Law of Constant Proportions (Proust): In a chemical substance, elements are always combined in a fixed proportion by mass (e.g. pure water anywhere on Earth is always $1 : 8$ hydrogen to oxygen by mass).

2. Writing Chemical Formulas: Criss-Cross Method

To write formulas, write symbols with their valencies below, and criss-cross:
• Aluminum Oxide: $\text{Al}^{3+}$ and $\text{O}^{2-} \implies \mathbf{\text{Al}_2\text{O}_3}$
• Calcium Hydroxide: $\text{Ca}^{2+}$ and $\text{OH}^{1-} \implies \mathbf{\text{Ca(OH)}_2}$.

3. The Mole Concept & Avogadro's Number

One Mole of any substance contains exactly $\mathbf{6.022 \times 10^{23}}$ elementary particles (atoms or molecules). The mass of 1 mole in grams equals its atomic or molecular mass in unified units (u) (e.g. 1 mole of $\text{H}_2\text{O}$ has a mass of $18\text{ g}$ and contains $6.022 \times 10^{23}$ water molecules).

Visual Learning & Conceptual Map

Atoms and Molecules Master Matrix

Conceptual framework, core mechanisms, and analytical relationships
Academic Architecture

1. The Two Fundamental Laws of Chemical Combination • 2. Writing Chemical Formulas: Criss-Cross Method

Chapter Summary & 10 Key Takeaways

Takeaway 1
Conservation of Mass: $\text{Mass of Reactants} = \text{Mass of Products}$.
Takeaway 2
Constant Proportions: Elements combine in fixed mass ratios.
Takeaway 3
Valency Criss-Cross: Swap oxidation numbers to balance neutral compounds.
Takeaway 4
Atomic Mass Unit (u): Standardized relative to $1/12$th mass of carbon-12 atom.
Takeaway 5
Avogadro Constant: $N_A = 6.022 \times 10^{23}\text{ particles/mole}$.

Check Your Understanding (Diagnostic Practice Questions)

Diagnostic questions testing core conceptual clarity. Answers are hidden initially — solve each problem first, then click to reveal the step-by-step verified solution.

1
Calculate the molecular mass of nitric acid ($\text{HNO}_3$). (Given: H=1 u, N=14 u, O=16 u).
Reveal Answer & Explanation
Answer: $1(1) + 1(14) + 3(16) = 1 + 14 + 48 = 63\text{ u}$.
Sum of constituent atomic masses.
2
Write the chemical formula for: (a) Magnesium chloride (b) Aluminum sulfate.
Reveal Answer & Explanation
Answer: (a) $\text{Mg}^{2+}$ and $\text{Cl}^- \implies \text{MgCl}_2$. (b) $\text{Al}^{3+}$ and $\text{SO}_4^{2-} \implies \text{Al}_2(\text{SO}_4)_3$.
Criss-cross valencies.
3
How many moles are present in 52 g of Helium gas? (Atomic mass of He = 4 u).
Reveal Answer & Explanation
Answer: $\text{Number of moles} = \frac{\text{Given Mass}}{\text{Molar Mass}} = \frac{52\text{ g}}{4\text{ g/mol}} = 13\text{ moles}$.
Mass divided by molar mass.
4
In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid, producing 2.2 g of carbon dioxide, 0.9 g of water, and 8.2 g of sodium ethanoate. Show that this obeys the Law of Conservation of Mass.
Reveal Answer & Explanation
Answer: Reactants $= 5.3 + 6.0 = 11.3\text{ g}$. Products $= 2.2 + 0.9 + 8.2 = 11.3\text{ g}$. Since $\text{Mass of Reactants} = \text{Mass of Products}$, the law is verified!
Total reactant mass equals product mass.
5
What is the mass of 0.5 moles of water molecules?
Reveal Answer & Explanation
Answer: $0.5 \times 18\text{ g/mol} = 9\text{ grams}$.
0.5 times 18.
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Timed CBT Practice Tests (Exam Simulator)

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