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ICSE • Class 8 • Mathematics • Ch 2
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Rational Numbers

In ICSE Class 8 Mathematics, "Rational Numbers" provides an authoritative, axiomatic master study guide investigating the closure, algebraic structure, arithmetic operations, density property, and number line representations of rational numbers $\mathbb{Q}$. This comprehensive chapter explores Definition of a Rational Number (Any number expressible in the form $\frac{p}{q}$ where $p, q \in \mathbb{Z}$ and $q \ne 0$; Positive, Negative, and Zero as a rational number; Standard form: $q > 0$ and $\gcd(p, q) = 1$), The Core Axiomatic Properties (1. Closure Property under addition, subtraction, and multiplication, 2. Commutative Property: $a + b = b + a$ and $a \times b = b \times a$; Non-commutativity of subtraction and division, 3. Associative Property: $(a + b) + c = a + (b + c)$ and $(a \times b) \times c = a \times (b \times c)$, 4. Distributive Property of Multiplication over Addition and Subtraction: $a(b \pm c) = ab \pm ac$, 5. Identity Elements: Additive identity $0$ and Multiplicative identity $1$, 6. Inverses: Additive inverse / negative $-a$ and Multiplicative inverse / reciprocal $\frac{1}{a}$ where $a \ne 0$), Finding Rational Numbers Between Two Given Rational Numbers (The Mean / Midpoint Method: $\frac{a + b}{2}$; The Common Denominator / Scaling Method), Representation on the Real Number Line, Decimal Representation of Rational Numbers (Terminating decimals vs Non-terminating recurring / repeating decimals; Identifying termination via prime factors of denominator: $q = 2^m \times 5^n$), and Real-World Multi-Step Word Problems aligned with the 2026–27 CISCE ICSE curriculum.

Why Did Ancient Greek Mathematicians Throw a Man Overboard into the Mediterranean Sea for Discovering a Number That Refused to Be a Fraction?

In the 5th century BCE in southern Italy, the secret brotherhood of the Pythagoreans worshipped a sacred mathematical doctrine: "All is Number." They believed with religious fervor that every measurement in the entire universe—the musical harmony of a lyre string, the orbits of the stars, the height of a temple—could be expressed as a clean ratio of two whole integers: a RATIONAL NUMBER ($\frac{p}{q}$)! But then, a brilliant Pythagorean philosopher named Hippasus of Metapontum drew a simple square of side 1 and calculated the length of its diagonal using Pythagoras' own theorem ($d = \sqrt{1^2 + 1^2} = \sqrt{2}$). Hippasus tried to write $\sqrt{2}$ as a fraction $\frac{p}{q}$ and discovered a terrifying truth: it was mathematically impossible! His discovery shattered the universe of the Pythagoreans. Legend says the brotherhood took Hippasus out on a boat into the deep Mediterranean Sea and threw him overboard to drown, desperate to bury the secret! Why is a rational number defined strictly with $q \ne 0$? How does the Density Property prove that between any two rational numbers, there are INFINITE rational numbers? Let's master rational numbers.

Why This Chapter Matters

Rational numbers form the foundation of continuous quantitative mathematics: financial interest calculations, precision engineering blueprints, fractional cooking measurements, scientific data plotting, and computer floating-point calculations. Mastering axiomatic closure, distributivity, and common denominator scaling is a core ICSE algebra requirement.

Before You Begin (Prerequisites)

  • Integers ($\mathbb{Z}$) and rules of positive/negative signs from Class 7.
  • Simplifying and finding equivalent fractions.
  • LCM and HCF of integers.

What You Will Learn (Core Objectives)

  • Express rational numbers in standard form with a positive denominator and co-prime terms.
  • Verify and apply Closure, Commutative, Associative, and Distributive properties across all operations.
  • Identify additive inverse ($-a$) and multiplicative inverse / reciprocal ($1/a$) correctly.
  • Insert any specified number of rational numbers between two given rational numbers.
  • Determine whether a rational number yields a terminating or recurring decimal by factoring its denominator ($2^m \times 5^n$).
  • Plot positive and negative rational numbers accurately on the number line.

Chapter Roadmap & Progression

1 1. Definition, Standard Form & The...
2 2. Axiomatic Properties of Rational...
3 3. Inserting Rational Numbers: Two...
4 4. Terminating vs Repeating Decimal...

Complete Concept Guide (100% Curriculum Coverage)

1. Definition, Standard Form & The Density Property

Understand
A. Definition & Standard Form:

A number that can be expressed in the form $\mathbf{\frac{p}{q}}$, where $p$ and $q$ are integers and $\mathbf{q \ne 0}$, is called a Rational Number ($\mathbb{Q}$).

  • Standard Form: A rational number $\frac{p}{q}$ is in standard form if:
    1. Its denominator $q$ is strictly positive ($q > 0$).
    2. The numerator $p$ and denominator $q$ have no common factor other than $1$ (they are co-prime: $\gcd(|p|, q) = 1$).
    3. Example: Express $\frac{36}{-54}$ in standard form: $\frac{36 \div (-18)}{-54 \div (-18)} = \mathbf{-\frac{2}{3}}$.
B. The Density Property of Rational Numbers:

Between any two distinct rational numbers $a$ and $b$, there exist infinitely many rational numbers! There is no such thing as the "next" rational number.

2. Axiomatic Properties of Rational Numbers

Axiomatic Properties
  1. Closure Property: Rational numbers are closed under Addition, Subtraction, and Multiplication. $$a + b \in \mathbb{Q}, \quad a - b \in \mathbb{Q}, \quad a \times b \in \mathbb{Q}$$ *(Division is closed ONLY if the divisor is non-zero: $\frac{a}{b} \in \mathbb{Q}$ for $b \ne 0$)*.
  2. Commutative Property:
    • Addition is commutative: $a + b = b + a$.
    • Multiplication is commutative: $a \times b = b \times a$.
    • *Subtraction and Division are NOT commutative!* ($a - b \ne b - a$ and $a \div b \ne b \div a$).
  3. Associative Property: $$(a + b) + c = a + (b + c) \quad \land \quad (a \times b) \times c = a \times (b \times c)$$
  4. Distributive Property of Multiplication over Addition/Subtraction: $$\mathbf{a(b \pm c) = ab \pm ac}$$
  5. Identities & Inverses:
    • Additive Identity: $0$ ($a + 0 = 0 + a = a$).
    • Multiplicative Identity: $1$ ($a \times 1 = 1 \times a = a$).
    • Additive Inverse: $-a$ (such that $a + (-a) = 0$).
    • Multiplicative Inverse (Reciprocal): $\frac{1}{a}$ for $a \ne 0$ (such that $a \times \frac{1}{a} = 1$). Zero has NO reciprocal!

3. Inserting Rational Numbers: Two Methods

Inserting Numbers
Method 1: The Mean / Average Method:

To find a rational number strictly between $a$ and $b$ (where $a < b$):

$$\mathbf{m = \frac{a + b}{2} \implies a < \frac{a + b}{2} < b}$$

Repeat successively to generate multiple numbers: $a < \frac{a + m}{2} < m < \frac{m + b}{2} < b$.

Method 2: Common Denominator & Scaling Method (Faster for multiple numbers):

To insert $n$ rational numbers between $\frac{a}{b}$ and $\frac{c}{d}$:

  1. Convert both fractions to have an identical common denominator using LCM.
  2. Multiply both numerator and denominator of both fractions by $(n + 1)$ (or 10).
  3. Select intermediate numerators directly!
  4. Example: Insert 5 rational numbers between $-\frac{1}{3}$ and $\frac{1}{2}$:

    Common denominator LCM(3, 2) = 6: $-\frac{2}{6}$ and $\frac{3}{6}$. Multiply by 2: $-\frac{4}{12}$ and $\frac{6}{12}$.

    Intermediate rational numbers: $\mathbf{-\frac{3}{12}, -\frac{2}{12}, -\frac{1}{12}, \frac{1}{12}, \frac{2}{12}}$.

4. Terminating vs Repeating Decimals (Condition on $q$)

Decimal Representation
The Prime Factorisation Test:

Let $x = \frac{p}{q}$ be a rational number in its simplest standard form ($\gcd(p, q) = 1$):

  • Terminating Decimal: The decimal expansion terminates (ends) if and only if the prime factorisation of the denominator $q$ contains ONLY powers of 2 and/or 5: $$\mathbf{q = 2^m \times 5^n \quad (m, n \in \mathbb{W})}$$ Examples: $\frac{7}{40} = \frac{7}{2^3 \times 5^1} = 0.175$ (terminates!). $\frac{3}{25} = \frac{3}{5^2} = 0.12$ (terminates!).
  • Non-Terminating Repeating (Recurring) Decimal: If $q$ has any prime factor other than 2 or 5 (such as 3, 7, 11, 13), the decimal expansion is non-terminating and periodic: Examples: $\frac{1}{3} = 0.333\dots = 0.\bar{3}$; $\quad \frac{2}{7} = 0.\overline{285714}$.

Key Formulas, Identities & Theorems

Rational Number Standard Definition
$$\mathbb{Q} = \left\{ \frac{p}{q} \;\middle|\; p, q \in \mathbb{Z}, \; q \ne 0, \; \gcd(|p|, q) = 1 \right\}$$
Set of all rational numbers.
Decimal Termination Criterion
$$q = 2^m \times 5^n \iff \text{Decimal representation is terminating}$$
Applies strictly when p/q is in irreducible lowest terms.

Rational Numbers: Number Line & Axiomatic Properties

Rational Numbers: Axioms, Density & Decimal Classification CORE AXIOMATIC PROPERTIES • Closure: Closed under +, -, × (Division closed only if divisor ≠ 0) • Commutative: a+b = b+a • ab = ba Subtraction & Division are NOT commutative! • Distributive Law: a(b ± c) = ab ± ac • Identity & Inverse Elements: Additive Identity = 0 • Multiplicative Identity = 1 Additive Inverse = -a • Reciprocal = 1/a ZERO HAS NO RECIPROCAL! DENSITY & TERMINATION CRITERION 1. Density Property: Infinite Numbers Between Any Two Mean method: m = (a + b) / 2 0 ½ 1 2. Terminating Decimal Test: q = 2m × 5n ⇒ TERMINATES! 7/40 = 7/(23×51) = 0.175 (Terminating) 1/3, 2/7 = Non-terminating recurring (0.333...) RATIONAL NUMBERS: p/q (q≠0) • DENSITY: INFINITE INTERMEDIATES • q=2^m × 5^n TERMINATES

Chapter Summary & 10 Key Takeaways

Takeaway 1
A rational number is any number expressible as p/q where p and q are integers and q != 0.
Takeaway 2
Standard form requires a positive denominator and co-prime numerator and denominator (gcd = 1).
Takeaway 3
Rational numbers are closed under addition, subtraction, and multiplication.
Takeaway 4
Multiplication is distributive over addition and subtraction: a(b +- c) = ab +- ac.
Takeaway 5
Additive identity is 0; Multiplicative identity is 1.
Takeaway 6
The additive inverse of a is -a; the multiplicative inverse (reciprocal) of a is 1/a (for a != 0).
Takeaway 7
Zero has NO reciprocal because division by zero is undefined.
Takeaway 8
The Density Property states that between any two rational numbers lie infinitely many rational numbers.
Takeaway 9
Two methods for inserting numbers: the Mean Method (a+b)/2 and Common Denominator Scaling.
Takeaway 10
A rational number p/q terminates in decimal form if and only if the prime factors of q are only 2 and/or 5.

Check Your Understanding (Diagnostic Practice Questions)

Diagnostic questions testing core conceptual clarity. Answers are hidden initially — solve each problem first, then click to reveal the step-by-step verified solution.

1
Using the Distributive Property, evaluate: $\left( -\frac{3}{7} \right) \times \frac{5}{12} + \frac{11}{12} \times \left( -\frac{3}{7} \right)$.
Reveal Answer & Explanation
Answer: Notice that $\left( -\frac{3}{7} \right)$ is a common factor in both terms.
Apply the Distributive Property $ab + ac = a(b + c)$:
$$= \left( -\frac{3}{7} \right) \times \left( \frac{5}{12} + \frac{11}{12} \right)$$
$$= \left( -\frac{3}{7} \right) \times \left( \frac{5 + 11}{12} \right)$$
$$= \left( -\frac{3}{7} \right) \times \frac{16}{12}$$
Simplify $\frac{16}{12} = \frac{4}{3}$:
$$= \left( -\frac{3}{7} \right) \times \frac{4}{3} = \mathbf{-\frac{4}{7}}$$.
Factor out $(-3/7)$: $(-3/7) \times (5/12 + 11/12) = (-3/7) \times (16/12) = -4/7$.
2
Insert 5 rational numbers between $\frac{2}{3}$ and $\frac{4}{5}$ using the common denominator scaling method.
Reveal Answer & Explanation
Answer: Step 1: Find LCM of denominators (3, 5) = $15$. Convert to like fractions:
$$\frac{2}{3} = \frac{2 \times 5}{3 \times 5} = \frac{10}{15}$$
$$\frac{4}{5} = \frac{4 \times 3}{5 \times 3} = \frac{12}{15}$$
Step 2: There is only one integer between 10 and 12 (which is 11). To insert 5 numbers, multiply both numerator and denominator by $(5 + 1) = 6$ (or by 10):
$$\frac{10 \times 6}{15 \times 6} = \frac{60}{90}$$
$$\frac{12 \times 6}{15 \times 6} = \frac{72}{90}$$
Step 3: Select any 5 intermediate fractions:
$$\mathbf{\frac{61}{90}, \frac{62}{90}, \frac{63}{90}, \frac{64}{90}, \frac{65}{90}}$$.
Convert to common denominator 15, then scale by 6: $60/90$ and $72/90$. Pick intermediate fractions.
3
Without actual division, determine whether each of the following rational numbers will have a terminating or non-terminating repeating decimal expansion:
(a) $\frac{13}{80}$
(b) $\frac{29}{343}$
(c) $\frac{77}{210}$.
Reveal Answer & Explanation
Answer:

• (a) $\frac{13}{80}$:
Already in simplest form ($\gcd(13, 80) = 1$). Prime factorise denominator $80$:

$$80 = 2^4 \times 5^1$$


Since the prime factors are only 2 and 5, it has a TERMINATING decimal expansion.

• (b) $\frac{29}{343}$:
Simplest form. Denominator: $343 = 7^3$.
Contains the prime factor $7$ (other than 2 or 5), so it has a NON-TERMINATING REPEATING decimal expansion.

• (c) $\frac{77}{210}$:
Reduce to simplest terms first! Divide by 7:

$$\frac{77 \div 7}{210 \div 7} = \frac{11}{30}$$


Prime factorise denominator $30 = 2 \times 3 \times 5$.
Contains the prime factor $3$, so it has a NON-TERMINATING REPEATING decimal expansion.


Always simplify to lowest terms first, then factorise denominator $q$. If $q = 2^m \times 5^n$, it terminates.
4
Find the multiplicative inverse (reciprocal) of: $\left( -\frac{5}{8} \right) \times \left( -\frac{3}{7} \right)$.
Reveal Answer & Explanation
Answer: Step 1: Evaluate the product:
$$\left( -\frac{5}{8} \right) \times \left( -\frac{3}{7} \right) = \frac{(-5) \times (-3)}{8 \times 7} = \frac{15}{56}$$
Step 2: The multiplicative inverse (reciprocal) of $\frac{a}{b}$ is $\frac{b}{a}$:
$$\text{Reciprocal of } \frac{15}{56} = \mathbf{\frac{56}{15}}$$.
Multiply first: $(-5/8) \times (-3/7) = 15/56$. The reciprocal is $56/15$.
5
Verify the Associative Property of Addition for $x = -\frac{2}{3}, y = \frac{4}{5}, z = -\frac{5}{6}$.
Reveal Answer & Explanation
Answer:

Associative Property: $(x + y) + z = x + (y + z)$.
• LHS: $(x + y) + z = \left( -\frac{2}{3} + \frac{4}{5} \right) + \left( -\frac{5}{6} \right)$

$$= \left( \frac{-10 + 12}{15} \right) - \frac{5}{6} = \frac{2}{15} - \frac{5}{6}$$


LCM of 15 and 6 is 30:

$$= \frac{4 - 25}{30} = -\frac{21}{30} = -\frac{7}{10}$$


• RHS: $x + (y + z) = -\frac{2}{3} + \left( \frac{4}{5} - \frac{5}{6} \right)$

$$= -\frac{2}{3} + \left( \frac{24 - 25}{30} \right) = -\frac{2}{3} - \frac{1}{30}$$


$$= \frac{-20 - 1}{30} = -\frac{21}{30} = -\frac{7}{10}$$


Since $\text{LHS} = \text{RHS} = -\frac{7}{10}$, the Associative Property is verified!


Compute LHS and RHS separately: both equal $-21/30 = -7/10$.
6
The product of two rational numbers is $-\frac{14}{27}$. If one of the numbers is $\frac{7}{9}$, find the other number.
Reveal Answer & Explanation
Answer: Let the unknown number be $x$.
According to the problem:
$$\frac{7}{9} \times x = -\frac{14}{27}$$
Multiply both sides by the reciprocal of $\frac{7}{9}$ (which is $\frac{9}{7}$):
$$x = -\frac{14}{27} \times \frac{9}{7}$$
Cancel common factors ($-14 \div 7 = -2$, and $27 \div 9 = 3$):
$$x = \frac{-2 \times 1}{3 \times 1} = \mathbf{-\frac{2}{3}}$$.
$x = (-14/27) \div (7/9) = (-14/27) \times (9/7) = -2/3$.
7
What should be subtracted from $\left( \frac{3}{4} - \frac{2}{3} \right)$ to get $-\frac{1}{6}$?
Reveal Answer & Explanation
Answer: Step 1: Simplify the bracket $\left( \frac{3}{4} - \frac{2}{3} \right)$:
$$\text{LCM}(4, 3) = 12 \implies \frac{9 - 8}{12} = \frac{1}{12}$$
Step 2: Let the required number to be subtracted be $x$:
$$\frac{1}{12} - x = -\frac{1}{6}$$
Transpose $x$ to RHS and $-\frac{1}{6}$ to LHS:
$$x = \frac{1}{12} + \frac{1}{6} = \frac{1 + 2}{12} = \frac{3}{12} = \mathbf{\frac{1}{4}}$$.
Evaluate $(3/4 - 2/3) = 1/12$. Set $1/12 - x = -1/6 \implies x = 1/12 + 2/12 = 3/12 = 1/4$.
8
Explain why the number zero ($0$) has no reciprocal in the set of rational numbers.
Reveal Answer & Explanation
Answer:

• The reciprocal of a rational number $a$ is defined as $\frac{1}{a}$, which satisfies $a \times \frac{1}{a} = 1$.
• If $a = 0$, its reciprocal would be $\frac{1}{0}$.
• In mathematics, division by zero is strictly undefined, because there is no finite real number which, when multiplied by $0$, yields $1$ ($0 \times x = 0 \ne 1$ for all $x$).
• Therefore, zero is the only rational number that has NO reciprocal.


The reciprocal would be $1/0$, and division by zero is undefined because $0 \times x = 0 \ne 1$.
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