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WBB • Class X • Mathematics • Ch 1
Estimated Time: 120 minutes
Study Progress: In Progress

Quadratic Equations in One Variable

Quadratic Equations in One Variable forms the cornerstone of the WBBSE Class 10 Mathematics curriculum Ganit Prakash. A polynomial equation of the second degree in a single variable is known as a quadratic equation in one variable. Its standard mathematical form is ax^2 + bx + c = 0, where a, b, and c are real numbers and the leading coefficient a is strictly non-zero. If a were zero, the second-degree term would vanish, reducing the equation to a linear equation bx + c = 0. Quadratic equations are classified into pure quadratic equations where the linear coefficient b is zero, and adfected or mixed quadratic equations where b is non-zero. The chapter systematically equips students with three foundational solution techniques: factorization by splitting the middle term, completing the square, and applying the universal quadratic formula discovered by the ancient Indian mathematician Sridhar Acharya. The nature of the two roots is governed entirely by the discriminant D = b^2 - 4ac. When D is greater than zero, the roots are real and unequal; if D is a perfect square with rational coefficients, the roots are rational, whereas if D is not a perfect square, they form irrational conjugate pairs. When D equals zero, the roots are real and coincident. When D is less than zero, no real roots exist. The chapter also rigorously explores the relations between roots and coefficients, demonstrating that the sum of the roots equals -b/a and their product equals c/a, enabling students to construct quadratic equations from known roots. Finally, students learn how to translate complex practical situations—such as speed-distance-time variations, tap filling rates, geometric dimensions, and digit problems—into solvable quadratic equations.

Have You Ever Wondered?

How can a single algebraic equation predict the trajectory of an artillery shell, model the maximum profit of an enterprise, determine the exact speed of a train battling a headwind, and unlock the fundamental symmetries of physics? Originating from ancient Babylonian clay tablets and perfected by the Indian master mathematician Sridhar Acharya in the 9th century, quadratic equations form the primary bridge from elementary algebra to higher mathematical analysis.

Why This Chapter Matters

Mastery of quadratic equations is essential not only for scoring top marks in the WBBSE Madhyamik examination but also as an indispensable foundation for higher mathematics, physics, engineering, and data science. In Madhyamik, quadratic equations account for significant weightage across multiple-choice questions, short answer questions, and compulsory 3-mark and 4-mark algebraic word problems. Beyond examinations, quadratic equations model projectile motion, planetary orbits, optimization in economics, electrical circuits with impedance, and architectural arch designs. The historical derivation by Sridhar Acharya demonstrates the profound heritage of Indian mathematics and trains students in rigorous deductive logic, algebraic manipulation, and real-world mathematical modeling.

Before You Begin (Prerequisites)

  • Algebraic factorization techniques including splitting the middle term and algebraic identities (a + b)^2, (a - b)^2, and a^2 - b^2.
  • Basic arithmetic operations on signed real numbers, fractions, and square roots.
  • Linear equations in one variable and the zero product rule (if ab = 0, then a = 0 or b = 0).
  • Translating verbal statements into algebraic equations.

What You Will Learn (Core Objectives)

  • Identify and formulate the standard general form of a quadratic equation in one variable: ax^2 + bx + c = 0 with a != 0, recognizing why a cannot be zero.
  • Differentiate between pure quadratic equations (b = 0) and adfected quadratic equations (b != 0).
  • Solve quadratic equations efficiently using the factorization method and completing the square.
  • Derive and apply Sridhar Acharya's quadratic formula x = (-b +- sqrt(b^2 - 4ac)) / (2a) to find real roots.
  • Analyze the nature of roots using the discriminant D = b^2 - 4ac across positive, zero, and negative values.
  • Establish the fundamental relationships between the roots (alpha, beta) and the coefficients: alpha + beta = -b/a and alpha * beta = c/a.
  • Construct quadratic equations from given roots and evaluate symmetric expressions of roots.
  • Model and solve real-world board exam word problems involving digits, speeds, geometric dimensions, and cistern taps.

Chapter Roadmap & Progression

1 Module 1: General Form of Quadratic...
2 Module 2: Solution by Factorization...
3 Module 3: Sridhar Acharya's Quadrat...
4 Module 4: Relations between Roots &...
5 Module 5: Board Standard Real-World...

Complete Concept Guide (100% Curriculum Coverage)

Module 1: General Form of Quadratic Equations & Classification

1.1 Definition & Standard Form

An equation containing a single variable whose highest power (degree) is $2$ is called a Quadratic Equation in One Variable (একচলবিশিষ্ট দ্বিঘাত সমীকরণ). In standard mathematical notation, it is written as:

Standard Form: $ax^2 + bx + c = 0 \quad (a eq 0, \quad a, b, c \in \mathbb{R})$

Here, $x$ is the unknown variable, $a$ is the coefficient of $x^2$ (leading coefficient), $b$ is the coefficient of $x$, and $c$ is the constant term. The condition $a eq 0$ is essential: if $a = 0$, the $x^2$ term vanishes, reducing the equation to $bx + c = 0$, which is a linear equation of degree $1$.

1.2 Classification: Pure vs. Adfected Quadratic Equations

Quadratic equations are categorized based on whether the linear term ($bx$) is present:

Category Condition Algebraic Form Examples
Pure Quadratic (বিশুদ্ধ দ্বিঘাত) $b = 0$ $ax^2 + c = 0$ $4x^2 - 9 = 0 \implies x = \pm rac{3}{2}$
Adfected / Mixed (মিশ্র দ্বিঘাত) $b eq 0$ $ax^2 + bx + c = 0$ $3x^2 - 5x + 2 = 0$
Fundamental Theorem of Algebra Note:

Every polynomial equation of degree $n$ has exactly $n$ roots (real or complex). Therefore, a quadratic equation (degree $2$) always possesses exactly two roots, which may be distinct, coincident, or non-real.

Module 2: Solution by Factorization & Completing the Square

2.1 Solution by Factorization (উৎপাদকে বিশ্লেষণ)

The factorization method relies on the Zero Product Principle: if the product of two real expressions is zero, then at least one of the expressions must be zero:

If $A \cdot B = 0$, then either $A = 0$ or $B = 0$ (or both $A = 0$ and $B = 0$).

Step-by-step procedure for splitting the middle term:

  1. Express the equation in standard form: $ax^2 + bx + c = 0$.
  2. Compute the product of the leading coefficient and the constant term: $P = a \cdot c$.
  3. Find two real numbers $p$ and $q$ such that their sum equals the middle coefficient $b$ ($p + q = b$) and their product equals $P$ ($p \cdot q = ac$).
  4. Rewrite $bx$ as $px + qx$ and factor by grouping: $(mx + n)(rx + s) = 0$.
  5. Set each linear factor equal to zero: $mx + n = 0 \implies x = -n/m$ or $rx + s = 0 \implies x = -s/r$.
2.2 Solution by Completing the Square (পূর্ণবর্গকরণ পদ্ধতি)

When a quadratic expression cannot be easily factored with rational numbers, the method of completing the square converts the equation into the form $(x + k)^2 = d$:

  1. Divide through by $a$ ($a eq 0$): $x^2 + rac{b}{a}x + rac{c}{a} = 0$.
  2. Transpose the constant term: $x^2 + rac{b}{a}x = - rac{c}{a}$.
  3. Add the square of half the coefficient of $x$, namely $\left( rac{b}{2a} ight)^2 = rac{b^2}{4a^2}$, to both sides:
    $$x^2 + 2 \cdot x \cdot rac{b}{2a} + \left( rac{b}{2a} ight)^2 = rac{b^2}{4a^2} - rac{c}{a}$$
  4. Write the left side as a perfect square:
    $$\left(x + rac{b}{2a} ight)^2 = rac{b^2 - 4ac}{4a^2}$$
  5. Take the square root on both sides:
    $$x + rac{b}{2a} = \pm rac{\sqrt{b^2 - 4ac}}{2a} \implies x = rac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

Module 3: Sridhar Acharya's Quadratic Formula & Discriminant Analysis

3.1 Sridhar Acharya's Formula & Its Classical Derivation

Sridhar Acharya (শ্রীধর আচার্য), the illustrious 9th-century Indian mathematician, provided an ingenious technique to eliminate fractions during completing the square by multiplying the entire equation by $4a$:

Rigorous Derivation:

Given: $ax^2 + bx + c = 0 \quad (a eq 0)$
Multiply both sides by $4a$:
$$4a(ax^2 + bx + c) = 0 \implies 4a^2 x^2 + 4abx + 4ac = 0$$
Express the first two terms as a square: $(2ax)^2 + 2(2ax)(b) + b^2 - b^2 + 4ac = 0$
$$(2ax + b)^2 = b^2 - 4ac$$
Taking the square root of both sides:
$$2ax + b = \pm \sqrt{b^2 - 4ac} \implies 2ax = -b \pm \sqrt{b^2 - 4ac}$$
Dividing by $2a$ yields Sridhar Acharya's Formula:
$$x = rac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

3.2 The Discriminant (নিরূপক) and Nature of Roots

The quantity under the radical sign, $b^2 - 4ac$, discriminates between different types of roots and is called the Discriminant, denoted by $D$:

Discriminant: $D = b^2 - 4ac$
Value of Discriminant ($D$) Nature of Roots Roots Expression Geometric Interpretation
$D > 0$ and a perfect square Real, Rational, and Unequal $x_1 eq x_2 \in \mathbb{Q}$ Parabola cuts $x$-axis at two distinct rational points
$D > 0$ and NOT a perfect square Real, Irrational conjugate pairs ($p \pm \sqrt{q}$) $x = rac{-b \pm \sqrt{D}}{2a}$ Parabola cuts $x$-axis at two distinct irrational points
$D = 0$ Real and Equal (Coincident roots) $x_1 = x_2 = - rac{b}{2a}$ Parabola touches $x$-axis at exactly one point (vertex)
$D < 0$ No Real Roots (Complex conjugate roots) $x = rac{-b \pm i\sqrt{|D|}}{2a}$ Parabola does not intersect the $x$-axis
Madhyamik Exam Tip:

If a question states that the roots of $ax^2 + bx + c = 0$ are "real and equal", you must immediately set $b^2 - 4ac = 0$. If it says "real roots", set $b^2 - 4ac \ge 0$.

Module 4: Relations between Roots & Coefficients, Symmetric Expressions

4.1 Relations Between Roots and Coefficients (বীজদ্বয় ও সহগের সম্পর্ক)

Let $lpha$ and $eta$ be the two roots of $ax^2 + bx + c = 0$ ($a eq 0$). Then:

$$lpha = rac{-b + \sqrt{b^2 - 4ac}}{2a} \quad ext{and} \quad eta = rac{-b - \sqrt{b^2 - 4ac}}{2a}$$

1. Sum of Roots:

$$lpha + eta = rac{-b + \sqrt{D} + (-b - \sqrt{D})}{2a} = rac{-2b}{2a} = - rac{b}{a} = - rac{ ext{Coefficient of } x}{ ext{Coefficient of } x^2}$$

2. Product of Roots:

$$lpha eta = \left( rac{-b + \sqrt{D}}{2a} ight)\left( rac{-b - \sqrt{D}}{2a} ight) = rac{(-b)^2 - (b^2 - 4ac)}{4a^2} = rac{4ac}{4a^2} = rac{c}{a} = rac{ ext{Constant term}}{ ext{Coefficient of } x^2}$$
4.2 Forming a Quadratic Equation from Given Roots

If $lpha$ and $eta$ are the roots of a quadratic equation, the equation is given by:

$$(x - lpha)(x - eta) = 0 \iff x^2 - (lpha + eta)x + lpha eta = 0$$
$$x^2 - ( ext{Sum of Roots})x + ( ext{Product of Roots}) = 0$$
4.3 High-Yield Symmetric Expressions of Roots

Madhyamik exam problems frequently require calculating symmetric values using only $(lpha + eta)$ and $(lpha eta)$:

  • $lpha^2 + eta^2 = (lpha + eta)^2 - 2lpha eta = \left(- rac{b}{a} ight)^2 - 2\left( rac{c}{a} ight) = rac{b^2 - 2ac}{a^2}$
  • $lpha - eta = \pm \sqrt{(lpha + eta)^2 - 4lpha eta} = \pm rac{\sqrt{b^2 - 4ac}}{a}$
  • $ rac{1}{lpha} + rac{1}{eta} = rac{lpha + eta}{lpha eta} = rac{-b/a}{c/a} = - rac{b}{c}$
  • $lpha^3 + eta^3 = (lpha + eta)^3 - 3lpha eta(lpha + eta) = \left(- rac{b}{a} ight)^3 - 3\left( rac{c}{a} ight)\left(- rac{b}{a} ight) = rac{3abc - b^3}{a^3}$
  • $ rac{lpha}{eta} + rac{eta}{lpha} = rac{lpha^2 + eta^2}{lpha eta} = rac{(lpha + eta)^2 - 2lpha eta}{lpha eta} = rac{b^2 - 2ac}{ac}$

Module 5: Board Standard Real-World Word Problems (বাস্তব সমস্যাভিত্তিক সমাধান)

5.1 Mathematical Modeling Strategy for Word Problems

Translating real-world situations into quadratic equations involves five disciplined steps:

  1. Assign Unknown: Let the unknown quantity be $x$, specifying physical units (km/h, minutes, meters, years).
  2. Express Other Quantities: Express related quantities in terms of $x$.
  3. Formulate Equation: Translate the relationship stated in the problem into an algebraic equation.
  4. Solve: Reduce to $ax^2 + bx + c = 0$ and solve by factorization or Sridhar Acharya's formula.
  5. Feasibility Check: Reject non-physical roots (negative lengths, negative times, negative speeds, or non-integer digit values).
5.2 Core Types of Madhyamik Word Problems
  • Speed-Distance-Time: $ ext{Time} = rac{ ext{Distance}}{ ext{Speed}}$. If speed increases by $v$, time taken decreases: $ rac{D}{s} - rac{D}{s + v} = \Delta t$.
  • Cistern and Pipe Filling: If tap A fills in $x$ hours, part filled in 1 hour is $ rac{1}{x}$. If tap B takes $(x + 5)$ hours, together in 1 hour they fill $ rac{1}{x} + rac{1}{x + 5} = rac{1}{T_{ ext{total}}}$.
  • Digit Problems: A two-digit number with tens digit $x$ and units digit $y$ is $10x + y$. When digits are reversed, the number becomes $10y + x$.
  • Geometric Dimensions: Area of rectangle $= ext{length} imes ext{breadth}$. In right triangles: $ ext{base}^2 + ext{height}^2 = ext{hypotenuse}^2$.

Key Formulas, Identities & Theorems

Standard Quadratic Equation Form
$$ax^2 + bx + c = 0$$
Pure Quadratic Equation
$$ax^2 + c = 0$$
Zero Product Rule
A * B = 0 => A = 0 or B = 0
Sridhar Acharya's Quadratic Formula
$$x = (-b +- sqrt(b^2 - 4ac)) / (2a)$$
Discriminant (D)
$$D = b^2 - 4ac$$
Condition for Real and Equal Roots
$$b^2 - 4ac = 0$$
Sum of Roots
alpha + beta = -b / a
Product of Roots
alpha * beta = c / a
Forming Quadratic Equation from Roots
$$x^2 - (alpha + beta)x + alpha * beta = 0$$
Difference of Roots Formula
$$alpha - beta = +- sqrt((alpha + beta)^2 - 4*alpha*beta)$$

Conceptual Solved Examples & Case Studies

Example 1
Solve the quadratic equation by factorization: 2x^2 - 5x + 3 = 0.
Step-by-Step Solution:
Step 1: Identify coefficients: a = 2, b = -5, c = 3. Step 2: Product ac = 2 * 3 = 6. We need two numbers whose product is 6 and sum is -5. These numbers are -2 and -3. Step 3: Split the middle term: 2x^2 - 2x - 3x + 3 = 0 Step 4: Group terms and factor common factors: 2x(x - 1) - 3(x - 1) = 0 (x - 1)(2x - 3) = 0 Step 5: Apply the zero product principle: Either x - 1 = 0 => x = 1 Or 2x - 3 = 0 => 2x = 3 => x = 3/2. Hence, the required roots are x = 1 and x = 3/2.
Example 2
Apply Sridhar Acharya's formula to solve: 3x^2 + 2x - 1 = 0.
Step-by-Step Solution:
Step 1: Compare with standard form ax^2 + bx + c = 0: a = 3, b = 2, c = -1. Step 2: Calculate the discriminant D: D = b^2 - 4ac = (2)^2 - 4(3)(-1) = 4 + 12 = 16. Since D = 16 > 0, the equation has two real and rational roots. Step 3: Apply Sridhar Acharya's formula: x = (-b +- sqrt(D)) / (2a) x = (-2 +- sqrt(16)) / (2 * 3) x = (-2 +- 4) / 6 Step 4: Evaluate the two roots: x_1 = (-2 + 4) / 6 = 2 / 6 = 1/3 x_2 = (-2 - 4) / 6 = -6 / 6 = -1 Hence, the roots are x = 1/3 and x = -1.
Example 3
If the roots of the equation (k - 1)x^2 - 2(k - 1)x + 1 = 0 are real and equal, find the value of k.
Step-by-Step Solution:
Step 1: Identify coefficients: a = (k - 1), b = -2(k - 1), c = 1. Since this is a quadratic equation, leading coefficient a != 0 => k - 1 != 0 => k != 1. Step 2: For real and equal roots, the discriminant D must be zero: D = b^2 - 4ac = 0 [-2(k - 1)]^2 - 4(k - 1)(1) = 0 4(k - 1)^2 - 4(k - 1) = 0 Step 3: Factorize the expression: 4(k - 1)[(k - 1) - 1] = 0 4(k - 1)(k - 2) = 0 Step 4: Solve for k: Either k - 1 = 0 => k = 1 (rejected because leading coefficient becomes 0) Or k - 2 = 0 => k = 2. Hence, the permissible value of k is 2.
Example 4
If alpha and beta are the roots of 2x^2 - 3x + 5 = 0, find the value of (alpha/beta + beta/alpha).
Step-by-Step Solution:
Step 1: Find sum and product of roots from 2x^2 - 3x + 5 = 0: a = 2, b = -3, c = 5. alpha + beta = -b/a = -(-3)/2 = 3/2. alpha * beta = c/a = 5/2. Step 2: Express the required algebraic fraction with a common denominator: alpha/beta + beta/alpha = (alpha^2 + beta^2) / (alpha * beta) Step 3: Use the symmetric identity alpha^2 + beta^2 = (alpha + beta)^2 - 2*alpha*beta: alpha^2 + beta^2 = (3/2)^2 - 2*(5/2) = 9/4 - 5 = 9/4 - 20/4 = -11/4. Step 4: Divide by alpha * beta: (alpha/beta + beta/alpha) = (-11/4) / (5/2) = (-11/4) * (2/5) = -22/20 = -11/10. Hence, the value is -11/10.
Example 5
A superfast train takes 2 hours less than a passenger train to travel a distance of 300 km. If the speed of the superfast train is 5 km/h more than that of the passenger train, find the speed of both trains.
Step-by-Step Solution:
Step 1: Assign variable: Let the speed of the passenger train be x km/h. Then the speed of the superfast train is (x + 5) km/h. Step 2: Express time taken by both trains: Distance = 300 km. Time taken by passenger train = 300 / x hours. Time taken by superfast train = 300 / (x + 5) hours. Step 3: Formulate equation according to the condition: 300/x - 300/(x + 5) = 2 Step 4: Simplify algebraically: 300[(x + 5) - x] / [x(x + 5)] = 2 300 * 5 / (x^2 + 5x) = 2 1500 = 2(x^2 + 5x) 750 = x^2 + 5x x^2 + 5x - 750 = 0 Step 5: Solve by factorization: We need two numbers whose product is -750 and sum is 5: 30 and -25. x^2 + 30x - 25x - 750 = 0 x(x + 30) - 25(x + 30) = 0 (x + 30)(x - 25) = 0 Either x + 30 = 0 => x = -30 (rejected, speed cannot be negative) Or x - 25 = 0 => x = 25. Step 6: State conclusion: Speed of passenger train = 25 km/h. Speed of superfast train = 25 + 5 = 30 km/h.

Common Misconceptions & Examiner Traps

Common Misconception

Cancelling x on both sides in equations like x^2 = 5x to write x = 5.

Scientific Reality & Correction

Transpose terms to one side: x^2 - 5x = 0 => x(x - 5) = 0 => x = 0 or x = 5.

Common Misconception

Forgetting the +- sign when taking the square root in x^2 = k, writing only x = sqrt(k).

Scientific Reality & Correction

Always write x = +-sqrt(k). A quadratic equation must yield two roots.

Common Misconception

Writing the quadratic formula with incomplete denominator: x = -b +- sqrt(b^2 - 4ac) / 2a.

Scientific Reality & Correction

The entire expression (-b +- sqrt(b^2 - 4ac)) is divided by 2a.

Common Misconception

Taking a = 0 in ax^2 + bx + c = 0 and treating it as a quadratic equation.

Scientific Reality & Correction

Ensure a != 0. If a = 0, the equation is linear.

Common Misconception

Confusing sum of roots formula as b/a instead of -b/a.

Scientific Reality & Correction

Sum of roots is always -b/a (with a negative sign).

Common Misconception

Accepting negative values in physical word problems without justification.

Scientific Reality & Correction

Explicitly state: 'Since speed / length / age cannot be negative, we reject x = -k'.

Common Misconception

Incorrectly calculating (-b)^2 as negative in the discriminant.

Scientific Reality & Correction

Always write (-b)^2 = +b^2. Square of any real number is non-negative.

Concept Map: Quadratic Equations in One Variable (WBBSE Class 10 Ganit Prakash)

Quadratic Equations in One Variable (একচলবিশিষ্ট দ্বিঘাত সমীকরণ) WBBSE Class 10 Mathematics • Chapter 1 • Standard Form, Formula & Discriminant 1. Standard Form & Types • Standard: ax^2 + bx + c = 0 (a, b, c in R, a != 0)• Leading coefficient a != 0 (if a=0, linear)• Pure Quadratic: b = 0 (ax^2 + c = 0, x = +-sqrt(-c/a))• Adfected Quadratic: b != 0 (e.g. 2x^2 - 5x + 3 = 0) 2. Solution Methods • Factorization: Split middle term, zero product rule• Completing Square: (x + b/(2a))^2 = (b^2-4ac)/(4a^2)• Sridhar Acharya Formula: x = (-b +- sqrt(D))/(2a)• Ancient Indian derivation via 4a multiplication 3. Discriminant & Nature of Roots • Discriminant: D = b^2 - 4ac• D > 0: Two real and unequal roots• D = 0: Two real and equal roots (x = -b/2a)• D < 0: No real roots (roots are complex) 4. Roots & Coefficients • Sum of roots: alpha + beta = -b/a• Product of roots: alpha * beta = c/a• Equation: x^2 - (sum)x + (product) = 0• Applications: Train speeds, digits, cisterns

Chapter Summary & 10 Key Takeaways

Takeaway 1
A quadratic equation in one variable has the general form ax^2 + bx + c = 0 where a, b, c are real numbers and a != 0.
Takeaway 2
Equations with b = 0 are pure quadratic equations; equations with b != 0 are adfected or mixed quadratic equations.
Takeaway 3
Quadratic equations can be solved by factorization (using zero product rule), completing the square, or Sridhar Acharya's formula.
Takeaway 4
Sridhar Acharya's formula x = (-b +- sqrt(b^2 - 4ac)) / (2a) solves any quadratic equation with real coefficients.
Takeaway 5
The discriminant D = b^2 - 4ac dictates root nature: D > 0 (real and unequal), D = 0 (real and equal), D < 0 (no real roots).
Takeaway 6
If D > 0 and is a perfect square (with rational coefficients), roots are rational; if not, roots are conjugate irrational surds.
Takeaway 7
Sum of roots alpha + beta = -b/a; product of roots alpha * beta = c/a.
Takeaway 8
A quadratic equation with roots alpha and beta is formed as x^2 - (alpha + beta)x + alpha * beta = 0.

Check Your Understanding (Diagnostic Practice Questions)

Diagnostic questions testing core conceptual clarity. Answers are hidden initially — solve each problem first, then click to reveal the step-by-step verified solution.

1
What happens to the equation ax^2 + bx + c = 0 if a = 0 and b != 0?
Reveal Answer & Explanation
Answer: If a = 0 and b != 0, the equation reduces to bx + c = 0, which is a linear equation of degree 1 having only one root x = -c/b.
2
What is the condition for the roots of ax^2 + bx + c = 0 to be reciprocal of each other?
Reveal Answer & Explanation
Answer: Let the roots be alpha and 1/alpha. Their product is alpha * (1/alpha) = 1. Since product of roots = c/a, we have c/a = 1 => c = a. Hence, the constant term must equal the coefficient of x^2.
3
What is the condition for the roots of ax^2 + bx + c = 0 to be equal in magnitude but opposite in sign?
Reveal Answer & Explanation
Answer: Let the roots be alpha and -alpha. Their sum is alpha + (-alpha) = 0. Since sum of roots = -b/a, we have -b/a = 0 => b = 0. Hence, the linear coefficient b must be zero (pure quadratic).
4
State the nature of the roots of 2x^2 - 4x + 3 = 0 without solving.
Reveal Answer & Explanation
Answer: Compute discriminant D = b^2 - 4ac = (-4)^2 - 4(2)(3) = 16 - 24 = -8. Since D < 0, the equation has no real roots.
5
Form the quadratic equation whose roots are 3 + sqrt(5) and 3 - sqrt(5).
Reveal Answer & Explanation
Answer: Sum of roots = (3 + sqrt(5)) + (3 - sqrt(5)) = 6. Product of roots = (3 + sqrt(5))(3 - sqrt(5)) = 3^2 - (sqrt(5))^2 = 9 - 5 = 4. Equation: x^2 - (Sum)x + (Product) = 0 => x^2 - 6x + 4 = 0.
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