Follow Us
মাধ্যম নির্বাচন করুন / Select Medium:
Eng (English) Beng (বাংলা) Hindi (हिन्दी)
পশ্চিমবঙ্গ মধ্যশিক্ষা পর্ষদ (WBBSE) • শ্রেণি X • Mathematics • অধ্যায় 1
আনুমানিক সময়: 120 minutes
অগ্রগতি: অধ্যয়নে সক্রিয়

Quadratic Equations in One Variable

Quadratic Equations in One Variable forms the cornerstone of the WBBSE Class 10 Mathematics curriculum Ganit Prakash. A polynomial equation of the second degree in a single variable is known as a quadratic equation in one variable. Its standard mathematical form is ax^2 + bx + c = 0, where a, b, and c are real numbers and the leading coefficient a is strictly non-zero. If a were zero, the second-degree term would vanish, reducing the equation to a linear equation bx + c = 0. Quadratic equations are classified into pure quadratic equations where the linear coefficient b is zero, and adfected or mixed quadratic equations where b is non-zero. The chapter systematically equips students with three foundational solution techniques: factorization by splitting the middle term, completing the square, and applying the universal quadratic formula discovered by the ancient Indian mathematician Sridhar Acharya. The nature of the two roots is governed entirely by the discriminant D = b^2 - 4ac. When D is greater than zero, the roots are real and unequal; if D is a perfect square with rational coefficients, the roots are rational, whereas if D is not a perfect square, they form irrational conjugate pairs. When D equals zero, the roots are real and coincident. When D is less than zero, no real roots exist. The chapter also rigorously explores the relations between roots and coefficients, demonstrating that the sum of the roots equals -b/a and their product equals c/a, enabling students to construct quadratic equations from known roots. Finally, students learn how to translate complex practical situations—such as speed-distance-time variations, tap filling rates, geometric dimensions, and digit problems—into solvable quadratic equations.

কখনও কি ভেবে দেখেছেন?

How can a single algebraic equation predict the trajectory of an artillery shell, model the maximum profit of an enterprise, determine the exact speed of a train battling a headwind, and unlock the fundamental symmetries of physics? Originating from ancient Babylonian clay tablets and perfected by the Indian master mathematician Sridhar Acharya in the 9th century, quadratic equations form the primary bridge from elementary algebra to higher mathematical analysis.

অধ্যায়টির গুরুত্ব

Mastery of quadratic equations is essential not only for scoring top marks in the WBBSE Madhyamik examination but also as an indispensable foundation for higher mathematics, physics, engineering, and data science. In Madhyamik, quadratic equations account for significant weightage across multiple-choice questions, short answer questions, and compulsory 3-mark and 4-mark algebraic word problems. Beyond examinations, quadratic equations model projectile motion, planetary orbits, optimization in economics, electrical circuits with impedance, and architectural arch designs. The historical derivation by Sridhar Acharya demonstrates the profound heritage of Indian mathematics and trains students in rigorous deductive logic, algebraic manipulation, and real-world mathematical modeling.

পাঠের পূর্বে প্রয়োজনীয় ধারণা

  • Algebraic factorization techniques including splitting the middle term and algebraic identities (a + b)^2, (a - b)^2, and a^2 - b^2.
  • Basic arithmetic operations on signed real numbers, fractions, and square roots.
  • Linear equations in one variable and the zero product rule (if ab = 0, then a = 0 or b = 0).
  • Translating verbal statements into algebraic equations.

শিখন লক্ষ্যমাত্রা ও ফলাফল

  • Identify and formulate the standard general form of a quadratic equation in one variable: ax^2 + bx + c = 0 with a != 0, recognizing why a cannot be zero.
  • Differentiate between pure quadratic equations (b = 0) and adfected quadratic equations (b != 0).
  • Solve quadratic equations efficiently using the factorization method and completing the square.
  • Derive and apply Sridhar Acharya's quadratic formula x = (-b +- sqrt(b^2 - 4ac)) / (2a) to find real roots.
  • Analyze the nature of roots using the discriminant D = b^2 - 4ac across positive, zero, and negative values.
  • Establish the fundamental relationships between the roots (alpha, beta) and the coefficients: alpha + beta = -b/a and alpha * beta = c/a.
  • Construct quadratic equations from given roots and evaluate symmetric expressions of roots.
  • Model and solve real-world board exam word problems involving digits, speeds, geometric dimensions, and cistern taps.

অধ্যায়ের বিষয়সূচি ও রূপরেখা

1 Module 1: General Form of Quadratic...
2 Module 2: Solution by Factorization...
3 Module 3: Sridhar Acharya's Quadrat...
4 Module 4: Relations between Roots &...
5 Module 5: Board Standard Real-World...

সম্পূর্ণ তত্ত্ব ও ধারণাগত আলোচনা

Module 1: General Form of Quadratic Equations & Classification

1.1 Definition & Standard Form

An equation containing a single variable whose highest power (degree) is $2$ is called a Quadratic Equation in One Variable (একচলবিশিষ্ট দ্বিঘাত সমীকরণ). In standard mathematical notation, it is written as:

Standard Form: $ax^2 + bx + c = 0 \quad (a eq 0, \quad a, b, c \in \mathbb{R})$

Here, $x$ is the unknown variable, $a$ is the coefficient of $x^2$ (leading coefficient), $b$ is the coefficient of $x$, and $c$ is the constant term. The condition $a eq 0$ is essential: if $a = 0$, the $x^2$ term vanishes, reducing the equation to $bx + c = 0$, which is a linear equation of degree $1$.

1.2 Classification: Pure vs. Adfected Quadratic Equations

Quadratic equations are categorized based on whether the linear term ($bx$) is present:

Category Condition Algebraic Form Examples
Pure Quadratic (বিশুদ্ধ দ্বিঘাত) $b = 0$ $ax^2 + c = 0$ $4x^2 - 9 = 0 \implies x = \pm rac{3}{2}$
Adfected / Mixed (মিশ্র দ্বিঘাত) $b eq 0$ $ax^2 + bx + c = 0$ $3x^2 - 5x + 2 = 0$
Fundamental Theorem of Algebra Note:

Every polynomial equation of degree $n$ has exactly $n$ roots (real or complex). Therefore, a quadratic equation (degree $2$) always possesses exactly two roots, which may be distinct, coincident, or non-real.

Module 2: Solution by Factorization & Completing the Square

2.1 Solution by Factorization (উৎপাদকে বিশ্লেষণ)

The factorization method relies on the Zero Product Principle: if the product of two real expressions is zero, then at least one of the expressions must be zero:

If $A \cdot B = 0$, then either $A = 0$ or $B = 0$ (or both $A = 0$ and $B = 0$).

Step-by-step procedure for splitting the middle term:

  1. Express the equation in standard form: $ax^2 + bx + c = 0$.
  2. Compute the product of the leading coefficient and the constant term: $P = a \cdot c$.
  3. Find two real numbers $p$ and $q$ such that their sum equals the middle coefficient $b$ ($p + q = b$) and their product equals $P$ ($p \cdot q = ac$).
  4. Rewrite $bx$ as $px + qx$ and factor by grouping: $(mx + n)(rx + s) = 0$.
  5. Set each linear factor equal to zero: $mx + n = 0 \implies x = -n/m$ or $rx + s = 0 \implies x = -s/r$.
2.2 Solution by Completing the Square (পূর্ণবর্গকরণ পদ্ধতি)

When a quadratic expression cannot be easily factored with rational numbers, the method of completing the square converts the equation into the form $(x + k)^2 = d$:

  1. Divide through by $a$ ($a eq 0$): $x^2 + rac{b}{a}x + rac{c}{a} = 0$.
  2. Transpose the constant term: $x^2 + rac{b}{a}x = - rac{c}{a}$.
  3. Add the square of half the coefficient of $x$, namely $\left( rac{b}{2a} ight)^2 = rac{b^2}{4a^2}$, to both sides:
    $$x^2 + 2 \cdot x \cdot rac{b}{2a} + \left( rac{b}{2a} ight)^2 = rac{b^2}{4a^2} - rac{c}{a}$$
  4. Write the left side as a perfect square:
    $$\left(x + rac{b}{2a} ight)^2 = rac{b^2 - 4ac}{4a^2}$$
  5. Take the square root on both sides:
    $$x + rac{b}{2a} = \pm rac{\sqrt{b^2 - 4ac}}{2a} \implies x = rac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

Module 3: Sridhar Acharya's Quadratic Formula & Discriminant Analysis

3.1 Sridhar Acharya's Formula & Its Classical Derivation

Sridhar Acharya (শ্রীধর আচার্য), the illustrious 9th-century Indian mathematician, provided an ingenious technique to eliminate fractions during completing the square by multiplying the entire equation by $4a$:

Rigorous Derivation:

Given: $ax^2 + bx + c = 0 \quad (a eq 0)$
Multiply both sides by $4a$:
$$4a(ax^2 + bx + c) = 0 \implies 4a^2 x^2 + 4abx + 4ac = 0$$
Express the first two terms as a square: $(2ax)^2 + 2(2ax)(b) + b^2 - b^2 + 4ac = 0$
$$(2ax + b)^2 = b^2 - 4ac$$
Taking the square root of both sides:
$$2ax + b = \pm \sqrt{b^2 - 4ac} \implies 2ax = -b \pm \sqrt{b^2 - 4ac}$$
Dividing by $2a$ yields Sridhar Acharya's Formula:
$$x = rac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

3.2 The Discriminant (নিরূপক) and Nature of Roots

The quantity under the radical sign, $b^2 - 4ac$, discriminates between different types of roots and is called the Discriminant, denoted by $D$:

Discriminant: $D = b^2 - 4ac$
Value of Discriminant ($D$) Nature of Roots Roots Expression Geometric Interpretation
$D > 0$ and a perfect square Real, Rational, and Unequal $x_1 eq x_2 \in \mathbb{Q}$ Parabola cuts $x$-axis at two distinct rational points
$D > 0$ and NOT a perfect square Real, Irrational conjugate pairs ($p \pm \sqrt{q}$) $x = rac{-b \pm \sqrt{D}}{2a}$ Parabola cuts $x$-axis at two distinct irrational points
$D = 0$ Real and Equal (Coincident roots) $x_1 = x_2 = - rac{b}{2a}$ Parabola touches $x$-axis at exactly one point (vertex)
$D < 0$ No Real Roots (Complex conjugate roots) $x = rac{-b \pm i\sqrt{|D|}}{2a}$ Parabola does not intersect the $x$-axis
Madhyamik Exam Tip:

If a question states that the roots of $ax^2 + bx + c = 0$ are "real and equal", you must immediately set $b^2 - 4ac = 0$. If it says "real roots", set $b^2 - 4ac \ge 0$.

Module 4: Relations between Roots & Coefficients, Symmetric Expressions

4.1 Relations Between Roots and Coefficients (বীজদ্বয় ও সহগের সম্পর্ক)

Let $lpha$ and $eta$ be the two roots of $ax^2 + bx + c = 0$ ($a eq 0$). Then:

$$lpha = rac{-b + \sqrt{b^2 - 4ac}}{2a} \quad ext{and} \quad eta = rac{-b - \sqrt{b^2 - 4ac}}{2a}$$

1. Sum of Roots:

$$lpha + eta = rac{-b + \sqrt{D} + (-b - \sqrt{D})}{2a} = rac{-2b}{2a} = - rac{b}{a} = - rac{ ext{Coefficient of } x}{ ext{Coefficient of } x^2}$$

2. Product of Roots:

$$lpha eta = \left( rac{-b + \sqrt{D}}{2a} ight)\left( rac{-b - \sqrt{D}}{2a} ight) = rac{(-b)^2 - (b^2 - 4ac)}{4a^2} = rac{4ac}{4a^2} = rac{c}{a} = rac{ ext{Constant term}}{ ext{Coefficient of } x^2}$$
4.2 Forming a Quadratic Equation from Given Roots

If $lpha$ and $eta$ are the roots of a quadratic equation, the equation is given by:

$$(x - lpha)(x - eta) = 0 \iff x^2 - (lpha + eta)x + lpha eta = 0$$
$$x^2 - ( ext{Sum of Roots})x + ( ext{Product of Roots}) = 0$$
4.3 High-Yield Symmetric Expressions of Roots

Madhyamik exam problems frequently require calculating symmetric values using only $(lpha + eta)$ and $(lpha eta)$:

  • $lpha^2 + eta^2 = (lpha + eta)^2 - 2lpha eta = \left(- rac{b}{a} ight)^2 - 2\left( rac{c}{a} ight) = rac{b^2 - 2ac}{a^2}$
  • $lpha - eta = \pm \sqrt{(lpha + eta)^2 - 4lpha eta} = \pm rac{\sqrt{b^2 - 4ac}}{a}$
  • $ rac{1}{lpha} + rac{1}{eta} = rac{lpha + eta}{lpha eta} = rac{-b/a}{c/a} = - rac{b}{c}$
  • $lpha^3 + eta^3 = (lpha + eta)^3 - 3lpha eta(lpha + eta) = \left(- rac{b}{a} ight)^3 - 3\left( rac{c}{a} ight)\left(- rac{b}{a} ight) = rac{3abc - b^3}{a^3}$
  • $ rac{lpha}{eta} + rac{eta}{lpha} = rac{lpha^2 + eta^2}{lpha eta} = rac{(lpha + eta)^2 - 2lpha eta}{lpha eta} = rac{b^2 - 2ac}{ac}$

Module 5: Board Standard Real-World Word Problems (বাস্তব সমস্যাভিত্তিক সমাধান)

5.1 Mathematical Modeling Strategy for Word Problems

Translating real-world situations into quadratic equations involves five disciplined steps:

  1. Assign Unknown: Let the unknown quantity be $x$, specifying physical units (km/h, minutes, meters, years).
  2. Express Other Quantities: Express related quantities in terms of $x$.
  3. Formulate Equation: Translate the relationship stated in the problem into an algebraic equation.
  4. Solve: Reduce to $ax^2 + bx + c = 0$ and solve by factorization or Sridhar Acharya's formula.
  5. Feasibility Check: Reject non-physical roots (negative lengths, negative times, negative speeds, or non-integer digit values).
5.2 Core Types of Madhyamik Word Problems
  • Speed-Distance-Time: $ ext{Time} = rac{ ext{Distance}}{ ext{Speed}}$. If speed increases by $v$, time taken decreases: $ rac{D}{s} - rac{D}{s + v} = \Delta t$.
  • Cistern and Pipe Filling: If tap A fills in $x$ hours, part filled in 1 hour is $ rac{1}{x}$. If tap B takes $(x + 5)$ hours, together in 1 hour they fill $ rac{1}{x} + rac{1}{x + 5} = rac{1}{T_{ ext{total}}}$.
  • Digit Problems: A two-digit number with tens digit $x$ and units digit $y$ is $10x + y$. When digits are reversed, the number becomes $10y + x$.
  • Geometric Dimensions: Area of rectangle $= ext{length} imes ext{breadth}$. In right triangles: $ ext{base}^2 + ext{height}^2 = ext{hypotenuse}^2$.

গুরুত্বপূর্ণ গাণিতিক সূত্র, অভেদ ও উপপাদ্য

Standard Quadratic Equation Form
$$ax^2 + bx + c = 0$$
Pure Quadratic Equation
$$ax^2 + c = 0$$
Zero Product Rule
A * B = 0 => A = 0 or B = 0
Sridhar Acharya's Quadratic Formula
$$x = (-b +- sqrt(b^2 - 4ac)) / (2a)$$
Discriminant (D)
$$D = b^2 - 4ac$$
Condition for Real and Equal Roots
$$b^2 - 4ac = 0$$
Sum of Roots
alpha + beta = -b / a
Product of Roots
alpha * beta = c / a
Forming Quadratic Equation from Roots
$$x^2 - (alpha + beta)x + alpha * beta = 0$$
Difference of Roots Formula
$$alpha - beta = +- sqrt((alpha + beta)^2 - 4*alpha*beta)$$

সমাধানকৃত উদাহরণ ও প্রয়োগ (Solved Examples)

উদাহরণ 1
Solve the quadratic equation by factorization: 2x^2 - 5x + 3 = 0.
ধাপে ধাপে সমাধান / উত্তর:
Step 1: Identify coefficients: a = 2, b = -5, c = 3. Step 2: Product ac = 2 * 3 = 6. We need two numbers whose product is 6 and sum is -5. These numbers are -2 and -3. Step 3: Split the middle term: 2x^2 - 2x - 3x + 3 = 0 Step 4: Group terms and factor common factors: 2x(x - 1) - 3(x - 1) = 0 (x - 1)(2x - 3) = 0 Step 5: Apply the zero product principle: Either x - 1 = 0 => x = 1 Or 2x - 3 = 0 => 2x = 3 => x = 3/2. Hence, the required roots are x = 1 and x = 3/2.
উদাহরণ 2
Apply Sridhar Acharya's formula to solve: 3x^2 + 2x - 1 = 0.
ধাপে ধাপে সমাধান / উত্তর:
Step 1: Compare with standard form ax^2 + bx + c = 0: a = 3, b = 2, c = -1. Step 2: Calculate the discriminant D: D = b^2 - 4ac = (2)^2 - 4(3)(-1) = 4 + 12 = 16. Since D = 16 > 0, the equation has two real and rational roots. Step 3: Apply Sridhar Acharya's formula: x = (-b +- sqrt(D)) / (2a) x = (-2 +- sqrt(16)) / (2 * 3) x = (-2 +- 4) / 6 Step 4: Evaluate the two roots: x_1 = (-2 + 4) / 6 = 2 / 6 = 1/3 x_2 = (-2 - 4) / 6 = -6 / 6 = -1 Hence, the roots are x = 1/3 and x = -1.
উদাহরণ 3
If the roots of the equation (k - 1)x^2 - 2(k - 1)x + 1 = 0 are real and equal, find the value of k.
ধাপে ধাপে সমাধান / উত্তর:
Step 1: Identify coefficients: a = (k - 1), b = -2(k - 1), c = 1. Since this is a quadratic equation, leading coefficient a != 0 => k - 1 != 0 => k != 1. Step 2: For real and equal roots, the discriminant D must be zero: D = b^2 - 4ac = 0 [-2(k - 1)]^2 - 4(k - 1)(1) = 0 4(k - 1)^2 - 4(k - 1) = 0 Step 3: Factorize the expression: 4(k - 1)[(k - 1) - 1] = 0 4(k - 1)(k - 2) = 0 Step 4: Solve for k: Either k - 1 = 0 => k = 1 (rejected because leading coefficient becomes 0) Or k - 2 = 0 => k = 2. Hence, the permissible value of k is 2.
উদাহরণ 4
If alpha and beta are the roots of 2x^2 - 3x + 5 = 0, find the value of (alpha/beta + beta/alpha).
ধাপে ধাপে সমাধান / উত্তর:
Step 1: Find sum and product of roots from 2x^2 - 3x + 5 = 0: a = 2, b = -3, c = 5. alpha + beta = -b/a = -(-3)/2 = 3/2. alpha * beta = c/a = 5/2. Step 2: Express the required algebraic fraction with a common denominator: alpha/beta + beta/alpha = (alpha^2 + beta^2) / (alpha * beta) Step 3: Use the symmetric identity alpha^2 + beta^2 = (alpha + beta)^2 - 2*alpha*beta: alpha^2 + beta^2 = (3/2)^2 - 2*(5/2) = 9/4 - 5 = 9/4 - 20/4 = -11/4. Step 4: Divide by alpha * beta: (alpha/beta + beta/alpha) = (-11/4) / (5/2) = (-11/4) * (2/5) = -22/20 = -11/10. Hence, the value is -11/10.
উদাহরণ 5
A superfast train takes 2 hours less than a passenger train to travel a distance of 300 km. If the speed of the superfast train is 5 km/h more than that of the passenger train, find the speed of both trains.
ধাপে ধাপে সমাধান / উত্তর:
Step 1: Assign variable: Let the speed of the passenger train be x km/h. Then the speed of the superfast train is (x + 5) km/h. Step 2: Express time taken by both trains: Distance = 300 km. Time taken by passenger train = 300 / x hours. Time taken by superfast train = 300 / (x + 5) hours. Step 3: Formulate equation according to the condition: 300/x - 300/(x + 5) = 2 Step 4: Simplify algebraically: 300[(x + 5) - x] / [x(x + 5)] = 2 300 * 5 / (x^2 + 5x) = 2 1500 = 2(x^2 + 5x) 750 = x^2 + 5x x^2 + 5x - 750 = 0 Step 5: Solve by factorization: We need two numbers whose product is -750 and sum is 5: 30 and -25. x^2 + 30x - 25x - 750 = 0 x(x + 30) - 25(x + 30) = 0 (x + 30)(x - 25) = 0 Either x + 30 = 0 => x = -30 (rejected, speed cannot be negative) Or x - 25 = 0 => x = 25. Step 6: State conclusion: Speed of passenger train = 25 km/h. Speed of superfast train = 25 + 5 = 30 km/h.

সাধারণ ভুলত্রুটি ও সতর্কতা (Common Traps)

সাধারণ ভুল ধারণা

Cancelling x on both sides in equations like x^2 = 5x to write x = 5.

সঠিক পদ্ধতি ও সমাধান

Transpose terms to one side: x^2 - 5x = 0 => x(x - 5) = 0 => x = 0 or x = 5.

সাধারণ ভুল ধারণা

Forgetting the +- sign when taking the square root in x^2 = k, writing only x = sqrt(k).

সঠিক পদ্ধতি ও সমাধান

Always write x = +-sqrt(k). A quadratic equation must yield two roots.

সাধারণ ভুল ধারণা

Writing the quadratic formula with incomplete denominator: x = -b +- sqrt(b^2 - 4ac) / 2a.

সঠিক পদ্ধতি ও সমাধান

The entire expression (-b +- sqrt(b^2 - 4ac)) is divided by 2a.

সাধারণ ভুল ধারণা

Taking a = 0 in ax^2 + bx + c = 0 and treating it as a quadratic equation.

সঠিক পদ্ধতি ও সমাধান

Ensure a != 0. If a = 0, the equation is linear.

সাধারণ ভুল ধারণা

Confusing sum of roots formula as b/a instead of -b/a.

সঠিক পদ্ধতি ও সমাধান

Sum of roots is always -b/a (with a negative sign).

সাধারণ ভুল ধারণা

Accepting negative values in physical word problems without justification.

সঠিক পদ্ধতি ও সমাধান

Explicitly state: 'Since speed / length / age cannot be negative, we reject x = -k'.

সাধারণ ভুল ধারণা

Incorrectly calculating (-b)^2 as negative in the discriminant.

সঠিক পদ্ধতি ও সমাধান

Always write (-b)^2 = +b^2. Square of any real number is non-negative.

Concept Map: Quadratic Equations in One Variable (WBBSE Class 10 Ganit Prakash)

Quadratic Equations in One Variable (একচলবিশিষ্ট দ্বিঘাত সমীকরণ) WBBSE Class 10 Mathematics • Chapter 1 • Standard Form, Formula & Discriminant 1. Standard Form & Types • Standard: ax^2 + bx + c = 0 (a, b, c in R, a != 0)• Leading coefficient a != 0 (if a=0, linear)• Pure Quadratic: b = 0 (ax^2 + c = 0, x = +-sqrt(-c/a))• Adfected Quadratic: b != 0 (e.g. 2x^2 - 5x + 3 = 0) 2. Solution Methods • Factorization: Split middle term, zero product rule• Completing Square: (x + b/(2a))^2 = (b^2-4ac)/(4a^2)• Sridhar Acharya Formula: x = (-b +- sqrt(D))/(2a)• Ancient Indian derivation via 4a multiplication 3. Discriminant & Nature of Roots • Discriminant: D = b^2 - 4ac• D > 0: Two real and unequal roots• D = 0: Two real and equal roots (x = -b/2a)• D < 0: No real roots (roots are complex) 4. Roots & Coefficients • Sum of roots: alpha + beta = -b/a• Product of roots: alpha * beta = c/a• Equation: x^2 - (sum)x + (product) = 0• Applications: Train speeds, digits, cisterns

অধ্যায় সারসংক্ষেপ ও গুরুত্বপূর্ণ বিষয়

মূল বিষয় 1
A quadratic equation in one variable has the general form ax^2 + bx + c = 0 where a, b, c are real numbers and a != 0.
মূল বিষয় 2
Equations with b = 0 are pure quadratic equations; equations with b != 0 are adfected or mixed quadratic equations.
মূল বিষয় 3
Quadratic equations can be solved by factorization (using zero product rule), completing the square, or Sridhar Acharya's formula.
মূল বিষয় 4
Sridhar Acharya's formula x = (-b +- sqrt(b^2 - 4ac)) / (2a) solves any quadratic equation with real coefficients.
মূল বিষয় 5
The discriminant D = b^2 - 4ac dictates root nature: D > 0 (real and unequal), D = 0 (real and equal), D < 0 (no real roots).
মূল বিষয় 6
If D > 0 and is a perfect square (with rational coefficients), roots are rational; if not, roots are conjugate irrational surds.
মূল বিষয় 7
Sum of roots alpha + beta = -b/a; product of roots alpha * beta = c/a.
মূল বিষয় 8
A quadratic equation with roots alpha and beta is formed as x^2 - (alpha + beta)x + alpha * beta = 0.

স্ব-মূল্যায়ন অনুশীলন (Check Your Understanding)

মূল ধারণাগত স্পষ্টতা যাচাই করার জন্য অনুশীলন প্রশ্ন। উত্তর দেখার আগে নিজে সমাধান করার চেষ্টা করো।

1
What happens to the equation ax^2 + bx + c = 0 if a = 0 and b != 0?
উত্তর ও ব্যাখ্যা দেখুন
উত্তর: If a = 0 and b != 0, the equation reduces to bx + c = 0, which is a linear equation of degree 1 having only one root x = -c/b.
2
What is the condition for the roots of ax^2 + bx + c = 0 to be reciprocal of each other?
উত্তর ও ব্যাখ্যা দেখুন
উত্তর: Let the roots be alpha and 1/alpha. Their product is alpha * (1/alpha) = 1. Since product of roots = c/a, we have c/a = 1 => c = a. Hence, the constant term must equal the coefficient of x^2.
3
What is the condition for the roots of ax^2 + bx + c = 0 to be equal in magnitude but opposite in sign?
উত্তর ও ব্যাখ্যা দেখুন
উত্তর: Let the roots be alpha and -alpha. Their sum is alpha + (-alpha) = 0. Since sum of roots = -b/a, we have -b/a = 0 => b = 0. Hence, the linear coefficient b must be zero (pure quadratic).
4
State the nature of the roots of 2x^2 - 4x + 3 = 0 without solving.
উত্তর ও ব্যাখ্যা দেখুন
উত্তর: Compute discriminant D = b^2 - 4ac = (-4)^2 - 4(2)(3) = 16 - 24 = -8. Since D < 0, the equation has no real roots.
5
Form the quadratic equation whose roots are 3 + sqrt(5) and 3 - sqrt(5).
উত্তর ও ব্যাখ্যা দেখুন
উত্তর: Sum of roots = (3 + sqrt(5)) + (3 - sqrt(5)) = 6. Product of roots = (3 + sqrt(5))(3 - sqrt(5)) = 3^2 - (sqrt(5))^2 = 9 - 5 = 4. Equation: x^2 - (Sum)x + (Product) = 0 => x^2 - 6x + 4 = 0.
অধ্যায় পড়া শেষ হয়েছে?
অনুশীলন শুরু করো

অনলাইন মক টেস্ট দিয়ে প্রস্তুতি যাচাই করো

পশ্চিমবঙ্গ মধ্যশিক্ষা পর্ষদ (WBBSE) পাঠ্যক্রম অনুযায়ী বহু বিকল্পীয় প্রশ্ন (MCQ) সমাধান করো। তাৎক্ষণিক ফলাফল, সঠিক ব্যাখ্যা এবং নিজের স্কোর জেনে নাও।

শ্রেণি 10 Mathematics — সকল অধ্যায়

অধ্যায় 1: Quadratic Equations in One Variable অধ্যায় 2: Simple Interest অধ্যায় 3: Theorems related to Circle অধ্যায় 4: Rectangular Parallelopiped or Cuboid অধ্যায় 5: Ratio and Proportion অধ্যায় 6: Compound Interest and Uniform Rate of Increase or Decrease অধ্যায় 7: Theorems Related to Angles in a Circle অধ্যায় 8: Right Circular Cylinder অধ্যায় 9: Quadratic Surd অধ্যায় 10: Theorems Related to Cyclic Quadrilateral অধ্যায় 11: Construction of Circumcircle and Incircle of a Triangle অধ্যায় 12: Sphere অধ্যায় 13: Variation অধ্যায় 14: Partnership Business অধ্যায় 15: Theorems Related to Tangent to a Circle অধ্যায় 16: Right Circular Cone অধ্যায় 17: Construction of Tangent to a Circle অধ্যায় 18: Similarity অধ্যায় 19: Problems Related to Different Solid Objects অধ্যায় 20: Trigonometry: Concept of Measurement of Angle অধ্যায় 21: Construction: Determination of Mean Proportional অধ্যায় 22: Pythagoras Theorem অধ্যায় 23: Trigonometric Ratios and Trigonometric Identities অধ্যায় 24: Trigonometric Ratios of Complementary Angle অধ্যায় 25: Application of Trigonometric Ratios: Heights and Distances অধ্যায় 26: Statistics: Mean, Median, Ogive, Mode

AI সহায়ক

তাত্ক্ষণিক সমাধান

Quadratic Equations in One Variable অধ্যায়ে কোনো প্রশ্ন বা সন্দেহ আছে? আমাদের AI শিক্ষক থেকে সহজ সমাধান ও ব্যাখ্যা নিন।