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WBB • कक्षा X • Mathematics • अध्याय 2
अनुमानित समय: 100 minutes
प्रगति: अध्ययनरत

Simple Interest

Simple Interest constitutes the second chapter of the WBBSE Class 10 Mathematics curriculum Ganit Prakash. In commercial arithmetic, when money is borrowed from a lender or deposited in a financial institution, a fee is paid for the privilege of using that capital over time. The original sum of money lent or deposited is designated as the Principal P. The additional remuneration paid over and above the principal is called the Interest I. When the interest is computed uniformly on the original principal alone throughout the entire duration of the transaction, it is termed Simple Interest. The time duration T is always expressed in years, and the rate of interest R is defined as the interest accrued on one hundred rupees for one complete year. The total sum returned at the expiration of the loan period is the Amount A, which equals Principal plus Interest (A = P + I). The entire framework rests upon the fundamental proportional relationship I = (P * R * T) / 100. From this singular equation, algebraic rearrangements yield direct formulas for calculating Principal, Rate, and Time. The chapter provides rigorous practice in adjusting time units when expressed in months or days, navigating variable interest rates across successive years, solving simultaneous loan conditions where amounts at different milestones are provided, and dividing capital into multiple accounts to achieve specific financial parity.

क्या आपने कभी सोचा है?

When money is lent or invested, how is the price of time calculated without the complexity of compound growth? From rural agricultural cooperative societies across Bengal to nationalized commercial banks and the Indian Post Office, Simple Interest governs fundamental financial transactions, short-term debt instruments, and basic capital accumulation.

यह अध्याय क्यों महत्वपूर्ण है

Simple interest is an indispensable topic for every Madhyamik candidate, carrying compulsory representation in the 5-mark arithmetic long question section as well as recurring short answer and objective questions. Beyond board examinations, simple interest is the cornerstone of consumer financial literacy. It underpins agricultural micro-loans, retail financing installments, vehicle financing, employee provident fund advances, and post office monthly income schemes. Understanding the proportional mechanics of simple interest empowers students to make sound personal financial evaluations, decipher banking terms, compare loan products, and prepare for competitive civil service and banking examinations.

अध्ययन से पूर्व (आवश्यक ज्ञान)

  • Elementary arithmetic operations including percentage calculations (r% = r/100).
  • Unit conversions for time: converting months into years (m/12) and days into years (d/365).
  • Linear algebraic equations in one and two variables for solving simultaneous financial conditions.
  • Basic ratio and proportion to divide capital across multiple investments.

इस अध्याय के लक्ष्य

  • Define and articulate the foundational commercial terms: Principal (P), Time (T), Rate of Interest per annum (R), Simple Interest (I), and Total Amount (A).
  • Derive and apply the master formula I = (P * R * T) / 100 and its algebraic variations for P, R, and T.
  • Standardize time given in months (T = m/12) and days (T = d/365) including calendar day-counting rules.
  • Solve problems with variable interest rates over successive time periods.
  • Analyze comparative returns between different financial institutions like commercial banks and post offices.
  • Formulate and solve simultaneous linear equations arising from multi-term loan and investment agreements.
  • Model real-world trust fund and inheritance distributions to yield equal future amounts for beneficiaries of different ages.

अध्याय रूपरेखा एवं प्रगति

1 Module 1: Fundamental Terminology a...
2 Module 2: Algebraic Variations & De...
3 Module 3: Standardizing Time Units...
4 Module 4: Variable Rates, Simultane...

सम्पूर्ण सैद्धांतिक एवं वैचारिक अध्ययन

Module 1: Fundamental Terminology and the Master Formula

1.1 Foundational Financial Terminology

In commercial transactions involving loans and savings, five core mathematical variables interact:

Term (English / Bengali) Symbol Mathematical Definition Standard Unit
Principal (আসল বা মূলধন) $P$ The initial sum of money borrowed, lent, or deposited. Rupees (₹)
Rate of Interest (বার্ষিক সুদের হার) $R$ or $r\%$ The interest accrued on ₹100 for a duration of 1 year. Percent per annum (% p.a.)
Time (সময়) $T$ or $t$ The total duration for which the principal is utilized. Years (বছর)
Simple Interest (মোট সরল সুদ) $I$ The uniform charge paid exclusively on the original principal. Rupees (₹)
Amount (সবৃদ্ধিমূল বা সুদাসল) $A$ Total return: Principal + Total Interest ($A = P + I$). Rupees (₹)
1.2 Derivation of the Master Formula

By definition, the interest on ₹100 for 1 year is ₹$R$.
Using the unitary method:
Interest on ₹1 for 1 year = ₹$ rac{R}{100}$
Interest on ₹$P$ for 1 year = ₹$ rac{P imes R}{100}$
Interest on ₹$P$ for $T$ years = ₹$ rac{P imes R imes T}{100}$

The Master Formula: $I = rac{P \cdot R \cdot T}{100}$

Total Amount formula in terms of $P, R, T$:

$A = P + I = P + rac{PRT}{100} = P\left(1 + rac{RT}{100} ight) = rac{P(100 + RT)}{100}$

Module 2: Algebraic Variations & Determination of P, R, and T

2.1 Transposition for Unknown Quantities

The master equation $100 \cdot I = P \cdot R \cdot T$ allows any single unknown variable to be isolated when the remaining three are known:

Unknown Variable Formula When Given Amount ($A$) Instead of $I$
Principal ($P$) $P = rac{100 imes I}{R imes T}$ $P = rac{100 imes A}{100 + R imes T}$
Rate of Interest ($R$) $R = rac{100 imes I}{P imes T}$ $R = rac{100 imes (A - P)}{P imes T}$
Time ($T$) $T = rac{100 imes I}{P imes R}$ $T = rac{100 imes (A - P)}{P imes R}$
The Multiplication Factor Rule (Doubling / Tripling):

If a principal doubles ($A = 2P$), then $I = 2P - P = P$. Substituting into $I = rac{PRT}{100} \implies P = rac{PRT}{100} \implies \mathbf{R imes T = 100}$.
If a principal becomes $n$-times ($A = nP$), then $I = (n - 1)P$, giving $\mathbf{R imes T = 100(n - 1)}$.

Module 3: Standardizing Time Units (Months, Days & Calendar Calculations)

3.1 Fractional Years from Months and Days

The variable $T$ in $I = rac{PRT}{100}$ must always be expressed in years. When time is given in alternative units, convert as follows:

  • Time in months ($m$): $T = rac{m}{12}$ years. (e.g., $9$ months $= rac{9}{12} = rac{3}{4}$ year).
  • Time in years and months: $2$ years $4$ months $= 2 + rac{4}{12} = 2 + rac{1}{3} = rac{7}{3}$ years.
  • Time in days ($d$): $T = rac{d}{365}$ years (unless a leap year is specifically stated, standard commercial banking uses $365$ days). Common multiples: $73$ days $= rac{73}{365} = rac{1}{5}$ year; $146$ days $= rac{146}{365} = rac{2}{5}$ year; $219$ days $= rac{3}{5}$ year.
Banking Day Counting Convention:

When calculating days between two calendar dates, the day on which money is deposited is counted, but the day on which money is withdrawn is excluded (or vice versa). Total number of days = (Days remaining in start month) + (Full days of intermediate months) + (Date of withdrawal).

Module 4: Variable Rates, Simultaneous Loans & Board Problem Models

4.1 Successive Variable Interest Rates

If the rate of interest changes over successive periods ($R_1\%$ for $T_1$ years, $R_2\%$ for $T_2$ years, etc.), total simple interest is the linear sum of interest for each interval:

$$I_{ ext{total}} = rac{P \cdot R_1 \cdot T_1}{100} + rac{P \cdot R_2 \cdot T_2}{100} + \dots = rac{P}{100}\left(R_1 T_1 + R_2 T_2 + \dots ight)$$
4.2 Solving Simultaneous Milestone Conditions

A classic Madhyamik problem provides the amount at two different times (e.g., amount is $A_1$ in $T_1$ years and $A_2$ in $T_2$ years):

  1. Express both amounts: $P + I_{T_1} = A_1$ and $P + I_{T_2} = A_2$.
  2. Subtract the two equations: $I_{T_2} - I_{T_1} = A_2 - A_1$. Because simple interest is uniform, the interest for $(T_2 - T_1)$ years is exactly $(A_2 - A_1)$.
  3. Determine interest for $1$ year: $I_1 = rac{A_2 - A_1}{T_2 - T_1}$.
  4. Compute interest for $T_1$ years: $I_{T_1} = T_1 imes I_1$, then deduce principal: $P = A_1 - I_{T_1}$.
  5. Finally, calculate rate of interest: $R = rac{100 imes I_1}{P imes 1}$.

महत्वपूर्ण सूत्र, सर्वसमिकाएँ एवं प्रमेय

Simple Interest Master Formula
I = (P * R * T) / 100
Total Amount Formula
A = P + I = P(1 + (R * T)/100)
Principal from Interest
P = (100 * I) / (R * T)
Rate of Interest Formula
R = (100 * I) / (P * T)
Time Period Formula
T = (100 * I) / (P * R)
Principal from Total Amount
P = (100 * A) / (100 + R * T)
Doubling Capital Rule
R * T = 100
n-fold Capital Rule
R * T = 100 * (n - 1)
Monthly Time Conversion
T = m / 12 years
Daily Time Conversion
T = d / 365 years

अवधारणात्मक हल उदाहरण एवं अनुप्रयोग (Solved Examples)

उदाहरण 1
Calculate the simple interest and total amount on ₹7,200 for 2 years 6 months at 7.5% per annum.
विस्तृत समाधान / उत्तर:
Step 1: Identify given values: Principal P = ₹7,200. Rate R = 7.5% = 15/2% p.a. Time T = 2 years 6 months = 2 + 6/12 = 2 + 1/2 = 5/2 years. Step 2: Apply the simple interest formula: I = (P * R * T) / 100 I = [7200 * (15/2) * (5/2)] / 100 I = [7200 * 75] / [4 * 100] I = 72 * 75 / 4 = 18 * 75 = ₹1,350. Step 3: Calculate the total amount A: A = P + I = ₹7,200 + ₹1,350 = ₹8,550. Hence, Simple Interest = ₹1,350 and Amount = ₹8,550.
उदाहरण 2
A certain sum of money amounts to ₹7,100 in 7 years and to ₹6,200 in 4 years at simple interest. Find the principal and the annual rate of interest.
विस्तृत समाधान / उत्तर:
Step 1: Set up the milestone equations: Principal + Simple Interest for 7 years = ₹7,100 ... (1) Principal + Simple Interest for 4 years = ₹6,200 ... (2) Step 2: Subtract equation (2) from equation (1): Simple Interest for (7 - 4) years = ₹7,100 - ₹6,200 Simple Interest for 3 years = ₹900 Step 3: Find simple interest for 1 year and for 4 years: Interest for 1 year = ₹900 / 3 = ₹300 Interest for 4 years = 4 * ₹300 = ₹1,200 Step 4: Determine Principal P: P = Amount in 4 years - Interest for 4 years = ₹6,200 - ₹1,200 = ₹5,000. Step 5: Determine Rate of Interest R: R = (100 * I) / (P * T) = (100 * 300) / (5000 * 1) = 30000 / 5000 = 6% p.a. Hence, Principal = ₹5,000 and Rate of Interest = 6% p.a.
उदाहरण 3
A person divided ₹1,00,000 between a bank and a post office at 6% and 7% annual simple interest respectively. If the total annual interest received was ₹6,500, how much money was deposited in each institution?
विस्तृत समाधान / उत्तर:
Step 1: Assign variables: Let the money deposited in the bank be ₹x. Then the money deposited in the post office is ₹(1,00,000 - x). Step 2: Express annual interest from both sources: Interest from bank for 1 year = (x * 6 * 1) / 100 = 6x / 100 Interest from post office for 1 year = [(100000 - x) * 7 * 1] / 100 = (700000 - 7x) / 100 Step 3: Formulate equation according to the condition: 6x / 100 + (700000 - 7x) / 100 = 6,500 Step 4: Clear denominators and solve for x: 6x + 700000 - 7x = 6500 * 100 700000 - x = 650000 x = 700000 - 650000 = 50,000 Step 5: State conclusion: Deposit in bank = ₹50,000. Deposit in post office = ₹1,00,000 - ₹50,000 = ₹50,000.
उदाहरण 4
A sum of money becomes 3 times itself in 16 years at simple interest. In how many years will it become 5 times itself at the same rate of interest?
विस्तृत समाधान / उत्तर:
Step 1: Analyze the first scenario (becoming 3 times): Let Principal = P. Amount A_1 = 3P. Simple Interest I_1 = A_1 - P = 3P - P = 2P. Time T_1 = 16 years. Step 2: Calculate the rate of interest R: R = (100 * I_1) / (P * T_1) = (100 * 2P) / (P * 16) = 200 / 16 = 12.5% p.a. Step 3: Analyze the second scenario (becoming 5 times): Amount A_2 = 5P. Simple Interest I_2 = A_2 - P = 5P - P = 4P. Rate R = 12.5% = 25/2% p.a. Step 4: Calculate required time T_2: T_2 = (100 * I_2) / (P * R) = (100 * 4P) / [P * (25/2)] = 400 / (25/2) = (400 * 2) / 25 = 16 * 2 = 32 years. Alternative Direct Proportion: In simple interest, interest is directly proportional to time. To earn 2P interest takes 16 years; to earn 4P interest takes (16 / 2P) * 4P = 32 years. Hence, the money will become 5 times in 32 years.
उदाहरण 5
A father deposited ₹1,87,500 in a bank for his two sons aged 12 years and 14 years in such a way that each will receive an equal amount at the age of 18 years. If the rate of simple interest is 5% per annum, find the principal deposited for each son.
विस्तृत समाधान / उत्तर:
Step 1: Determine the investment periods for both sons: For the younger son (aged 12): time until 18 = 18 - 12 = 6 years (T_1 = 6). For the elder son (aged 14): time until 18 = 18 - 14 = 4 years (T_2 = 4). Step 2: Assign principal variables: Let the principal for the younger son be ₹x. Then the principal for the elder son is ₹y, with x + y = 1,87,500. Step 3: Express maturity amounts at 5% p.a.: Amount for younger son A_1 = x[1 + (5 * 6)/100] = x[1 + 30/100] = 130x / 100 Amount for elder son A_2 = y[1 + (5 * 4)/100] = y[1 + 20/100] = 120y / 100 Step 4: Equate the two amounts (A_1 = A_2): 130x / 100 = 120y / 100 => 13x = 12y => x/y = 12/13 Step 5: Divide total sum according to ratio 12:13: Sum of ratio terms = 12 + 13 = 25. x = (12 / 25) * 1,87,500 = 12 * 7,500 = ₹90,000. y = (13 / 25) * 1,87,500 = 13 * 7,500 = ₹97,500. Hence, deposit for younger son = ₹90,000 and for elder son = ₹97,500.

सामान्य गलतियाँ एवं परीक्षक के जाल (Examiner Traps)

सामान्य भ्रम / गलत उत्तर

Using time T directly in months (e.g. T = 8) without dividing by 12.

सही वैज्ञानिक तथ्य

Always convert months into years by dividing by 12: T = 8/12 = 2/3 years.

सामान्य भ्रम / गलत उत्तर

Confusing Amount (A) with Interest (I) in formula P = 100I / (RT).

सही वैज्ञानिक तथ्य

If Amount is given, either compute I = A - P first, or use P = 100A / (100 + RT).

सामान्य भ्रम / गलत उत्तर

Assuming interest quadruples when a sum becomes 4 times itself.

सही वैज्ञानिक तथ्य

When amount becomes 4P, interest earned is 4P - P = 3P (not 4P).

सामान्य भ्रम / गलत उत्तर

Counting both the start date and the end date in calendar day calculations.

सही वैज्ञानिक तथ्य

Count either the deposit date or the withdrawal date, never both.

सामान्य भ्रम / गलत उत्तर

Adding interest to principal each year during simple interest computations.

सही वैज्ञानिक तथ्य

In simple interest, principal remains constant throughout all years.

सामान्य भ्रम / गलत उत्तर

Dividing days by 360 instead of 365 in Indian board syllabus.

सही वैज्ञानिक तथ्य

WBBSE curriculum uses standard 365 days per year unless leap year is explicitly stated.

Concept Map: Simple Interest (WBBSE Class 10 Ganit Prakash)

Simple Interest (সরল সুদকষা) WBBSE Class 10 Mathematics • Chapter 2 • Formulas, Conversions & Applications 1. Core Variables & Master Formula • Principal (P): Initial money lent/deposited• Rate (R): Annual interest per ₹100• Time (T): Duration strictly in years• Master Formula: I = (P * R * T) / 100 2. Algebraic Variations • Principal: P = (100 * I) / (R * T)• Rate: R = (100 * I) / (P * T)• Time: T = (100 * I) / (P * R)• Amount: A = P + I = P(1 + RT/100) 3. Time Unit Standardization • Months to years: T = m / 12 years• Days to years: T = d / 365 years• Day counting: Include deposit day, exclude withdrawal• Variable rates: I = P*(R1*T1 + R2*T2 + ...)/100 4. Board Applications & Schemes • Bank vs Post Office comparison problems• Simultaneous conditions (Amount in 3 & 5 yrs)• Doubling rule: R * T = 100 for A = 2P• Trust funds for children reaching age 18

अध्याय का सार संक्षेप एवं 10 मुख्य निष्कर्ष

मुख्य बिंदु 1
Principal (P) is the money borrowed or deposited; Interest (I) is the cost of borrowing; Time (T) is duration in years; Rate (R) is interest per ₹100 per annum.
मुख्य बिंदु 2
The master simple interest formula is I = (P * R * T) / 100.
मुख्य बिंदु 3
Total Amount (A) equals Principal plus Interest: A = P + I = P(1 + RT/100).
मुख्य बिंदु 4
Algebraic variations isolate individual unknowns: P = 100I/(RT), R = 100I/(PT), and T = 100I/(PR).
मुख्य बिंदु 5
Time must be expressed in years: m months = m/12 years; d days = d/365 years.
मुख्य बिंदु 6
When capital doubles at simple interest, R * T = 100; when it becomes n-fold, R * T = 100(n - 1).
मुख्य बिंदु 7
In milestone problems where amounts for two different years are given, the difference between amounts gives simple interest for the difference in years.
मुख्य बिंदु 8
When dividing capital to yield equal future amounts, the capital shares are inversely proportional to (100 + RT).

स्व-मूल्यांकन अभ्यास (Check Your Understanding)

मूल वैचारिक स्पष्टता की जांच के लिए नैदानिक प्रश्न। पहले स्वयं हल करें, फिर उत्तर देखें।

1
At what rate of simple interest per annum will a sum of money double itself in 10 years?
उत्तर एवं व्याख्या देखें
उत्तर: For principal to double, I = P. Using R * T = 100 => R * 10 = 100 => R = 10% per annum.
2
If the simple interest on ₹1,200 for 3 years is ₹216, what is the rate percent per annum?
उत्तर एवं व्याख्या देखें
उत्तर: R = (100 * I) / (P * T) = (100 * 216) / (1200 * 3) = 21600 / 3600 = 6% per annum.
3
How long will it take for ₹5,000 to yield ₹1,250 as simple interest at 5% per annum?
उत्तर एवं व्याख्या देखें
उत्तर: T = (100 * I) / (P * R) = (100 * 1250) / (5000 * 5) = 125000 / 25000 = 5 years.
4
What is the simple interest on ₹2,500 for 73 days at 6% per annum?
उत्तर एवं व्याख्या देखें
उत्तर: T = 73/365 = 1/5 year. I = (P * R * T)/100 = (2500 * 6 * 1/5)/100 = (500 * 6)/100 = ₹30.
5
If a sum of money becomes ₹800 in 2 years and ₹920 in 3 years at simple interest, what is the principal?
उत्तर एवं व्याख्या देखें
उत्तर: Interest for 1 year = ₹920 - ₹800 = ₹120. Interest for 2 years = 2 * ₹120 = ₹240. Principal = ₹800 - ₹240 = ₹560.
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कक्षा 10 Mathematics के सभी अध्याय

अध्याय 1: Quadratic Equations in One Variable अध्याय 2: Simple Interest अध्याय 3: Theorems related to Circle अध्याय 4: Rectangular Parallelopiped or Cuboid अध्याय 5: Ratio and Proportion अध्याय 6: Compound Interest and Uniform Rate of Increase or Decrease अध्याय 7: Theorems Related to Angles in a Circle अध्याय 8: Right Circular Cylinder अध्याय 9: Quadratic Surd अध्याय 10: Theorems Related to Cyclic Quadrilateral अध्याय 11: Construction of Circumcircle and Incircle of a Triangle अध्याय 12: Sphere अध्याय 13: Variation अध्याय 14: Partnership Business अध्याय 15: Theorems Related to Tangent to a Circle अध्याय 16: Right Circular Cone अध्याय 17: Construction of Tangent to a Circle अध्याय 18: Similarity अध्याय 19: Problems Related to Different Solid Objects अध्याय 20: Trigonometry: Concept of Measurement of Angle अध्याय 21: Construction: Determination of Mean Proportional अध्याय 22: Pythagoras Theorem अध्याय 23: Trigonometric Ratios and Trigonometric Identities अध्याय 24: Trigonometric Ratios of Complementary Angle अध्याय 25: Application of Trigonometric Ratios: Heights and Distances अध्याय 26: Statistics: Mean, Median, Ogive, Mode

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