Physical Concept of Mechanical Work:
In physical mechanics, work is defined as the product of the component of force along the direction of displacement and the magnitude of the displacement of the point of application of the force. If a constant force $\vec{F}$ acts on a body and produces a displacement $\vec{s}$ at an angle $\theta$ with respect to the line of action of the force, the work done $W$ is mathematically given by the scalar (dot) product:
$$\mathbf{W = \vec{F} \cdot \vec{s} = F s \cos \theta}$$Three Cases of Work Done:
- Positive Work ($0^\circ \le \theta < 90^\circ$): When displacement has a component along the direction of the force. $\cos \theta > 0$. Example: A horse pulling a cart forwards, or gravity acting on a falling stone ($ heta = 0^\circ \implies W = +mgh$).
- Zero Work ($ heta = 90^\circ$ or $s = 0$): When the force is perpendicular to displacement or no motion occurs. $\cos 90^\circ = 0 \implies W = 0$. Examples: A porter carrying a suitcase on his head while walking horizontally on a platform (force of gravity acts vertically downwards at $90^\circ$ to horizontal displacement); centripetal force acting on an orbiting satellite (always radially perpendicular to the tangential velocity); a man pushing against a rigid brick wall ($s = 0$).
- Negative Work ($90^\circ < \theta \le 180^\circ$): When the force opposes the motion. $\cos 180^\circ = -1 \implies W = -F s$. Example: The retarding work done by friction or brakes when stopping a moving automobile.
Units of Work and Energy:
- SI Unit: Joule ($\text{J}$). $1\text{ Joule} = 1\text{ Newton} \times 1\text{ meter} = 1\text{ N}\cdot\text{m} = 1\text{ kg}\cdot\text{m}^2\cdot\text{s}^{-2}$.
- CGS Unit: Erg. $1\text{ erg} = 1\text{ dyne} \times 1\text{ cm} = 10^{-5}\text{ N} \times 10^{-2}\text{ m} = 10^{-7}\text{ J} \implies \mathbf{1\text{ J} = 10^7\text{ ergs}}$.
- Commercial Unit: Kilowatt-hour ($\text{kWh}$). $1\text{ kWh} = 1,000\text{ W} \times 3,600\text{ s} = \mathbf{3.6 \times 10^6\text{ J} = 3.6\text{ MJ}}$.
- Atomic Unit: Electron-volt ($\text{eV}$). $1\text{ eV} = 1.6 \times 10^{-19}\text{ J}$.