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ICSE • Class X • Science • Ch 2
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Work, Energy and Power

Understand work definitions, angle dependence, energy forms, work-energy theorem, conservation of mechanical energy, and power metrics.

Why This Chapter Matters

Understand work definitions, angle dependence, energy forms, work-energy theorem, conservation of mechanical energy, and power metrics.

Chapter Roadmap & Progression

1 1. Work: Physical Definition, Angle...
2 2. Kinetic Energy, Potential Energy...
3 3. Law of Conservation of Mechanica...
4 4. Comprehensive ICSE Board Solved...
5 5. Laboratory Investigation Protoco...
6 6. Advanced Comparative Matrix & Co...
7 7. CISCE Board Examination Marking...
8 8. Rapid-Fire Revision Checklist &...
9 9. Advanced Analytical Derivations...
10 10. Contemporary Industrial Applica...
11 11. Advanced ICSE Board 5-Problem D...
12 12. Diagnostic Assertion-Reasoning...
13 13. Historical Epistemology & Found...
14 14. Examination Hall Protocol & Tim...

Complete Concept Guide (100% Curriculum Coverage)

1. Work: Physical Definition, Angle Dependence & Mathematical Forms

Work & Vectors
Physical Concept of Mechanical Work:

In physical mechanics, work is defined as the product of the component of force along the direction of displacement and the magnitude of the displacement of the point of application of the force. If a constant force $\vec{F}$ acts on a body and produces a displacement $\vec{s}$ at an angle $\theta$ with respect to the line of action of the force, the work done $W$ is mathematically given by the scalar (dot) product:

$$\mathbf{W = \vec{F} \cdot \vec{s} = F s \cos \theta}$$
Three Cases of Work Done:
  • Positive Work ($0^\circ \le \theta < 90^\circ$): When displacement has a component along the direction of the force. $\cos \theta > 0$. Example: A horse pulling a cart forwards, or gravity acting on a falling stone ($ heta = 0^\circ \implies W = +mgh$).
  • Zero Work ($ heta = 90^\circ$ or $s = 0$): When the force is perpendicular to displacement or no motion occurs. $\cos 90^\circ = 0 \implies W = 0$. Examples: A porter carrying a suitcase on his head while walking horizontally on a platform (force of gravity acts vertically downwards at $90^\circ$ to horizontal displacement); centripetal force acting on an orbiting satellite (always radially perpendicular to the tangential velocity); a man pushing against a rigid brick wall ($s = 0$).
  • Negative Work ($90^\circ < \theta \le 180^\circ$): When the force opposes the motion. $\cos 180^\circ = -1 \implies W = -F s$. Example: The retarding work done by friction or brakes when stopping a moving automobile.
Units of Work and Energy:
  • SI Unit: Joule ($\text{J}$). $1\text{ Joule} = 1\text{ Newton} \times 1\text{ meter} = 1\text{ N}\cdot\text{m} = 1\text{ kg}\cdot\text{m}^2\cdot\text{s}^{-2}$.
  • CGS Unit: Erg. $1\text{ erg} = 1\text{ dyne} \times 1\text{ cm} = 10^{-5}\text{ N} \times 10^{-2}\text{ m} = 10^{-7}\text{ J} \implies \mathbf{1\text{ J} = 10^7\text{ ergs}}$.
  • Commercial Unit: Kilowatt-hour ($\text{kWh}$). $1\text{ kWh} = 1,000\text{ W} \times 3,600\text{ s} = \mathbf{3.6 \times 10^6\text{ J} = 3.6\text{ MJ}}$.
  • Atomic Unit: Electron-volt ($\text{eV}$). $1\text{ eV} = 1.6 \times 10^{-19}\text{ J}$.

2. Kinetic Energy, Potential Energy & The Work-Energy Theorem

Energy Transformations
Kinetic Energy ($K$) and Mathematical Derivation:

Kinetic energy is the energy possessed by a body by virtue of its state of motion. For a body of mass $m$ moving with speed $v$:

$$\mathbf{K = \frac{1}{2} m v^2}$$

Relationship Between Kinetic Energy and Momentum ($p = mv$):

$$p = mv \implies v = \frac{p}{m} \implies K = \frac{1}{2} m \left(\frac{p}{m}\right)^2 = \mathbf{\frac{p^2}{2m}} \iff \mathbf{p = \sqrt{2mK}}$$
Potential Energy ($U$):

Potential energy is the energy possessed by a body by virtue of its position, configuration, or state of strain. Gravitational potential energy at height $h$ near Earth's surface:

$$\mathbf{U = m g h}$$

Elastic potential energy stored in a compressed or elongated spring with spring constant $k$: $U = \frac{1}{2} k x^2$.

The Work-Energy Theorem:

The work done by the net resultant force acting on a body is equal to the net change produced in its kinetic energy:

$$\mathbf{W_{\text{net}} = K_f - K_i = \frac{1}{2} m v^2 - \frac{1}{2} m u^2 = \Delta K}$$

Analytical Derivation: From Newton's third kinematic equation $v^2 - u^2 = 2as \implies a = \frac{v^2 - u^2}{2s}$. Multiplying both sides by $m$: $F = ma = m\left(\frac{v^2 - u^2}{2s}\right) \implies F s = \frac{1}{2} m v^2 - \frac{1}{2} m u^2 = \Delta K$.

3. Law of Conservation of Mechanical Energy & Free-Falling Body Proof

Conservation of Energy
Statement of the Conservation of Mechanical Energy:

In an isolated conservative system (where dissipative forces such as friction and air resistance are negligible), the total mechanical energy—the sum of kinetic energy ($K$) and potential energy ($U$)—remains strictly constant throughout the motion:

$$\mathbf{E_{\text{total}} = K + U = \text{Constant}}$$
Rigorous Proof for a Body of Mass $m$ Falling Freely from Height $H$:
  1. At Initial Position A (Height $H$, at rest):
    Velocity $u = 0 \implies K_A = \frac{1}{2} m (0)^2 = 0$.
    Height $= H \implies U_A = mgH$.
    Total Mechanical Energy: $\mathbf{E_A = K_A + U_A = 0 + mgH = mgH}$.
  2. At Intermediate Position B (After falling distance $x$, at height $H - x$):
    From $v_B^2 = u^2 + 2gx = 0 + 2gx = 2gx$.
    Kinetic Energy: $K_B = \frac{1}{2} m v_B^2 = \frac{1}{2} m (2gx) = mgx$.
    Height from ground $= H - x \implies U_B = mg(H - x) = mgH - mgx$.
    Total Mechanical Energy: $\mathbf{E_B = K_B + U_B = mgx + (mgH - mgx) = mgH}$.
  3. At Final Position C (Just before striking ground, height $0$):
    From $v_C^2 = u^2 + 2gH = 2gH$.
    Kinetic Energy: $K_C = \frac{1}{2} m v_C^2 = \frac{1}{2} m (2gH) = mgH$.
    Height $= 0 \implies U_C = 0$.
    Total Mechanical Energy: $\mathbf{E_C = K_C + U_C = mgH + 0 = mgH}$.

Since $E_A = E_B = E_C = mgH$, mechanical energy is perfectly conserved at every point during free fall!

4. Comprehensive ICSE Board Solved Numericals & Algorithmic Workflows for Work, Energy and Power

Problem 1: Work Done Under Angled Tension

Question: A boy pulls a toy cart of mass $5\text{ kg}$ along a horizontal floor with a force of $20\text{ N}$ applied through a rope inclined at $60^\circ$ to the horizontal. If the cart moves through a distance of $8\text{ m}$ in $4\text{ s}$, calculate: (i) the work done by the boy, (ii) the work done by gravity, and (iii) the average power developed by the boy.

Solution:
(i) Work done by the boy: $W = F s \cos \theta = 20\text{ N} \times 8\text{ m} \times \cos 60^\circ = 160 \times 0.5 = \mathbf{80\text{ J}}$.
(ii) Work done by gravity: Gravity acts vertically downward at $90^\circ$ to the horizontal displacement. Therefore, $W_g = mg \times s \times \cos 90^\circ = 0\text{ J}$.
(iii) Average Power: $P = \frac{W}{t} = \frac{80\text{ J}}{4\text{ s}} = \mathbf{20\text{ W}}$.

Problem 2: Momentum Doubling and Kinetic Energy Percentage Increase

Question: If the linear momentum of a body is increased by $100\%$, calculate the percentage increase in its kinetic energy.

Solution:
Let initial momentum be $p_1$. Kinetic energy $K_1 = \frac{p_1^2}{2m}$.
When momentum increases by $100\%$, the new momentum is $p_2 = p_1 + 1.00 p_1 = 2p_1$.
New Kinetic Energy: $K_2 = \frac{p_2^2}{2m} = \frac{(2p_1)^2}{2m} = \frac{4p_1^2}{2m} = 4 K_1$.
Increase in Kinetic Energy: $\Delta K = K_2 - K_1 = 4K_1 - K_1 = 3K_1$.
Percentage Increase: $\frac{\Delta K}{K_1} \times 100\% = \frac{3K_1}{K_1} \times 100\% = \mathbf{300\%}$.

Problem 3: Hydroelectric Dam Power Generation

Question: Water falls from a reservoir behind a hydroelectric dam at a rate of $2,000\text{ kg/s}$ from a vertical height of $60\text{ m}$ onto turbine blades. If the turbine generator converts $75\%$ of the gravitational potential energy into electricity, calculate the electrical power output in Kilowatts (take $g = 10\text{ m/s}^2$).

Solution:
Rate of potential energy input $= \frac{mgh}{t} = \left(\frac{m}{t}\right) g h = 2,000\text{ kg/s} \times 10\text{ m/s}^2 \times 60\text{ m} = 1,200,000\text{ J/s} = 1,200\text{ kW}$.
Efficiency $\eta = 75\% = 0.75$.
Electrical Power Output $P_{\text{out}} = \eta \times P_{\text{in}} = 0.75 \times 1,200\text{ kW} = \mathbf{900\text{ kW}}$.

5. Laboratory Investigation Protocols & Experimental Demonstrations for Work, Energy and Power

Experimental Verification
Laboratory Demonstration: Conservation of Energy Using a Simple Pendulum:

To experimentally demonstrate the conservation of mechanical energy and interconversion between potential and kinetic energy:

  • Setup: Suspend a heavy spherical brass bob from a rigid clamp using fine cotton thread. Place a photogate timer at the lowest equilibrium position $O$.
  • Procedure: Displace the bob to an extreme position $A$ at vertical height $h$ above $O$ and release from rest. Measure the transit speed $v$ at the lowest point $O$ using the photogate.
  • Verification: Theoretical velocity $v = \sqrt{2gh}$. Compare measured speed with theoretical prediction. Accounting for negligible string friction, energy conversion efficiency exceeds $98\%$.

6. Advanced Comparative Matrix & Conceptual Distinctions in Work, Energy and Power

CriterionWorkPowerEnergy
DefinitionForce acting through a displacement ($F s \cos \theta$)Rate of doing work ($\frac{W}{t}$)Capacity of a body to do work
SI UnitJoule ($\text{J} = \text{N}\cdot\text{m}$)Watt ($\text{W} = \text{J/s}$)Joule ($\text{J}$)
Time DependenceCompletely independent of time takenInversely proportional to time takenIndependent of time
Scalar / VectorScalar quantityScalar quantityScalar quantity

7. CISCE Board Examination Marking Rubrics & Examiner Insights for Work, Energy and Power

Examiner Marking Standards
How ICSE Examiners Grade Questions in Work, Energy and Power:

Based on official CISCE Council Examiner Reports, candidates should adhere to these evaluation standards:

  • SI Units & Dimensions: Always express final numerical answers with correct standard SI units (e.g., Joules, Watts, Ohms, Volts, Amperes, Becquerel). Writing an answer without a unit results in the loss of 1 mark.
  • Ray Diagrams & Circuit Schematics: Every optical ray MUST feature an arrowhead indicating its direction of propagation. Electrical circuit diagrams must have polarities marked on batteries and arrows showing conventional current flow from positive to negative terminals.
  • Principle Citations: State the governing physical law or theorem before applying it. Method marks ($M_1$) are awarded for the formula itself.
  • Reasoning in Parentheses: In descriptive or qualitative questions, accompany statements with core scientific reasons (e.g. '[by conservation of energy]', '[due to total internal reflection]').

8. Rapid-Fire Revision Checklist & Formula Master-Sheet for Work, Energy and Power

Formula Sheet
High-Yield Mathematical Formulations for Work, Energy and Power:

Review and memorize the core relations to ensure instant recall during time-constrained examinations.

  • Review dimensional consistency across all terms in every equation.
  • Verify sign conventions for work, lens equations, and thermal exchanges.
  • Double check decimal positions and power-of-ten exponents during calculations.

9. Advanced Analytical Derivations & First-Principle Foundations in Work, Energy and Power

Theoretical Foundations
Rigorous First-Principle Derivation:

In the academic progression of CISCE ICSE Class 10 Science, students are required to transcend qualitative descriptions and master rigorous analytical derivations grounded in invariant physical and chemical conservation laws.

When modeling systems in Work, Energy and Power, three core conservation principles serve as analytical anchors:

  • Conservation of Mass-Energy: The total energy of an isolated physical system remains invariant over time, merely transforming between kinetic, potential, thermal, chemical, or radiant configurations. In relativistic domains, $E = mc^2$ establishes the exact equivalence between mass deficit and released radiation.
  • Conservation of Momentum & Charge: Linear and angular momentum, as well as fundamental electrical charges, are conserved across all physical interactions and chemical transformations without exception.
  • Thermodynamic Entropy & Dissipation: In every macroscopic real-world mechanical, thermodynamic, or chemical transformation, useful mechanical work is partially degraded into disordered thermal dissipation due to internal friction, viscosity, electrical resistance, or non-elastic particle collisions.

By establishing governing differential relations and integrating boundary conditions, candidates build a predictive mathematical framework capable of solving complex multi-stage problems without memorizing isolated special-case formulas.

10. Contemporary Industrial Applications & Technological Horizons in Work, Energy and Power

Industrial Applications
Real-World Technological Implementations:

The theoretical constructs developed in Work, Energy and Power form the engineering backbone of modern global infrastructure, aerospace engineering, biomedical diagnostics, renewable energy generation, and semiconductor microelectronics.

1. Precision Mechanical & Optical Systems

Principles of force balancing, moments, wave propagation, and refractive optics govern the design of robotic arm actuators, high-aperture astronomical telescopes, photolithography stepper lenses for microchip manufacturing, and fiber-optic telecommunication backbones carrying terabits of global internet traffic across undersea cables.

2. Sustainable Energy & Power Distribution

From multi-megawatt hydroelectric turbines harnessing gravitational potential energy to photovoltaic solar panels and nuclear fission reactors, the quantitative modeling of energy transformation efficiency is central to combating global climate change and designing resilient zero-carbon power grids.

Understanding the engineering compromises between theoretical maximum efficiency (governed by ideal physical laws) and operational real-world constraints (governed by material fatigue, thermal dissipation, and parasitic electrical impedances) distinguishes top-tier scientific thinkers.

11. Advanced ICSE Board 5-Problem Diagnostic Master Drill for Work, Energy and Power

Diagnostic Master Drill
High-Yield Problem Solving Protocol:

Practice these standard problem archetypes representing the full spectrum of ICSE examination question formats:

  1. Type A: Direct Numerical Substitution & Fundamental SI Unit Verification
    Given standard physical inputs, state the governing algebraic formula, convert all non-standard metric quantities (e.g. grams to kilograms, minutes to seconds, centimeters to meters), substitute the values, and evaluate the final magnitude with appropriate SI units.
  2. Type B: Reverse Engineering Unknown System Parameters
    Given the final observed equilibrium state or total energy output, set up an algebraic equation to solve backwards for an unknown intermediate variable (such as friction coefficient, focal length, specific heat capacity, or internal resistance).
  3. Type C: Multi-Stage Conservation & Transfer Modeling
    Model systems where energy or mass transfers sequentially across multiple stages (e.g. mechanical to thermal, or electrical to mechanical), applying conservation laws across each transitional interface while accounting for intermediate transmission losses.
  4. Type D: Graphical Analysis & Slope/Area Interpretations
    Extract physical constants directly from experimental graphs by calculating line gradients or computing geometric areas enclosed beneath curves (e.g. force-displacement area yielding work, or velocity-time area yielding displacement).
  5. Type E: Qualitative Reasoning & Scientific Cause-Effect Exposition
    Provide structured scientific justifications for natural phenomena or engineering designs, citing the precise physical mechanism, naming the governing scientific law, and contrasting ideal conditions with everyday observations.

12. Diagnostic Assertion-Reasoning & Rapid Quantitative Drill for Work, Energy and Power

Assertion & Reasoning
ICSE Examination Diagnostic Item Bank:

Item 1 (Assertion-Reasoning):
Assertion (A): An ideal physical model provides an unachievable upper bound for operational efficiency.
Reason (R): In macroscopic terrestrial systems, non-conservative dissipation mechanisms (frictional drag, contact resistance, acoustic emissions, and thermal radiation) irreversibly degrade mechanical or electrical free energy into disordered ambient heat.
Evaluation: Both (A) and (R) are true, and (R) is the correct physical explanation of (A).

Item 2 (Methodological Protocol):
Guidance on Intermediate Decimals: When evaluating multi-step numericals, retain at least three significant figures during intermediate algebraic manipulations. Premature truncation to a single decimal place induces rounding drift that can alter the final reported answer by several percent, jeopardizing accuracy marks.

Item 3 (Scientific Communication Standard):
Justification Format: In answer scripts, always organize descriptive answers in numbered bullet points. Highlight the governing scientific principle first, follow with the operational mechanism, and conclude with the tangible physical consequence. This structured format enables examiners to rapidly identify scoring keywords.

13. Historical Epistemology & Foundational Scientific Discoveries in Work, Energy and Power

Scientific History
The Evolution of Scientific Understanding in Work, Energy and Power:

The principles explored in Work, Energy and Power represent milestones in the scientific revolution. From early empirical observations by pioneers such as Galileo Galilei, Sir Isaac Newton, and James Prescott Joule to modern quantum electrodynamics and thermodynamics, our understanding of nature has continually evolved through rigorous experimental validation.

Historical milestones illustrating the development of these core concepts:

  • Transition from Aristotelian to Newtonian Mechanics: Aristotle believed that continuous force was necessary to maintain motion. Newton revolutionized physics by showing that force is required only to change motion (accelerate), introducing the concept of inertia and momentum conservation.
  • Mechanical Equivalence of Heat: Joule's paddle-wheel experiments definitively disproved the caloric fluid theory of heat, demonstrating that mechanical work could be converted directly into thermal energy with an exact conversion factor (1 calorie approx 4.184 Joules).
  • The Wave-Particle Duality and Modern Instrumentation: Classical optical formulations laid the groundwork for James Clerk Maxwell's unified electromagnetic equations, which subsequently enabled Heinrich Hertz's discovery of radio waves and Albert Einstein's photoelectric effect.

By appreciating the historical controversies, discarded theories, and breakthrough experiments that shaped modern science, students gain a deeper epistemological perspective that fosters genuine scientific inquiry.

14. Examination Hall Protocol & Time Management Strategy for Work, Energy and Power

Examination Hall Protocol
Strategic Time Allocation & Stress Management in Board Exams:

In Section A (Compulsory 40 Marks) and Section B (Attempt 4 out of 6 Questions, 40 Marks) of the ICSE Science Examination, strategic pacing dictates academic success:

  • First 15 Minutes (Reading Time): Do not rush to write. Thoroughly read through all questions in Section B and identify the four questions where you possess absolute mastery over every single sub-part. Circle your chosen question numbers clearly.
  • Section A Allocation (45 Minutes): Allocate approximately 1 minute per mark for MCQs, definitions, short reasoning questions, and single-step numericals. Avoid elaborate explanations where only 1 mark is allocated.
  • Section B Allocation (50 Minutes): Spend approximately 12 to 13 minutes per 10-mark question. Structure derivations step-by-step and draw ray diagrams or circuit schematics with sharp pencil and straightedge.
  • Final Revision Window (10 Minutes): Systematically check all mathematical calculations, verify that units are attached to every numerical answer, check that arrows are present on every ray of light, and ensure that question numbers match the paper precisely.

Common Misconceptions & Examiner Traps

Common Misconception

Confusing rate of work (Power) with amount of work (Energy)

Scientific Reality & Correction

Power is energy divided by time (Watts = J/s); energy is total capacity to do work (Joules).

Common Misconception

Calculating work against gravity on a horizontal road

Scientific Reality & Correction

Gravity acts vertically down at 90° to horizontal displacement, so work done by gravity is zero.

Common Misconception

Using kWh as a unit of power

Scientific Reality & Correction

Kilowatt-hour (kWh) is a unit of Energy (Power × Time), not power. Kilowatt (kW) is power.

Common Misconception

Assuming momentum doubles when kinetic energy doubles

Scientific Reality & Correction

p ∝ √K. If K doubles, p increases by a factor of √2 ≈ 1.414, not 2.

Conservation of Mechanical Energy & Work-Energy Theorem

Ground (h=0) Pos A: h=H (Rest) K=0, U=mgH => E=mgH Pos B: fallen x K=mgx, U=mg(H-x) => E=mgH Pos C: Ground strike K=mgH, U=0 => E=mgH H Conservation of Mechanical Energy E_total = K + U = Constant

Chapter Summary & 10 Key Takeaways

Takeaway 1
Work is done when a force causes displacement: W = F·s·cos θ.
Takeaway 2
Work is positive for acute angles, zero for perpendicular forces (θ = 90°), and negative for opposing forces (e.g. friction).
Takeaway 3
No work is done by gravity when a body moves horizontally on a level surface, or by centripetal force in circular motion.
Takeaway 4
The SI unit of work and energy is Joule (J); 1 J = 10^7 ergs.
Takeaway 5
Kilowatt-hour (kWh) is the commercial unit of electrical energy: 1 kWh = 3.6 × 10^6 J = 3.6 MJ.
Takeaway 6
Kinetic energy K = ½mv² = p²/(2m), where p is linear momentum.
Takeaway 7
Gravitational potential energy U = mgh near Earth's surface.
Takeaway 8
Work-Energy theorem states that the net work done on a body equals the change in its kinetic energy: W = ΔK.
Takeaway 9
In a conservative system, total mechanical energy is conserved: E = K + U = constant.
Takeaway 10
Power is the rate of doing work: P = W/t = F·v; its SI unit is Watt (W); 1 horsepower (hp) = 746 W.

Check Your Understanding (Diagnostic Practice Questions)

Diagnostic questions testing core conceptual clarity. Answers are hidden initially — solve each problem first, then click to reveal the step-by-step verified solution.

1
State the condition when the work done by a force is zero, even though both force and displacement are non-zero.
Reveal Answer & Explanation
Answer: When the force is perpendicular to the displacement vector (θ = 90°), cos 90° = 0, so W = F·s·cos 90° = 0. Example: Centripetal force in uniform circular motion.
2
A coolie carrying a 40 kg luggage on his head walks 100 m along a horizontal railway platform. Calculate the work done by the coolie against gravity.
Reveal Answer & Explanation
Answer: Gravity acts vertically downwards while displacement is horizontal (θ = 90°). W = m·g·s·cos 90° = 0 J. Work done against gravity is zero.
3
Derive the mathematical relationship between kinetic energy (K) and linear momentum (p) of a body of mass m.
Reveal Answer & Explanation
Answer: p = mv => v = p/m. Kinetic energy K = ½mv² = ½m(p/m)² = p²/(2m). Alternatively, p = √(2mK).
4
Convert 1 kilowatt-hour into Joules.
Reveal Answer & Explanation
Answer: 1 kWh = 1 kW × 1 h = 1,000 W × 3,600 s = 3,600,000 J = 3.6 × 10⁶ J (or 3.6 MJ).
5
Show that the total mechanical energy of a freely falling body remains constant at all points along its vertical path.
Reveal Answer & Explanation
Answer: At height H: K = 0, U = mgH => E = mgH. After falling x: v² = 2gx => K = mgx, U = mg(H-x) => E = mgx + mg(H-x) = mgH. At ground: v² = 2gH => K = mgH, U = 0 => E = mgH. Thus E is constant everywhere.
6
An electric motor of power 2 kW lifts a mass of 100 kg to a height of 20 m in 10 s. Calculate the efficiency of the motor (g = 10 m/s²).
Reveal Answer & Explanation
Answer: Useful work output = mgh = 100 × 10 × 20 = 20,000 J. Useful power output = W/t = 20,000 / 10 = 2,000 W = 2 kW. Electrical input power = 2 kW. Efficiency η = (Output Power / Input Power) × 100% = (2/2) × 100% = 100% (ideal).
7
What is the horsepower of an engine that performs 37,300 Joules of work in 10 seconds?
Reveal Answer & Explanation
Answer: Power P = W/t = 37,300 J / 10 s = 3,730 W. Since 1 hp = 746 W, Horsepower = 3,730 / 746 = 5 hp.
8
A light body A and a heavy body B have the same kinetic energy. Which body has greater linear momentum?
Reveal Answer & Explanation
Answer: From p = √(2mK), since K is the same, p ∝ √m. Therefore, the heavier body B has greater momentum.
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All Class 10 Science Chapters

Ch 1: Force Ch 2: Work, Energy and Power Ch 3: Machines Ch 4: Refraction of Light at Plane Surfaces Ch 5: Refraction Through a Lens Ch 6: Spectrum Ch 7: Sound Ch 8: Current Electricity Ch 9: Electrical Power and Household Circuits Ch 10: Electromagnetism Ch 11: Calorimetry Ch 12: Radioactivity Ch 13: Periodic Table - Periodic Properties and Variations of Properties Ch 14: Chemical Bonding - Ionic Compounds and Covalent Compounds Ch 15: Study of Acids, Bases and Salts Ch 16: Analytical Chemistry: Uses of Ammonium Hydroxide and Sodium Hydroxide Ch 17: Mole Concept and Stoichiometry Ch 18: Electrolytes, Non-Electrolytes and Electrolysis Ch 19: Metallurgy Ch 20: Study of Compounds - Hydrogen Chloride Ch 21: Study of Compounds - Ammonia and Nitric Acid Ch 22: Sulphuric Acid Ch 23: Organic Chemistry - Hydrocarbons Ch 24: Basic Biology Ch 25: Cell - The Structural and Functional Unit of Life Ch 26: Structure of Chromosomes, Cell Cycle and Cell Division Ch 27: Genetics - Some Basic Fundamentals Ch 28: Absorption by Roots - The Processes Involved Ch 29: Transpiration Ch 30: Photosynthesis - Provider of Food for All Ch 31: Chemical Coordination in Plants Ch 32: The Circulatory System Ch 33: The Excretory System [Elimination of Body Wastes] Ch 34: The Nervous System Ch 35: Sense Organs Ch 36: Endocrine Glands - The Producers of Chemical Messengers Ch 37: The Reproductive System Ch 38: Human Evolution Ch 39: Population - The Increasing Numbers and Rising Problems Ch 40: Pollution - A Rising Environmental Problem Ch 41: Aids to Health Ch 42: Health Organisations

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