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ICSE • Class 6 • Mathematics • Ch 6
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Decimals

Decimals represent one of the most powerful and elegant conceptual breakthroughs in the history of elementary mathematics. In the Council for the Indian School Certificate Examinations (CISCE) curriculum for Class 6, this chapter marks the critical transition from counting discrete whole objects to measuring continuous real-world quantities with arbitrary precision. In the base-ten decimal place value system, every time we move one position to the left, the place value increases by a factor of ten: units become tens, tens become hundreds, and hundreds become thousands. For centuries, this system stopped abruptly at the units place. The conceptual breakthrough of decimal fractions was the realization that the exact same rule could continue indefinitely to the right of the units place, with each successive position representing one-tenth of the value of the place immediately to its left. Thus, moving one step to the right of the units place yields tenths (one-tenth or one divided by ten), the next step yields hundredths (one divided by one hundred), the next yields thousandths (one divided by one thousand), followed by ten-thousandths, hundred-thousandths, and beyond. A decimal numeral consists of three distinct anatomical components: first, the integral part (or whole number part) situated to the left of the decimal separator; second, the decimal point, which is a small period or dot serving as the decisive boundary line between whole units and fractional parts; and third, the decimal fractional part situated to the right of the decimal point. For example, in the decimal numeral twenty-five point seven four, the number twenty-five is the integral part, the dot is the decimal point, and seven tenths plus four hundredths forms the decimal fractional part. It is vital to note that while the whole number part is read as a standard compound numeral (twenty-five), the digits following the decimal point must be read individually as digits (seven four, never seventy-four), because each digit occupies a specific power-of-ten fractional denominator. The place value chart provides the fundamental structural blueprint for understanding and manipulating decimals. Just as a whole number can be expressed in expanded form as the sum of the values of its individual digits, any decimal number can be expanded in two complementary ways: fractional expanded form and decimal expanded form. Taking three hundred seventy-five point four eight two, its fractional expansion is three hundred plus seventy plus five plus four tenths plus eight hundredths plus two thousandths. Its decimal expansion is three hundred plus seventy plus five plus zero point four plus zero point zero eight plus zero point zero zero two. This clear decomposition demystifies the relationship between digits, face values, and place values. Geometric visualization on the number line provides deep intuitive grounding for decimal magnitudes. Just as the distance between zero and one represents one whole unit, dividing that unit into ten equal intervals creates tenths, marked as zero point one, zero point two, up to zero point nine. If the interval between zero point six and zero point seven is magnified and divided into ten further sub-intervals, each tiny step represents one hundredth (zero point zero one), allowing precise location of points like zero point six four. By zooming in successively by powers of ten, any decimal number can be pinpointed with visual clarity. This number line model reveals the golden law of decimal ordering: a decimal number is strictly smaller than another if it lies to the left on the number line, and strictly greater if it lies to the right. A critical distinction in the curriculum is between like decimals and unlike decimals. Decimals that have the exact same number of digits after the decimal point are called like decimals, such as three point four five and twelve point zero eight. Decimals having different numbers of digits after the decimal point are called unlike decimals, such as five point two and eight point seven three nine. Here, the Trailing Zeros Invariance Principle plays a foundational role: appending or annexing zeros at the extreme right end of a decimal part does not alter the numerical value in any way. For example, zero point five is identical in value to zero point five zero, which is identical to zero point five zero zero, because five tenths, fifty hundredths, and five hundred thousandths all represent the exact same fraction (one half). This invariance allows students to effortlessly convert unlike decimals into like decimals by padding trailing zeros, which is an essential prerequisite for vertical column addition, subtraction, and comparison. The bi-directional conversion bridge between fractions and decimals constitutes another major syllabus pillar. Converting a terminating decimal into a vulgar fraction involves writing the numeral without the decimal point as the numerator, and placing a denominator of one followed by as many zeros as there are decimal digits, followed by reducing the resulting fraction to its lowest terms. Conversely, converting vulgar fractions into decimals can be achieved either by finding an equivalent fraction whose denominator is ten, one hundred, or one thousand (such as multiplying three fourths by twenty-five over twenty-five to obtain seventy-five hundredths or zero point seven five), or by using long division to divide the numerator by the denominator, adding decimal places to the dividend as needed. Finally, the arithmetic operations of decimals govern real-world applications across measurement and financial systems. In addition and subtraction, the absolute golden rule is vertical alignment of decimal points: units must align with units, tenths with tenths, and hundredths with hundredths, with trailing zeros padded to avoid place value misalignment. In multiplication, factors are multiplied as standard whole numbers ignoring decimal points, after which the total number of decimal places across all factors is summed, and the decimal point is placed that many digits from the right end of the product. Multiplying or dividing by powers of ten corresponds to dynamic decimal shifts: multiplying by ten shifts the point one place to the right, while dividing by ten shifts the point one place to the left. In decimal division, if the divisor contains decimal places, both dividend and divisor are multiplied by a suitable power of ten to make the divisor an integer before executing standard division. Mastering these principles equips students with the quantitative precision necessary for science, commerce, geometry, and higher secondary mathematics.

Have You Ever Wondered?

When an Olympic sprinter clocks 9.58 seconds in the 100-meter dash, or when a precision laboratory scale measures a chemical sample as 0.0045 grams, or when the petrol pump meter shows 4.825 liters for rupees 463.20, whole numbers completely fail to capture the reality of the physical world. For thousands of years, humans struggled with cumbersome fractions like seven-twelfths or thirty-seven sixty-fourths to express measurements that fell between consecutive whole units. In 1585, Flemish mathematician Simon Stevin published a groundbreaking pamphlet titled De Thiende (The Tenth), demonstrating that the brilliant base-ten Hindu-Arabic place value system—which made whole number addition and multiplication so effortless—could be extended seamlessly to fractions whose denominators are powers of ten. John Napier later introduced the modest decimal dot, and overnight, global commerce, navigation, astronomy, and modern engineering were revolutionized. Decimals are not a separate species of numbers; they are the magnificent natural bridge extending the power of place value into the infinite realm of the fractional world.

Why This Chapter Matters

The mastery of decimals is not merely an academic exercise; it is the universal quantitative language of modern human civilization. Every monetary transaction conducted in commerce, banking, retail, and international finance relies entirely on decimal precision, from calculating sales tax and interest rates to expressing currency conversions between rupees, dollars, and euros. The International System of Units (SI metric system)—the foundation of all global science, industry, medicine, and engineering—is strictly decimal-based. Lengths in millimeters, centimeters, meters, and kilometers; masses in milligrams, grams, and kilograms; and volumes in milliliters and liters all translate seamlessly through powers of ten, making decimal conversion an everyday necessity. In healthcare, a physician calculating a pediatric antibiotic dosage of zero point zero five milligrams per kilogram of body weight depends on exact decimal arithmetic, where an error of a single misplaced decimal point could prove catastrophic. In computer science and digital technology, floating-point numbers govern 3D graphics rendering, GPS coordinates, machine learning algorithms, and aerospace trajectory calculations. By mastering decimal place value, comparison, conversion, and four operations in Class 6, students build the indispensable numerical fluency required for all scientific disciplines, practical life management, and advanced algebraic problem-solving.

Before You Begin (Prerequisites)

  • Familiarity with the Indian and International Place Value systems for whole numbers, including place value, face value, and expanded notation.
  • Clear understanding of common fractions (proper, improper, mixed fractions) and finding equivalent fractions by multiplying or dividing numerator and denominator.
  • Fluency in standard multi-digit whole number arithmetic: addition with carrying, subtraction with borrowing, multiplication, and long division.
  • Concept of a number line and representing whole numbers and simple fractions as points or lengths on a line.
  • Basic exposure to metric units of measurement (rupees and paise, meters and centimeters, kilograms and grams, liters and milliliters).

What You Will Learn (Core Objectives)

  • Explain the conceptual extension of the base-ten place value system to fractional places (tenths, hundredths, thousandths) and identify the anatomy of a decimal number.
  • Read, write, and express decimal numbers in words, standard numeral form, fractional expanded notation, and decimal expanded notation.
  • Plot, identify, and visually interpret decimal numbers on a magnified number line using subdivision into tenths and hundredths.
  • Distinguish between like and unlike decimals and apply the Trailing Zeros Invariance Principle to convert unlike decimals to like decimals without altering value.
  • Compare and order decimal numbers in ascending and descending sequences using systematic left-to-right place value evaluation.
  • Seamlessly convert terminating decimals into vulgar fractions in simplest lowest terms, and convert fractions into decimals using equivalent power-of-ten denominators and long division.
  • Perform vertical column addition and subtraction of decimals with meticulous decimal point alignment, zero padding, and regrouping across decimal boundaries.
  • Multiply and divide decimals by powers of ten via directional point shifting, multiply decimals by whole numbers and decimals, and execute decimal division with real-world applications in money, length, mass, and capacity.

Chapter Roadmap & Progression

1 Module 1: Historical Evolution, Nee...
2 Module 2: The Decadic Place Value C...
3 Module 3: Representation on the Num...
4 Module 4: The Conversion Bridge: De...
5 Module 5: Addition & Subtraction of...
6 Module 6: Multiplication of Decimal...
7 Module 7: Division of Decimals: Pow...

Complete Concept Guide (100% Curriculum Coverage)

Module 1: Historical Evolution, Need for Decimal Fractions & Anatomy of a Decimal Numeral

1.1 The Inadequacy of Whole Numbers & The Decimal Breakthrough

In ordinary counting, we use whole numbers: $1, 2, 3, 4, \dots$ to count discrete individual objects like books, pens, and chairs. However, when we transition from counting objects to measuring continuous quantities—such as the length of a ribbon, the mass of a jewel, the volume of a liquid, or the time taken to run a race—nature rarely conforms to convenient integer amounts.

A pencil might be longer than $14\text{ cm}$ but shorter than $15\text{ cm}$. While vulgar fractions such as $14\frac{7}{10}\text{ cm}$ can express this measurement, performing arithmetic operations like adding, subtracting, multiplying, or comparing fractions with unlike denominators (e.g., comparing $\frac{7}{10}$ with $\frac{18}{25}$ and $\frac{73}{100}$) was historically tedious and error-prone. The invention of decimals solved this universal challenge by extending the genius of the base-10 positional place value system directly into the realm of fractions.

1.2 Historical Milestones: From Ancient India to Simon Stevin & Napier

Ancient Indian Base-10 System

The base-10 positional place value system, using zero and nine digits ($0$ to $9$), originated in India and was transmitted to the Islamic world and Europe. Its inherent symmetry laid the conceptual foundation for fractions with denominators of $10, 100, 1000$.

Simon Stevin (1585: De Thiende)

Flemish mathematician Simon Stevin published De Thiende ("The Tenth"), demonstrating that all calculations with fractions could be performed as easily as whole numbers if fractions were systematized into tenths, hundredths, and thousandths.

John Napier (1617: Decimal Point)

Scottish mathematician John Napier popularized the simple, elegant dot (or period) as the separator between whole numbers and decimal fractions, giving birth to modern decimal notation worldwide.

1.3 The Tripartite Anatomy of a Decimal Numeral

Every decimal number consists of exactly three distinct structural parts:

84.529
Integral / Whole Number Part Decimal Point (Separator) Decimal Fractional Part

1. Integral Part (Whole Number)

Situated to the left of the decimal point. Represents whole units ($0, 1, 2, \dots$). Read as a standard compound numeral: "eighty-four".

2. Decimal Point (.)

The small dot placed on the baseline separating whole units from fractions. Read aloud simply as "point".

3. Decimal Fractional Part

Situated to the right of the decimal point. Represents fractions of a unit (tenths, hundredths, thousandths). Must be read digit-by-digit: "five two nine" (NEVER "five hundred twenty-nine").

⚠️ Critical Pronunciation & Notation Rule

A decimal like $15.48$ must be read as "fifteen point four eight". Saying "fifteen point forty-eight" is mathematically incorrect because the digit $4$ represents four-tenths and $8$ represents eight-hundredths, not forty-eight whole units.

Module 2: The Decadic Place Value Chart & Expanded Form (Tenths, Hundredths, Thousandths)

2.1 The Universal Principle of Positional Place Value

The fundamental axiom of any base-10 system is that each place has a value ten times greater than the place immediately to its right, or conversely, one-tenth ($\frac{1}{10}$) of the place immediately to its left.

$$\text{Thousands} \xrightarrow{\div 10} \text{Hundreds} \xrightarrow{\div 10} \text{Tens} \xrightarrow{\div 10} \text{Ones} \xrightarrow{\div 10} \mathbf{\text{Tenths}} \xrightarrow{\div 10} \mathbf{\text{Hundredths}} \xrightarrow{\div 10} \mathbf{\text{Thousandths}}$$

2.2 Master Decimal Place Value Chart

Whole Number Part (Integral) Separator Decimal Fractional Part
Hundreds Tens Ones (Units) Point Tenths Hundredths Thousandths
$100$ $10$ $1$ . $\frac{1}{10} = 0.1$ $\frac{1}{100} = 0.01$ $\frac{1}{1000} = 0.001$
$4$ $7$ $2$ . $6$ $8$ $3$
$4 \times 100 = 400$ $7 \times 10 = 70$ $2 \times 1 = 2$ - $\frac{6}{10} = 0.6$ $\frac{8}{100} = 0.08$ $\frac{3}{1000} = 0.003$

2.3 Face Value vs Place Value of a Decimal Digit

Just as in whole numbers, every digit in a decimal numeral possesses two distinct values:

Face Value (अंकीय मान)

The absolute intrinsic numerical identity of the digit itself, regardless of where it appears in the numeral. For example, in $472.683$, the face value of $8$ is simply $8$.

Place Value (स्थानीय मान)

$$\text{Place Value} = \text{Face Value} \times \text{Value of the Position}$$ In $472.683$, the digit $8$ is in the hundredths place. Hence its place value is $8 \times \frac{1}{100} = \frac{8}{100} = \mathbf{0.08}$.

2.4 Two Dual Representations of Expanded Notation

Any decimal numeral can be expanded in two standard mathematical notations:

A. Fractional Expanded Form

Expressed using common vulgar fractions for the decimal places:

$$472.683 = 400 + 70 + 2 + \frac{6}{10} + \frac{8}{100} + \frac{3}{1000}$$

B. Decimal Expanded Form

Expressed using pure decimal numbers for each position:

$$472.683 = 400 + 70 + 2 + 0.6 + 0.08 + 0.003$$

Module 3: Representation on the Number Line, Like/Unlike Decimals & Systematic Ordering

3.1 Geometric Representation: Number Line Subdivisions

Just as whole numbers are represented by equidistant points on a line, decimals correspond to precise points lying strictly between consecutive integers:

  1. Tenths Subdivision: To locate a decimal with one decimal place (e.g. $0.7$ or $2.4$), divide the unit distance between consecutive integers into $10$ equal intervals. Each mark represents $\frac{1}{10} = 0.1$. The point $0.7$ is the $7^{\text{th}}$ mark to the right of $0$.
  2. Hundredths Magnification: To locate a decimal with two decimal places (e.g. $0.64$), take the interval between $0.6$ and $0.7$ and subdivide it into $10$ further micro-intervals. Each micro-step represents $\frac{1}{100} = 0.01$. The point $0.64$ is the $4^{\text{th}}$ tick to the right of $0.6$.

3.2 Like vs Unlike Decimals & The Trailing Zeros Invariance Principle

Like Decimals (समान दशमलव)

Decimals having the same number of decimal places (digits after point):

$5.38, \; 19.04, \; 0.72$ (All have 2 places)

Unlike Decimals (असमान दशमलव)

Decimals having different numbers of decimal places:

$4.8$ (1 pl), $\; 12.35$ (2 pl), $\; 0.609$ (3 pl)

⭐ The Trailing Zeros Invariance Principle

Annexing or removing zeros at the extreme right of the decimal part does not change the numerical value of the decimal number.

$$0.7 = 0.70 = 0.700 = \frac{7}{10} = \frac{70}{100} = \frac{700}{1000}$$

Conversion Protocol: To convert unlike decimals to like decimals, identify the maximum number of decimal places and annex trailing zeros to the other decimals until all have an identical count of decimal places.

3.3 The Systematic Algorithm for Comparing Decimals

To compare any two decimal numbers $A$ and $B$, execute this strict left-to-right hierarchy:

Step 1: Compare Integral Parts

The number with the greater whole number part is greater ($15.2 > 9.876$ because $15 > 9$).

Step 2: Compare Tenths

If integral parts are equal, compare tenths ($7.82 > 7.59$ because $8 > 5$).

Step 3: Compare Hundredths

If tenths are equal, compare hundredths ($3.48 > 3.42$ because $8 > 2$).

Step 4: Continue Rightwards

Pad trailing zeros if needed to prevent length bias ($0.5 = 0.50 > 0.09$).

Example: Arrange in Ascending Order (Smallest to Greatest):

Given: $6.4, \; 6.04, \; 6.404, \; 0.64$

1. Convert to like decimals (3 places): $6.400, \; 6.040, \; 6.404, \; 0.640$
2. Compare: $0.640 < 6.040 < 6.400 < 6.404$
3. Final Ascending Order: $0.64 < 6.04 < 6.4 < 6.404$

Module 4: The Conversion Bridge: Decimals ↔ Vulgar Fractions & Benchmark Equivalents

4.1 Converting Terminating Decimals into Vulgar Fractions in Lowest Terms

Converting any finite (terminating) decimal into a common fraction is a mechanical three-step process rooted in place value:

  1. Numerator: Write the entire numeral without the decimal point as the numerator. (Drop any leading zeros unless they are part of the value).
  2. Denominator: Write $1$ followed by as many zeros as there are decimal places (digits to the right of the point).
  3. Simplification: Divide both numerator and denominator by their Highest Common Factor (HCF) to express the fraction in its irreducible simplest form.
Example 1: Single Place (Tenths)
$$0.6 = \frac{6}{10} = \frac{6 \div 2}{10 \div 2} = \mathbf{\frac{3}{5}}$$
Example 2: Two Places (Hundredths)
$$0.75 = \frac{75}{100} = \frac{75 \div 25}{100 \div 25} = \mathbf{\frac{3}{4}}$$
Example 3: Three Places (Thousandths)
$$2.125 = 2\frac{125}{1000} = 2\frac{125 \div 125}{1000 \div 125} = \mathbf{2\frac{1}{8}}$$

4.2 Converting Vulgar Fractions into Decimals (Two Standard Pathways)

Pathway 1: Equivalent Denominator Method

Applicable whenever the denominator has prime factors of only $2$ and/or $5$. Multiply numerator and denominator to convert denominator to $10, 100,$ or $1000$:

  • $2 \times 5 = 10$
  • $4 \times 25 = 100$
  • $8 \times 125 = 1000$
  • $20 \times 5 = 100$
$$\frac{7}{8} = \frac{7 \times 125}{8 \times 125} = \frac{875}{1000} = \mathbf{0.875}$$

Pathway 2: Long Division Method

The universal method for any fraction. Divide the numerator by the denominator:

  1. If numerator is smaller, place a decimal point in the quotient and annex a zero to the dividend.
  2. Continue standard long division, annexing zeros to remainders until remainder is zero.
$$5 \div 8 \implies 5.000 \div 8 = \mathbf{0.625}$$

4.3 Essential Benchmark Equivalents (Board Exam Memory Bank)

Memorizing these common fractions and their decimal values provides immediate speed in exams:

Halves Fourths (Quarters) Fifths Eighths
$\frac{1}{2} = 0.5$ $\frac{1}{4} = 0.25$ $\frac{1}{5} = 0.2$ $\frac{1}{8} = 0.125$
- $\frac{2}{4} = 0.5$ $\frac{2}{5} = 0.4$ $\frac{3}{8} = 0.375$
- $\frac{3}{4} = 0.75$ $\frac{3}{5} = 0.6$ $\frac{5}{8} = 0.625$
- - $\frac{4}{5} = 0.8$ $\frac{7}{8} = 0.875$

Module 5: Addition & Subtraction of Decimals: Precision Column Alignment & Real-World Metric Applications

5.1 The Cardinal Rule: Vertical Decimal Point Alignment

The single most crucial requirement in adding or subtracting decimals is that digits of identical place values must reside in the exact same vertical column.

Step-by-Step Vertical Addition Protocol:

  1. Step 1 (Convert to Like Decimals): Check the maximum number of decimal places among all addends. Annex trailing zeros to all other numbers so that every number has the exact same count of decimal places.
  2. Step 2 (Vertical Placement): Write the numbers one beneath the other such that all decimal points form a perfectly straight vertical line.
  3. Step 3 (Execute Arithmetic): Add or subtract column-by-column from right to left, carrying over or borrowing across the decimal point exactly as in standard whole numbers.
  4. Step 4 (Place Point): Bring the decimal point directly downward into the sum or difference line.
Addition: $18.4 + 9.075 + 125.62$
    018.400  (pad zeros)
  + 009.075
  + 125.620
  ─────────
  = 153.095
Subtraction: Subtract $14.865$ from $20.3$
    20.300  (pad zeros to borrow)
  - 14.865
  ─────────
  = 05.435

5.2 Real-World Metric Measurement Conversion Matrix

Because the SI metric system is purely base-10, converting smaller units to larger units is executed by writing decimals with appropriate power-of-10 denominators:

Domain Fundamental Metric Identity Decimal Conversion Formula Board Exam Example
Money $₹1 = 100\text{ paise}$ $1\text{ paisa} = ₹\frac{1}{100} = ₹0.01$ $₹45\text{ and } 7\text{ paise} = ₹45.07$ (NOT ₹45.7)
Length (cm to m) $1\text{ m} = 100\text{ cm}$ $1\text{ cm} = \frac{1}{100}\text{ m} = 0.01\text{ m}$ $3\text{ m } 45\text{ cm} = 3.45\text{ m}$
Length (m to km) $1\text{ km} = 1000\text{ m}$ $1\text{ m} = \frac{1}{1000}\text{ km} = 0.001\text{ km}$ $8\text{ km } 65\text{ m} = 8.065\text{ km}$
Mass (g to kg) $1\text{ kg} = 1000\text{ g}$ $1\text{ g} = \frac{1}{1000}\text{ kg} = 0.001\text{ kg}$ $5\text{ kg } 8\text{ g} = 5.008\text{ kg}$

Module 6: Multiplication of Decimals: Powers of 10 Shifts & The Product Decimal Places Summation Law

6.1 Multiplying by Powers of 10: Dynamic Rightward Decimal Shifts

Multiplying a decimal by $10, 100, 1000, \dots$ requires no standard multi-digit multiplication algorithm whatsoever!

Rule of Rightward Decimal Shift:

To multiply a decimal number by $10^n$, shift the decimal point to the RIGHT by exactly $n$ places (equal to the number of zeros in the multiplier). If there are insufficient digits, annex trailing zeros.

• $3.456 \times 10 = \mathbf{34.56}$ (1 zero → 1 place right)
• $3.456 \times 100 = \mathbf{345.6}$ (2 zeros → 2 places right)
• $3.456 \times 1000 = \mathbf{3456}$ (3 zeros → 3 places right)
• $3.456 \times 10000 = \mathbf{34560}$ (pad 1 zero)

6.2 The General Algorithm for Multiplying Decimals

To multiply two decimal numbers (or a decimal by a whole number), execute these three sequential steps:

Step 1: Multiply as Whole Numbers

Ignore the decimal points completely and multiply the numbers as if they were ordinary positive integers.

Step 2: Sum the Decimal Places

Count the number of decimal places in the first factor ($d_1$) and the second factor ($d_2$). Total places = $d_1 + d_2$.

Step 3: Insert Decimal Point from Right

Starting at the extreme right digit of the product, count leftwards by $(d_1 + d_2)$ places and insert the decimal point. If insufficient digits, prefix zeros.

Worked Example: Evaluate $0.35 \times 0.04$

• Whole number multiplication: $35 \times 4 = 140$
• Decimal places in $0.35 = 2$; decimal places in $0.04 = 2$
• Total decimal places required in product = $2 + 2 = \mathbf{4\text{ places}}$
• Counting 4 places from right of $140$: we must prefix a zero → $0.0140 = \mathbf{0.014}$

Module 7: Division of Decimals: Powers of 10 Shifts, Whole Number Divisors & Real-World Modeling

7.1 Dividing by Powers of 10: Dynamic Leftward Decimal Shifts

Division by $10, 100, 1000, \dots$ is the exact geometric inverse of multiplication:

Rule of Leftward Decimal Shift:

To divide a decimal number by $10^n$, shift the decimal point to the LEFT by exactly $n$ places (equal to the number of zeros in the divisor). If there are insufficient digits, prefix zeros.

• $48.5 \div 10 = \mathbf{4.85}$ (1 zero → 1 place left)
• $48.5 \div 100 = \mathbf{0.485}$ (2 zeros → 2 places left)
• $48.5 \div 1000 = \mathbf{0.0485}$ (prefix zero)
• $7 \div 1000 = \mathbf{0.007}$ (3 places left)

7.2 Division of a Decimal by another Decimal (Clearing the Divisor)

We cannot easily perform long division when the divisor is a decimal. Therefore, we utilize the fundamental property of fractions: multiplying both dividend and divisor by the exact same non-zero number leaves the quotient unchanged.

The Divisor Integerization Protocol:

  1. Count the number of decimal places in the divisor ($k$ places).
  2. Multiply both the dividend and the divisor by $10^k$. This shifts the decimal point $k$ places to the right in both numbers, converting the divisor into an integer!
  3. Divide the new dividend by the new integer divisor using standard decimal long division.

Worked Example: Evaluate $25.5 \div 0.15$

• The divisor $0.15$ has $2$ decimal places. Multiply both numbers by $100$:
$$\frac{25.5}{0.15} = \frac{25.5 \times 100}{0.15 \times 100} = \frac{2550}{15}$$
• Now execute whole number division: $2550 \div 15 = \mathbf{170}$.

7.3 Real-World Application Case Study

Context: Cost, Consumption & Rate Analysis

A car travels a total distance of $324.8\text{ km}$ on $14.5\text{ liters}$ of petrol. If petrol costs $₹102.50$ per liter, find: (a) the mileage (distance covered per liter), and (b) the total cost incurred for the entire journey.

(a) Mileage: $324.8 \div 14.5 = \frac{3248}{145} = \mathbf{22.4\text{ km per liter}}$
(b) Total Cost: $14.5 \times 102.50 = 14.5 \times 102.5 = \mathbf{₹1,486.25}$

Key Formulas, Identities & Theorems

Base-10 Fractional Place Value Formula
$$\text{Place Value} = \text{Face Value} \times \frac{1}{10^k} = \text{Face Value} \times 10^{-k}$$
Trailing Zeros Invariance Principle
$$0.a_1 a_2 \dots a_k = 0.a_1 a_2 \dots a_k \underbrace{00\dots 0}_{m \text{ zeros}} = \frac{a_1 a_2 \dots a_k}{10^k}$$
Terminating Decimal to Vulgar Fraction Reduction Formula
$$N.d_1 d_2 \dots d_k = \frac{\text{Number without decimal point}}{10^k} = \frac{(N \times 10^k) + \sum_{i=1}^k d_i 10^{k-i}}{10^k}$$
Equivalent Denominator Power-of-10 Conversion Formula
$$\frac{a}{2^m \times 5^n} = \frac{a \times 2^{k-m} \times 5^{k-n}}{10^k} \quad \text{where } k = \max(m, n)$$
SI Metric Unit Decimal Conversion Identity
$$\text{Value in Larger Unit} = \frac{\text{Value in Smaller Unit}}{10^p} \quad (p = 2 \text{ for m/cm, paise/₹}; p = 3 \text{ for km/m, kg/g, L/mL})$$
Powers of 10 Decimal Shift Principle
$$x \times 10^n \implies \text{Shift Point } n \text{ Places Right}; \quad x \div 10^n \implies \text{Shift Point } n \text{ Places Left}$$
Product Decimal Places Summation Law
$$\text{Decimal Places in Product} = \text{DecPlaces}(A) + \text{DecPlaces}(B)$$
Divisor Integerization Principle (Quotient Invariance)
$$\frac{A}{B} = \frac{A \times 10^k}{B \times 10^k} \quad \text{where } k = \text{DecPlaces}(B)$$

Conceptual Solved Examples & Case Studies

Example 1
In the decimal numeral $745.385$, write the expanded form in both fractional and decimal formats. Also find the difference between the place values of the two fives appearing in this number.
Step-by-Step Solution:

Step 1: Writing the Expanded Forms:
• Fractional Expanded Form:

$$745.385 = 700 + 40 + 5 + \frac{3}{10} + \frac{8}{100} + \frac{5}{1000}$$


• Decimal Expanded Form:

$$745.385 = 700 + 40 + 5 + 0.3 + 0.08 + 0.005$$



Step 2: Identifying Place Values of the Two Fives:
• The first $5$ is in the ones place: $\text{Place value} = 5 \times 1 = 5.000$
• The second $5$ is in the thousandths place: $\text{Place value} = 5 \times \frac{1}{1000} = 0.005$

Step 3: Calculating the Difference:
Aligning decimal points and subtracting:

$$\begin{array}{r@{\quad}l} 5.000 & \\ - 0.005 & \\ \hline \mathbf{4.995} & \end{array}$$



Final Answer:
The difference between the place values of the two fives is $4.995$.

Example 2
(a) Convert the decimal $3.075$ into a mixed fraction in its simplest lowest terms.\n(b) Convert the mixed fraction $4\frac{7}{16}$ into an exact terminating decimal numeral.
Step-by-Step Solution:
Part (a): Converting $3.075$ into Lowest Terms:
$3.075$ has $3$ decimal places, so the denominator is $1000$:
$$3.075 = 3 + 0.075 = 3\frac{75}{1000}$$
Finding the HCF of $75$ and $1000$: both are divisible by $25$:
$$\frac{75 \div 25}{1000 \div 25} = \frac{3}{40}$$
Thus, in simplest form:
$$3.075 = \mathbf{3\frac{3}{40}} \quad \left(\text{or } \frac{123}{40}\right)$$

Part (b): Converting $4\frac{7}{16}$ into a Decimal:
The whole number part is $4$. We convert the fractional part $\frac{7}{16}$ into a decimal.
Since $16 = 2^4$, we multiply numerator and denominator by $5^4 = 625$ to achieve a power-of-10 denominator ($10^4 = 10000$):
$$\frac{7}{16} = \frac{7 \times 625}{16 \times 625} = \frac{4375}{10000} = 0.4375$$
Combining with the integral part $4$:
$$4 + 0.4375 = \mathbf{4.4375}$$

Final Answer:
(a) $3.075 = \mathbf{3\frac{3}{40}}$
(b) $4\frac{7}{16} = \mathbf{4.4375}$
Example 3
Given the set of unlike decimals: $\{ 5.6, \; 5.06, \; 5.606, \; 0.56, \; 5.066 \}$.\n(a) Convert them to like decimals.\n(b) Arrange them in ascending order.\n(c) Find the difference between the greatest and smallest decimal numbers in the set.
Step-by-Step Solution:

Part (a): Converting to Like Decimals:
The maximum number of decimal places is $3$ (in $5.606$ and $5.066$).
Padding trailing zeros using the Trailing Zeros Invariance Principle:
• $5.6 \implies 5.600$
• $5.06 \implies 5.060$
• $5.606 \implies 5.606$
• $0.56 \implies 0.560$
• $5.066 \implies 5.066$

Part (b): Arranging in Ascending Order:

  1. Comparing integral parts: $0.560$ has integral part $0$, while the others have $5$. Hence $0.560$ is smallest.
  2. Comparing the decimals with integral part $5$:
    Tenths: $5.060$ and $5.066$ have tenths digit $0$; $5.600$ and $5.606$ have tenths digit $6$.
    Hundredths and thousandths: $5.060 < 5.066$ and $5.600 < 5.606$.
  3. Sequence: $0.560 < 5.060 < 5.066 < 5.600 < 5.606$.
    Writing in original form:

$$\mathbf{0.56 < 5.06 < 5.066 < 5.6 < 5.606}$$



Part (c): Difference between Greatest and Smallest:
• Greatest number: $5.606$
• Smallest number: $0.560$

$$\begin{array}{r@{\quad}l} 5.606 & \\ - 0.560 & \\ \hline \mathbf{5.046} & \end{array}$$



Final Answer:
(a) Like decimals: $5.600, \; 5.060, \; 5.606, \; 0.560, \; 5.066$
(b) Ascending Order: $0.56 < 5.06 < 5.066 < 5.6 < 5.606$
(c) Difference = $5.046$

Example 4
A tailor bought three rolls of fabric for school uniforms:\n• Roll 1 measured $18\text{ m } 75\text{ cm}$\n• Roll 2 measured $24\text{ m } 8\text{ cm}$\n• Roll 3 measured $15\text{ m } 4\text{ mm}$\n(a) Express the length of each roll in meters using decimal notation.\n(b) Find the total length of fabric purchased in meters.\n(c) If the tailor used $42\text{ m } 65\text{ cm } 8\text{ mm}$ of fabric to stitch shirts, how much fabric is left?
Step-by-Step Solution:

Part (a): Expressing Lengths in Meters using Decimals:
Metric identities: $1\text{ cm} = 0.01\text{ m}$ and $1\text{ mm} = 0.001\text{ m}$.
• Roll 1: $18\text{ m } 75\text{ cm} = 18 + \frac{75}{100} = \mathbf{18.750\text{ m}}$
• Roll 2: $24\text{ m } 8\text{ cm} = 24 + \frac{8}{100} = \mathbf{24.080\text{ m}}$ (Note: 8 cm = 0.08 m, NOT 0.8 m)
• Roll 3: $15\text{ m } 4\text{ mm} = 15 + \frac{4}{1000} = \mathbf{15.004\text{ m}}$

Part (b): Total Length of Fabric Purchased:
Aligning decimal points vertically with 3 decimal places:

$$\begin{array}{r@{\quad}l} 18.750 & \text{m} \\ + 24.080 & \text{m} \\ + 15.004 & \text{m} \\ \hline \mathbf{57.834} & \text{m} \end{array}$$


Total fabric purchased = $57.834\text{ m}$.

Part (c): Fabric Left after Stitching:
• Fabric used: $42\text{ m } 65\text{ cm } 8\text{ mm} = 42 + 0.65 + 0.008 = \mathbf{42.658\text{ m}}$
Subtracting fabric used from total fabric:

$$\begin{array}{r@{\quad}l} 57.834 & \text{m} \\ - 42.658 & \text{m} \\ \hline \mathbf{15.176} & \text{m} \end{array}$$


Converting $15.176\text{ m}$ back to compound metric units: $15\text{ m } 17\text{ cm } 6\text{ mm}$.

Final Answer:
(a) Roll 1 = $18.75\text{ m}$, Roll 2 = $24.08\text{ m}$, Roll 3 = $15.004\text{ m}$
(b) Total fabric purchased = $57.834\text{ m}$
(c) Fabric remaining = $15.176\text{ m}$ ($15\text{ m } 17\text{ cm } 6\text{ mm}$)

Example 5
Evaluate the following with complete step-by-step working:\n(a) $0.048 \times 10000$\n(b) $3.25 \times 0.064$\n(c) A rectangular playground has length $48.75\text{ meters}$ and breadth $24.8\text{ meters}$. Find its perimeter and area.
Step-by-Step Solution:

Part (a): Evaluating $0.048 \times 10000$:
The multiplier $10000$ has $4$ zeros. Shift the decimal point $4$ places to the right:

$$0.048 \times 10000 = 00480. = \mathbf{480}$$



Part (b): Evaluating $3.25 \times 0.064$:

  1. Multiply as whole numbers: $325 \times 64$

$$325 \times 64 = 325 \times (60 + 4) = 19500 + 1300 = 20800$$


2. Count total decimal places:
• Decimal places in $3.25 = 2$
• Decimal places in $0.064 = 3$
• Total places required $= 2 + 3 = 5\text{ places}$
3. Count 5 digits from the right of $20800$:

$$20800 \implies 0.20800 = \mathbf{0.208}$$



Part (c): Playground Perimeter and Area:
Given: Length $l = 48.75\text{ m}$, Breadth $b = 24.8\text{ m}$.

  1. Perimeter: $P = 2 \times (l + b)$

$$l + b = 48.75 + 24.80 = 73.55\text{ m}$$


$$P = 2 \times 73.55 = \mathbf{147.1\text{ m}}$$


2. Area: $A = l \times b = 48.75 \times 24.8$
Multiply whole numbers: $4875 \times 248 = 1,209,000$
Total decimal places: $2 + 1 = 3\text{ places}$

$$A = 1209.000 = \mathbf{1209\text{ sq meters } (\text{m}^2)}$$



Final Answer:
(a) $0.048 \times 10000 = \mathbf{480}$
(b) $3.25 \times 0.064 = \mathbf{0.208}$
(c) Perimeter = $147.1\text{ m}$; Area = $1209\text{ m}^2$

Example 6
A transport van loaded with 28 identical crates of machine spare parts travels from Mumbai to Pune.\n• The gross total weight of all 28 crates combined is $394.8\text{ kg}$.\n• The total distance between the warehouses is $148.8\text{ km}$.\n• The van consumed $12.4\text{ liters}$ of diesel for the entire one-way trip.\n• Diesel costs $₹94.50$ per liter.\n(a) Find the weight of one crate in kilograms.\n(b) Find the vehicle's fuel efficiency (mileage in km per liter of diesel).\n(c) Find the quantity of diesel needed to travel $1\text{ km}$.\n(d) Calculate the total expenditure incurred on diesel for the trip.
Step-by-Step Solution:

Part (a): Weight of One Crate:
Total weight = $394.8\text{ kg}$ for $28$ crates.

$$\text{Weight per crate} = 394.8 \div 28$$


Executing division:
• $39 \div 28 = 1$ with remainder $11$
• Bring down $4$: $114 \div 28 = 4$ with remainder $2$ ($28 \times 4 = 112$)
• Place decimal point in quotient and bring down $8$: $28 \div 28 = 1$

$$\text{Weight per crate} = \mathbf{14.1\text{ kg}}$$



Part (b): Vehicle Fuel Efficiency (Mileage in km/L):
Distance = $148.8\text{ km}$, Fuel consumed = $12.4\text{ L}$.

$$\text{Mileage} = \frac{148.8}{12.4}$$


The divisor $12.4$ has $1$ decimal place. Multiply numerator and denominator by $10$ to clear the divisor:

$$\frac{148.8 \times 10}{12.4 \times 10} = \frac{1488}{124}$$


Dividing $1488$ by $124$:
• $148 \div 124 = 1$ with remainder $24$
• Bring down $8$: $248 \div 124 = 2$

$$\text{Mileage} = \mathbf{12\text{ km per liter}}$$



Part (c): Quantity of Diesel Needed to Travel $1\text{ km}$:

$$\text{Diesel per km} = \frac{\text{Fuel consumed}}{\text{Total distance}} = \frac{12.4}{148.8} = \frac{124}{1488}$$


Alternatively, since mileage is $12\text{ km/L}$, diesel per km is $\frac{1}{12}\text{ L}$:

$$1 \div 12 = 0.0833\dots\text{ L} \approx \mathbf{0.083\text{ liters per km}}$$



Part (d): Total Cost of Diesel for the Trip:
Total diesel = $12.4\text{ liters}$, Cost per liter = $₹94.50 = ₹94.5$.

$$\text{Total cost} = 12.4 \times 94.5$$


1. Multiply as whole numbers: $124 \times 945$

$$124 \times 945 = 124 \times (900 + 40 + 5) = 111600 + 4960 + 620 = 117180$$


2. Sum of decimal places: $1 + 1 = 2\text{ places}$
3. Insert decimal point $2$ places from right:

$$117180 \implies 1171.80$$


$$\text{Total cost} = \mathbf{₹1,171.80}$$



Final Summary Answers:
(a) Weight of one crate = $14.1\text{ kg}$
(b) Fuel efficiency = $12\text{ km/L}$
(c) Diesel per kilometer = $\frac{1}{12}\text{ L} \approx 0.083\text{ L}$
(d) Total fuel expenditure = $₹1,171.80$

Common Misconceptions & Examiner Traps

Common Misconception

Reading the fractional part as a compound number (e.g. reading 15.48 as 'fifteen point forty-eight').

Scientific Reality & Correction

15.48 must strictly be read as 'fifteen point four eight'.

Common Misconception

Suffering from 'length bias' in decimal comparison (e.g. assuming 0.089 is greater than 0.4 because 89 is greater than 4).

Scientific Reality & Correction

0.4 is strictly greater than 0.089 (0.4 > 0.089).

Common Misconception

Misaligning decimal numbers vertically by right-aligning digits rather than lining up decimal points.

Scientific Reality & Correction

Always vertically align the decimal points (.) directly above each other before adding or subtracting.

Common Misconception

Neglecting leading zeros in multiplication products (e.g. writing 0.2 × 0.3 = 0.6 instead of 0.06).

Scientific Reality & Correction

0.2 × 0.3 = 0.06 (requiring 1 + 1 = 2 decimal places).

Common Misconception

Failing to multiply the dividend by the same power of 10 when clearing the divisor's decimal point in division.

Scientific Reality & Correction

In 36 ÷ 0.04, multiply BOTH numbers by 100 to get 3600 ÷ 4 = 900 (NOT 36 ÷ 4 = 9).

Common Misconception

Metric place-value conversion blunders (e.g. writing ₹7 and 5 paise as ₹7.5 instead of ₹7.05, or 4 km 25 m as 4.25 km instead of 4.025 km).

Scientific Reality & Correction

₹7 and 5 paise = ₹7.05; 4 km 25 m = 4.025 km.

Visual Learning & Conceptual Map

ICSE Class 6 Mathematics • Decimals (Place Value, Operations & Conversion) Base-10 Fractional Extension • Place Value Grid • Number Line Magnification • Like & Unlike Decimals • Four Operations CISCE / ICSE CLASS 6 1. Base-10 Decimal Place Value Architecture & Expanded Notation Hundreds (100) 3 3 × 100 = 300 Tens (10) 7 7 × 10 = 70 Ones / Units (1) 5 5 × 1 = 5 POINT SEP (.) Tenths (1/10 = 0.1) 4 4/10 = 0.4 Hundredths (1/100 = 0.01) 8 8/100 = 0.08 Thousandths (1/1000) 2 2/1000 = 0.002 Expanded Notation: 375.482 = 300 + 70 + 5 + 0.4 + 0.08 + 0.002 = 300 + 70 + 5 + (4/10) + (8/100) + (2/1000) 2. Number Line Magnification Level 1: Interval [0 to 1] in Tenths (0.1) 0 0.6 1 ZOOM [0.6 to 0.7] Level 2: Hundredths Grid (0.01 steps) 0.60 0.64 0.70 Trailing Zeros Invariance Principle: 0.5 = 0.50 = 0.500 = 5/10 = 1/2 • Adding zeros at extreme right after decimal point   does NOT alter the value of the decimal! • Essential tool to convert Unlike → Like decimals. 3. Decimal ↔ Fraction Conversion A. Decimal → Vulgar Fraction 0.75 = 75/100 ÷ 25/25 = 3/4 • Write number without point as numerator. • Put 1 followed by N zeros in denominator. Reduce! B. Fraction → Decimal (Equivalent Method) 3/8 = (3 × 125) / (8 × 125) = 375/1000 = 0.375 • Convert denominator to 10, 100, or 1000:   2 × 5 = 10 | 4 × 25 = 100 | 8 × 125 = 1000 • Or use long division if denominator is not 2 or 5. Key Benchmark Equivalents (Memory Bank): 1/2 = 0.5 1/4 = 0.25 3/4 = 0.75 1/5 = 0.2 2/5 = 0.4 4/5 = 0.8 1/8 = 0.125 3/8 = 0.375 5/8 = 0.625 4. Decimal Operations & Shift Laws 1. Column Addition / Subtraction Rule:   12.350 ← Pad zero to like decimal +  4.082 ← Align points vertically   16.432 2. Multiplication Decimal Places Law: 0.24 (2 pl) × 0.3 (1 pl) = 0.072 (3 pl) • Multiply as whole numbers: 24 × 3 = 72. • Total places = 2 + 1 = 3 places → insert 0 to get 0.072. 3. Powers of 10 Decimal Shift Rules: MULTIPLICATION (× 10ⁿ) → SHIFT RIGHT 4.275 × 100 = 427.5 (2 zeroes → 2 places right) DIVISION (÷ 10ⁿ) → SHIFT LEFT 427.5 ÷ 100 = 4.275 (2 zeroes → 2 places left) 💡 Divisor with decimal: Multiply both by 10ⁿ to clear divisor! TargetExams Master Study Material • CISCE / ICSE Class 6 Mathematics • Decimals Comprehensive Guide www.targetexams.com

Chapter Summary & 10 Key Takeaways

Takeaway 1
A decimal numeral is an extension of the base-10 positional place value system to fractions whose denominators are powers of ten (10, 100, 1000, etc.).
Takeaway 2
Every decimal number consists of three structural components: the integral (whole number) part, the decimal point (separator dot), and the decimal fractional part.
Takeaway 3
In the decimal place value chart, positions to the right of the units place are tenths (1/10 = 0.1), hundredths (1/100 = 0.01), and thousandths (1/1000 = 0.001).
Takeaway 4
Decimals can be expanded in two equivalent formats: fractional expanded notation (using fractions with powers-of-10 denominators) and decimal expanded notation.
Takeaway 5
On the number line, decimals are located by dividing the unit interval between consecutive integers into 10 equal tenths, and subdividing tenths into 10 equal hundredths.
Takeaway 6
Like decimals have an equal number of decimal places, while unlike decimals have differing numbers of decimal places.
Takeaway 7
The Trailing Zeros Invariance Principle states that annexing or removing zeros at the extreme right end of a decimal part does not change its numerical value (e.g., 0.6 = 0.60 = 0.600).
Takeaway 8
To convert a terminating decimal into a fraction, write the digits without the point over 1 followed by as many zeros as decimal places, and reduce to simplest form using the HCF.
Takeaway 9
In column addition and subtraction, decimal points must align vertically in a straight line, and unlike decimals should be converted to like decimals by zero-padding.
Takeaway 10
In multiplication, sum the decimal places of all factors to insert the point in the product; in division, multiply both dividend and divisor by a power of 10 to clear any decimal places in the divisor.

Check Your Understanding (Diagnostic Practice Questions)

Diagnostic questions testing core conceptual clarity. Answers are hidden initially — solve each problem first, then click to reveal the step-by-step verified solution.

1
Write the decimal numeral for: 'Seven hundred six and thirty-five thousandths'. Also write its decimal expanded form.
Reveal Answer & Explanation
Answer: Numeral = 706.035. Decimal expanded form = 700 + 6 + 0.03 + 0.005.
Hundreds = 7, Tens = 0, Ones = 6. Thousandths has 3 decimal places (0 tenths, 3 hundredths, 5 thousandths).
2
Convert the unlike decimals 4.5, 0.72, and 12.008 into like decimals.
Reveal Answer & Explanation
Answer: Like decimals: 4.500, 0.720, and 12.008.
Identify the maximum decimal places (3 places in 12.008) and pad trailing zeros to the other numbers.
3
Convert the vulgar fraction 17/40 into an exact terminating decimal without using long division.
Reveal Answer & Explanation
Answer: (17 × 25) / (40 × 25) = 425 / 1000 = 0.425.
Since 40 = 2^3 × 5, multiply numerator and denominator by 5^2 = 25 to achieve a denominator of 1000.
4
Subtract 28.675 from 45.2. Show your vertical working with like decimals.
Reveal Answer & Explanation
Answer: 45.200 - 28.675: Aligning columns and borrowing yields 16.525.
Convert 45.2 to 45.200 before borrowing across the decimal point.
5
Find the product: 0.12 × 0.05 × 0.4.
Reveal Answer & Explanation
Answer: Total places = 5. Prefixing zeros to 240 gives 0.00240 = 0.0024.
Multiply whole numbers 12 × 5 × 4 = 240. Count total decimal places: 2 + 2 + 1 = 5 places.
6
A stack of 35 identical mathematics notebooks has a total thickness of 59.5 cm. Find the thickness of a single notebook in millimeters.
Reveal Answer & Explanation
Answer: 59.5 ÷ 35 = 1.7 cm. In millimeters: 1.7 × 10 = 17 mm.
Divide 59.5 by 35 to find thickness in cm, then multiply by 10 to convert to mm.
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