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ICSE • Class 9 • Science • Ch 3
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Laws of Motion

In ICSE Class 9 Physics, "Laws of Motion" represents the monumental foundation of classical Newtonian mechanics, connecting kinematic motion with its dynamical causes—forces. A force is an external agent (push or pull) that changes or tends to change the state of rest, uniform motion, direction, or dimensions of a body. The chapter rigorously develops Sir Isaac Newton's three laws of motion: (1) Newton's First Law of Motion (The Law of Inertia), defining force qualitatively: "A body continues in its state of rest or of uniform motion in a straight line unless compelled by an external unbalanced force to change that state." Inertia is the inherent resistance of a body to any change in its velocity, quantitatively measured strictly by its mass ($m$); the three forms of inertia (inertia of rest, inertia of motion, inertia of direction) are analyzed with daily-life examples. (2) Linear Momentum ($p = mv$) and Newton's Second Law of Motion, defining force quantitatively: "The rate of change of momentum of a body is directly proportional to the applied unbalanced force and takes place in the direction of the force": $F \propto \frac{\Delta p}{\Delta t} \implies F = kma$ (where $k = 1$ in SI units, yielding $\mathbf{F = ma}$). One Newton ($1\text{ N}$) is formally defined as the force which produces an acceleration of $1\text{ m/s}^2$ in a mass of $1\text{ kg}$ ($1\text{ N} = 10^5\text{ dynes}$). Impulsive forces ($J = F \times \Delta t = \Delta p$) explain why cricket fielders pull their hands backwards while catching a fast ball. (3) Newton's Third Law of Motion: "To every action, there is always an equal and opposite reaction" ($F_{AB} = -F_{BA}$); action and reaction act simultaneously on two different bodies and never cancel out. The chapter culminates in Newton's Universal Law of Gravitation ($F = G\frac{m_1m_2}{r^2}$), the difference between Mass (scalar, constant) and Weight ($W = mg$, vector, variable), free fall, and apparent weightlessness.

The Apple That Shook the Cosmos: How Newton Connected Falling Fruit to the Moon's Eternal Orbit

In the autumn of 1666, as the Great Plague forced the University of Cambridge to shut its doors, a 23-year-old student named Isaac Newton was sitting in his mother's garden at Woolsthorpe Manor in Lincolnshire. As he watched a ripe apple drop from a tree branch to the ground, Newton asked a question that nobody in human history had ever dared to ask: *"If the gravitational pull of the Earth reaches up to the highest apple tree, could that exact same invisible force reach all the way up to the Moon?"* Newton realized that the Moon is not floating peacefully in space; it is in continuous free fall toward Earth! Why doesn't the Moon crash into our heads? Because it is moving sideways so fast that as it falls, the curved surface of the Earth curves away underneath it at the exact same rate! With three simple mathematical laws—inertia, $F=ma$, and action-reaction—Newton united the falling of an apple with the orbits of the planets and the tides of the oceans! How do seatbelts save lives through inertia? Why do rockets fly in the vacuum of space? Let us explore Newton's laws of motion!

Why This Chapter Matters

Newton's laws govern all vehicular safety design (airbags, crumple zones), rocket propulsion, satellite launch trajectories, elevator engineering, sports athletics, and planetary astrophysics.

Before You Begin (Prerequisites)

  • Kinematics concepts from Chapter 2: velocity, acceleration, and equations of motion.
  • Basic vectors and free-body force arrows.

What You Will Learn (Core Objectives)

  • State and explain Newton's First Law of Motion and define inertia and mass.
  • Distinguish between inertia of rest, motion, and direction with practical examples.
  • Define linear momentum and derive the fundamental equation of motion $F = ma$ from Newton's Second Law.
  • Define the SI unit of force (Newton) and CGS unit (dyne) and prove $1\text{ N} = 10^5\text{ dynes}$.
  • State Newton's Third Law of Motion and identify action-reaction force pairs on interacting bodies.
  • State the Universal Law of Gravitation and differentiate rigorously between mass and weight.

Chapter Roadmap & Progression

1 1. First Law of Motion and the Conc...
2 2. Momentum, Second Law & Derivatio...
3 3. Newton's Third Law of Motion
4 4. Gravitation: Mass vs Weight
5 5. Worked ICSE Problem Archetypes

Complete Concept Guide (100% Curriculum Coverage)

1. First Law of Motion and the Concept of Inertia

First Law & Inertia
A. Newton's First Law of Motion:

"An object remains in a state of rest or of uniform motion in a straight line unless acted upon by an external unbalanced force."

  • Qualitatively defines Force: an external agency that alters the state of rest or uniform motion.
  • Introduces Inertia: the inherent natural property of a body to resist any change in its velocity.
  • Measure of Inertia: Mass is the quantitative measure of inertia ($M \propto \text{Inertia}$). A heavier body possesses greater inertia.
B. Three Manifestations of Inertia:
  1. Inertia of Rest: When a stationary bus abruptly accelerates forward, passengers jerk backward because their feet move with the bus floor while their upper bodies tend to stay at rest.
  2. Inertia of Motion: When a speeding car suddenly brakes, passengers lurch forward because their bodies tend to maintain their forward velocity. (Hence, seatbelts are mandatory!).
  3. Inertia of Direction: When a car takes a sharp left curve, passengers lean toward the right because their inertia resists turning and tends to continue in a straight line.

2. Momentum, Second Law & Derivation of $F = ma$

Second Law & Force Metric
A. Linear Momentum ($p$):

The total quantity of motion contained in a body, defined as the product of its mass and velocity:

$$\mathbf{\vec{p} = m\vec{v}}$$

SI unit: $\mathbf{\text{kg}\cdot\text{m/s}}$ or $\text{N}\cdot\text{s}$ (Vector quantity, direction identical to velocity).

B. Derivation of $F = ma$:

Newton's Second Law states: Rate of change of momentum is proportional to applied force:

$$F \propto \frac{\Delta p}{\Delta t} = \frac{p_2 - p_1}{t} = \frac{mv - mu}{t} = \frac{m(v - u)}{t}$$

Since $\frac{v - u}{t} = a$ (acceleration):

$$F \propto ma \implies F = kma$$

In the SI system, the unit of force (Newton) is chosen such that $k = 1$:

$$\mathbf{F = ma}$$
  • One Newton ($1\text{ N}$): The force that acts on a mass of $1\text{ kg}$ to produce an acceleration of $1\text{ m/s}^2$: $$1\text{ N} = 1\text{ kg} \times 1\text{ m/s}^2 = 1000\text{ g} \times 100\text{ cm/s}^2 = \mathbf{10^5\text{ dynes}}$$
C. Impulse of a Force:
$$\mathbf{J = F \times \Delta t = \Delta p = m(v - u)}$$

A cricket fielder pulls his hands backward while catching a ball to increase the contact time $\Delta t$. By increasing $\Delta t$, the retarding force $F = \frac{\Delta p}{\Delta t}$ is dramatically reduced, preventing pain and injury to the hands!

3. Newton's Third Law of Motion

Third Law: Action-Reaction
Statement:

"To every action, there is always an equal and opposite reaction."

$$\mathbf{\vec{F}_{AB} = -\vec{F}_{BA}}$$

where $\vec{F}_{AB}$ is force exerted on body $A$ by body $B$, and $\vec{F}_{BA}$ is force exerted on body $B$ by body $A$.

Crucial Characteristics:
  • Forces always occur in matched pairs; single isolated forces cannot exist in the universe.
  • Action and reaction act on TWO DIFFERENT BODIES. Therefore, they never cancel each other out!
  • Examples: (1) Walking: foot pushes ground backwards (action), ground pushes foot forward (reaction); (2) Rocket propulsion: high-speed exhaust gases expelled downward (action) push rocket upward (reaction); (3) Recoil of gun: bullet propelled forward, gun recoils backward.

4. Gravitation: Mass vs Weight

Gravitation
A. Universal Law of Gravitation:
$$\mathbf{F = G \frac{m_1 m_2}{r^2}}$$

where $G = 6.674 \times 10^{-11} \text{ N}\cdot\text{m}^2/\text{kg}^2$ is the Universal Gravitational Constant.

B. Mass vs Weight:
PropertyMass ($m$)Weight ($W = mg$)
DefinitionQuantity of matter contained in a bodyForce of gravitational attraction exerted by Earth
NatureScalar quantityVector quantity (directed toward Earth's center)
SI UnitKilogram ($\text{kg}$)Newton ($\text{N}$) or $\text{kgf}$ ($1\text{ kgf} = 9.8\text{ N}$)
ConstancyConstant everywhere in the universeVariable; changes with local gravity $g$ (e.g., $W_{\text{moon}} = \frac{1}{6}W_{\text{earth}}$)
MeasurementBeam balanceSpring balance

5. Worked ICSE Problem Archetypes

Exemplary Solutions
Problem 1: A force acts for $0.1\text{ second}$ on a body of mass $2\text{ kg}$ initially at rest. The force ceases to act, and the body moves through $4\text{ meters}$ in the next $2\text{ seconds}$. Find the magnitude of the applied force.

Solution:

1. After the force ceases to act, the body moves with constant velocity $v$:

$$v = \frac{\text{Distance}}{\text{Time}} = \frac{4\text{ m}}{2\text{ s}} = 2\text{ m/s}$$

2. During the first $0.1\text{ s}$, the body accelerated from $u = 0$ to $v = 2\text{ m/s}$:

$$a = \frac{v - u}{t} = \frac{2 - 0}{0.1} = 20\text{ m/s}^2$$

3. Magnitude of Force:

$$F = ma = 2\text{ kg} \times 20\text{ m/s}^2 = \mathbf{40\text{ Newtons}}$$
Problem 2: A bullet of mass $20\text{ g}$ moving at $300\text{ m/s}$ penetrates a sandbag and is brought to rest in $0.05\text{ seconds}$. Calculate: (i) The impulse of the force, (ii) The average retarding force exerted by the sand.

Solution:

Mass $m = 20\text{ g} = 0.02\text{ kg}$, Initial velocity $u = 300\text{ m/s}$, Final velocity $v = 0$, Time $\Delta t = 0.05\text{ s}$.

(i) Impulse ($J$):

$$J = \Delta p = m(v - u) = 0.02(0 - 300) = \mathbf{-6\text{ N}\cdot\text{s}} \quad (\text{Magnitude: } 6\text{ N}\cdot\text{s})$$

(ii) Average Retarding Force ($F$):

$$F = \frac{J}{\Delta t} = \frac{-6}{0.05} = -120\text{ N} \implies \mathbf{\text{Retarding Force} = 120\text{ Newtons}}$$

Key Formulas, Reactions & Definitions

Linear Momentum
p = mv
Vector quantity in direction of velocity.
Newton's Second Law
$$F = ma = m\frac{v - u}{t}$$
1 N = 10^5 dynes.
Impulse of Force
$$J = F \times \Delta t = \Delta p = m(v - u)$$
Change in momentum.
Newton's Third Law
$$F_{AB} = -F_{BA}$$
Equal and opposite forces on different bodies.
Universal Gravitation
$$F = G\frac{m_1 m_2}{r^2}$$
G = 6.674 * 10^-11 N m^2 / kg^2.
Weight Relation
W = mg
1 kgf = 9.8 N.

Physics: Newton's Three Laws of Motion & Free-Body Forces

Physics: Newton's Three Laws of Motion & Free-Body Force Diagram Free Body Diagram (FBD) of Mass m Mass m F_applied f_friction Normal Reaction N Weight W = mg Net Horizontal Force: F_net = F - f = ma Summary of Newton's Three Laws 1st Law (Law of Inertia): • Qualitative definition of force • Resistance to change ∝ Mass (Inertia) 2nd Law (Law of Force & Momentum): • Quantitative: F = dp/dt = m × a • 1 Newton = 10⁵ Dynes • Impulse J = F Δt = Δp 3rd Law (Action & Reaction): • F_AB = - F_BA • Act on DIFFERENT bodies (never cancel out!) Universal Gravitation: F = G m₁m₂ / r²

Chapter Summary & 10 Key Takeaways

Takeaway 1
A force is an external agency that alters or tends to alter the state of rest or uniform motion of a body.
Takeaway 2
Newton's First Law defines force qualitatively and introduces the property of inertia.
Takeaway 3
Mass is the direct quantitative measure of a body's inertia: greater mass means greater inertia.
Takeaway 4
Linear momentum is the quantity of motion: p = mv (SI unit: kg m/s).
Takeaway 5
Newton's Second Law defines force quantitatively: F = ma (rate of change of momentum).
Takeaway 6
One Newton is the force that accelerates a 1 kg mass at 1 m/s^2: 1 N = 10^5 dynes.
Takeaway 7
Impulse is the product of force and contact time (J = F * Δt = Δp); catching a ball with yielding hands reduces the impact force.
Takeaway 8
Newton's Third Law: Action and reaction are equal in magnitude, opposite in direction, and act on two different bodies.
Takeaway 9
Universal Law of Gravitation: F = G * m1 * m2 / r^2.
Takeaway 10
Mass is a constant scalar measured by a beam balance; weight (W = mg) is a variable vector measured by a spring balance.

Check Your Understanding (Diagnostic Practice Questions)

Diagnostic questions testing core conceptual clarity. Answers are hidden initially — solve each problem first, then click to reveal the step-by-step verified solution.

1
State Newton's Second Law of Motion. Derive the formula $F = ma$ from this law.
Reveal Answer & Explanation
Answer:

• Statement: The rate of change of linear momentum of a body is directly proportional to the applied unbalanced force and takes place in the direction of the force.
• Derivation:
Let a body of mass $m$ have initial velocity $u$. Under an applied force $F$ for time $t$, its velocity changes to $v$.
Initial momentum $p_1 = mu$, Final momentum $p_2 = mv$.
Change in momentum $\Delta p = mv - mu = m(v - u)$.
Rate of change of momentum $= \frac{\Delta p}{t} = \frac{m(v - u)}{t}$.
By the second law: $F \propto \frac{m(v - u)}{t}$.
Since acceleration $a = \frac{v - u}{t}$, we have $F \propto ma \implies F = kma$.
In SI units, $k = 1$, giving $\mathbf{F = ma}$. $\blacksquare$


Rate of change of momentum is proportional to force. dp/dt = m(v - u)/t = ma.
2
Prove that $1\text{ Newton} = 10^5\text{ dynes}$.
Reveal Answer & Explanation
Answer:

• In the SI system, the unit of force is the Newton ($\text{N}$):

$$1\text{ N} = 1\text{ kg} \times 1\text{ m/s}^2$$


• Convert kilograms to grams ($1\text{ kg} = 1000\text{ g} = 10^3\text{ g}$) and meters to centimeters ($1\text{ m} = 100\text{ cm} = 10^2\text{ cm}$):

$$1\text{ N} = (10^3\text{ g}) \times (10^2\text{ cm/s}^2) = 10^5\text{ g}\cdot\text{cm/s}^2$$


• Since $1\text{ dyne} = 1\text{ g}\cdot\text{cm/s}^2$ in the CGS system:

$$\mathbf{1\text{ N} = 10^5\text{ dynes}} \quad \blacksquare$$


1 N = 1 kg * 1 m/s^2 = 1000 g * 100 cm/s^2 = 10^5 dynes.
3
Why does a cricket player lower his hands while catching a fast cricket ball?
Reveal Answer & Explanation
Answer:

• From the impulse-momentum theorem, the impulsive force is inversely proportional to the contact time for a given change in momentum:

$$F = \frac{\Delta p}{\Delta t}$$


• When a fielder pulls his hands backward with the ball, he increases the contact time $\Delta t$ taken to reduce the ball's velocity to zero.
• By increasing $\Delta t$, the rate of change of momentum is greatly reduced, thereby minimizing the retarding force $F$ exerted on his palms, preventing pain and injury.


Increasing time interval Δt reduces the force F = Δp / Δt on the hands.
4
Action and reaction are equal and opposite. Why do they not cancel each other out to produce equilibrium?
Reveal Answer & Explanation
Answer:

• Two equal and opposite forces can cancel each other out if and only if they act on the SAME single body.
• In Newton's Third Law, action and reaction act simultaneously on TWO COMPLETELY DIFFERENT BODIES.
• For example, when you jump off a boat: your foot exerts an action force on the boat (pushing it backward), while the boat exerts a reaction force on your foot (pushing you forward). Since each force acts on a different object, they cannot cancel out.


Action and reaction act on two different bodies, not on the same body.
5
A body of mass $5\text{ kg}$ is acted upon by two perpendicular forces: $8\text{ N}$ along the $X$-axis and $6\text{ N}$ along the $Y$-axis. Find the magnitude of the resulting acceleration.
Reveal Answer & Explanation
Answer: • Since the two forces are perpendicular ($\theta = 90^\circ$), the resultant force $F_{\text{net}}$ is given by the Pythagoras Theorem:
$$F_{\text{net}} = \sqrt{F_x^2 + F_y^2} = \sqrt{8^2 + 6^2} = \sqrt{64 + 36} = \sqrt{100} = 10\text{ Newtons}$$
• Using $F_{\text{net}} = ma$:
$$a = \frac{F_{\text{net}}}{m} = \frac{10\text{ N}}{5\text{ kg}} = \mathbf{2\text{ m/s}^2}$$
Resultant force = √(8^2 + 6^2) = 10 N. a = F/m = 10 / 5 = 2 m/s^2.
6
Differentiate between the mass and weight of a body on Earth and on the Moon.
Reveal Answer & Explanation
Answer:

• Mass: The actual quantity of matter in the body. It is an intrinsic scalar quantity measured in $\text{kg}$ that remains identical on Earth and on the Moon ($m_{\text{moon}} = m_{\text{earth}}$).
• Weight ($W = mg$): The gravitational force pulling the body downward. Since gravity on the Moon is one-sixth of Earth's gravity ($g_{\text{moon}} = \frac{g}{6}$), an object's weight on the Moon is only one-sixth of its weight on Earth ($W_{\text{moon}} = \frac{W_{\text{earth}}}{6}$).


Mass is constant everywhere. Weight W = mg is 6 times smaller on the Moon.
7
Explain why dust falls off a hanging rug or carpet when it is beaten with a wooden stick.
Reveal Answer & Explanation
Answer:

• This is a direct consequence of the Inertia of Rest.
• When the carpet is beaten with a stick, the carpet fabric is suddenly jerked into rapid forward motion by the blow.
• The dust particles embedded in the carpet fibers tend to remain at their original position of rest due to their inertia of rest.
• As a result, the dust particles separate from the moving carpet fibers and fall down to the ground under gravity.


Carpet moves suddenly; dust particles stay at rest due to inertia of rest and drop under gravity.
8
A constant force acts on an object of mass $5\text{ kg}$ for a duration of $2\text{ s}$, increasing its velocity from $3\text{ m/s}$ to $7\text{ m/s}$. Find: (i) The magnitude of the force, (ii) The final velocity if the same force acted for $5\text{ s}$.
Reveal Answer & Explanation
Answer:

• (i) Magnitude of Force:

$$a = \frac{v - u}{t} = \frac{7 - 3}{2} = \frac{4}{2} = 2\text{ m/s}^2$$


$$F = ma = 5\text{ kg} \times 2\text{ m/s}^2 = \mathbf{10\text{ Newtons}}$$


• (ii) Final Velocity if force acts for $5\text{ s}$:

$$v' = u + at' = 3 + (2 \times 5) = 3 + 10 = \mathbf{13\text{ m/s}}$$


a = (7 - 3)/2 = 2 m/s^2. F = 5 * 2 = 10 N. For t = 5 s: v = 3 + 2(5) = 13 m/s.
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