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WBB • Class 7 • Mathematics (গণিত প্রভা) • Ch 14
Estimated Time: 50 minutes
Study Progress: In Progress

Properties of Triangles

Welcome to Chapter 14: "Properties of Triangles" (ত্রিভুজের ধর্ম / त्रिभुज के गुणधर्म) of the West Bengal Board (WBBSE) Class 7 Mathematics curriculum (Ganit Prabha). Formatted under the TargetExams Gold-Standard 5-Step Pedagogy System, this core geometry chapter establishes the Exterior Angle Theorem ($\angle ACD = \angle A + \angle B$), the four concurrent centers of a triangle (Centroid $G$ with its $2:1$ median ratio, Orthocenter $O$ across acute, right, and obtuse triangles, Circumcenter $S$ at hypotenuse midpoints, and Incenter $I$), and the fundamental Triangle Inequality Theorems ($a+b > c$).

📐 The Balance Center: How a Cardboard Triangle Balances on a Fingertip!

Have you ever balanced a cutout triangle on the very tip of a pencil or your index finger without it tilting or falling?

Regardless of whether a triangle is scalene or irregular, there is exactly one special interior point where its entire mass is evenly balanced. This point is called the Centroid ($G$)! It is the intersection of the triangle's three medians, and it divides every median in an exact $2 : 1$ ratio.

In this chapter, you will discover the four concurrent centers of a triangle and explore the fundamental inequalities that govern why triangles exist!

Why This Chapter Matters

Welcome to Chapter 14: "Properties of Triangles" (ত্রিভুজের ধর্ম / त्रिभुज के गुणधर्म) of the West Bengal Board (WBBSE) Class 7 Mathematics curriculum (Ganit Prabha). Formatted under the TargetExams Gold-Standard 5-Step Pedagogy System, this core geometry chapter establishes the Exterior Angle Theorem ($\angle ACD = \angle A + \angle B$), the four concurrent centers of a triangle (Centroid $G$ with its $2:1$ median ratio, Orthocenter $O$ across acute, right, and obtuse triangles, Circumcenter $S$ at hypotenuse midpoints, and Incenter $I$), and the fundamental Triangle Inequality Theorems ($a+b > c$).

Before You Begin (Prerequisites)

  • Basic definition of triangles, vertices, and sides
  • Angle sum property of a triangle ($\angle A + \angle B + \angle C = 180^\circ$)
  • Concept of perpendicular lines and midpoints
  • Ratio concepts and internal division ($2 : 1$)

What You Will Learn (Core Objectives)

  • State and prove the Exterior Angle Theorem ($\angle ACD = \angle A + \angle B$)
  • Understand the 3 medians and the $2:1$ centroid division property
  • Locate the orthocenter in acute, right, and obtuse triangles
  • Distinguish between circumcenter and incenter properties
  • Apply the triangle inequality theorem ($a+b > c$) to determine valid side lengths

Chapter Roadmap & Progression

1 Concept 1: Exterior Angle Theorem &...
2 Concept 2: Medians and the Centroid...
3 Concept 3: Altitudes & the Orthocen...
4 Concept 4: Circumcenter (Perpendicu...
5 Concept 5: Triangle Inequalities ($...

Complete Concept Guide (100% Curriculum Coverage)

Concept 1: Exterior Angle Theorem & Angle Sums ($180^\circ$ and $360^\circ$)

Step 1
Exterior Angle Theorem Proof

An exterior angle formed by producing any side of a triangle equals the sum of its two remote interior angles: $\angle ACD = \angle A + \angle B$.

Step 2
Sum of Exterior Angles ($360^\circ$)

The sum of the three exterior angles formed by producing sides in cyclic order is always $360^\circ$ (four right angles).

Step 3
Worked Example

If exterior angle is $120^\circ$ and ratio of remote angles is $1:2$: $x + 2x = 120^\circ \implies x = 40^\circ$. Angles are $40^\circ$ and $80^\circ$.

Step 4
Examiner Traps

Never include the adjacent interior angle. The theorem applies only to remote interior angles.

Step 5
Real-World Application

Maritime Navigation: The distance-off-by-doubling-the-angle-on-the-bow technique uses exterior angle geometry to find distance to a lighthouse.

Concept 2: Medians and the Centroid ($2:1$ Ratio)

Step 1
Definition of Medians & Centroid

A median joins a vertex to the midpoint of the opposite side. The three medians concur at the Centroid ($G$), which always lies inside the triangle.

Step 2
The $2:1$ Ratio Property

The centroid divides each median in a $2 : 1$ ratio from vertex to base ($AG = \frac{2}{3}AD$, $GD = \frac{1}{3}AD$).

Step 3
Worked Example

For median $12\text{ cm}$, $BG = \frac{2}{3} \times 12 = 8\text{ cm}$ and $GE = 4\text{ cm}$.

Step 4
Examiner Traps

Medians bisect sides, not angles (except in isosceles/equilateral triangles).

Step 5
Real-World Application

Aerospace Design: Aircraft center-of-gravity calculations for triangular wing surfaces use centroid coordinates.

Concept 3: Altitudes & the Orthocenter (Position Across Triangle Types)

Step 1
Definitions

An altitude is a perpendicular dropped from a vertex to the opposite side. The three altitudes concur at the Orthocenter ($O$).

Step 2
Orthocenter Spatial Locations
  • Acute triangle: strictly inside.
  • Right triangle: exactly at the right-angled vertex.
  • Obtuse triangle: strictly outside behind the obtuse vertex.
Step 3
Worked Example

In $\triangle ABC$ right-angled at $B$, the orthocenter is vertex $B$ itself.

Step 4
Examiner Traps

Do not confuse the orthocenter with the centroid. The orthocenter can be outside the triangle.

Step 5
Real-World Application

Structural Engineering: Stress and load vector intersections in triangular transmission towers correspond to orthocentric geometry.

Concept 4: Circumcenter (Perpendicular Bisectors) & Incenter (Angle Bisectors)

Step 1
Definitions & Concurrency

Circumcenter ($S$): Concurrency point of perpendicular bisectors of sides (equidistant from all 3 vertices: $SA=SB=SC=R$).

Incenter ($I$): Concurrency point of internal angle bisectors (equidistant from all 3 sides: radius $r$).

Step 2
Right Triangle Circumcenter Rule

In a right-angled triangle, the circumcenter lies precisely at the midpoint of the hypotenuse ($R = \frac{\text{Hypotenuse}}{2}$).

Step 3
Worked Example

If hypotenuse is $10\text{ cm}$, circumradius $R = 10 / 2 = 5\text{ cm}$.

Step 4
Examiner Traps

The incenter is always inside the triangle, whereas the circumcenter lies outside for obtuse triangles.

Step 5
Real-World Application

Facility Location: Urban planners place regional emergency hubs equidistant from three towns using the circumcenter.

Concept 5: Triangle Inequalities ($a+b > c$ & Side-Angle Relations)

Step 1
Triangle Inequality Theorem

A triangle can be formed if and only if the sum of the lengths of any two sides is strictly greater than the third side: $a+b > c$.

Step 2
Side-Angle Correspondence

The side opposite the largest angle is the longest side, and the side opposite the smallest angle is the shortest side.

Step 3
Worked Example

If $\angle A = 70^\circ, \angle B = 60^\circ \implies \angle C = 50^\circ$. The longest side is $BC$ and the shortest is $AB$.

Step 4
Examiner Traps

If $a+b=c$, no triangle forms; the points are collinear.

Step 5
Real-World Application

GPS Route Optimization: A straight-line flight is always shorter than a stopover flight because $AC < AB + BC$.

Key Formulas, Identities & Theorems

Exterior Angle Theorem
$$\angle ACD = \angle A + \angle B$$
An exterior angle equals the sum of the two opposite interior angles.
Sum of Three Exterior Angles
$$\text{Sum of Exterior Angles} = 360^\circ \quad (\text{Four Right Angles})$$
Sum of exterior angles formed by producing sides in order is 360°.
Centroid Division of Medians
$$AG : GD = 2 : 1$$
Centroid divides each median from vertex to base midpoint in a 2:1 ratio.
Triangle Inequality Theorem
$$a + b > c, \quad b + c > a, \quad c + a > b$$
The sum of any two sides must be strictly greater than the third side.
Difference of Two Sides Inequality
$$|a - b| < c$$
The difference between any two sides is strictly less than the third side.

Conceptual Solved Examples & Case Studies

Example 1
An exterior angle of a triangle is $115^\circ$ and one opposite interior angle is $50^\circ$. Find the other opposite interior angle.
Step-by-Step Solution:
By Exterior Angle Theorem: $\angle ACD = \angle A + \angle B$
$115^\circ = 50^\circ + \angle B \implies \angle B = 115^\circ - 50^\circ = 65^\circ$.
Example 2
Median $AD = 9\text{ cm}$. If $G$ is the centroid, find lengths of $AG$ and $GD$.
Step-by-Step Solution:
The centroid divides the median in ratio $2 : 1$.
$AG = \frac{2}{3} \times 9 = 6\text{ cm}$ and $GD = \frac{1}{3} \times 9 = 3\text{ cm}$.
Example 3
Can a triangle have side lengths $3\text{ cm}$, $4\text{ cm}$, and $8\text{ cm}$? Justify your answer.
Step-by-Step Solution:
Sum of two smaller sides $= 3 + 4 = 7\text{ cm}$.
Third side $= 8\text{ cm}$.
Since $7 < 8$, the sum is less than the third side. Hence, no triangle can be formed.

Common Misconceptions & Examiner Traps

Common Misconception

Searching for the orthocenter inside an obtuse triangle.

Scientific Reality & Correction

The orthocenter of an obtuse triangle lies strictly outside the triangle behind the obtuse vertex.

Common Misconception

Confusing a median with an altitude.

Scientific Reality & Correction

A median connects a vertex to the midpoint of the opposite side. An altitude drops perpendicularly ($90^\circ$) to the opposite side.

Common Misconception

Writing centroid ratio as 1:2.

Scientific Reality & Correction

From the vertex to the centroid is 2 parts; from the centroid to the midpoint is 1 part ($2:1$).

Exterior Angle Theorem & Centroid 2:1 Median Division Model

Exterior Angle: ∠ACD = ∠A + ∠B & Centroid G (2 : 1 Ratio) D A B C Exterior ∠ACD G (Centroid) 2 parts 1 part Key Triangle Theorems 1. Exterior Angle Theorem: ∠ACD = ∠A + ∠B 2. Centroid G Ratio: AG : GD = 2 : 1 3. Orthocenter O: Concurrency of 3 altitudes Triangle Inequality: a + b > c

Chapter Summary & 10 Key Takeaways

Takeaway 1
An exterior angle equals the sum of the two remote interior angles ($\angle ACD = \angle A + \angle B$).
Takeaway 2
Sum of the three exterior angles in order is always 360° (four right angles).
Takeaway 3
Medians meet at the Centroid ($G$), dividing each median in a 2 : 1 ratio.
Takeaway 4
Altitudes meet at the Orthocenter ($O$), which is at the right-angle vertex in right triangles.
Takeaway 5
Perpendicular bisectors meet at the Circumcenter ($S$), lying at the hypotenuse midpoint in right triangles.
Takeaway 6
Internal angle bisectors meet at the Incenter ($I$).
Takeaway 7
Triangle formation condition: sum of any two sides must exceed the third ($a+b > c$).
Takeaway 8
The longest side is always opposite the largest angle.

Check Your Understanding (Diagnostic Practice Questions)

Diagnostic questions testing core conceptual clarity. Answers are hidden initially — solve each problem first, then click to reveal the step-by-step verified solution.

1
An exterior angle is $110^\circ$ and one remote interior angle is $45^\circ$. Find the other remote interior angle.
Reveal Answer & Explanation
Answer: $110^\circ - 45^\circ = 65^\circ$.
Subtract from exterior angle.
2
If a median is $15\text{ cm}$, find the distance from vertex to centroid.
Reveal Answer & Explanation
Answer: $\frac{2}{3} \times 15 = 10\text{ cm}$.
This is 2/3 of the median.
3
In which type of triangle does the orthocenter lie outside?
Reveal Answer & Explanation
Answer: Obtuse-angled triangle.
A triangle with an angle greater than 90°.
4
Can sides of $2\text{ cm}, 3\text{ cm}, 5\text{ cm}$ form a triangle?
Reveal Answer & Explanation
Answer: No, because $2 + 3 = 5$, not strictly greater than 5.
Compare $2 + 3 = 5$.
5
The hypotenuse of a right triangle is $16\text{ cm}$. Find its circumradius.
Reveal Answer & Explanation
Answer: $16 / 2 = 8\text{ cm}$.
Half of the hypotenuse.
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