Follow Us
Select Medium / माध्यम चुनें:
Eng (English) Hindi (हिन्दी)
JAC • Class 7 • Mathematics • Ch 22
Estimated Time: 45 Mins
Study Progress: In Progress

Data Handling and Probability

JCERT · Class 7 · Chapter 22 · Data Handling and Probability. Topic notes aligned to the official chapter; these are not solutions to every textbook exercise.

Why This Chapter Matters

JCERT · Class 7 · Chapter 22 · Data Handling and Probability. Topic notes aligned to the official chapter; these are not solutions to every textbook exercise.

Before You Begin (Prerequisites)

  • Revise relevant arithmetic and ideas from the previous grade.

What You Will Learn (Core Objectives)

  • Organise data with tally marks and frequency tables and label bar-chart scales. Mean is sum divided by count; median is the middle ordered value; mode is the most frequent value. With equally likely outcomes, probability is the fraction of favourable outcomes.

Chapter Roadmap & Progression

1 Syllabus, textbook and notes alignm...
2 Concept and method
3 Check and common pitfall

Complete Concept Guide (100% Curriculum Coverage)

Syllabus, textbook and notes alignment

JCERT · Regular schools (Non-SOE) · Class 7 · Chapter 22 — Data Handling and Probability
Official syllabus pages 289–311. Official syllabus · Prescribed Hindi book (22 chapters) · Separate supplementary reference.

These topic notes and teaching examples are not a complete answer key to every textbook question. English notes use this same JCERT chapter order; a matching English textbook PDF has not been verified.

Official Hindi PDF for this exact chapter

Concept and method

Organise data with tally marks and frequency tables and label bar-chart scales. Mean is sum divided by count; median is the middle ordered value; mode is the most frequent value. With equally likely outcomes, probability is the fraction of favourable outcomes.

Check and common pitfall

Order data before finding a median and average the two middle values. The die calculation assumes fairness.

Key Formulas, Identities & Theorems

Key relationships
Mean = sum/count; P(event) = favourable equally likely outcomes / total outcomes
Observe the stated conditions and units.

Conceptual Solved Examples & Case Studies

Example 1
Find the mean and median of 2, 5, 8, 11. What is the probability of six on a fair die?
Step-by-Step Solution:

Mean = 26/4 = 6.5; median = (5 + 8)/2 = 6.5; P(6) = 1/6

Order data before finding a median and average the two middle values. The die calculation assumes fairness.

Finished Studying This Chapter?
READY TO PRACTICE?

Timed CBT Practice Tests (Exam Simulator)

Put your concepts to the test with official curriculum-aligned Foundation and Advanced practice tests. Get instant accuracy scores, time metrics, and step-by-step verified explanations.

STAY UPDATED

Get the Latest Updates

New test series, syllabus updates, exam notifications and more.

Syllabus
Updates
Exam
Alerts
Study
Resources