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JAC • Class 7 • Mathematics • Ch 16
Estimated Time: 45 Mins
Study Progress: In Progress

Symmetry

JCERT · Class 7 · Chapter 16 · Symmetry. Topic notes aligned to the official chapter; these are not solutions to every textbook exercise.

Why This Chapter Matters

JCERT · Class 7 · Chapter 16 · Symmetry. Topic notes aligned to the official chapter; these are not solutions to every textbook exercise.

Before You Begin (Prerequisites)

  • Revise relevant arithmetic and ideas from the previous grade.

What You Will Learn (Core Objectives)

  • Reflection symmetry gives matching mirror halves across a line. Rotational order counts matching orientations in a full turn. A regular polygon has as many symmetry lines and rotational order as it has sides.

Chapter Roadmap & Progression

1 Syllabus, textbook and notes alignm...
2 Concept and method
3 Check and common pitfall

Complete Concept Guide (100% Curriculum Coverage)

Syllabus, textbook and notes alignment

JCERT · Regular schools (Non-SOE) · Class 7 · Chapter 16 — Symmetry
Official syllabus pages 225–235. Official syllabus · Prescribed Hindi book (22 chapters) · Separate supplementary reference.

These topic notes and teaching examples are not a complete answer key to every textbook question. English notes use this same JCERT chapter order; a matching English textbook PDF has not been verified.

Official Hindi PDF for this exact chapter

Concept and method

Reflection symmetry gives matching mirror halves across a line. Rotational order counts matching orientations in a full turn. A regular polygon has as many symmetry lines and rotational order as it has sides.

Check and common pitfall

The lines are the two diagonals and the two lines through opposite side midpoints.

Key Formulas, Identities & Theorems

Key relationships
Regular n-gon: rotational order n; smallest positive matching turn = 360°/n
Observe the stated conditions and units.

Conceptual Solved Examples & Case Studies

Example 1
How many reflection lines and what rotational order does a square have?
Step-by-Step Solution:

4 lines; order 4; 360° ÷ 4 = 90°

The lines are the two diagonals and the two lines through opposite side midpoints.

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