Follow Us
माध्यम चुनें / Select Medium:
Eng (English) Hindi (हिन्दी)
CBSE • कक्षा XI • Biology • अध्याय 12
अनुमानित समय: 45 Mins
प्रगति: अध्ययनरत

पादप में श्वसन

In Class 11 Biology, "Respiration in Plants" provides an authoritative, curriculum-verified master resource aligned with the 2026–27 NCERT syllabus.

🔥 Have You Ever Wondered?

How does a tiny microscopic cell break down glucose to generate 38 molecules of ATP without bursting into flames like an open fire? Cellular respiration dismantles chemical bonds in controlled steps across the cytoplasm and mitochondria.

यह अध्याय क्यों महत्वपूर्ण है

In Class 11 Biology, "Respiration in Plants" provides an authoritative, curriculum-verified master resource aligned with the 2026–27 NCERT syllabus.

अध्ययन से पूर्व (आवश्यक ज्ञान)

  • Mitochondria structure from Chapter 8.
  • Cellular respiration from Class 10.
  • ATP and energy currency.

इस अध्याय के लक्ष्य

  • Distinguish Aerobic respiration and Anaerobic respiration (Fermentation: Alcoholic vs Lactic acid).
  • Trace Glycolysis (EMP Pathway, 10 enzymatic steps in cytoplasm, net yield: $2\text{ ATP} + 2\text{ NADH}$).
  • Explain the Link Reaction: Oxidative decarboxylation of Pyruvate to Acetyl-CoA by Pyruvate Dehydrogenase.
  • Trace the Tricarboxylic Acid (TCA / Krebs) Cycle in the mitochondrial matrix.
  • Explain the Electron Transport System (ETS) and Oxidative Phosphorylation: Complexes I to V in inner mitochondrial membrane.
  • Calculate Respiratory Quotient (RQ): Carbohydrates ($1.0$), Fats ($0.7$), Proteins ($0.9$).

अध्याय रूपरेखा एवं प्रगति

1 1. Glycolysis (EMP Pathway)
2 2. The Krebs Cycle (TCA Cycle)
3 3. Electron Transport System (ETS)...

सम्पूर्ण सैद्धांतिक एवं वैचारिक अध्ययन

1. Glycolysis (EMP Pathway)

Discovered by Embden, Meyerhof, and Parnas. Occurs in the cytoplasm of all living cells (anaerobic, requires zero oxygen):
• 1 Glucose ($6C$) is phosphorylated and cleaved into two molecules of Pyruvate ($3C$).
• Key regulatory enzyme: Phosphofructokinase (PFK).
• Net Yield: Consumes 2 ATP; produces 4 ATP → Net $+2\text{ ATP}$ and $+2\text{ NADH}$.

2. The Krebs Cycle (TCA Cycle)

Inside the mitochondrial matrix:
• Link Reaction: $\text{Pyruvate} + \text{CoA} + \text{NAD}^+ \xrightarrow{\text{PDH}} \text{Acetyl-CoA} + \text{CO}_2 + \text{NADH}$.
• TCA Cycle: $2C$ Acetyl-CoA condenses with $4C$ Oxaloacetate to form $6C$ Citric acid. Per glucose (2 turns): produces $\mathbf{6\text{ NADH} + 2\text{ FADH}_2 + 2\text{ GTP/ATP} + 4\text{ CO}_2}$!

3. Electron Transport System (ETS) & RQ

In the inner mitochondrial membrane, electrons from NADH and $\text{FADH}_2$ cascade through Complexes I to IV to the final electron acceptor: Oxygen (forming $\text{H}_2\text{O}$)! Protons pumped into the intermembrane space drive Complex V (ATP Synthase):
• $1\text{ NADH} \implies 3\text{ ATP}$ (or $2.5\text{ ATP}$).
• $1\text{ FADH}_2 \implies 2\text{ ATP}$ (or $1.5\text{ ATP}$).
• Respiratory Quotient: $\mathbf{RQ = \frac{\text{Volume of } \text{CO}_2 \text{ evolved}}{\text{Volume of } \text{O}_2 \text{ consumed}}}$.

Respiration in Plants - Key Biological & Anatomical Model

Respiration in Plants - Biological Architecture Cellular & Anatomical Organization Histology, membrane kinetics & organ systems Physiological & Metabolic Pathways Enzyme kinetics, ATP energetics & respiration CBSE Class 11 Board & NEET Medical Foundation Clinical pathology, laboratory experiments & comparative physiology

अध्याय का सार संक्षेप एवं 10 मुख्य निष्कर्ष

मुख्य बिंदु 1
EMP Glycolytic Cascade: Cytoplasmic anaerobic breakdown producing 2 net ATP and 2 NADH.
मुख्य बिंदु 2
Link Reaction: Mitochondrial gateway converting pyruvate to acetyl-CoA and releasing CO2.
मुख्य बिंदु 3
Krebs Cycle: Matrix enzymatic furnace producing reducing power equivalents NADH and FADH2.
मुख्य बिंदु 4
Complex V ATP Synthase: Rotary nanomachine harnessing intermembrane proton motive force.
मुख्य बिंदु 5
Respiratory Quotient (RQ): Gas exchange volumetric ratio diagnosing metabolised fuel substrate.

स्व-मूल्यांकन अभ्यास (Check Your Understanding)

मूल वैचारिक स्पष्टता की जांच के लिए नैदानिक प्रश्न। पहले स्वयं हल करें, फिर उत्तर देखें।

1
Trace the sequential enzymatic reactions of Glycolysis (EMP Pathway). What is the net yield of ATP and NADH?
उत्तर एवं व्याख्या देखें
उत्तर: Ten reactions in cytoplasm: Glucose is phosphorylated to Glucose-6-phosphate by hexokinase → isomerized to Fructose-6-phosphate → phosphorylated to Fructose-1,6-bisphosphate → cleaved into DHAP and PGAL → oxidized to 1,3-bisphosphoglycerate → dephosphorylated to 3-phosphoglycerate → 2-phosphoglycerate → PEP → Pyruvate. Net yield: 2 ATP and 2 NADH per glucose molecule.
10-step cytoplasmic cascade; net yield of 2 ATP and 2 NADH per glucose.
2
What is the final electron acceptor in aerobic cellular respiration? What product is formed?
उत्तर एवं व्याख्या देखें
उत्तर: Molecular Oxygen ($O_2$) is the terminal electron acceptor at Complex IV (Cytochrome c oxidase) of the electron transport system. It combines with protons ($H^+$) and electrons to form metabolic Water ($\text{H}_2\text{O}$).
Oxygen is the terminal electron acceptor, forming water.
3
Define Respiratory Quotient (RQ). Calculate the RQ value for: (i) Glucose, (ii) Tripalmitin (fat).
उत्तर एवं व्याख्या देखें
उत्तर: RQ is the ratio of the volume of $\text{CO}_2$ evolved to the volume of $O_2$ consumed during cellular respiration: $RQ = \frac{\text{Volume of CO}_2}{\text{Volume of O}_2}$. (i) For glucose: $\text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2 \to 6\text{CO}_2 + 6\text{H}_2\text{O} \implies RQ = 6/6 = 1.0$. (ii) For tripalmitin: $2\text{C}_{51}\text{H}_{98}\text{O}_6 + 145\text{O}_2 \to 102\text{CO}_2 + 98\text{H}_2\text{O} \implies RQ = 102/145 = 0.7$.
RQ = CO2 / O2; Glucose = 1.0, Tripalmitin = 0.7.
4
Why is the Krebs cycle also called the Amphibolic pathway?
उत्तर एवं व्याख्या देखें
उत्तर: Because it is involved in both catabolism (breakdown of carbohydrates, fats, and proteins to release energy) and anabolism (intermediates like $\alpha$-ketoglutarate, oxaloacetate, and succinyl-CoA are constantly withdrawn for synthesizing amino acids, fatty acids, and chlorophyll).
Serves dual roles in both catabolic breakdown and anabolic synthesis.
5
What is the major difference between Fermentation and Aerobic Respiration regarding energy release and NADH oxidation?
उत्तर एवं व्याख्या देखें
उत्तर: Fermentation is an anaerobic partial breakdown of glucose yielding only 2 ATP with slow oxidation of NADH to $\text{NAD}^+$ without an ETS; Aerobic respiration is complete oxidation of glucose to $\text{CO}_2$ and $\text{H}_2\text{O}$ yielding 36-38 ATP with rapid, vigorous oxidative phosphorylation through an electron transport system.
Partial oxidation with 2 ATP (Fermentation) vs complete oxidation with 36-38 ATP (Aerobic).
अध्याय का अध्ययन पूर्ण हुआ?
अभ्यास के लिए तैयार?

ऑनलाइन CBT टेस्ट देकर तैयारी का मूल्यांकन करें

झारखण्ड बोर्ड परीक्षा पैटर्न पर आधारित बहुविकल्पीय प्रश्नों का ऑनलाइन टेस्ट दें। तुरंत परिणाम, समय विश्लेषण और प्रत्येक प्रश्न का विस्तृत हल प्राप्त करें।

कक्षा 11 Biology के सभी अध्याय

अध्याय 1: जीव जगत (The Living World) अध्याय 2: जीव जगत का वर्गीकरण अध्याय 3: वनस्पति जगत (Plant Kingdom) अध्याय 4: प्राणि जगत अध्याय 5: पुष्पी पादपों की आकारिकी अध्याय 6: पुष्पी पादपों का शारीर अध्याय 7: प्राणियों में संरचनात्मक संगठन अध्याय 8: कोशिका: जीवन की इकाई अध्याय 9: जैव-अणु (Biomolecules) अध्याय 10: कोशिका चक्र और कोशिका विभाजन अध्याय 11: उच्च पादपों में प्रकाश-संश्लेषण अध्याय 12: पादप में श्वसन अध्याय 13: पादप वृद्धि एवं परिवर्धन अध्याय 14: श्वसन और गैसों का विनिमय अध्याय 15: शरीर द्रव तथा परिसंचरण अध्याय 16: उत्सर्जी उत्पाद एवं उनका निष्कासन अध्याय 17: गमन एवं संचलन अध्याय 18: तंत्रिकीय नियंत्रण एवं समन्वय अध्याय 19: रासायनिक समन्वय तथा एकीकरण

AI अध्ययन मित्र

त्वरित शंका समाधान

पादप में श्वसन में कोई संदेह या प्रश्न है? हमारे AI अध्ययन मित्र से तुरंत समझें।