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JAC • Class 7 • Mathematics • Ch 17
Estimated Time: 45 Mins
Study Progress: In Progress

Practical Geometry

JCERT · Class 7 · Chapter 17 · Practical Geometry. Topic notes aligned to the official chapter; these are not solutions to every textbook exercise.

Why This Chapter Matters

JCERT · Class 7 · Chapter 17 · Practical Geometry. Topic notes aligned to the official chapter; these are not solutions to every textbook exercise.

Before You Begin (Prerequisites)

  • Revise relevant arithmetic and ideas from the previous grade.

What You Will Learn (Core Objectives)

  • Begin with a rough sketch showing the given sides and angles. Draw a measured base and locate the third vertex with compass arcs or constructed angles. For an SSS construction, the sum of any two sides must exceed the third.

Chapter Roadmap & Progression

1 Syllabus, textbook and notes alignm...
2 Concept and method
3 Check and common pitfall

Complete Concept Guide (100% Curriculum Coverage)

Syllabus, textbook and notes alignment

JCERT · Regular schools (Non-SOE) · Class 7 · Chapter 17 — Practical Geometry
Official syllabus pages 236–245. Official syllabus · Prescribed Hindi book (22 chapters) · Separate supplementary reference.

These topic notes and teaching examples are not a complete answer key to every textbook question. English notes use this same JCERT chapter order; a matching English textbook PDF has not been verified.

Official Hindi PDF for this exact chapter

Concept and method

Begin with a rough sketch showing the given sides and angles. Draw a measured base and locate the third vertex with compass arcs or constructed angles. For an SSS construction, the sum of any two sides must exceed the third.

Check and common pitfall

The arc intersection is the third vertex. Lengths 2, 3, 5 cm cannot form a triangle because equality is insufficient.

Key Formulas, Identities & Theorems

Key relationships
Triangle inequality: a + b > c, b + c > a, c + a > b
Observe the stated conditions and units.

Conceptual Solved Examples & Case Studies

Example 1
How do you construct a triangle with sides 3, 4 and 5 cm?
Step-by-Step Solution:

BC = 5 cm; arc from B radius 3 cm; arc from C radius 4 cm; intersection A; join AB, AC.

The arc intersection is the third vertex. Lengths 2, 3, 5 cm cannot form a triangle because equality is insufficient.

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