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WBB • Class XI • Mathematics • Ch 1
Estimated Time: 65 minutes
Study Progress: In Progress

Sets

Set theory, founded by German mathematician Georg Cantor in the late 19th century, forms the bedrock of modern mathematics, underpinning mathematical analysis, algebra, probability, topology, and computer science. A set is rigorously defined as a well-defined collection of distinct mathematical objects, meaning that given any object, an unambiguous rule exists to determine whether it belongs to the collection or not. Sets can be represented either by the tabular or roster method or by the set-builder or rule method. Fundamental classifications include empty sets, singleton sets, finite and infinite sets, equal sets, and equivalent sets based on cardinality. The power set of a set with n elements encapsulates all its 2^n subsets, providing the structural basis for combinatorial mathematics. Graphical visualization through Venn diagrams illustrates set-theoretic operations including union, intersection, difference, symmetric difference, and complementation. Crucial algebraic laws such as the idempotent, commutative, associative, distributive, and De Morgan laws govern set manipulations. The principle of inclusion-exclusion resolves real-world multi-attribute surveys and counting problems, while Cartesian products provide the essential springboard to relations and functions.

Why This Chapter Matters

Mastery of set theory is indispensable for higher secondary mathematics, competitive entrance examinations like WBJEE and JEE Main, and advanced scientific computing. In calculus, functions and their domains, ranges, continuity, and differentiability are formally defined as relations between sets of real numbers. In modern computer science and database management systems (DBMS), relational algebra, structured query language (SQL) operations such as INNER JOIN, LEFT JOIN, and UNION, and indexing mechanisms are direct implementations of set operations and Cartesian products. Search engine algorithms rely heavily on Boolean set algebra to filter millions of web documents using AND, OR, and NOT operators. Furthermore, modern axiomatic probability theory, developed by Andrey Kolmogorov, relies fundamentally on sets where sample spaces are universal sets and events are subsets governed by the principle of inclusion-exclusion. In the WBCHSE Class 11 annual examination, questions on set algebra, De Morgan laws, and 3-set survey word problems represent guaranteed, high-scoring questions carrying 4 to 6 marks.

Chapter Roadmap & Progression

1 1. Historical Genesis, Set Axioms &...
2 2. Types of Sets, Cardinality, Subs...
3 3. Power Set, Universal Set & Venn...
4 4. Operations on Sets: Union, Inter...
5 5. Algebra of Sets & Rigorous Proof...
6 6. Cardinality Principles, Inclusio...

Complete Concept Guide (100% Curriculum Coverage)

1. Historical Genesis, Set Axioms & Representations

Set theory was conceived in the late 19th century by the German mathematician Georg Cantor (1845–1918) while investigating trigonometric series and the mathematical continuum. Today, it serves as the universal foundational language in which all of modern mathematics is formulated.

1.1 Definition of a Set & The "Well-Defined" Criterion

A set is a well-defined collection of distinct mathematical objects. The objects belonging to a set are called its elements or members.

The "Well-Defined" Criterion: A collection is well-defined if and only if there exists an objective, unambiguous rule or property that allows one to decide definitively whether any given object belongs to the collection or not.
  • Valid Sets: "The collection of all vowels in the English alphabet" — well-defined, since {a, e, i, o, u} is unambiguous. "The collection of all prime numbers less than 20" — well-defined ({2, 3, 5, 7, 11, 13, 17, 19}).
  • Invalid Collections (Not Sets): "The collection of the five best cricketers in India" — not well-defined, because the descriptor "best" is subjective and varies from person to person. "The collection of difficult chapters in Class 11 Math" — not a set.
1.2 Mathematical Notation & Membership

Sets are conventionally denoted by uppercase English letters ($A, B, C, X, Y, Z$), while their elements are denoted by lowercase letters ($a, b, c, x, y, z$), numbers, or mathematical symbols.

  • If $x$ is an element of set $A$, we write $x \in A$ (read as "$x$ belongs to $A$" or "$x$ is an element of $A$").
  • If $x$ is not an element of set $A$, we write $x \notin A$ (read as "$x$ does not belong to $A$").
1.3 Methods of Representing Sets

There are two principal methods used to describe or specify a set:

Method Description & Rules Standard Examples
1. Roster or Tabular Method All elements of the set are listed explicitly, separated by commas, and enclosed within curly braces $\{ \}$.
Rule 1: The order of elements is irrelevant: $\{1, 2, 3\} = \{3, 1, 2\}$.
Rule 2: Elements are not repeated: the set of letters in "MATHEMATICS" is $\{M, A, T, H, E, I, C, S\}$.
$V = \{a, e, i, o, u\}$
$P = \{2, 3, 5, 7, 11\}$
$E = \{2, 4, 6, 8, \dots\}$ (infinite)
2. Set-Builder or Rule Method Instead of listing elements, a characterizing property $P(x)$ possessed by all and only the elements of the set is stated.
General format: $A = \{x : P(x)\}$ or $A = \{x \mid P(x)\}$, read as: "the set of all $x$ such that $x$ satisfies property $P(x)$".
$V = \{x : x \text{ is a vowel in English}\}$
$S = \{x \in \mathbb{N} : x^2 - 5x + 6 = 0\}$
$A = \{x : x = 2n, n \in \mathbb{N}\}$
1.4 Standard Number Sets in Mathematics

The following symbols are globally standardized in mathematics:

  • $\mathbb{N} = \{1, 2, 3, 4, \dots\}$ : Set of all natural numbers (positive integers).
  • $\mathbb{W} = \{0, 1, 2, 3, \dots\}$ : Set of all whole numbers.
  • $\mathbb{Z}$ or $\mathbb{I} = \{\dots, -3, -2, -1, 0, 1, 2, 3, \dots\}$ : Set of all integers.
  • $\mathbb{Z}^+$ or $\mathbb{N}$ : Set of all positive integers; $\mathbb{Z}^-$ : Set of all negative integers.
  • $\mathbb{Q} = \left\{\frac{p}{q} : p, q \in \mathbb{Z}, q \neq 0, \gcd(p, q) = 1\right\}$ : Set of all rational numbers.
  • $\mathbb{R}$ : Set of all real numbers (rationals and irrationals combined).
  • $\mathbb{C} = \{a + ib : a, b \in \mathbb{R}, i = \sqrt{-1}\}$ : Set of all complex numbers.

2. Types of Sets, Cardinality, Subsets & Real Intervals

Understanding the taxonomy of sets and the precise hierarchy of subset inclusion is essential for algebraic logic and analysis.

2.1 Taxonomy of Sets & Cardinality
  • Empty Set (Null Set / Void Set): A set that contains no elements at all. Denoted by the Scandinavian letter $\emptyset$ or by empty braces $\{\}$.
    Cardinality: $n(\emptyset) = 0$.
    Examples: $A = \{x \in \mathbb{R} : x^2 + 1 = 0 \text{ and } x \in \mathbb{R}\} = \emptyset$; $B = \{x \in \mathbb{N} : 1 < x < 2\} = \emptyset$.
    Critical Trap: $\{\emptyset\}$ is NOT an empty set! It is a singleton set containing one element, which happens to be the empty set. Similarly, $\{0\}$ is a singleton set containing the number 0.
  • Singleton Set (Unit Set): A set containing exactly one element. $n(A) = 1$.
    Example: $A = \{x \in \mathbb{N} : x^2 = 9\} = \{3\}$. The set of even prime numbers: $\{2\}$.
  • Finite Set vs. Infinite Set:
    A set is finite if it is empty or consists of a definite, countable number of elements. The number of distinct elements in a finite set $A$ is called its cardinal number or cardinality, denoted by $n(A)$ or $|A|$.
    A set whose element count is not finite is an infinite set (e.g., $\mathbb{N}, \mathbb{Z}, \mathbb{R}$, or the set of points on a line segment).
  • Equal Sets ($A = B$): Two sets $A$ and $B$ are equal if and only if they have exactly the same elements.
    Symbolically: $A = B \iff (\forall x, x \in A \iff x \in B)$.
    Example: $A = \{1, 2, 3\}$ and $B = \{x \in \mathbb{N} : (x-1)(x-2)(x-3) = 0\} \implies A = B$.
  • Equivalent Sets ($A \sim B$): Two finite sets $A$ and $B$ are equivalent if they have the same cardinality, i.e., $n(A) = n(B)$. There exists a one-to-one correspondence (bijection) between their elements.
    Fundamental Fact: Equal sets are always equivalent, but equivalent sets need not be equal! (e.g., $\{1, 2, 3\} \sim \{a, b, c\}$ since both have cardinality 3, but they are not equal).
2.2 Subsets and Supersets

A set $A$ is said to be a subset of a set $B$ if every element of $A$ is also an element of $B$.

Formal Definition: $A \subseteq B \iff (\forall x, x \in A \implies x \in B)$
If $A \subseteq B$, we say "$A$ is contained in $B$" or "$B$ is a superset of $A$" ($B \supseteq A$).
  • Every set is a subset of itself: For any set $A$, $A \subseteq A$ (reflexive property).
  • The empty set is a subset of every set: For any set $A$, $\emptyset \subseteq A$.
  • Proper Subset ($A \subset B$): If $A \subseteq B$ and $A \neq B$, then $A$ is a proper subset of $B$, meaning $B$ contains at least one element that is not in $A$.
    Example: If $A = \{1, 2\}$ and $B = \{1, 2, 3\}$, then $A \subset B$.
  • Transitive Property: If $A \subseteq B$ and $B \subseteq C$, then $A \subseteq C$.
  • Criterion for Set Equality: $A = B \iff (A \subseteq B \text{ and } B \subseteq A)$. This is the primary technique used to prove set identities!
2.3 Intervals as Subsets of $\mathbb{R}$

In calculus and real analysis, continuous subsets of the real line $\mathbb{R}$ cannot be listed in roster form. They are defined as intervals:

Interval Name Notation Set-Builder Definition Geometric Line Representation
Open Interval $(a, b)$ $\{x \in \mathbb{R} : a < x < b\}$ Hollow circles at endpoints $a$ and $b$; segment between them shaded. Endpoints excluded.
Closed Interval $[a, b]$ $\{x \in \mathbb{R} : a \le x \le b\}$ Solid dots at endpoints $a$ and $b$; segment between them shaded. Both endpoints included.
Semi-open / Semi-closed $[a, b)$ $\{x \in \mathbb{R} : a \le x < b\}$ Solid dot at $a$, hollow circle at $b$. Includes $a$, excludes $b$.
Semi-closed / Semi-open $(a, b]$ $\{x \in \mathbb{R} : a < x \le b\}$ Hollow circle at $a$, solid dot at $b$. Excludes $a$, includes $b$.
Infinite Intervals $[a, \infty)$, $(-\infty, b)$ $\{x \in \mathbb{R} : x \ge a\}$, $\{x \in \mathbb{R} : x < b\}$ Ray extending indefinitely to $+\infty$ or $-\infty$. Note: $\infty$ is never enclosed by a square bracket!

3. Power Set, Universal Set & Venn Diagram Architecture

The power set introduces combinatorial exponential growth into set theory, while Venn diagrams transform abstract set logic into intuitive spatial geometry.

3.1 The Power Set & Subsets Formula

The collection of all possible subsets of a set $A$ is called the Power Set of $A$, denoted by $P(A)$ or $\mathcal{P}(A)$.

Formal Definition: $P(A) = \{S : S \subseteq A\}$

Notice that every element of $P(A)$ is itself a set! Furthermore, for any set $A$:

  • $\emptyset \in P(A)$ (since $\emptyset \subseteq A$).
  • $A \in P(A)$ (since $A \subseteq A$).
Theorem on Power Set Cardinality

If $A$ is a finite set with $n$ elements (i.e., $n(A) = n$), then:

  1. The total number of subsets of $A$ is $2^n$, so $n(P(A)) = |P(A)| = 2^n$.
  2. The number of proper subsets of $A$ is $2^n - 1$ (excluding the set $A$ itself).
  3. The number of non-empty subsets of $A$ is $2^n - 1$ (excluding the empty set $\emptyset$).
  4. The number of non-empty proper subsets is $2^n - 2$ (excluding both $\emptyset$ and $A$).
Nested Power Sets (Frequent Exam Question):
If $A = \emptyset$, then $n(A) = 0$.
$P(A) = P(\emptyset) = \{\emptyset\} \implies n(P(A)) = 2^0 = 1$.
$P(P(A)) = P(\{\emptyset\}) = \{\emptyset, \{\emptyset\}\} \implies n(P(P(A))) = 2^1 = 2$.
$P(P(P(A))) = \{\emptyset, \{\emptyset\}, \{\{\emptyset\}\}, \{\emptyset, \{\emptyset\}\}\} \implies n(P(P(P(A)))) = 2^2 = 4$.
In general: $n(P(P(\dots P(A)\dots))) = 2^{2^{\dots^n}}$.
3.2 Universal Set ($U$ or $\xi$)

In any mathematical context or investigation, all the sets under discussion are subsets of a fixed, sufficiently comprehensive larger set called the Universal Set, denoted by $U$ or $\xi$.

  • In human population studies, $U$ could be the set of all human beings on Earth.
  • In 2D coordinate geometry, $U$ is the Cartesian plane $\mathbb{R}^2 = \mathbb{R} \times \mathbb{R}$.
  • In number theory of integers, $U$ is the set of all integers $\mathbb{Z}$.
3.3 Venn Diagram Conventions

Introduced by English logician John Venn (1834–1923), Venn diagrams represent sets pictorially:

  • The Universal Set $U$ is represented geometrically by the interior of a rectangle.
  • Subsets of $U$ (such as $A, B, C$) are represented by closed planar curves, usually circles or ellipses within the rectangle.
  • Individual elements are represented by labeled points inside the corresponding regions.
  • Subsets ($A \subseteq B$) are drawn with circle $A$ completely lying inside circle $B$.
  • Disjoint sets ($A \cap B = \emptyset$) are drawn as non-overlapping, separated circles.

4. Operations on Sets: Union, Intersection, Difference & Complement

Just as addition and multiplication are fundamental operations on numbers, union, intersection, difference, and complement are fundamental operations that combine sets to produce new sets.

4.1 Union of Sets ($A \cup B$)

The union of two sets $A$ and $B$ is the set of all elements that belong to $A$, or to $B$, or to both.

Set-Builder Definition: $A \cup B = \{x : x \in A \lor x \in B\}$

Example: If $A = \{1, 2, 3, 4\}$ and $B = \{3, 4, 5, 6\}$, then $A \cup B = \{1, 2, 3, 4, 5, 6\}$.

4.2 Intersection of Sets ($A \cap B$)

The intersection of two sets $A$ and $B$ is the set of all elements that belong simultaneously to both $A$ and $B$.

Set-Builder Definition: $A \cap B = \{x : x \in A \land x \in B\}$

Example: For the same $A$ and $B$ above, $A \cap B = \{3, 4\}$.

  • Disjoint Sets: If two sets have no elements in common, their intersection is the empty set, i.e., $A \cap B = \emptyset$. Such sets are called mutually disjoint.
4.3 Difference of Sets ($A - B$ or $A \setminus B$)

The difference of set $A$ and set $B$ (also called the relative complement of $B$ in $A$) is the set of all elements that belong to $A$ but do not belong to $B$.

Set-Builder Definition: $A - B = \{x : x \in A \land x \notin B\} = A \cap B'$

Important Property: In general, set difference is not commutative: $A - B \neq B - A$ unless $A = B$.

Example: With $A = \{1, 2, 3, 4\}$ and $B = \{3, 4, 5, 6\}$:
$A - B = \{1, 2\}$
$B - A = \{5, 6\}$
Notice that $(A - B)$, $(A \cap B)$, and $(B - A)$ are mutually pairwise disjoint sets whose union is $A \cup B$!

4.4 Symmetric Difference of Sets ($A \Delta B$)

The symmetric difference of sets $A$ and $B$ is the set of elements that belong to $A$ or to $B$, but not to both.

Algebraic Formula: $A \Delta B = (A - B) \cup (B - A) = (A \cup B) - (A \cap B)$

Example: For $A = \{1, 2, 3, 4\}$ and $B = \{3, 4, 5, 6\}$, $A \Delta B = \{1, 2\} \cup \{5, 6\} = \{1, 2, 5, 6\}$.
Properties: $A \Delta B = B \Delta A$ (commutative); $A \Delta A = \emptyset$; $A \Delta \emptyset = A$.

4.5 Complement of a Set ($A'$ or $A^c$)

Let $U$ be the universal set. The complement of a subset $A \subseteq U$ is the set of all elements in $U$ that do not belong to $A$.

Set-Builder Definition: $A' = U - A = \{x \in U : x \notin A\}$

Fundamental Complement Properties:

  1. $A \cup A' = U$ (Complement Union Law)
  2. $A \cap A' = \emptyset$ (Complement Intersection Law)
  3. $(A')' = A$ (Law of Involution / Double Complement)
  4. $U' = \emptyset$ and $\emptyset' = U$ (Universal and Empty Set Complements)

5. Algebra of Sets & Rigorous Proofs of De Morgan's Laws

The algebra of sets provides the symbolic and axiomatic system governing operations on sets. It mirrors Boolean algebra and propositional logic.

5.1 Fundamental Laws of Set Algebra
Law Name Union Formulation Intersection Formulation
1. Idempotent Laws $A \cup A = A$ $A \cap A = A$
2. Identity Laws $A \cup \emptyset = A$ ($\emptyset$ is identity for $\cup$) $A \cap U = A$ ($U$ is identity for $\cap$)
3. Domination (Annihilation) $A \cup U = U$ $A \cap \emptyset = \emptyset$
4. Commutative Laws $A \cup B = B \cup A$ $A \cap B = B \cap A$
5. Associative Laws $(A \cup B) \cup C = A \cup (B \cup C)$ $(A \cap B) \cap C = A \cap (B \cap C)$
6. Distributive Laws $A \cup (B \cap C) = (A \cup B) \cap (A \cup C)$ $A \cap (B \cup C) = (A \cap B) \cup (A \cap C)$
5.2 De Morgan's Laws

Formulated by British mathematician Augustus De Morgan (1806–1871), these laws describe how complementation interacts with union and intersection:

First Law: The complement of the union of two sets equals the intersection of their individual complements: $$(A \cup B)' = A' \cap B'$$ Second Law: The complement of the intersection of two sets equals the union of their individual complements: $$(A \cap B)' = A' \cup B'$$
Rigorous Analytical Proof of De Morgan's First Law: $(A \cup B)' = A' \cap B'$

To prove that two sets $X$ and $Y$ are equal, we must demonstrate mutual subset inclusion: $X \subseteq Y$ and $Y \subseteq X$.

Part 1: Prove $(A \cup B)' \subseteq A' \cap B'$

  1. Let $x$ be an arbitrary element of $(A \cup B)'$.
  2. $\implies x \in (A \cup B)'$
  3. $\implies x \notin (A \cup B)$ (by definition of complement)
  4. $\implies \text{it is false that } (x \in A \text{ or } x \in B)$
  5. $\implies x \notin A \text{ and } x \notin B$ (by basic logic negation of disjunction)
  6. $\implies x \in A' \text{ and } x \in B'$ (by definition of complement)
  7. $\implies x \in (A' \cap B')$ (by definition of intersection)
  8. Since every element of $(A \cup B)'$ is in $A' \cap B'$, we have: $(A \cup B)' \subseteq A' \cap B'$ ... (Equation 1)

Part 2: Prove $A' \cap B' \subseteq (A \cup B)'$

  1. Let $y$ be an arbitrary element of $A' \cap B'$.
  2. $\implies y \in A' \text{ and } y \in B'$
  3. $\implies y \notin A \text{ and } y \notin B$
  4. $\implies y \notin (A \cup B)$ (for if $y \in A \cup B$, $y$ would have to be in at least one of them, which contradicts step 3)
  5. $\implies y \in (A \cup B)'$ (by definition of complement)
  6. Since every element of $A' \cap B'$ is in $(A \cup B)'$, we have: $A' \cap B' \subseteq (A \cup B)'$ ... (Equation 2)

From Equations (1) and (2), by the definition of set equality, we conclude: $(A \cup B)' = A' \cap B'$. $\quad \blacksquare$

6. Cardinality Principles, Inclusion-Exclusion & Cartesian Products

Cardinality principles enable mathematicians to compute counts of elements across intersecting sets without double-counting overlapping elements.

6.1 Two-Set Cardinality Principle

Let $A$ and $B$ be finite sets. The union $A \cup B$ can be partitioned into three mutually disjoint subsets: $(A - B)$, $(A \cap B)$, and $(B - A)$.

Therefore: $n(A \cup B) = n(A - B) + n(A \cap B) + n(B - A)$.

Since $n(A) = n(A - B) + n(A \cap B) \implies n(A - B) = n(A) - n(A \cap B)$, and similarly $n(B - A) = n(B) - n(A \cap B)$, substituting yields the master formula:

Master Two-Set Cardinality Formula: $$n(A \cup B) = n(A) + n(B) - n(A \cap B)$$

Important Corollaries:

  • If $A$ and $B$ are disjoint ($A \cap B = \emptyset$), then $n(A \cap B) = 0 \implies \mathbf{n(A \cup B) = n(A) + n(B)}$.
  • Number of elements in exactly one of $A$ or $B$: $$n(A \Delta B) = n(A - B) + n(B - A) = n(A) + n(B) - 2n(A \cap B) = n(A \cup B) - n(A \cap B)$$
  • Number of elements belonging to neither $A$ nor $B$: $$n(A' \cap B') = n((A \cup B)') = n(U) - n(A \cup B)$$
6.2 Three-Set Principle of Inclusion-Exclusion (PIE)

For any three finite sets $A, B$, and $C$:

Master Three-Set Formula: $$n(A \cup B \cup C) = n(A) + n(B) + n(C) - [n(A \cap B) + n(B \cap C) + n(C \cap A)] + n(A \cap B \cap C)$$

Why is $n(A \cap B \cap C)$ added at the end? In the single terms $n(A) + n(B) + n(C)$, the central intersection $A \cap B \cap C$ is counted 3 times. In the pairwise subtraction $-[n(A \cap B) + n(B \cap C) + n(C \cap A)]$, it is subtracted 3 times (net count = 0). To account for it exactly once in the union, it must be added back!

Detailed Sub-Region Counting Formulas for 3 Sets
  • Number of elements belonging to EXACTLY TWO sets: $$n(\text{exactly two}) = [n(A \cap B) + n(B \cap C) + n(C \cap A)] - 3n(A \cap B \cap C)$$
  • Number of elements belonging to AT LEAST TWO sets: $$n(\text{at least two}) = [n(A \cap B) + n(B \cap C) + n(C \cap A)] - 2n(A \cap B \cap C)$$
  • Number of elements belonging to EXACTLY ONE set: $$n(\text{exactly one}) = n(A) + n(B) + n(C) - 2[n(A \cap B) + n(B \cap C) + n(C \cap A)] + 3n(A \cap B \cap C)$$
6.3 Introduction to Cartesian Product ($A \times B$)

Given two non-empty sets $A$ and $B$, the Cartesian Product $A \times B$ is the set of all ordered pairs $(a, b)$ such that $a \in A$ and $b \in B$:

$$A \times B = \{(a, b) : a \in A \land b \in B\}$$
  • Ordered Pair: $(a, b) = (c, d) \iff a = c \text{ and } b = d$. Thus, $(1, 2) \neq (2, 1)$.
  • Non-Commutative: $A \times B \neq B \times A$ unless $A = B$ or one of the sets is empty.
  • Cardinality Theorem: If $n(A) = p$ and $n(B) = q$, then $n(A \times B) = p \times q$.
  • The total number of relations from set $A$ to set $B$ is the number of subsets of $A \times B$, which equals $2^{pq}$. (This bridges Chapter 1 to Chapter 2: Relations and Functions!).

Key Formulas, Identities & Theorems

Power Set Cardinality
$$2^n subsets$$
For a set with n elements, P(A) contains 2^n subsets including ∅ and A. The number of proper subsets is 2^n - 1.
Proper Subsets Formula
$$2^n - 1 subsets$$
Excludes the improper subset A itself. Non-empty proper subsets count is 2^n - 2 (excluding both ∅ and A).
Two-Set Cardinality Principle
n(A) + n(B) - n(A ∩ B)
Prevents double counting of overlapping elements. If A and B are mutually disjoint, n(A ∪ B) = n(A) + n(B).
Symmetric Difference Cardinality
$$n(A \cup B) - n(A \cap B)$$
Counts elements belonging strictly to either set A or set B, but not to both simultaneously.
Three-Set Inclusion-Exclusion Formula
n(A)+n(B)+n(C) - [n(AB)+n(BC)+n(CA)] + n(ABC)
Standard 5-mark WBCHSE survey question formula. Adds back the triple intersection after pairwise subtractions.
De Morgan's First & Second Laws
Dual complement identities
Crucial for logic gates, computer search algorithms, and probability complement rules.

Conceptual Solved Examples & Case Studies

Example 1
Step-by-Step Solution:

Part (a): Solving the Quadratic Inequality in ℤ [2 Marks]

  1. Consider the inequality: $x^2 - 3x - 10 \le 0$.
  2. Factorize the quadratic expression:

$$(x - 5)(x + 2) \le 0$$

  1. By the sign-scheme (wavy-curve method), the product is non-positive between the roots $-2$ and $5$:

$$-2 \le x \le 5$$

  1. Since $x \in \mathbb{Z}$ (integers), we list all integer values in this closed interval:

$$S = \{-2, -1, 0, 1, 2, 3, 4, 5\}$$

[Award 1 Mark for factorizing and interval, 1 Mark for correct roster list]

Part (b): Listing P(A) and Computing Nested Power Sets [3 Marks]

  1. Given $A = \{x, y\}$, the number of elements is $n = 2$. The total number of subsets is $2^2 = 4$. Listing all subsets:

$$P(A) = \{\emptyset, \{x\}, \{y\}, \{x, y\}\}$$

[Award 1 Mark for listing P(A)] 2. To evaluate $n(P(P(P(\emptyset))))$:

  • For the empty set $\emptyset$, $n(\emptyset) = 0$.
  • First power set: $n(P(\emptyset)) = 2^0 = 1$ (the set is $\{\emptyset\}$).
  • Second power set: $n(P(P(\emptyset))) = 2^1 = 2$ (the set is $\{\emptyset, \{\emptyset\}\}$).
  • Third power set: $n(P(P(P(\emptyset)))) = 2^2 = 4$.

$$\therefore n(P(P(P(\emptyset)))) = 4$$

[Award 2 Marks for step-by-step evaluation of powers of 2]

Example 2
Step-by-Step Solution:

Part (a): Formal Analytical Proof [4 Marks] To prove $(A \cap B)' = A' \cup B'$, we prove mutual subset containment:

Step 1: Prove $(A \cap B)' \subseteq A' \cup B'$

  1. Let $x$ be an arbitrary element of $(A \cap B)'$.
  2. $\implies x \in (A \cap B)'$
  3. $\implies x \notin (A \cap B)$ [by definition of complement]
  4. $\implies \text{it is not true that } (x \in A \text{ and } x \in B)$
  5. $\implies x \notin A \text{ or } x \notin B$ [by logical negation of conjunction]
  6. $\implies x \in A' \text{ or } x \in B'$ [by definition of complement]
  7. $\implies x \in (A' \cup B')$ [by definition of union]
  8. Since $x$ was arbitrary: $(A \cap B)' \subseteq A' \cup B'$ ... (1) [Award 2 Marks for Step 1]

Step 2: Prove $A' \cup B' \subseteq (A \cap B)'$

  1. Let $y$ be an arbitrary element of $A' \cup B'$.
  2. $\implies y \in A' \text{ or } y \in B'$
  3. $\implies y \notin A \text{ or } y \notin B$
  4. $\implies y \notin (A \cap B)$ [since if $y \in A \cap B$, it must belong to both, which contradicts step 3]
  5. $\implies y \in (A \cap B)'$
  6. Since $y$ was arbitrary: $A' \cup B' \subseteq (A \cap B)'$ ... (2) [Award 1.5 Marks for Step 2]

From (1) and (2), we conclude:

$$\mathbf{(A \cap B)' = A' \cup B'}$$

[Award 0.5 Mark for conclusion]

Part (b): Numerical Verification [1 Mark] Given: $U = \{1, 2, 3, 4, 5, 6, 7, 8\}$, $A = \{2, 4, 6, 8\}$, $B = \{2, 3, 5, 7\}$.

  • LHS: $A \cap B = \{2\} \implies (A \cap B)' = U - \{2\} = \{1, 3, 4, 5, 6, 7, 8\}$.
  • RHS: $A' = U - A = \{1, 3, 5, 7\}$; $B' = U - B = \{1, 4, 6, 8\}$. $A' \cup B' = \{1, 3, 5, 7\} \cup \{1, 4, 6, 8\} = \{1, 3, 4, 5, 6, 7, 8\}$. Since $\text{LHS} = \text{RHS}$, the law is verified! [Award 1 Mark]
Example 3
Step-by-Step Solution:

Step 1: Define Sets and Given Cardinalities

  • Let $U$ be the universal set of surveyed students $\implies n(U) = 100$.
  • Let $P$ be the set of students who like physics $\implies n(P) = 65$.
  • Let $C$ be the set of students who like chemistry $\implies n(C) = 45$.
  • Students who like neither subject: $n(P' \cap C') = n((P \cup C)') = 15$.

Step 2: Find $n(P \cup C)$

$$n(P \cup C) = n(U) - n((P \cup C)') = 100 - 15 = 85$$

Part (i): Students liking both subjects $n(P \cap C)$ [2 Marks] Using the 2-set cardinality formula:

$$n(P \cup C) = n(P) + n(C) - n(P \cap C)$$

$$85 = 65 + 45 - n(P \cap C)$$

$$85 = 110 - n(P \cap C)$$

$$n(P \cap C) = 110 - 85 = 25$$

$\therefore$ 25 students like both physics and chemistry. [Award 2 Marks]

Part (ii): Students liking physics only [1 Mark]

$$n(P - C) = n(P) - n(P \cap C) = 65 - 25 = 40$$

$\therefore$ 40 students like physics only. [Award 1 Mark]

Part (iii): Students liking chemistry only [1 Mark]

$$n(C - P) = n(C) - n(P \cap C) = 45 - 25 = 20$$

$\therefore$ 20 students like chemistry only. [Award 1 Mark]

Verification Check: $40 \text{ (physics only)} + 25 \text{ (both)} + 20 \text{ (chem only)} + 15 \text{ (neither)} = 100 \text{ total}$. Perfect!

Example 4
Step-by-Step Solution:

Step 1: Record Given Cardinalities

  • $n(U) = 200$
  • $n(T) = 100, \quad n(A) = 70, \quad n(B) = 60$
  • $n(T \cap A) = 35, \quad n(T \cap B) = 30, \quad n(A \cap B) = 25$
  • $n(T \cap A \cap B) = 15$

Part (a): Readers who read at least one newspaper $n(T \cup A \cup B)$ [2 Marks] By the Principle of Inclusion-Exclusion for 3 sets:

$$n(T \cup A \cup B) = n(T) + n(A) + n(B) - [n(T \cap A) + n(T \cap B) + n(A \cap B)] + n(T \cap A \cap B)$$

Substitute the numerical values:

$$n(T \cup A \cup B) = 100 + 70 + 60 - [35 + 30 + 25] + 15$$

$$n(T \cup A \cup B) = 230 - 90 + 15 = 155$$

$\therefore$ 155 readers read at least one of the three newspapers. [Award 2 Marks]

Part (b): Readers who read none of the newspapers [1 Mark]

$$n(\text{None}) = n((T \cup A \cup B)') = n(U) - n(T \cup A \cup B)$$

$$n(\text{None}) = 200 - 155 = 45$$

$\therefore$ 45 readers read none of the three newspapers. [Award 1 Mark]

Part (c): Readers who read EXACTLY TWO newspapers [2 Marks] Each pairwise intersection $n(X \cap Y)$ includes the triple intersection $n(T \cap A \cap B)$. To find readers who read exactly two papers, subtract the triple intersection from each pairwise intersection:

  • Exactly $T$ and $A$ only $= n(T \cap A) - n(T \cap A \cap B) = 35 - 15 = 20$
  • Exactly $T$ and $B$ only $= n(T \cap B) - n(T \cap A \cap B) = 30 - 15 = 15$
  • Exactly $A$ and $B$ only $= n(A \cap B) - n(T \cap A \cap B) = 25 - 15 = 10$ Summing these three mutually exclusive regions:

$$\text{Total reading exactly two} = 20 + 15 + 10 = 45$$

Alternative Direct Formula:

$$n(\text{exactly two}) = [n(T \cap A) + n(T \cap B) + n(A \cap B)] - 3n(T \cap A \cap B)$$

$$n(\text{exactly two}) = 90 - 3(15) = 90 - 45 = 45$$

$\therefore$ 45 readers read exactly two newspapers. [Award 2 Marks]

Example 5
Step-by-Step Solution:

Step 1: Prove $A \cap (B \cup C) \subseteq (A \cap B) \cup (A \cap C)$ [2 Marks]

  1. Let $x \in A \cap (B \cup C)$ be an arbitrary element.
  2. $\implies x \in A$ and $x \in (B \cup C)$ [by definition of intersection]
  3. $\implies x \in A$ and ($x \in B$ or $x \in C$) [by definition of union]
  4. Case I: If $x \in B$: Since $x \in A$ and $x \in B \implies x \in A \cap B \implies x \in (A \cap B) \cup (A \cap C)$.
  5. Case II: If $x \in C$: Since $x \in A$ and $x \in C \implies x \in A \cap C \implies x \in (A \cap B) \cup (A \cap C)$.
  6. In both cases, $x \in (A \cap B) \cup (A \cap C)$.
  7. Therefore: $A \cap (B \cup C) \subseteq (A \cap B) \cup (A \cap C)$ ... (1) [Award 2 Marks for Step 1]

Step 2: Prove $(A \cap B) \cup (A \cap C) \subseteq A \cap (B \cup C)$ [2 Marks]

  1. Let $y \in (A \cap B) \cup (A \cap C)$ be an arbitrary element.
  2. $\implies y \in (A \cap B)$ or $y \in (A \cap C)$ [by definition of union]
  3. Case I: If $y \in (A \cap B)$: $\implies y \in A$ and $y \in B \implies y \in A$ and $y \in (B \cup C) \implies y \in A \cap (B \cup C)$.
  4. Case II: If $y \in (A \cap C)$: $\implies y \in A$ and $y \in C \implies y \in A$ and $y \in (B \cup C) \implies y \in A \cap (B \cup C)$.
  5. In both cases, $y \in A \cap (B \cup C)$.
  6. Therefore: $(A \cap B) \cup (A \cap C) \subseteq A \cap (B \cup C)$ ... (2) [Award 1.5 Marks for Step 2]

From (1) and (2), we establish:

$$\mathbf{A \cap (B \cup C) = (A \cap B) \cup (A \cap C)}$$

[Award 0.5 Mark for final conclusion]

Example 6
Step-by-Step Solution:

Part (i): Computing A × B and B × A [2 Marks]

  1. $A \times B = \{(a, b) : a \in A, b \in B\}$ With $A = \{1, 2, 3\}$ and $B = \{3, 4\}$:

$$A \times B = \{(1, 3), (1, 4), (2, 3), (2, 4), (3, 3), (3, 4)\}$$

  1. $B \times A = \{(b, a) : b \in B, a \in A\}$:

$$B \times A = \{(3, 1), (3, 2), (3, 3), (4, 1), (4, 2), (4, 3)\}$$

  1. Comparing elements: $(1, 3) \in A \times B$, but $(1, 3) \notin B \times A$ (since $(3, 1) \neq (1, 3)$).

$$\therefore A \times B \neq B \times A$$

Cartesian product is non-commutative. [Award 2 Marks]

Part (ii): Finding $(A \times B) \cap (B \times A)$ [1 Mark] Looking for common ordered pairs in both sets: Only the pair $(3, 3)$ appears in both $A \times B$ and $B \times A$.

$$\therefore (A \times B) \cap (B \times A) = \{(3, 3)\}$$

General Formula Note: $(A \times B) \cap (B \times A) = (A \cap B) \times (B \cap A) = \{3\} \times \{3\} = \{(3, 3)\}$. [Award 1 Mark]

Part (iii): Total Number of Relations from A to B [1 Mark]

  • $n(A) = 3$ and $n(B) = 2 \implies n(A \times B) = 3 \times 2 = 6$.
  • Any subset of $A \times B$ defines a relation from $A$ to $B$.
  • Total number of subsets of $A \times B = 2^{n(A \times B)} = 2^6 = 64$. $\therefore$ There are 64 possible relations from $A$ to $B$. [Award 1 Mark]

Common Misconceptions & Examiner Traps

Common Misconception

Writing {∅} or {0} when an empty set is required, or asserting that ∅ = {0} = {∅}.

Scientific Reality & Correction

The empty set has zero elements and is written simply as ∅ or {}. In sharp contrast, {0} is a singleton set containing the number 0 (n({0}) = 1), and {∅} is a singleton set containing the empty set as its single element (n({∅}) = 1).

Common Misconception

Confusing membership (∈) with subset inclusion (⊆), e.g., writing 1 ⊆ {1, 2} or {1} ∈ {1, 2}.

Scientific Reality & Correction

∈ links an individual element to a set (e.g., 1 ∈ {1, 2}), while ⊆ links one set to another set (e.g., {1} ⊆ {1, 2}). If an element itself happens to be a set, like A = {{1}, 2}, then {1} ∈ A and {{1}} ⊆ A.

Common Misconception

Calculating proper subsets of a set with n elements as 2^n instead of 2^n - 1.

Scientific Reality & Correction

A subset S ⊆ A is proper if and only if S ≠ A. Because every set contains itself (A ⊆ A), exactly one subset is improper. Hence, the number of proper subsets is strictly 2^n - 1.

Common Misconception

Mishandling operators in De Morgan's Laws, such as writing (A ∪ B)' = A' ∪ B'.

Scientific Reality & Correction

Complementation reverses the logical operator: Union becomes Intersection, and Intersection becomes Union! Specifically: (A ∪ B)' = A' ∩ B' and (A ∩ B)' = A' ∪ B'.

Common Misconception

Subtracting the triple intersection in the 3-set inclusion-exclusion formula instead of adding it back.

Scientific Reality & Correction

The elements in A ∩ B ∩ C are counted 3 times in n(A)+n(B)+n(C), and then subtracted 3 times in -[n(AB)+n(BC)+n(CA)]. This leaves them counted 0 times! To include them once in the union, +n(A ∩ B ∩ C) MUST be added.

Sets & Venn Diagram Algebra Architectural Roadmap

WBCHSE CLASS 11 MATHEMATICS • UNIT I: SETS & FUNCTIONS FOUNDATIONS OF SET THEORY, VENN ALGEBRA & CARDINALITY Georg Cantor Axioms • Set Operations • De Morgan Laws • Inclusion-Exclusion Principles 1. SET FOUNDATIONS & FORMS Well-Defined Collections & Membership Well-defined collection of distinct mathematical objects x ∈ A (x belongs to A), x ∉ A (x does not belong to A) Roster vs Set-Builder Form Roster (Tabular): A = {2, 3, 5, 7, 11} Set-Builder: {x : x is a prime number, x ≤ 11} Types of Sets & Real Intervals • Empty / Null Set: ∅ or {}, n(∅) = 0 • Singleton Set: exactly 1 element, n(A) = 1 • Subset (A ⊆ B), Proper Subset (A ⊂ B) • Intervals on ℝ: [a, b], (a, b), [a, b), (a, b] Power Set P(A) & Cardinality Total Subsets of finite set = 2^n Proper Subsets = 2^n - 1 Power Set: P(A) = {S : S ⊆ A}, |P(A)| = 2^n 2. VENN DIAGRAMS & OPERATIONS U A B Union: A ∪ B {x : x ∈ A or x ∈ B or both} n(A∪B) = n(A)+n(B)-n(A∩B) U A B Intersection: A ∩ B {x : x ∈ A and x ∈ B} A ∩ B = ∅ ⇒ Disjoint Sets U A-B B Difference: A - B {x : x ∈ A and x ∉ B} = A ∩ B' n(A - B) = n(A) - n(A ∩ B) U A-B B-A Symmetric Diff: A Δ B (A - B) ∪ (B - A) = (A ∪ B) - (A ∩ B) n(AΔB) = n(A)+n(B)-2n(A∩B) U A A' Complement: A' U - A = {x ∈ U : x ∉ A} A ∪ A' = U | A ∩ A' = ∅ 3. ALGEBRA OF SETS & CARDINALITY De Morgan's Laws (A ∪ B)' = A' ∩ B' (A ∩ B)' = A' ∪ B' Distributive & Involution Laws A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C) A ∪ (B ∩ C) = (A ∪ B) ∩ (A ∪ C) (A')' = A, A ∪ A' = U, A ∩ A' = ∅ 2-Set Cardinality Principle n(A ∪ B) = n(A) + n(B) - n(A ∩ B) Disjoint Sets (A ∩ B = ∅): n(A ∪ B) = n(A) + n(B) 3-Set Inclusion-Exclusion Formula n(A ∪ B ∪ C) = n(A) + n(B) + n(C) - [n(A∩B) + n(B∩C) + n(C∩A)] + n(A ∩ B ∩ C) TargetExams Gold Standard • WBCHSE Class 11 Mathematics • Chapter 1: Sets

Chapter Summary & 10 Key Takeaways

Takeaway 1
A set is a well-defined collection of distinct objects; collections based on subjective qualifiers like "best" or "intelligent" are mathematically invalid.
Takeaway 2
Sets are represented in Roster (Tabular) form by listing elements inside braces separated by commas, or in Set-Builder (Rule) form using a characteristic predicate P(x).
Takeaway 3
The Empty or Null set ∅ contains no elements; its cardinality is n(∅) = 0. Notice that {∅} is a non-empty singleton set containing ∅ as an element.
Takeaway 4
For a finite set A with n elements, the total number of subsets is 2^n, the number of proper subsets is 2^n - 1, and the number of non-empty subsets is 2^n - 1.
Takeaway 5
The Power Set P(A) is the set of all subsets of A; its cardinality is |P(A)| = 2^n, and |P(P(A))| = 2^(2^n).
Takeaway 6
Subsets of real numbers ℝ are represented geometrically as open intervals (a, b), closed intervals [a, b], and semi-open intervals [a, b) or (a, b].
Takeaway 7
Set operations include Union (A ∪ B, logical OR), Intersection (A ∩ B, logical AND), Difference (A - B = A ∩ B'), and Symmetric Difference (A Δ B = (A - B) ∪ (B - A)).
Takeaway 8
De Morgan's Laws state that the complement of a union is the intersection of complements: (A ∪ B)' = A' ∩ B', and the complement of an intersection is the union of complements: (A ∩ B)' = A' ∪ B'.
Takeaway 9
The Two-Set Cardinality Principle states n(A ∪ B) = n(A) + n(B) - n(A ∩ B); when sets are disjoint (A ∩ B = ∅), n(A ∪ B) = n(A) + n(B).
Takeaway 10
The Three-Set Inclusion-Exclusion Formula is n(A ∪ B ∪ C) = n(A) + n(B) + n(C) - [n(A ∩ B) + n(B ∩ C) + n(C ∩ A)] + n(A ∩ B ∩ C).

Check Your Understanding (Diagnostic Practice Questions)

Diagnostic questions testing core conceptual clarity. Answers are hidden initially — solve each problem first, then click to reveal the step-by-step verified solution.

1
State whether the collection of all natural numbers that are roots of the equation x² - 7x + 12 = 0 is a finite or infinite set, and write it in roster form.
Reveal Answer & Explanation
Answer: Solving x² - 7x + 12 = 0 gives (x - 3)(x - 4) = 0, so x = 3 or x = 4. Both 3 and 4 are natural numbers. In roster form, the set is {3, 4}. Since it has a finite count of elements (cardinality 2), it is a finite set.
Factorize the quadratic expression into (x - a)(x - b) = 0 and verify if the roots are in ℕ.
2
If a finite set A has 5 elements, find: (i) the total number of subsets, (ii) the total number of proper subsets, and (iii) the cardinality of its power set P(A).
Reveal Answer & Explanation
Answer: (i) Total subsets = 2^5 = 32. (ii) Total proper subsets = 2^5 - 1 = 31. (iii) Cardinality of power set |P(A)| = 2^5 = 32.
Recall that the total number of subsets and the cardinality of P(A) are given by 2^n.
3
Under what mathematical condition is A - B = A? Under what condition is A - B = ∅?
Reveal Answer & Explanation
Answer:
  1. A - B = A if and only if A and B have no elements in common, i.e., A ∩ B = ∅ (A and B are disjoint sets).
  2. A - B = ∅ if and only if every element of A is also in B, i.e., A ⊆ B.

Consider what elements are removed from A when subtracting B.
4
Let U = {x ∈ ℕ : x ≤ 10}, A = {1, 3, 5, 7, 9}, and B = {2, 3, 5, 7}. Find (A Δ B)' and verify its elements.
Reveal Answer & Explanation
Answer: U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. A - B = {1, 9}; B - A = {2}. A Δ B = (A - B) ∪ (B - A) = {1, 2, 9}. Therefore, (A Δ B)' = U - {1, 2, 9} = {3, 4, 5, 6, 7, 8, 10}.
First find A Δ B = (A - B) ∪ (B - A), then find its complement in U.
5
In a survey of 50 students, 30 study Mathematics and 25 study Physics. If every student studies at least one of these two subjects, how many students study both subjects?
Reveal Answer & Explanation
Answer: Given n(M ∪ P) = 50, n(M) = 30, and n(P) = 25. 50 = 30 + 25 - n(M ∩ P) = 55 - n(M ∩ P). n(M ∩ P) = 55 - 50 = 5. Therefore, exactly 5 students study both Mathematics and Physics.
Use n(M ∪ P) = n(M) + n(P) - n(M ∩ P) with n(M ∪ P) = 50.
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