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WBB • Class XI • Mathematics • Ch 13
Estimated Time: 85 minutes
Study Progress: In Progress

Statistics

Statistics is the mathematical discipline dedicated to collecting, organizing, analyzing, interpreting, and presenting quantitative data to draw valid inferences and support decision-making under uncertainty. In secondary mathematics, students mastered measures of central tendency—arithmetic mean, median, and mode—which identify a single representative central value for a dataset. However, central tendency measures alone cannot capture how individual data values are scattered or dispersed around that center. Two completely different datasets can possess identical arithmetic means yet exhibit radically contrasting patterns of variability. In this chapter, students explore measures of dispersion, which quantify the degree of scatter, spread, or heterogeneity in a distribution. The curriculum systematically advances through the range, mean deviation about the mean and median, Karl Pearson root-mean-square standard deviation, variance, and the step-deviation calculation method. Furthermore, students analyze how algebraic transformations affect dispersion, prove that variance is invariant under origin translation but scales quadratically under dilation, and apply the coefficient of variation to evaluate consistency, uniformity, and stability across competing datasets.

Why This Chapter Matters

Measures of dispersion form the bedrock of empirical science, modern machine learning, quality control engineering, financial economics, and medical research. In financial portfolio management and algorithmic trading, variance and standard deviation serve as the formal definitions of market volatility and investment risk; the celebrated Sharpe Ratio relies directly on standard deviation to assess whether an asset returns justify its risk exposure. In manufacturing and industrial engineering, the Six Sigma methodology uses standard deviation to guarantee that defect rates remain below 3.4 parts per million in precision fabrication. In meteorology and climate science, standard deviations of temperature and rainfall anomalies distinguish natural periodic fluctuations from long-term climate change. In clinical pharmacology and epidemiology, comparing the coefficient of variation between drug treatment groups and placebos establishes biological efficacy and pharmacokinetic consistency. For students preparing for WBCHSE Class 11 annual examinations, WBJEE, and JEE Advanced, Statistics is a vital, high-scoring chapter that bridges arithmetic data handling with analytical probability theory.

Chapter Roadmap & Progression

1 1. Concept of Dispersion & Limitati...
2 2. Mean Deviation about Arithmetic...
3 3. Variance and Standard Deviation:...
4 4. Short-Cut & Step-Deviation Metho...
5 5. Mathematical Properties of Varia...
6 6. Coefficient of Variation (C.V.)...

Complete Concept Guide (100% Curriculum Coverage)

1. Concept of Dispersion & Limitations of Central Tendency

While measures of central tendency summarize a distribution by a single central value, measures of dispersion describe how individual values scatter around that center.

1.1 Why Measures of Central Tendency Are Insufficient

Consider three distinct data series, each containing 5 observations:

  • Series A: $50, \; 50, \; 50, \; 50, \; 50 \implies \text{Mean } \bar{x} = 50$
  • Series B: $48, \; 49, \; 50, \; 51, \; 52 \implies \text{Mean } \bar{x} = 50$
  • Series C: $0, \; 25, \; 50, \; 75, \; 100 \implies \text{Mean } \bar{x} = 50$

All three series have identical means, medians, and modes equal to $50$. Yet Series A has zero spread, Series B has very low spread, and Series C is wildly dispersed. Thus, a measure of central tendency alone fails to characterize the internal distribution of data.

1.2 Meaning and Definition of Dispersion
Dispersion: The degree to which numerical data tend to spread about an average value is called the variation or dispersion of the data.
  • Absolute Measures of Dispersion: Expressed in the same physical units as the original observations (e.g., Range, Mean Deviation, Standard Deviation).
  • Relative Measures of Dispersion: Pure, dimensionless ratios or percentages independent of measurement units, used to compare datasets with different units or disparate scales (e.g., Coefficient of Variation).
1.3 The Range

The simplest measure of dispersion is the Range ($R$), defined as the algebraic difference between the highest (maximum) and lowest (minimum) observations:

$$\mathbf{R = X_{\text{max}} - X_{\text{min}} = L - S}$$ where $L$ is the largest value and $S$ is the smallest value.
Coefficient of Range (Relative Measure): $$\text{Coefficient of Range} = \frac{L - S}{L + S}$$

Merits & Demerits of Range:

  • Merits: Extremely easy to compute and understand; useful in industrial statistical quality control charts (e.g., R-charts) and daily weather forecasts.
  • Demerits: Highly sensitive to extreme outliers; utilizes only two extreme values and completely ignores the distribution of the remaining $n - 2$ intermediate observations; cannot be computed for open-ended frequency tables.

2. Mean Deviation about Arithmetic Mean & Median

Mean Deviation measures dispersion by calculating the arithmetic average of the absolute differences between each observation and a chosen central value.

2.1 Mathematical Rationale for Absolute Values

By the algebraic property of the arithmetic mean, the sum of signed deviations from the mean is identically zero:

$$\sum_{i=1}^n (x_i - \bar{x}) = 0$$

To avoid this self-cancellation, we take the absolute value (modulus) of each deviation: $|x_i - \bar{x}| \ge 0$.

2.2 Mean Deviation for Ungrouped Data
Let $x_1, x_2, \dots, x_n$ be $n$ observations:
  • Mean Deviation about the Mean $\bar{x}$: $$\mathbf{\text{MD}(\bar{x}) = \frac{1}{n} \sum_{i=1}^n |x_i - \bar{x}|}$$
  • Mean Deviation about the Median $M$: $$\mathbf{\text{MD}(M) = \frac{1}{n} \sum_{i=1}^n |x_i - M|}$$
2.3 Mean Deviation for Grouped Data

For a discrete frequency distribution $(x_i, f_i)$ or continuous frequency distribution with class mid-points $x_i$ and total frequency $N = \sum_{i=1}^k f_i$:

$$\mathbf{\text{MD}(A) = \frac{\sum_{i=1}^k f_i |x_i - A|}{N} = \frac{\sum_{i=1}^k f_i |x_i - A|}{\sum_{i=1}^k f_i}}$$ where $A = \bar{x}$ (for mean deviation about mean) or $A = M$ (for mean deviation about median).
2.4 The Minimal Property of Median
Theorem: The sum of the absolute deviations of a set of observations is minimum when the deviations are taken about the median. $$\sum_{i=1}^n |x_i - M| \le \sum_{i=1}^n |x_i - A| \quad \text{for any real number } A$$ Consequently, $\text{MD}(M) \le \text{MD}(\bar{x})$ for any dataset.

3. Variance and Standard Deviation: Definition & Foundations

Introduced by Karl Pearson in 1893, the standard deviation overcomes the mathematical limitations of absolute values by squaring deviations, forming the gold standard of statistical dispersion.

3.1 Definition of Variance and Standard Deviation
Variance ($\sigma^2$): The arithmetic mean of the squares of the deviations of all observations from their arithmetic mean is defined as the Variance.
Standard Deviation ($\sigma$): The positive square root of the variance is called the Standard Deviation (root-mean-square deviation): $$\mathbf{\sigma = +\sqrt{\text{Variance}}}$$ Units: Standard deviation carries the exact same units as the original variable $x$, whereas variance carries squared units (e.g., $\text{cm}^2$, $\text{kg}^2$).
3.2 Formulas for Ungrouped Data

Let $x_1, x_2, \dots, x_n$ have mean $\bar{x} = \frac{1}{n}\sum x_i$:

  • Direct Definition Form: $$\mathbf{\sigma^2 = \frac{1}{n} \sum_{i=1}^n (x_i - \bar{x})^2}$$
  • Expanded Computational Form: $$\sigma^2 = \frac{1}{n}\sum (x_i^2 - 2x_i\bar{x} + \bar{x}^2) = \frac{1}{n}\sum x_i^2 - 2\bar{x}\left(\frac{\sum x_i}{n}\right) + \bar{x}^2 = \frac{1}{n}\sum x_i^2 - \bar{x}^2$$
    $$\mathbf{\sigma^2 = \frac{\sum x_i^2}{n} - \left(\frac{\sum x_i}{n}\right)^2 \iff \sigma = \sqrt{\frac{\sum x_i^2}{n} - \bar{x}^2}}$$
3.3 Formulas for Grouped Data (Discrete & Continuous)

Let $x_i$ denote the observations (or class mid-points in continuous intervals) with corresponding frequencies $f_i$, and total frequency $N = \sum f_i$:

$$\mathbf{\sigma^2 = \frac{1}{N} \sum_{i=1}^k f_i (x_i - \bar{x})^2 = \frac{\sum f_i x_i^2}{N} - \left(\frac{\sum f_i x_i}{N}\right)^2}$$ $$\mathbf{\sigma = \sqrt{\frac{\sum f_i x_i^2}{N} - \bar{x}^2}}$$

4. Short-Cut & Step-Deviation Methods for Large Distributions

When data values or class mid-points are large numbers with decimals, direct calculation of $x_i^2$ becomes tedious. Change of origin and scale radically streamlines arithmetic.

4.1 Assumed Mean (Short-Cut) Method

Let $A$ be an assumed mean. Define deviation $d_i = x_i - A$:

$$\bar{x} = A + \frac{\sum f_i d_i}{N}$$ $$\mathbf{\sigma^2 = \frac{\sum f_i d_i^2}{N} - \left(\frac{\sum f_i d_i}{N}\right)^2 \iff \sigma = \sqrt{\frac{\sum f_i d_i^2}{N} - \left(\frac{\sum f_i d_i}{N}\right)^2}}$$
4.2 Step-Deviation Method for Equal Class Widths ($h$)

When the data is grouped into continuous classes of equal interval width $h$, define the step-deviation variable:

$$u_i = \frac{x_i - A}{h} \iff x_i = A + h u_i$$
Arithmetic Mean: $$\mathbf{\bar{x} = A + h \cdot \bar{u} = A + h \left(\frac{\sum f_i u_i}{N}\right)}$$ Variance: $$\mathbf{\sigma^2 = h^2 \left[ \frac{\sum f_i u_i^2}{N} - \left(\frac{\sum f_i u_i}{N}\right)^2 \right]}$$ Standard Deviation: $$\mathbf{\sigma = h \sqrt{\frac{\sum f_i u_i^2}{N} - \left(\frac{\sum f_i u_i}{N}\right)^2}}$$ Crucial Caution: The factor $h$ is outside the square root; when calculating variance, remember to square $h$ to $h^2$!

5. Mathematical Properties of Variance & Linear Transformations

Understanding how linear transformations affect variance and standard deviation provides powerful theoretical shortcuts in competitive examinations.

5.1 Theorem: Invariance Under Origin Shift (Translation)
Property 1: The variance and standard deviation of a dataset are independent of the change of origin.
If each observation $x_i$ is increased or decreased by a constant $c$, such that $y_i = x_i \pm c$: $$\bar{y} = \bar{x} \pm c$$ $$\mathbf{\text{Var}(Y) = \text{Var}(X) \quad \text{and} \quad \sigma_y = \sigma_x}$$ Intuition: Shifting the entire dataset along the number line moves the center, but the distance between individual data points remains completely invariant.
5.2 Theorem: Scaling Under Dilation (Multiplication)
Property 2: The variance and standard deviation are dependent on the change of scale.
If each observation $x_i$ is multiplied by a non-zero constant $a$, such that $y_i = a x_i$: $$\bar{y} = a \bar{x}$$ $$\mathbf{\text{Var}(Y) = a^2 \text{Var}(X) \quad \text{and} \quad \sigma_y = |a| \sigma_x}$$
5.3 Combined Linear Transformation ($y = ax + b$)

Combining origin shift and scaling: if $y_i = a x_i + b$ for constants $a$ and $b$:

$$\mathbf{\bar{y} = a\bar{x} + b}$$ $$\mathbf{\text{Var}(Y) = a^2 \text{Var}(X)}$$ $$\mathbf{\sigma_y = |a| \sigma_x}$$ Notice that the additive constant $b$ has zero effect on variance or standard deviation!
5.4 Combined Variance of Two Groups

Let two groups have sizes $n_1$ and $n_2$, means $\bar{x}_1$ and $\bar{x}_2$, and variances $\sigma_1^2$ and $\sigma_2^2$:

  1. Combined Mean: $\mathbf{\bar{x} = \frac{n_1 \bar{x}_1 + n_2 \bar{x}_2}{n_1 + n_2}}$
  2. Let deviation of group means from combined mean be $d_1 = \bar{x}_1 - \bar{x}$ and $d_2 = \bar{x}_2 - \bar{x}$.
  3. Combined Variance: $$\mathbf{\sigma^2 = \frac{n_1(\sigma_1^2 + d_1^2) + n_2(\sigma_2^2 + d_2^2)}{n_1 + n_2}}$$

6. Coefficient of Variation (C.V.) & Comparative Data Analysis

When comparing dispersion between two distributions measured in different units (e.g., heights in cm vs weights in kg) or with widely different mean levels, standard deviation alone is inadequate.

6.1 Karl Pearson Coefficient of Variation
Definition: The Coefficient of Variation (C.V.) is defined as the ratio of the standard deviation to the arithmetic mean, expressed as a percentage: $$\mathbf{\text{C.V.} = \frac{\sigma}{\bar{x}} \times 100 \quad (\bar{x} > 0)}$$ Because $\sigma$ and $\bar{x}$ have identical physical units, the units cancel out, rendering C.V. a pure, dimensionless percentage.
6.2 Rules for Comparing Two Distributions
Statistical Metric Higher Value Lower Value
Coefficient of Variation (C.V.) Greater variability, greater scatter, less consistent, less uniform, less stable Lesser variability, tighter clustering, more consistent, more uniform, more stable
Equal Means ($\bar{x}_1 = \bar{x}_2$) The series with the larger $\sigma$ is less consistent The series with the smaller $\sigma$ is more consistent
6.3 Practical Applications in Science and Industry
  • Quality Assurance & Manufacturing: In production lines, batches with lower C.V. of dimensions indicate superior machine calibration and fewer defective parts.
  • Financial Risk Management: Investors evaluate the volatility per unit of expected return. Two stocks may offer 10% expected return, but the stock with lower C.V. delivers that return with much less risk.
  • Sports Performance Analytics: In cricket, baseball, and athletics, selecting reliable tournament squads requires identifying players whose scoring distributions exhibit small C.V.

Key Formulas, Identities & Theorems

Mean Deviation Formula
$$MD = (1/N) Σ f_i |x_i - A|$$
Minimization property: Σ |x_i - A| is minimum when A is the median.
Variance & Standard Deviation (Direct)
$$σ² = (1/N)Σf_i x_i² - x̄², σ = √Var$$
Standard deviation carries the same physical units as the original observations.
Step-Deviation Standard Deviation
σ = h √[(Σfu²/N) - (Σfu/N)²]
h is class width, A is assumed mean. Variance is σ² = h² [...].
Linear Transformation Rules
$$Var(ax + b) = a² Var(x), σ_y = |a| σ_x$$
Variance is independent of origin shift b, but scales with a².
Combined Variance Formula
σ² = [n₁(σ₁² + d₁²) + n₂(σ₂² + d₂²)] / (n₁ + n₂)
d₁ and d₂ represent deviations of group means from the pooled combined mean.
Coefficient of Variation (C.V.)
C.V. = (σ / x̄) × 100
Pure dimensionless percentage. Lower C.V. indicates greater consistency and stability.

Conceptual Solved Examples & Case Studies

Example 1
Find the mean deviation about the arithmetic mean for the data: \(4, 7, 8, 9, 10, 12, 13, 17\). [2 marks]
Step-by-Step Solution:
Solution: Given observations: $$4, \; 7, \; 8, \; 9, \; 10, \; 12, \; 13, \; 17$$ Number of observations $n = 8$. Step 1: Calculate the arithmetic mean ($\bar{x}$): $$\bar{x} = \frac{\sum x_i}{n} = \frac{4 + 7 + 8 + 9 + 10 + 12 + 13 + 17}{8} = \frac{80}{8} = 10$$ Step 2: Calculate absolute deviations $|x_i - \bar{x}|$: $$\begin{aligned} |4 - 10| &= 6 \\ |7 - 10| &= 3 \\ |8 - 10| &= 2 \\ |9 - 10| &= 1 \\ |10 - 10| &= 0 \\ |12 - 10| &= 2 \\ |13 - 10| &= 3 \\ |17 - 10| &= 7 \end{aligned}$$ Step 3: Sum the absolute deviations: $$\sum |x_i - \bar{x}| = 6 + 3 + 2 + 1 + 0 + 2 + 3 + 7 = 24$$ Step 4: Compute Mean Deviation about the mean: $$\mathbf{\text{MD}(\bar{x}) = \frac{\sum |x_i - \bar{x}|}{n} = \frac{24}{8} = 3}$$ Hence, the mean deviation about the mean is $3$.
Example 2
Find the mean deviation about the median for the observations: \(3, 9, 5, 3, 12, 10, 18, 4, 7, 19, 21\). [3 marks]
Step-by-Step Solution:
Solution: Given observations: $$3, \; 9, \; 5, \; 3, \; 12, \; 10, \; 18, \; 4, \; 7, \; 19, \; 21$$ Number of observations $n = 11$ (an odd integer). Step 1: Arrange data in ascending order: $$3, \; 3, \; 4, \; 5, \; 7, \; 9, \; 10, \; 12, \; 18, \; 19, \; 21$$ Step 2: Determine the median ($M$): $$\text{Median } M = \left(\frac{n + 1}{2}\right)\text{-th term} = \left(\frac{11 + 1}{2}\right)\text{-th term} = 6\text{-th term} = \mathbf{9}$$ Step 3: Compute absolute deviations from median $|x_i - M| = |x_i - 9|$: $$\begin{aligned} |3 - 9| &= 6, \quad |3 - 9| = 6, \quad |4 - 9| = 5, \quad |5 - 9| = 4, \quad |7 - 9| = 2 \\ |9 - 9| &= 0, \quad |10 - 9| = 1, \quad |12 - 9| = 3, \quad |18 - 9| = 9, \quad |19 - 9| = 10, \quad |21 - 9| = 12 \end{aligned}$$ Step 4: Sum of absolute deviations: $$\sum |x_i - M| = 6 + 6 + 5 + 4 + 2 + 0 + 1 + 3 + 9 + 10 + 12 = 58$$ Step 5: Compute Mean Deviation about the median: $$\mathbf{\text{MD}(M) = \frac{\sum |x_i - M|}{n} = \frac{58}{11} \approx 5.27}$$ Hence, the mean deviation about the median is $\frac{58}{11} \approx 5.27$.
Example 3
Prove that the variance of the first \(n\) natural numbers is \(\frac{n^2 - 1}{12}\). Hence, calculate the standard deviation for the first \(10\) natural numbers. [3 marks]
Step-by-Step Solution:
Solution: The first $n$ natural numbers are $1, 2, 3, \dots, n$. Step 1: Calculate the mean ($\bar{x}$): $$\sum_{i=1}^n x_i = \frac{n(n + 1)}{2} \implies \bar{x} = \frac{1}{n} \left(\frac{n(n + 1)}{2}\right) = \frac{n + 1}{2}$$ Step 2: Calculate the mean of squares $\frac{1}{n}\sum x_i^2$: $$\sum_{i=1}^n x_i^2 = \frac{n(n + 1)(2n + 1)}{6} \implies \frac{1}{n}\sum_{i=1}^n x_i^2 = \frac{(n + 1)(2n + 1)}{6}$$ Step 3: Compute the variance ($\sigma^2$): $$\begin{aligned} \sigma^2 &= \frac{1}{n}\sum x_i^2 - \bar{x}^2 = \frac{(n + 1)(2n + 1)}{6} - \left(\frac{n + 1}{2}\right)^2 \\ &= \frac{n + 1}{2} \left[ \frac{2n + 1}{3} - \frac{n + 1}{2} \right] \\ &= \frac{n + 1}{2} \left[ \frac{2(2n + 1) - 3(n + 1)}{6} \right] \\ &= \frac{n + 1}{2} \left[ \frac{4n + 2 - 3n - 3}{6} \right] = \frac{n + 1}{2} \cdot \frac{n - 1}{6} = \mathbf{\frac{n^2 - 1}{12}} \end{aligned}$$ Hence proved: $\text{Variance} = \frac{n^2 - 1}{12}$. Step 4: Standard deviation for first $10$ natural numbers ($n = 10$): $$\sigma^2 = \frac{10^2 - 1}{12} = \frac{100 - 1}{12} = \frac{99}{12} = \frac{33}{4} = 8.25$$ $$\mathbf{\sigma = \sqrt{8.25} = \frac{\sqrt{33}}{2} \approx 2.87}$$ Hence, the standard deviation is approximately $2.87$.
Example 4
Calculate the mean, variance, and standard deviation for the following discrete frequency distribution: [4 marks] Values (x): 6, 10, 14, 18, 24, 28, 30 Frequencies (f): 2, 4, 7, 12, 8, 4, 3
Step-by-Step Solution:
Solution: Construct the calculation table with assumed mean $A = 18$: $$\begin{array}{|c|c|c|c|c|c|} \hline x_i & f_i & d_i = x_i - 18 & f_i d_i & d_i^2 & f_i d_i^2 \\ \hline 6 & 2 & -12 & -24 & 144 & 288 \\ 10 & 4 & -8 & -32 & 64 & 256 \\ 14 & 7 & -4 & -28 & 16 & 112 \\ 18 & 12 & 0 & 0 & 0 & 0 \\ 24 & 8 & 6 & 48 & 36 & 288 \\ 28 & 4 & 10 & 40 & 100 & 400 \\ 30 & 3 & 12 & 36 & 144 & 432 \\ \hline \text{Total} & N = 40 & - & \sum f_i d_i = 40 & - & \sum f_i d_i^2 = 1776 \\ \hline \end{array}$$ 1. Arithmetic Mean ($\bar{x}$): $$\mathbf{\bar{x} = A + \frac{\sum f_i d_i}{N} = 18 + \frac{40}{40} = 18 + 1 = 19}$$ 2. Variance ($\sigma^2$): $$\begin{aligned} \sigma^2 &= \frac{\sum f_i d_i^2}{N} - \left(\frac{\sum f_i d_i}{N}\right)^2 \\ &= \frac{1776}{40} - (1)^2 = 44.4 - 1 = \mathbf{43.4} \end{aligned}$$ 3. Standard Deviation ($\sigma$): $$\mathbf{\sigma = \sqrt{43.4} \approx 6.59}$$ Hence, Mean = $19$, Variance = $43.4$, and Standard Deviation $\approx 6.59$.
Example 5
The mean and standard deviation of 20 observations were calculated as 10 and 2 respectively. On checking, it was discovered that an observation 8 was incorrect. Calculate the correct mean and standard deviation if: (i) the incorrect observation is omitted, and (ii) it is replaced by 12. [4 marks]
Step-by-Step Solution:
Solution: Given: $n = 20, \; \bar{x} = 10, \; \sigma = 2 \implies \sigma^2 = 4$. $$\bar{x} = \frac{\sum x}{20} = 10 \implies \sum x = 20 \times 10 = 200$$ Using $\sigma^2 = \frac{\sum x^2}{n} - \bar{x}^2$: $$4 = \frac{\sum x^2}{20} - 100 \implies \frac{\sum x^2}{20} = 104 \implies \sum x^2 = 2080$$
Case (i): When incorrect observation 8 is omitted: New number of observations $n' = 20 - 1 = 19$. $$\text{Correct } \sum x = 200 - 8 = 192$$ $$\text{Correct Mean } \mathbf{\bar{x}' = \frac{192}{19} \approx 10.11}$$ $$\text{Correct } \sum x^2 = 2080 - 8^2 = 2080 - 64 = 2016$$ $$\text{Correct } \sigma'^2 = \frac{2016}{19} - \left(\frac{192}{19}\right)^2 = \frac{2016 \times 19 - 36864}{361} = \frac{38304 - 36864}{361} = \frac{1440}{361} \approx 3.99$$ $$\text{Correct Standard Deviation } \mathbf{\sigma' = \frac{\sqrt{1440}}{19} = \frac{12\sqrt{10}}{19} \approx 1.997}$$
Case (ii): When incorrect observation 8 is replaced by 12: Number of observations remains $n = 20$. $$\text{Correct } \sum x = 200 - 8 + 12 = 204$$ $$\text{Correct Mean } \mathbf{\bar{x}'' = \frac{204}{20} = 10.2}$$ $$\text{Correct } \sum x^2 = 2080 - 8^2 + 12^2 = 2080 - 64 + 144 = 2160$$ $$\text{Correct } \sigma''^2 = \frac{2160}{20} - (10.2)^2 = 108 - 104.04 = \mathbf{3.96}$$ $$\text{Correct Standard Deviation } \mathbf{\sigma'' = \sqrt{3.96} \approx 1.99}$$
Example 6
Two plants A and B in a factory produce steel rods. The lengths (in cm) of rods produced by both plants across 50 sample tests have the following statistics: Plant A: Mean length = 20 cm, Standard Deviation = 1.6 cm Plant B: Mean length = 25 cm, Standard Deviation = 1.75 cm (a) Which plant produces longer rods on average? (b) Which plant shows greater consistency in manufacturing length? [5 marks]
Step-by-Step Solution:
Solution: Given statistics for the two plants: $$\begin{array}{|c|c|c|} \hline \text{Parameter} & \text{Plant A} & \text{Plant B} \\ \hline \text{Sample Size } (n) & 50 & 50 \\ \text{Mean } (\bar{x}) & 20 \text{ cm} & 25 \text{ cm} \\ \text{Standard Deviation } (\sigma) & 1.6 \text{ cm} & 1.75 \text{ cm} \\ \hline \end{array}$$
Part (a): Comparison of Average Length: $$\bar{x}_B = 25 \text{ cm} > \bar{x}_A = 20 \text{ cm}$$ Therefore, Plant B produces longer rods on average.
Part (b): Comparison of Manufacturing Consistency: To evaluate consistency between two distributions with different means, we must compute their respective Coefficients of Variation (C.V.): $$\text{C.V.} = \frac{\sigma}{\bar{x}} \times 100$$ For Plant A: $$\mathbf{\text{C.V.}_A = \frac{\sigma_A}{\bar{x}_A} \times 100 = \frac{1.6}{20} \times 100 = 0.08 \times 100 = 8.0\%}$$ For Plant B: $$\mathbf{\text{C.V.}_B = \frac{\sigma_B}{\bar{x}_B} \times 100 = \frac{1.75}{25} \times 100 = 0.07 \times 100 = 7.0\%}$$
Conclusion: Comparing the two coefficients of variation: $$\text{C.V.}_B = 7.0\% < \text{C.V.}_A = 8.0\%$$ Since Plant B has a lower Coefficient of Variation, its relative dispersion is smaller. Hence, Plant B shows greater consistency (uniformity/stability) in manufacturing rod lengths, despite having a slightly higher absolute standard deviation.

Common Misconceptions & Examiner Traps

Common Misconception

Scientific Reality & Correction

The sum of algebraic deviations from the arithmetic mean is always identically zero (Σ (x_i - x̄) = 0). You must take the absolute value |x_i - x̄| for every observation.

Common Misconception

Scientific Reality & Correction

In the step-deviation formula, standard deviation is multiplied by h (σ = h √[...]), whereas variance is multiplied by h² (σ² = h² [...]).

Common Misconception

Scientific Reality & Correction

Standard deviation is completely independent of origin shifts. Adding or subtracting a constant c shifts the mean by c, but the distances between points remain unchanged: σ_{x+c} = σ_x.

Common Misconception

Scientific Reality & Correction

A higher mean only indicates a higher average level, not consistency. Consistency is strictly measured by a lower Coefficient of Variation (C.V. = σ/x̄ × 100).

Common Misconception

Scientific Reality & Correction

Combined variance is NOT simply the weighted average of individual variances. You must include the shift terms d_i² = (x̄_i - x̄)²: σ² = [n₁(σ₁² + d₁²) + n₂(σ₂² + d₂²)] / (n₁ + n₂).

Measures of Dispersion, Variance & Coefficient of Variation Architecture

Σ Statistics: Measures of Dispersion & Variability Analysis WBCHSE Class 11 Mathematics (Mean Deviation, Variance, Standard Deviation & C.V.) Mean Deviation (M.D.) M.D. about Mean & Median About Mean: MD(x̄) = Σf|x - x̄| / N About Median: MD(M) = Σf|x - M| / N Property: Σ|x - A| is minimum when A = Median Ignores algebraic signs (|x - A| ≥ 0) Variance & Standard Deviation σ² = (1/N)Σf(x - x̄)² and σ = √Var Variance: σ² = (1/N)Σf x² - x̄² Standard Deviation: σ = √Variance (always ≥ 0) Mean (x̄) -1σ +1σ Step-Deviation Method u = (x - A)/h scaling method Step-deviation: σ = h √[(Σf u²/N) - (Σf u/N)²] Mean: x̄ = A + h(Σfu / N) Assumed Mean A, Class width h Drastically reduces arithmetic load Origin & Scale Invariance Var(ax + b) = a² Var(x) ■ Origin Independent: Var(x ± c) = Var(x) Adding/subtracting constant c shifts mean, but spread is invariant ■ Scale Dependent: SD(a·x) = |a|·SD(x) Multiplying by a scales variance by a² and S.D. by |a| Combined Variance: N σ² = n₁(σ₁² + d₁²) + n₂(σ₂² + d₂²) Coefficient of Variation (C.V.) C.V. = (σ / x̄) × 100 Relative Measure of Dispersion: Unit-Free Comparison Allows fair comparison between series with different units or scales ■ Higher C.V. ⇒ Greater variability, less consistent ■ Lower C.V. ⇒ More consistent, stable distribution Equal Means: Series with smaller σ is more consistent

Chapter Summary & 10 Key Takeaways

Takeaway 1
Dispersion measures the extent to which data observations scatter or deviate from a central tendency value.
Takeaway 2
Range is the difference between maximum and minimum values (R = L - S); it is simple to compute but highly sensitive to extreme outliers.
Takeaway 3
Mean deviation is the average of absolute deviations from mean or median: MD = (1/N) Σ f_i |x_i - A|.
Takeaway 4
The sum of absolute deviations is minimum when deviations are taken about the median: Σ |x_i - M| ≤ Σ |x_i - A|.
Takeaway 5
Variance (σ²) is the average of squared deviations from the mean: σ² = (1/N) Σ f_i x_i² - x̄².
Takeaway 6
Standard deviation (σ) is the positive square root of variance, carrying the same physical units as the original data.
Takeaway 7
Under the step-deviation method with u_i = (x_i - A)/h, the standard deviation is σ = h √[(Σ f_i u_i² / N) - (Σ f_i u_i / N)²].
Takeaway 8
Variance and standard deviation are invariant under change of origin: Var(x ± c) = Var(x).
Takeaway 9
Under change of scale, standard deviation scales by |a| and variance scales by a²: Var(ax + b) = a² Var(x).
Takeaway 10
The Coefficient of Variation C.V. = (σ / x̄) × 100 is a unitless relative measure; a smaller C.V. indicates greater consistency, uniformity, and stability.

Check Your Understanding (Diagnostic Practice Questions)

Diagnostic questions testing core conceptual clarity. Answers are hidden initially — solve each problem first, then click to reveal the step-by-step verified solution.

1
If the variance of 10 observations is 16, what will be the new variance if each observation is multiplied by 3 and then increased by 5?
Reveal Answer & Explanation
Answer: Here a = 3 and b = 5. New variance = a² Var(x) = 3² × 16 = 9 × 16 = 144.
Recall the linear transformation rule: Var(ax + b) = a² Var(x).
2
For what central value is the sum of absolute deviations Σ |x_i - A| minimized?
Reveal Answer & Explanation
Answer: The sum of absolute deviations is minimum when A is the Median of the distribution.
Consider the property of the median versus the mean.
3
Two distributions have C.V. 60% and 75% with means 25 and 20 respectively. Find the difference between their standard deviations.
Reveal Answer & Explanation
Answer: σ₁ = (60 × 25)/100 = 15. σ₂ = (75 × 20)/100 = 15. Difference = 15 - 15 = 0.
Use σ = (C.V. × x̄) / 100 for each distribution.
4
Calculate the variance of the first 7 natural numbers.
Reveal Answer & Explanation
Answer: Var = (7² - 1) / 12 = (49 - 1) / 12 = 48 / 12 = 4.
Use the formula Var = (n² - 1) / 12 with n = 7.
5
If all observations in a dataset are identical and equal to 9, what is the standard deviation?
Reveal Answer & Explanation
Answer: Mean is 9, each deviation (x_i - x̄) = 0. Therefore, Standard Deviation = 0.
When there is no variation or spread, what is the deviation from the mean?
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