Area of Circle

JCERT · Class 7 · Chapter 20 · Area of Circle. Topic notes aligned to the official chapter; these are not solutions to every textbook exercise.

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Why This Chapter Matters

JCERT · Class 7 · Chapter 20 · Area of Circle. Topic notes aligned to the official chapter; these are not solutions to every textbook exercise.

Before You Begin (Prerequisites)

Revise relevant arithmetic and ideas from the previous grade.

What You Will Learn (Core Objectives)

A circle’s diameter is twice its radius. Circumference measures its boundary; area measures its interior. Use the approximation for π specified in the question; 22/7 is not exactly π.

Chapter Roadmap & Progression

1 Syllabus, textbook and notes alignm...

2 Concept and method

3 Check and common pitfall

Complete Concept Guide (100% Curriculum Coverage)

Syllabus, textbook and notes alignment

JCERT · Regular schools (Non-SOE) · Class 7 · Chapter 20 — Area of Circle
Official syllabus pages 275–282. Official syllabus · Prescribed Hindi book (22 chapters) · Separate supplementary reference.

These topic notes and teaching examples are not a complete answer key to every textbook question. English notes use this same JCERT chapter order; a matching English textbook PDF has not been verified.

Official Hindi PDF for this exact chapter

Concept and method

A circle’s diameter is twice its radius. Circumference measures its boundary; area measures its interior. Use the approximation for π specified in the question; 22/7 is not exactly π.

Check and common pitfall

Square the radius in the area formula, not the diameter.

Key Formulas, Identities & Theorems

Key relationships

d = 2r; C = 2πr = πd; A = πr²

Observe the stated conditions and units.

Conceptual Solved Examples & Case Studies

Example 1

For radius 7 cm, find area and circumference using π = 22/7.

Step-by-Step Solution:

A = (22/7) × 49 = 154 cm²; C = 2 × (22/7) × 7 = 44 cm

Square the radius in the area formula, not the diameter.

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