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JAC • Class 7 • Mathematics • Ch 21
Estimated Time: 45 Mins
Study Progress: In Progress

Uses of Area in Daily Life

JCERT · Class 7 · Chapter 21 · Uses of Area in Daily Life. Topic notes aligned to the official chapter; these are not solutions to every textbook exercise.

Why This Chapter Matters

JCERT · Class 7 · Chapter 21 · Uses of Area in Daily Life. Topic notes aligned to the official chapter; these are not solutions to every textbook exercise.

Before You Begin (Prerequisites)

  • Revise relevant arithmetic and ideas from the previous grade.

What You Will Learn (Core Objectives)

  • Split composite regions into familiar shapes. Find a path, shaded region or annulus by subtracting the inner area from the outer area. Convert units consistently and avoid counting shared regions twice.

Chapter Roadmap & Progression

1 Syllabus, textbook and notes alignm...
2 Concept and method
3 Check and common pitfall

Complete Concept Guide (100% Curriculum Coverage)

Syllabus, textbook and notes alignment

JCERT · Regular schools (Non-SOE) · Class 7 · Chapter 21 — Uses of Area in Daily Life
Official syllabus pages 283–288. Official syllabus · Prescribed Hindi book (22 chapters) · Separate supplementary reference.

These topic notes and teaching examples are not a complete answer key to every textbook question. English notes use this same JCERT chapter order; a matching English textbook PDF has not been verified.

Official Hindi PDF for this exact chapter

Concept and method

Split composite regions into familiar shapes. Find a path, shaded region or annulus by subtracting the inner area from the outer area. Convert units consistently and avoid counting shared regions twice.

Check and common pitfall

The circle fits inside the rectangle because its diameter is 14 m.

Key Formulas, Identities & Theorems

Key relationships
Annulus: A = π(R² − r²); rectangular border: A = outer rectangle − inner rectangle
Observe the stated conditions and units.

Conceptual Solved Examples & Case Studies

Example 1
Remove a circle of radius 7 m from a 20 × 14 m rectangle. Find the remaining area using π = 22/7.
Step-by-Step Solution:

20 × 14 − (22/7) × 7² = 280 − 154 = 126 m²

The circle fits inside the rectangle because its diameter is 14 m.

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