Follow Us
Select Medium / माध्यम चुनें:
Eng (English) Beng (বাংলা) Hindi (हिन्दी)
WBB • Class XII • Physics • Ch 5
Estimated Time: 45 Mins
Study Progress: In Progress

Electromagnetic Waves

Electromagnetic Waves represents the crowning achievement of classical electrodynamics, synthesizing electricity, magnetism, and optics into a singular, unified mathematical framework formulated by James Clerk Maxwell in 1865. This chapter examines how time-varying electric fields generate magnetic fields through Maxwell's displacement current, resolving the classical Amperean circuit paradox during capacitor charging. It establishes Maxwell's four integral equations, derives the electromagnetic wave equation, demonstrates the transverse nature of field oscillations where the electric and magnetic vectors vibrate mutually perpendicular to each other and to the direction of propagation, analyzes Poynting vector energy transport and radiation pressure, and charts the complete electromagnetic spectrum from long-wavelength radio waves to ultra-high-frequency gamma rays.

Why This Chapter Matters

Without the theoretical discovery of electromagnetic waves and their practical generation by Heinrich Hertz and Sir Jagadish Chandra Bose, modern telecommunications, global satellite positioning, wireless internet, radar defense systems, and medical diagnostic radiology would not exist. In the WBCHSE Higher Secondary examination, Unit V is a crucial scoring domain that tests core conceptual foundations, including displacement current derivations, field vector amplitude relations, equipartition of electromagnetic energy density, radiation pressure on absorbing versus reflecting surfaces, and accurate wavelength-frequency boundaries with technological applications across the EM spectrum.

Chapter Roadmap & Progression

1 Displacement Current & The Ampère-M...
2 Maxwell's Equations & Foundations o...
3 Production, Transverse Nature & Pro...
4 Energy Density, Poynting Vector & R...
5 Electromagnetic Spectrum: Radio Wav...
6 Electromagnetic Spectrum: Visible,...

Complete Concept Guide (100% Curriculum Coverage)

Displacement Current & The Ampère-Maxwell Law

1.1 Inconsistency of Ampère's Circuital Law

In classical magnetostatics, Ampère's Circuital Law states that the line integral of magnetic field 𝐁 along any closed Amperian loop C bounding an open surface S equals μ₀ times the net conduction current I_c threading through the surface:

∮_C 𝐁 · d𝐥 = μ₀ I_c

In 1864, James Clerk Maxwell identified a fundamental logical inconsistency in this law when applied to time-dependent non-steady currents, such as the charging or discharging of a parallel-plate capacitor.

The Capacitor Paradox: Consider a circular Amperian loop C surrounding the wire leading to a capacitor plate being charged by a time-varying current i(t):

  • If we choose a flat circular surface S₁ bounded by C, the conduction current pierces S₁, giving:
    ∮_C 𝐁 · d𝐥 = μ₀ i(t)
  • If we choose a bulging bag-shaped surface S₂ with the same boundary loop C, but whose pouch extends into the gap between the capacitor plates, no conduction current threads S₂ because the gap contains only vacuum or an ideal dielectric (I_c = 0). This yields:
    ∮_C 𝐁 · d𝐥 = 0

Since the left-hand side depends solely on the boundary path C, two different surfaces sharing the exact same perimeter cannot yield two conflicting values (μ₀ i(t) ≠ 0). This proved that Ampère's circuital law was incomplete for time-varying electrodynamic fields.

1.2 Maxwell's Concept of Displacement Current

Maxwell recognized that while no mobile electric charges cross the dielectric gap, the electric field between the plates changes rapidly as charge accumulates. For plate area A carrying instantaneous charge q(t), the uniform electric field is:

E(t) = σ / ε₀ = q(t) / (ε₀ A)

The total electric flux Φ_E passing through surface S₂ inside the capacitor gap is:

Φ_E = E · A = [q(t) / (ε₀ A)] · A = q(t) / ε₀

Differentiating electric flux with respect to time:

dΦ_E / dt = (1 / ε₀) (dq / dt) ⟹ ε₀ (dΦ_E / dt) = dq / dt = i_c(t)

Maxwell postulated that this rate of change of electric flux acts as a source of magnetic field equivalent to a real current, defining the Displacement Current (I_d):

Displacement Current Formula:
I_d = ε₀ (dΦ_E / dt)

In a dielectric medium of permittivity ε = ε_r ε₀, the displacement current becomes I_d = ε (dΦ_E / dt).

1.3 Continuity of Total Current

The total current I_total is the sum of conduction current (carried by moving charges in conductors) and displacement current (produced by time-varying electric flux in space):

I_total = I_c + I_d = I_c + ε₀ (dΦ_E / dt)
Region Conduction Current (I_c) Displacement Current (I_d) Total Current (I_total)
Connecting Lead Wires i(t) = dq/dt 0 (E is constant along wire) i(t)
Capacitor Plate Gap 0 (No charge crosses gap) ε₀ (dΦ_E/dt) = dq/dt = i(t) i(t)

Thus, total current satisfies continuous flow across the entire circuit: outside the plates, current exists purely as conduction current, while inside the gap, it transitions seamlessly into displacement current.

1.4 Generalized Ampère-Maxwell Law

Incorporating displacement current into Ampère's circuital law produces the generalized Ampère-Maxwell Law:

∮_C 𝐁 · d𝐥 = μ₀ (I_c + I_d) = μ₀ [I_c + ε₀ (dΦ_E / dt)]

This symmetric formulation establishes that magnetic fields are produced by two distinct physical mechanisms: conventional moving electric charges (I_c) and time-varying electric fields (dΦ_E/dt).

Maxwell's Equations & Foundations of Electrodynamics

2.1 The Four Fundamental Maxwell's Equations

Maxwell synthesized all classical electric and magnetic phenomena into four elegant integral equations that form the foundations of electrodynamics:

1. Gauss's Law in Electrostatics:
∯_S 𝐄 · d𝐀 = Q_enclosed / ε₀
Physical Significance: Electric charges act as sources (positive) or sinks (negative) of electric field lines. The total electric flux through any closed surface is proportional to the net enclosed charge.
2. Gauss's Law in Magnetism:
∯_S 𝐁 · d𝐀 = 0
Physical Significance: Isolated magnetic monopoles do not exist in nature. Magnetic field lines are continuous closed loops with neither beginning nor end; every magnetic north pole is paired with an equal south pole.
3. Faraday-Lenz Law of Induction:
∮_C 𝐄 · d𝐥 = - (dΦ_B / dt) = - d/dt [∬_S 𝐁 · d𝐀]
Physical Significance: A time-varying magnetic field induces a non-conservative, rotational electric field in space, creating an electromotive force that opposes the change in magnetic flux.
4. Ampère-Maxwell Law:
∮_C 𝐁 · d𝐥 = μ₀ I_c + μ₀ ε₀ (dΦ_E / dt)
Physical Significance: Magnetic fields are generated both by conduction currents (moving charges) and by time-varying electric fields (displacement current).
2.2 Maxwell's Equations in Charge-Free Vacuum

In empty space devoid of free electric charges (ρ = 0 ⟹ Q_enclosed = 0) and conduction currents (I_c = 0), Maxwell's equations assume remarkable dual symmetry:

∯ 𝐄 · d𝐀 = 0
∯ 𝐁 · d𝐀 = 0
∮ 𝐄 · d𝐥 = - d/dt ∬ 𝐁 · d𝐀
∮ 𝐁 · d𝐥 = μ₀ ε₀ d/dt ∬ 𝐄 · d𝐀

A changing electric field generates a magnetic field, and a changing magnetic field generates an electric field. This mutual regeneration allows self-sustaining electromagnetic disturbances to propagate across space indefinitely as Electromagnetic Waves.

2.3 Wave Equation and Velocity of Light

By applying vector calculus curl operations (∇ × (∇ × 𝐄)) to Maxwell's vacuum equations, we derive the classical 3D wave equations for the electric and magnetic fields:

∇²𝐄 = μ₀ ε₀ (∂²𝐄 / ∂t²), ∇²𝐁 = μ₀ ε₀ (∂²𝐁 / ∂t²)

Comparing this with the standard wave equation ∇²ψ = (1/v²) (∂²ψ / ∂t²) reveals that the wave propagation speed c in vacuum is fundamentally determined by the electrostatic permittivity ε₀ and magnetic permeability μ₀:

Maxwell's Wave Speed Relation:
c = 1 / √(μ₀ ε₀)

Substituting standard SI laboratory values:

  • μ₀ = 4π × 10⁻⁷ T·m/A = 1.2566 × 10⁻⁶ N/A²
  • ε₀ = 8.8542 × 10⁻¹² C²/(N·m²)
c = 1 / √[(4π × 10⁻⁷) × (8.8542 × 10⁻¹²)] ≈ 2.9979 × 10⁸ m/s ≈ 3 × 10⁸ m/s

This exact agreement with the measured speed of light led Maxwell to his monumental synthesis: Light itself is an electromagnetic wave!

2.4 Wave Speed in Material Dielectrics

In a non-magnetic linear dielectric medium of relative permittivity (dielectric constant) ε_r = K and relative permeability μ_r ≈ 1, the speed of propagation v is reduced:

v = 1 / √(μ ε) = 1 / √(μ₀ μ_r · ε₀ ε_r) = c / √(μ_r ε_r) ≈ c / √ε_r

The refractive index n of the medium is therefore directly connected to electromagnetic material properties via Maxwell's Formula:

n = c / v = √(μ_r ε_r) = √(ε_r) (for non-magnetic materials where μ_r = 1)

Production, Transverse Nature & Propagation of EM Waves

3.1 Sources and Production of Electromagnetic Waves

To understand how electromagnetic waves originate, we classify charge behaviors:

  • Stationary Charge (v = 0): Produces only a static electrostatic field 𝐄; no magnetic field is generated, so no EM radiation occurs.
  • Uniformly Moving Charge (v = const, a = 0): Constitutes a steady direct current, producing a static magnetic field 𝐁 in addition to 𝐄. The total energy remains localized around the charge; no wave energy detaches or radiates into space.
  • Accelerated or Oscillating Charge (a ≠ 0): Produces time-varying electric and magnetic fields that continually regenerate each other and propagate outward through space as electromagnetic waves, carrying energy away from the source.

Hertz's Experimental Verification (1887): Heinrich Hertz produced the first artificial radio waves using an oscillating spark-gap circuit connected to large metal plates (LC oscillator). An oscillatory discharge across the primary gap induced high-frequency alternating currents, emitting EM waves detected across the laboratory by resonance sparks in an open wire loop detector.

J.C. Bose's Millimeter Waves (1895): In Kolkata, Sir Jagadish Chandra Bose pioneered ultra-high frequency electromagnetic waves with extremely short wavelengths (5 mm to 2.5 cm) using spark transmitters, horn antennas, dielectric lenses, and galena crystal detectors, laying the experimental foundation for modern microwave optics.

3.2 Mathematical Expression for a Plane Sinusoidal EM Wave

Consider a plane sinusoidal electromagnetic wave traveling along the positive x-axis in vacuum:

  • Electric field vector oscillates exclusively along the y-axis:
    𝐄(x, t) = E_y(x, t) 𝐣̂ = E₀ sin(k x - ω t) 𝐣̂
  • Magnetic field vector oscillates exclusively along the z-axis:
    𝐁(x, t) = B_z(x, t) 𝐤̂ = B₀ sin(k x - ω t) 𝐤̂

where:

  • E₀ and B₀ are the peak field amplitudes,
  • ω = 2π f is the angular frequency (rad/s),
  • k = 2π / λ = ω / c is the propagation constant or wave number (rad/m),
  • (k x - ω t) is the phase of the wave.
3.3 Transverse Nature of Electromagnetic Waves

Electromagnetic waves are strictly transverse waves. Both the electric field vector 𝐄 and the magnetic field vector 𝐁 are perpendicular to each other, and both are perpendicular to the wave propagation direction 𝐤̂:

Orthogonality Condition:
𝐄 ⟂ 𝐁, 𝐄 ⟂ 𝐤̂, 𝐁 ⟂ 𝐤̂
The unit propagation vector points along: 𝐧̂ = (𝐄 × 𝐁) / |𝐄 × 𝐁|

Proof of Transverse Nature from Gauss's Law: Consider a plane wave propagating in the x-direction. For a Gaussian pillbox with faces parallel to the y-z plane, Gauss's law in charge-free space requires ∂E_x / ∂x = 0. This means the longitudinal component E_x must be spatially constant and cannot propagate as a wave. Setting non-propagating static components to zero yields E_x = 0 and similarly B_x = 0. Hence, EM waves possess no longitudinal component along the direction of propagation.

3.4 Ratio of Field Amplitudes and In-Phase Oscillation

Substituting the sinusoidal wave expressions into Faraday's law in differential form (∂E_y/∂x = -∂B_z/∂t):

k E₀ cos(k x - ω t) = ω B₀ cos(k x - ω t)

Since the cosine phase functions cancel identically at all coordinates and times, we arrive at two fundamental conclusions:

  1. In-Phase Oscillation: The electric field 𝐄 and magnetic field 𝐁 reach their maxima, zero-crossings, and minima at the exact same instant in time and point in space. There is zero phase difference (Δφ = 0) between them.
  2. Amplitude Ratio: The ratio of electric to magnetic field amplitude equals the wave speed:
    E₀ / B₀ = ω / k = c ⟹ E(x, t) / B(x, t) = c

Because c ≈ 3 × 10⁸ m/s, the numerical value of E₀ is enormous compared to B₀ (e.g., if E₀ = 300 V/m, B₀ = 10⁻⁶ T = 1 μT). In optical interactions with matter, the Lorentz force 𝐅 = q(𝐄 + 𝐯 × 𝐁) is dominated by the electric field (since v ≪ c), making 𝐄 the primary light vector responsible for vision and chemical transitions.

Energy Density, Poynting Vector & Radiation Pressure

4.1 Energy Density in Electromagnetic Waves

An electromagnetic wave transports energy through space stored in both electric and magnetic fields:

  • Instantaneous electrostatic energy density:
    u_E = 1/2 ε₀ E² = 1/2 ε₀ E₀² sin²(k x - ω t)
  • Instantaneous magnetic energy density:
    u_B = B² / (2 μ₀) = B₀² sin²(k x - ω t) / (2 μ₀)

Equipartition of Energy: Since E₀ = c B₀ and c² = 1 / (μ₀ ε₀):

u_B = (B₀² / 2μ₀) = (E₀² / c²) / (2μ₀) = (μ₀ ε₀ E₀²) / (2μ₀) = 1/2 ε₀ E₀² = u_E

Thus, electromagnetic energy is distributed equally between the electric and magnetic fields!

Over a complete cycle, the time-average of sin²(k x - ω t) is 1/2. Therefore, the average energy densities are:

⟨u_E⟩ = 1/4 ε₀ E₀²
⟨u_B⟩ = B₀² / (4 μ₀) = 1/4 ε₀ E₀²
⟨u_total⟩ = ⟨u_E⟩ + ⟨u_B⟩ = 1/2 ε₀ E₀² = B₀² / (2 μ₀) = ε₀ E_rms²
4.2 The Poynting Vector and Wave Intensity

The rate of energy transport per unit surface area by an electromagnetic wave is quantified by the Poynting Vector 𝐒 (introduced by John Henry Poynting in 1884):

Poynting Vector:
𝐒 = (1 / μ₀) (𝐄 × 𝐁)

Properties of 𝐒:

  • The direction of 𝐒 represents the direction of energy propagation. Since 𝐄 = E_y 𝐣̂ and 𝐁 = B_z 𝐤̂, 𝐄 × 𝐁 = E_y B_z (𝐣̂ × 𝐤̂) = E_y B_z 𝐢̂, pointing along the propagation direction +x.
  • The SI unit of 𝐒 is Watts per square meter (W/m²).

Wave Intensity (I): The intensity of an electromagnetic wave is defined as the time-averaged magnitude of the Poynting vector:

I = ⟨|𝐒|⟩ = (E₀ B₀ / 2 μ₀) = ⟨u_total⟩ · c = 1/2 ε₀ c E₀² = (c B₀²) / (2 μ₀)
4.3 Momentum Transport and Radiation Pressure

Electromagnetic waves carry not only energy, but also linear momentum. When an electromagnetic wave delivering total radiant energy U is incident normally on a surface:

  • Case 1: Perfectly Absorbing Surface (Complete Absorption):
    Total momentum delivered: p = U / c
    The force exerted is F = dp/dt = (1/c)(dU/dt) = P_power / c.
    The resulting Radiation Pressure (P_rad = F / A) is:
    P_rad = I / c = ⟨u_total⟩
  • Case 2: Perfectly Reflecting Surface (Complete Reflection): The incident momentum is +U/c and the reflected momentum is -U/c. The net momentum transferred to the mirror is:
    Δp = p_initial - p_final = (U / c) - (-U / c) = 2 U / c
    The force is doubled (F = 2 P_power / c), and the radiation pressure is:
    P_rad = 2 I / c = 2 ⟨u_total⟩

Radiation pressure explains why comet tails always point radially away from the Sun and forms the operational basis of solar sails for deep-space probe propulsion.

Electromagnetic Spectrum: Radio Waves, Microwaves & Infrared

5.1 Overview of the Electromagnetic Spectrum

The Electromagnetic Spectrum encompasses the complete continuous distribution of electromagnetic waves classified according to their frequency (f) or wavelength (λ). In vacuum, all EM waves travel at the exact same speed c = f λ ≈ 3 × 10⁸ m/s. As frequency increases from radio waves to gamma rays, photon energy (E = h f = h c / λ) grows by more than twelve orders of magnitude.

5.2 Radio Waves
Wavelength Band λ > 0.1 m (from 1 mm up to tens of kilometers)
Frequency Range f ~ 500 kHz to 1000 MHz
Production Mechanism Accelerated movement of electrons in transmitting antennas connected to LC oscillator circuits
Detection Mechanism Resonant receiving tuned circuits with aerial wire antennas
Sub-Bands & Uses
  • AM Band (Amplitude Modulation): 530 kHz to 1710 kHz (ground wave and ionospheric sky wave broadcast).
  • Shortwave (SW) Band: 1.7 MHz to 30 MHz (long-distance global sky wave communication).
  • TV Broadcast: 54 MHz to 890 MHz.
  • FM Band (Frequency Modulation): 88 MHz to 108 MHz (line-of-sight space wave propagation with high audio fidelity).
  • Cellular Mobile Band: Ultra-High Frequency (UHF, 300 MHz to 3 GHz).
5.3 Microwaves
Wavelength Band 0.1 m to 1 mm (10⁻¹ m to 10⁻³ m)
Frequency Range 1 GHz to 300 GHz
Production Mechanism Specialized thermionic vacuum tubes such as cavity magnetrons, klystrons, and Gunn diodes
Detection Mechanism Point-contact crystal diodes, semiconductor Schottky diodes, and horn antennas
Key Applications
  • RADAR (Radio Detection and Ranging): Short wavelengths travel in narrow, collimated beams with minimal diffraction, ideal for aircraft navigation, speed traps, and missile tracking.
  • Satellite & Wi-Fi Telecommunications: Penetrates the ionosphere without reflection or attenuation.
  • Microwave Ovens: Operated at standard frequency 2.45 GHz (λ ≈ 12.2 cm). Water molecules possess permanent electric dipoles. The oscillating microwave field drives resonant rotational vibrations of water molecules in food, converting electromagnetic energy directly into thermal Joule heat with high energy efficiency.
5.4 Infrared Radiation (Heat Waves)
Wavelength Band 1 mm to 700 nm (10⁻³ m to 7 × 10⁻⁷ m)
Frequency Range 300 GHz to 4.3 × 10¹⁴ Hz
Production Mechanism Thermal vibrations and molecular rotations in hot bodies and incandescent matter
Detection Mechanism Thermopiles, bolometers, pyroelectric detectors, infrared photographic emulsions
Key Applications
  • Greenhouse Effect: Incoming visible solar radiation warms Earth's surface. The re-radiated long-wavelength infrared rays are trapped by greenhouse gases (CO₂, H₂O vapor, CH₄), maintaining Earth's habitable mean temperature (+15°C).
  • Night Vision & Thermography: Infrared sensors detect thermal silhouettes of humans and engines in complete darkness and through smoke.
  • Remote Controls: Low-power infrared light-emitting diodes (LEDs) transmit pulsed binary control codes to household electronic receivers.
  • Medical Physiotherapy: Infrared heat lamps relieve deep muscular spasms by promoting localized blood circulation.

Electromagnetic Spectrum: Visible, UV, X-Rays & Gamma Rays

6.1 Visible Light
Wavelength Band 700 nm to 400 nm (7 × 10⁻⁷ m to 4 × 10⁻⁷ m; 7000 Å to 4000 Å)
Frequency Range 4.3 × 10¹⁴ Hz to 7.5 × 10¹⁴ Hz
Production Mechanism Electronic orbital transitions of valence electrons in excited atoms and incandescent gases
Detection Mechanism Human retinal photoreceptors (rods and cones), photographic films, photocells, CCD sensors
Color Spectrum (VIBGYOR) Violet (~400 nm), Indigo (~440 nm), Blue (~480 nm), Green (~530 nm), Yellow (~580 nm), Orange (~620 nm), Red (~700 nm). Serves as the primary optical window for vision, plant photosynthesis, and optical microscopy.
6.2 Ultraviolet (UV) Radiation
Wavelength Band 400 nm to 1 nm (4 × 10⁻⁷ m to 10⁻⁹ m)
Frequency Range 7.5 × 10¹⁴ Hz to 3 × 10¹⁷ Hz
Production Mechanism High-voltage electric discharge arcs, mercury vapor lamps, the Sun, and excimer lasers
Detection Mechanism Fluorescent screens coated with phosphors, UV photodiodes, photochemical paper
Atmospheric & Medical Roles
  • Ozone Layer Shield: The stratospheric ozone (O₃) layer between 40–50 km altitude absorbs harmful solar UV-B and UV-C radiation below 310 nm, shielding life from cataracts and melanoma.
  • Water Purification & Sterilization: Germicidal UV-C (~254 nm) disrupts bacterial and viral DNA/RNA replication.
  • LASIK Eye Surgery: High-precision excimer lasers emit UV pulses to vaporize microscopic corneal layers without thermal scarring.
  • Forensics & Currency Verification: Fluorescent dyes embedded in banknotes illuminate under UV blacklight.
6.3 X-Rays (Röntgen Rays)
Wavelength Band 1 nm to 10⁻³ nm (10⁻⁹ m to 10⁻¹² m; 10 Å to 0.01 Å)
Frequency Range 3 × 10¹⁶ Hz to 3 × 10¹⁹ Hz
Production Mechanism Sudden deceleration of ultra-relativistic high-energy electrons bombarding heavy metal targets (Tungsten, Molybdenum) in Coolidge tubes (Bremsstrahlung) and inner-shell electronic transitions
Detection Mechanism Photographic film, Geiger-Müller counters, ionization chambers, flat-panel digital detectors
Key Applications
  • Diagnostic Radiography & CT Scans: Penetrates flesh easily but is heavily absorbed by dense calcium bones.
  • X-Ray Crystallography: Wavelengths (~1 Å) match interatomic lattice spacings, enabling Bragg diffraction to resolve 3D crystal structures and double-helix DNA geometry.
  • Industrial Non-Destructive Testing: Inspects welding joints, metal castings, and aerospace structures for micro-cracks.
6.4 Gamma (γ) Rays
Wavelength Band λ < 10⁻³ nm (λ < 10⁻¹² m; below 0.01 Å)
Frequency Range f > 3 × 10¹⁹ Hz (up to 10²³ Hz in cosmic gamma-ray bursts)
Production Mechanism Nuclear de-excitation, spontaneous radioactive decay of unstable radioisotopes (e.g., Cobalt-60, Caesium-137), nuclear fission, and matter-antimatter annihilation
Detection Mechanism Scintillation counters, solid-state semiconductor detectors, bubble chambers
Key Applications
  • Oncological Radiotherapy: Highly collimated Cobalt-60 gamma beams destroy malignant tumor cells without invasive surgery.
  • Medical Instrument Sterilization: Cold sterilization of disposable syringes, catheters, and surgical sutures without heat damage.
  • Food Preservation: Eliminates food-borne pathogens and inhibits tuber sprouting, extending shelf-life.
  • Nuclear Astrophysics: Probes extreme cosmic phenomena like supernovae and black hole accretion disks.

Key Formulas, Laws & Physical Constants

Displacement Current
$$I_d = ε₀ (dΦ_E / dt) = ε₀ A (dE / dt)$$
Ampère-Maxwell Circuital Law
$$∮ 𝐁 · d𝐥 = μ₀ (I_c + I_d) = μ₀ [I_c + ε₀ (dΦ_E / dt)]$$
Maxwell's Wave Speed Relation
$$c = 1 / √(μ₀ ε₀) and v = c / √(μ_r ε_r) = c / n$$
Electric and Magnetic Field Ratio
E₀ / B₀ = E(x, t) / B(x, t) = c
Total Average Energy Density & Intensity
⟨u⟩ = 1/2 ε₀ E₀² = B₀² / (2 μ₀) and I = ⟨|𝐒|⟩ = ⟨u⟩ c = 1/2 ε₀ c E₀²
Radiation Pressure & Momentum
$$P_rad = I / c (Absorber) and P_rad = 2 I / c (Reflector)$$

Conceptual Solved Examples & Case Studies

Example 1
A parallel-plate capacitor with circular plates of radius r = 0.1 m is being charged by a steady current of 0.2 A. (a) What is the displacement current between the plates? (b) Calculate the rate of change of the electric field between the plates.
Step-by-Step Solution:
Step 1: Determine the displacement current
By Maxwell's continuity theorem of total current, the total displacement current I_d between the capacitor plates is exactly equal to the external conduction current I_c during charging:
I_d = I_c = 0.2 A
Step 2: Calculate the rate of change of the electric field
The displacement current is given by:
I_d = ε₀ (dΦ_E / dt) = ε₀ A (dE / dt)
where the plate area is:
A = π r² = 3.1416 × (0.1)² = 3.1416 × 10⁻² m²
Rearranging for dE/dt:
dE / dt = I_d / (ε₀ A) = 0.2 / [(8.854 × 10⁻¹²) × (3.1416 × 10⁻²)]
dE / dt = 0.2 / (2.7816 × 10⁻¹³) ≈ 7.19 × 10¹¹ V/(m·s)
Final Answer: (a) Displacement current I_d = 0.2 A; (b) Rate of change of electric field dE/dt = 7.19 × 10¹¹ V/(m·s).
Example 2
The electric field of a plane electromagnetic wave propagating in vacuum is given by E_y = 54 sin(1.2 × 10⁷ x - 3.6 × 10¹⁵ t) V/m. Find: (a) The amplitude of the oscillating magnetic field B₀, (b) The wavelength λ and frequency f of the wave, and (c) The average energy density ⟨u⟩ of the wave.
Step-by-Step Solution:
Step 1: Find the magnetic field amplitude B₀
From the given expression, the electric field amplitude is E₀ = 54 V/m. Using the fundamental field ratio:
B₀ = E₀ / c = 54 / (3 × 10⁸) = 1.8 × 10⁻⁷ T = 0.18 μT
Step 2: Determine wavelength and frequency
Comparing with the standard form E_y = E₀ sin(k x - ω t):
  • Propagation constant k = 1.2 × 10⁷ rad/m:
    λ = 2π / k = (2 × 3.1416) / (1.2 × 10⁷) ≈ 5.24 × 10⁻⁷ m = 524 nm
  • Angular frequency ω = 3.6 × 10¹⁵ rad/s:
    f = ω / (2π) = (3.6 × 10¹⁵) / (2 × 3.1416) ≈ 5.73 × 10¹⁴ Hz
    (This lies in the green region of the visible light spectrum).
Step 3: Calculate average energy density
⟨u⟩ = 1/2 ε₀ E₀² = 0.5 × (8.854 × 10⁻¹² C²/(N·m²)) × (54 V/m)²
⟨u⟩ = 0.5 × (8.854 × 10⁻¹²) × 2916 ≈ 1.29 × 10⁻⁸ J/m³
Final Answer: (a) B₀ = 1.8 × 10⁻⁷ T; (b) λ = 524 nm, f = 5.73 × 10¹⁴ Hz; (c) ⟨u⟩ = 1.29 × 10⁻⁸ J/m³.
Example 3
A continuous laser beam has an output power of 30 mW and a beam cross-sectional area of 2 mm². The beam strikes a perfectly reflecting mirror at normal incidence. Calculate: (a) The radiation intensity of the laser beam, (b) The force exerted on the mirror, and (c) The radiation pressure experienced by the mirror surface.
Step-by-Step Solution:
Step 1: Calculate the radiation intensity (I)
Power P = 30 mW = 30 × 10⁻³ W = 0.03 W.
Cross-sectional area A = 2 mm² = 2 × 10⁻⁶ m².
I = P / A = 0.03 / (2 × 10⁻⁶) = 15,000 W/m² = 1.5 × 10⁴ W/m²
Step 2: Calculate the radiation force on a perfectly reflecting mirror
For complete reflection at normal incidence, the momentum change per photon is doubled:
F = 2 P / c = (2 × 0.03 W) / (3 × 10⁸ m/s) = 0.06 / (3 × 10⁸) = 2.0 × 10⁻¹⁰ N
Step 3: Calculate the radiation pressure (P_rad)
P_rad = F / A = (2.0 × 10⁻¹⁰ N) / (2 × 10⁻⁶ m²) = 1.0 × 10⁻⁴ N/m² (Pa)
[Alternatively: P_rad = 2 I / c = (2 × 15,000) / (3 × 10⁸) = 1.0 × 10⁻⁴ Pa]
Final Answer: (a) Intensity I = 1.5 × 10⁴ W/m²; (b) Force F = 2.0 × 10⁻¹⁰ N; (c) Radiation pressure P_rad = 1.0 × 10⁻⁴ Pa.
Example 4
A plane sinusoidal electromagnetic wave of frequency f = 25 MHz travels in vacuum along the positive x-direction. At a particular point and instant, the electric field has maximum amplitude E₀ = 120 V/m oriented along the +y direction. (a) Calculate the wavelength λ, wave number k, and angular frequency ω. (b) Determine the magnitude and direction of the magnetic field vector 𝐁 at that instant. (c) Write down vector expressions for 𝐄(x, t) and 𝐁(x, t). (d) Compute the average wave intensity I.
Step-by-Step Solution:
Step 1: Calculate wave parameters
Given frequency f = 25 MHz = 25 × 10⁶ Hz = 2.5 × 10⁷ Hz:
  • Wavelength:
    λ = c / f = (3 × 10⁸) / (25 × 10⁶) = 12 m
  • Wave number:
    k = 2π / λ = (2 × 3.1416) / 12 = 0.5236 rad/m
  • Angular frequency:
    ω = 2π f = 2 × 3.1416 × (2.5 × 10⁷) = 1.571 × 10⁸ rad/s
Step 2: Magnetic field amplitude and direction
The magnetic field amplitude is:
B₀ = E₀ / c = 120 / (3 × 10⁸) = 4.0 × 10⁻⁷ T = 0.4 μT
The wave propagates along +x (𝐢̂), and 𝐄 is along +y (𝐣̂). By the Poynting vector rule:
𝐄 × 𝐁 ∥ 𝐢̂ ⟹ 𝐣̂ × 𝐤̂ = 𝐢̂
Therefore, the magnetic field vector points strictly along the positive z-axis (+z, unit vector 𝐤̂). Step 3: Vector wave expressions
𝐄(x, t) = 120 sin(0.524 x - 1.57 × 10⁸ t) 𝐣̂ V/m
𝐁(x, t) = (4.0 × 10⁻⁷) sin(0.524 x - 1.57 × 10⁸ t) 𝐤̂ T
Step 4: Average intensity
I = 1/2 ε₀ c E₀² = 0.5 × (8.854 × 10⁻¹²) × (3 × 10⁸) × (120)²
I = 0.5 × (2.6562 × 10⁻³) × 14,400 ≈ 19.12 W/m²
Final Answer: (a) λ = 12 m, k = 0.524 rad/m, ω = 1.57 × 10⁸ rad/s; (b) B₀ = 4.0 × 10⁻⁷ T along +z; (c) expressions as derived above; (d) I = 19.12 W/m².
Example 5
A parallel-plate capacitor with circular plates of radius R = 5.0 cm and plate separation d = 2.0 mm is connected to an alternating voltage source V(t) = V₀ sin(ω t) with peak voltage V₀ = 240 V and angular frequency ω = 3000 rad/s. (a) Determine the capacitance C and peak charge Q₀ on the plates. (b) Derive an expression for the displacement current density J_d between the plates. (c) Calculate the maximum amplitude of the displacement current I_d,max. (d) Find the maximum induced magnetic field B_max at a radial distance r = 3.0 cm from the central axis.
Step-by-Step Solution:
Step 1: Calculate capacitance and peak charge
Plate radius R = 0.05 m, separation d = 2.0 × 10⁻³ m.
Plate area A = π R² = 3.1416 × (0.05)² = 7.854 × 10⁻³ m².
C = (ε₀ A) / d = [(8.854 × 10⁻¹²) × (7.854 × 10⁻³)] / (2.0 × 10⁻³) ≈ 3.477 × 10⁻¹¹ F = 34.77 pF
Q₀ = C V₀ = (3.477 × 10⁻¹¹ F) × 240 V ≈ 8.34 × 10⁻⁹ C = 8.34 nC
Step 2: Displacement current density J_d
The electric field between the plates is E(t) = V(t) / d = (V₀ / d) sin(ω t).
By definition:
J_d = ε₀ (∂E / ∂t) = ε₀ (V₀ ω / d) cos(ω t)
Step 3: Maximum displacement current
I_d(t) = J_d · A = [(ε₀ A / d) · V₀ · ω] cos(ω t) = C V₀ ω cos(ω t)
I_d,max = C V₀ ω = (3.477 × 10⁻¹¹ F) × 240 V × 3000 rad/s ≈ 2.50 × 10⁻⁵ A = 25.0 μA
Step 4: Induced magnetic field at r = 3 cm (< R)
Construct an Amperian loop of radius r = 0.03 m concentric with the plates. By Ampère-Maxwell's law:
∮ 𝐁 · d𝐥 = B(2π r) = μ₀ I_d,enclosed = μ₀ [I_d · (π r² / π R²)] = μ₀ I_d (r² / R²)
B(r) = (μ₀ I_d · r) / (2π R²)
At maximum displacement current (I_d,max = 2.50 × 10⁻⁵ A):
B_max = [(4π × 10⁻⁷) × (2.50 × 10⁻⁵) × 0.03] / [2π × (0.05)²]
B_max = [2 × 10⁻⁷ × (2.50 × 10⁻⁵) × 0.03] / 0.0025 = (1.50 × 10⁻¹³) / 0.0025 = 6.0 × 10⁻¹¹ T = 60 pT
Final Answer: (a) C = 34.77 pF, Q₀ = 8.34 nC; (b) J_d = ε₀(V₀ω/d) cos(ωt); (c) I_d,max = 25.0 μA; (d) B_max = 6.0 × 10⁻¹¹ T.
Example 6
A physics research observatory detects four distinct electromagnetic radiation signals: Signal A: λ = 21 cm; Signal B: λ = 10 μm; Signal C: λ = 250 nm; Signal D: λ = 0.02 Å (2 × 10⁻¹² m). (a) Identify the part of the electromagnetic spectrum to which each signal belongs. (b) State the primary physical production mechanism for each identified wave category. (c) Which signal possesses the maximum photon energy, and what is its value in electron-volts (eV)? (d) Give two distinct practical or technological applications for each category.
Step-by-Step Solution:
Step 1: Identify spectrum classification for each signal
  • Signal A (λ = 21 cm = 0.21 m): Falls in the λ > 0.1 m regime ⟹ Radio Waves / High-end Microwaves (specifically, the famous 21-cm interstellar neutral hydrogen hyperfine line).
  • Signal B (λ = 10 μm = 10⁻⁵ m): Falls in the range 700 nm < λ < 1 mm ⟹ Infrared Radiation (Thermal IR).
  • Signal C (λ = 250 nm = 2.5 × 10⁻⁷ m): Falls in the range 1 nm < λ < 400 nm ⟹ Ultraviolet (UV) Radiation (specifically germicidal UV-C).
  • Signal D (λ = 0.02 Å = 2 × 10⁻¹² m): Falls below 10⁻³ nm (10⁻¹² m) ⟹ Gamma (γ) Rays.
Step 2: Primary production mechanisms
  • Radio/Microwaves: High-frequency alternating electron currents in resonant LC circuits, antennas, or atomic hyperfine spin-flip transitions.
  • Infrared: Molecular vibrations and rotations in heated objects and warm bodies.
  • Ultraviolet: High-energy electronic orbital transitions of outer-shell valence electrons in excited atoms, discharge arcs, and mercury lamps.
  • Gamma Rays: Nuclear transitions, radioactive de-excitation of atomic nuclei, and particle-antiparticle annihilation.
Step 3: Photon energy calculation for maximum energy signal
Photon energy is given by E = h c / λ. Shorter wavelength corresponds to higher energy. Thus, Signal D (Gamma ray) possesses the highest energy:
E_D = (h c) / λ = [(6.626 × 10⁻³⁴ J·s) × (3.0 × 10⁸ m/s)] / (2.0 × 10⁻¹² m)
E_D = (1.9878 × 10⁻²⁵) / (2.0 × 10⁻¹²) = 9.939 × 10⁻¹⁴ Joules
Converting to electron-volts (1 eV = 1.602 × 10⁻¹⁹ J):
E_D = (9.939 × 10⁻¹⁴) / (1.602 × 10⁻¹⁹) ≈ 6.20 × 10⁵ eV = 620 keV (0.62 MeV)
Step 4: Distinct practical applications
  • Signal A (Radio/Microwave): (1) Long-distance audio/data broadcasting; (2) Radioastronomy mapping of galactic spiral arms via the 21-cm hydrogen emission.
  • Signal B (Infrared): (1) Thermal imaging cameras for search-and-rescue in fire or smoke; (2) Infrared remote controllers for consumer electronics.
  • Signal C (Ultraviolet): (1) Ultraviolet water disinfection and sterilizers; (2) High-precision refractive surgery (LASIK eye cornea contouring).
  • Signal D (Gamma Rays): (1) Gamma knife oncology radiotherapy for localized brain tumors; (2) Industrial cold sterilization of pre-packaged surgical instruments.
Final Answer: Signals identified as Radio/Microwave, IR, UV, and Gamma rays respectively; Signal D has maximum photon energy E = 620 keV; mechanisms and dual applications detailed above.

Common Misconceptions & Examiner Traps

Common Misconception

Thinking that because the dielectric between capacitor plates is an insulator, current breaks and stops flowing entirely inside the gap.

Scientific Reality & Correction

Conduction current (moving physical electrons) stops at the plate surfaces, but it transitions seamlessly into displacement current I_d = ε₀(dΦ_E/dt) within the dielectric. The total current (I_c + I_d) is strictly continuous throughout the entire circuit loop.

Common Misconception

Assuming that because the electric vector 𝐄 and magnetic vector 𝐁 oscillate along mutually perpendicular spatial axes, their temporal phases must also be 90° apart.

Scientific Reality & Correction

In free space electromagnetic waves, 𝐄 and 𝐁 are mutually perpendicular in space, but oscillate strictly IN PHASE in time (Δφ = 0). They reach their peaks, zero-crossings, and troughs at the exact same coordinates and instants.

Common Misconception

Calculating total average energy density as ⟨u⟩ = ε₀ E₀² by forgetting the time-averaging factor of 1/2 from sinusoidal oscillations.

Scientific Reality & Correction

Because ⟨sin²θ⟩ = 1/2, the average electric energy density is ⟨u_E⟩ = (1/4)ε₀ E₀² and magnetic density is ⟨u_B⟩ = (1/4)ε₀ E₀². Their sum yields total average energy density ⟨u⟩ = (1/2)ε₀ E₀² = B₀²/(2μ₀) = ε₀ E_rms².

Common Misconception

Applying P_rad = I/c indiscriminately for all surfaces, including shiny mirrors.

Scientific Reality & Correction

For a perfectly absorbing surface, momentum absorbed per unit time gives P_rad = I/c. For a perfectly reflecting surface, photons bounce back with reversed momentum (Δp = 2p), doubling both force and radiation pressure: P_rad = 2I/c.

Common Misconception

Assuming that any moving electric charge radiates electromagnetic waves.

Scientific Reality & Correction

A charge moving at constant velocity produces steady electric and magnetic fields whose energy remains bound to the charge without detaching. ONLY accelerated charges (dv/dt ≠ 0) or oscillating charges emit radiating electromagnetic waves.

Master Concept and Formula Architecture Blueprint for Electromagnetic Waves

ELECTROMAGNETIC WAVES: ARCHITECTURE & SPECTRUM BLUEPRINT WBCHSE Class 12 Physics • Chapter 5 • Maxwell's Equations, Displacement Current & EM Spectrum E × B c = 3×10⁸ m/s 1. Displacement Current & Ampère-Maxwell Law ▸ Capacitor Charging: Between plates conduction current I_c = 0 ▸ Displacement Current: I_d = ε₀ (dΦ_E / dt) (Continuity restored) ▸ Ampère-Maxwell Law: ∮ B · dl = μ₀(I_c + I_d) ▸ Electric Flux Rate: dΦ_E/dt = (1/ε₀)(dq/dt) ⟹ I_d = dq/dt ★ Total Current Continuity: I_c (in wire) = I_d (between plates) 2. Maxwell's Equations & Wave Velocity ▸ 1. Gauss (E): ∮ E·dA = q/ε₀ | 2. Gauss (B): ∮ B·dA = 0 ▸ 3. Faraday: ∮ E·dl = -dΦ_B/dt | 4. Ampère-Maxwell Equation ▸ Speed of Light in Vacuum: c = 1 / √(μ₀ε₀) ≈ 3 × 10⁸ m/s ▸ Speed in Dielectric: v = 1 / √(με) = c / √(μ_r ε_r) = c / n ★ Field Amplitude Ratio: E₀ / B₀ = c (E & B oscillate in-phase) 3. Energy Density, Poynting Vector & Radiation Pressure ▸ Electric Energy Density: u_E = 1/2 ε₀ E² | Magnetic: u_B = B²/(2μ₀) ▸ Total Average Density: u_avg = 1/2 ε₀ E₀² = B₀²/(2μ₀) (Equally shared) ▸ Poynting Vector: S = (1/μ₀)(E × B) | Intensity: I = u_avg · c ▸ Momentum Delivered: p = U / c (Absorption) | p = 2U / c (Reflection) ★ Radiation Pressure: P_rad = I / c (Absorbed) | 2I / c (Reflected) Energy Partition: u_E = u_B (50% Electric, 50% Magnetic) 4. Electromagnetic Spectrum (Decreasing λ Order) ▸ Radio Waves (λ > 0.1 m): Telecom, cellular networks (LC oscillator) ▸ Microwaves (0.1 m - 1 mm): Radar, cooking (Magnetron/Klystron) ▸ Infrared (1 mm - 700 nm): Heat radiation, thermal cameras, physiotherapy ▸ Visible (400 - 700 nm): VIBGYOR | UV (400 - 1 nm): Sterilization, LASIK ★ X-Rays (1 nm - 10⁻³ nm): Radiography | γ-Rays (< 10⁻³ nm): Nuclear decay Frequency Order: Radio < Micro < IR < Visible < UV < X-ray < Gamma WBCHSE Class 12 Physics • TargetExams Gold Standard Master Architecture

Chapter Summary & 10 Key Takeaways

Takeaway 1
Displacement current I_d = ε₀(dΦ_E/dt) is produced by time-varying electric flux, restoring continuity to Ampère's circuital law across capacitor gaps.
Takeaway 2
The generalized Ampère-Maxwell law ∮ 𝐁 · d𝐥 = μ₀(I_c + I_d) unifies electricity and magnetism, proving that changing electric fields generate magnetic fields.
Takeaway 3
Maxwell's four integral equations form the complete foundations of classical electrodynamics and predict the existence of self-propagating electromagnetic waves.
Takeaway 4
The wave propagation speed in vacuum is c = 1/√(μ₀ε₀) ≈ 3 × 10⁸ m/s, which matches the speed of light, identifying light as an electromagnetic phenomenon.
Takeaway 5
Electromagnetic waves are strictly transverse: electric field 𝐄, magnetic field 𝐁, and propagation vector 𝐤̂ are mutually perpendicular, with 𝐄 × 𝐁 pointing along 𝐤̂.
Takeaway 6
In free space, 𝐄 and 𝐁 oscillate strictly in phase, and their peak amplitudes satisfy the exact ratio E₀ / B₀ = c.
Takeaway 7
Electromagnetic energy is equally partitioned between electric and magnetic fields: ⟨u_E⟩ = ⟨u_B⟩ = (1/4)ε₀ E₀², giving total ⟨u⟩ = (1/2)ε₀ E₀² = B₀²/(2μ₀).
Takeaway 8
The Poynting vector 𝐒 = (1/μ₀)(𝐄 × 𝐁) represents instantaneous directional energy flux, with average wave intensity I = ⟨|𝐒|⟩ = ⟨u⟩ c = (1/2)ε₀ c E₀².
Takeaway 9
Radiation pressure exerted on a normal surface is P_rad = I/c for complete absorption and doubles to P_rad = 2I/c for complete reflection.
Takeaway 10
The electromagnetic spectrum spans from radio waves (λ > 0.1 m), microwaves, infrared, visible (400–700 nm), ultraviolet, X-rays, to gamma rays (λ < 10⁻¹² m).

Check Your Understanding (Diagnostic Practice Questions)

Diagnostic questions testing core conceptual clarity. Answers are hidden initially — solve each problem first, then click to reveal the step-by-step verified solution.

1
A parallel-plate capacitor with circular plates is being charged such that the electric field between the plates increases at a constant rate of 1.5 × 10¹² V/(m·s). If the radius of the plates is 4.0 cm, what is the displacement current between the plates?
Reveal Answer & Explanation
Answer: Plate area A = π × (0.04)² = 5.027 × 10⁻³ m². Displacement current I_d = (8.854 × 10⁻¹²) × (5.027 × 10⁻³) × (1.5 × 10¹²) = 0.0667 A ≈ 66.7 mA.
Use I_d = ε₀ A (dE/dt), where plate area is A = π r².
2
In a plane electromagnetic wave, the electric field oscillates sinusoidally with an amplitude of 750 V/m. Calculate: (a) the peak magnetic field B₀, and (b) the total average energy density of the wave.
Reveal Answer & Explanation
Answer: (a) B₀ = 750 / (3 × 10⁸) = 2.5 × 10⁻⁶ T = 2.5 μT. (b) ⟨u⟩ = 0.5 × (8.854 × 10⁻¹²) × (750)² = 0.5 × (8.854 × 10⁻¹²) × 562,500 ≈ 2.49 × 10⁻⁶ J/m³.
B₀ = E₀ / c, and ⟨u⟩ = (1/2) ε₀ E₀².
3
The average solar energy flux reaching the upper atmosphere of the Earth (solar constant) is approximately 1380 W/m². Assuming normal incidence on a perfectly absorbing solar collector of area 1.5 m², calculate the radiation force exerted on the collector.
Reveal Answer & Explanation
Answer: Total incident power P = I · A = 1380 × 1.5 = 2070 W. Radiation force F = 2070 / (3 × 10⁸) = 6.90 × 10⁻⁶ N = 6.9 μN.
For complete absorption, radiation force F = P_power / c = (I · A) / c.
4
State the wavelength range of microwaves and name the specialized vacuum tubes used to generate them.
Reveal Answer & Explanation
Answer: Wavelength range: 0.1 m to 1 mm (frequency 1 GHz to 300 GHz). They are produced by specialized vacuum tubes like magnetrons, klystrons, and traveling-wave tubes (TWT), or solid-state Gunn diodes.
Microwaves lie between radio waves and infrared radiation.
5
Why are infrared rays commonly referred to as 'heat waves'? Which greenhouse gas in Earth's atmosphere is primarily responsible for absorbing terrestrial infrared radiation?
Reveal Answer & Explanation
Answer: Infrared rays are called heat waves because water molecules and other polar bonds in matter readily absorb them, converting their energy directly into internal thermal vibrational energy. Carbon dioxide (CO₂) and water vapor (H₂O) are the primary greenhouse gases absorbing terrestrial infrared radiation.
Infrared wavelengths correspond to molecular vibrational frequencies in water and organic matter.
Finished Studying This Chapter?
READY TO PRACTICE?

Timed CBT Practice Tests (Exam Simulator)

Put your concepts to the test with official curriculum-aligned Foundation and Advanced practice tests. Get instant accuracy scores, time metrics, and step-by-step verified explanations.

STAY UPDATED

Get the Latest Updates

New test series, syllabus updates, exam notifications and more.

Syllabus
Updates
Exam
Alerts
Study
Resources